1.1.A.3 用原子质量单位(amu)表示单个原子或分子的质量是有用的,因为物质一个粒子(原子或分子)或式量单位的平均质量(以 amu 为单位),在数值上总是等于该物质的摩尔质量(以 g 为单位)。因此,物质的质量与其所含粒子数量之间存在定量关系。
公式:$n = m/M$
来源:College Board AP 课程与考试说明
English
Because atoms are far too small to count, chemists count in moles 摩尔. One mole contains Avogadro's number 阿伏伽德罗常数 of particles, approximately $6.022\times10^{23}$. The molar mass 摩尔质量 (grams per mole; use atomic masses from the periodic table and add them for a compound) converts between mass and moles:
$$n=\frac{m}{M}.$$
Moles are the bridge between the lab (grams you weigh) and the equation (particles that react).
The mole is the hub: convert between mass, particles, gas volume, and concentration
Worked example. How many moles, and how many molecules, are in $36.0\ \text{g}$ of water ($M=18.0\ \text{g/mol}$)?
排除说明: AP 考试不考核对含有多种元素的样品质谱的解读,也不考核除单电荷单原子离子以外的其他物种所产生的峰的分析。
来源:College Board AP 课程与考试说明
English
Mass spectrometry
A mass spectrometer 质谱仪 separates ions by mass-to-charge ratio, giving a mass spectrum 质谱. For singly charged atomic ions, its peaks identify each isotope 同位素 (same element, different neutron count), with signals showing their relative abundance 相对丰度. The element's average atomic mass is the abundance-weighted average of its isotope masses.
Relative atomic mass is the abundance-weighted average of the isotopesThe mass spectrum of chlorine: two isotopes with different abundances
Worked example. Chlorine is $75.8\%$ chlorine-35 and $24.2\%$ chlorine-37. Its average atomic mass is
$$A_r=(35)(0.758)+(37)(0.242)=26.5+8.95=35.5.$$
The average lies closer to $35$ because that isotope is more abundant – which is why the periodic-table value is $35.5$, not a whole number.
The percent composition 百分组成 of a compound is each element's mass fraction. From it you find the empirical formula 实验式 (simplest whole-number ratio of atoms) by converting each element's mass to moles and dividing by the smallest. The molecular formula 分子式 is a whole-number multiple of the empirical formula, found from the molar mass.
Finding the empirical formula: mass to moles, divide by the smallest, read the ratio
Worked example. A compound is $40.0\%$ C, $6.7\%$ H, and $53.3\%$ O by mass. Assuming $100\ \text{g}$, convert each mass to moles and divide by the smallest:
so the empirical formula is $\text{CH}_2\text{O}$. If the molar mass were $180\ \text{g/mol}$ ($=6\times30$), the molecular formula would be $\text{C}_6\text{H}_{12}\text{O}_6$ – glucose.
Unlike a pure compound, a mixture 混合物 has variable composition – its parts keep their own identities. Describe a mixture by the mass or mole fraction of each component; these do not follow a fixed formula. Spectroscopy (like PES or absorption) can measure how much of each component is present.
An atom is a tiny nucleus 原子核 (protons and neutrons) surrounded by electrons in shells and subshells (s, p, d, f). The electron configuration 电子排布 lists how electrons fill these, lowest energy first (e.g. $1s^2\,2s^2\,2p^6$). For main-group atoms, the outer-shell electrons are the valence electrons 价电子 that take part in bonding. Transition-metal bonding can also involve electrons in an inner d subshell. Coulomb's law explains their energies: electrons closer to, and less shielded from, the nucleus are held more tightly.
An atom: a tiny nucleus of protons and neutrons, with electrons in shellsFlame tests: each metal ion gives its own colour because heat excites its electrons and, as they drop back down, they emit light of specific wavelengths
Worked example. Write the electron configuration of sulfur ($Z=16$). Fill subshells in order until $16$ electrons are placed: $1s^2\,2s^2\,2p^6\,3s^2\,3p^4$. The $3s$ and $3p$ electrons (six in total) are the valence electrons, so sulfur tends to gain two electrons to complete its octet.
The periodic table organises elements by atomic structure — electron configuration explains the patterns
Photoelectron spectroscopy 光电子能谱 (PES) measures the energy needed to remove electrons from each subshell. Each peak is a subshell: its position gives the binding energy (how tightly held) and its height gives the number of electrons in it. PES data let you read an element's electron configuration and confirm shell structure directly.
Successive ionisation energies reveal the shell structure through big jumpsThe photoelectron spectrum of neon: one peak per subshell, height set by electron count
Atoms gain, lose, or share valence electrons to reach stable configurations. Metals (low ionization energy) lose electrons to form cations 阳离子; nonmetals gain electrons to form anions 阴离子. Oppositely charged ions attract into an ionic compound 离子化合物, whose formula balances the charges to make the whole neutral. For example, aluminium ($3+$) and oxide ($2-$) combine as $\text{Al}_2\text{O}_3$ so the $+6$ and $-6$ cancel.
Common mistakes.
Taking the simple average of the isotope masses. Weight each mass by its abundance: chlorine is 35.5, not 36.
Rounding a mole ratio such as $1:1.33$ to $1:1$. A decimal near $.33$, $.5$ or $.67$ means you multiply: $1:1.33\times3 = 3:4$.
Reading the tallest PES peak as the most tightly held electrons. Peak height gives the number of electrons; peak position (binding energy) gives how tightly they are held, and the core $1s$ peak is furthest out.
Explaining a smaller radius across a period by "more shells". Across a period the shell count stays the same; the nuclear charge rises while shielding hardly changes, so the electrons are pulled closer.
Removing a transition metal's $3d$ electrons before its $4s$ electrons when it forms an ion. The $4s$ electrons are lost first: $\text{Fe}^{2+}$ is $[\text{Ar}]\,3d^6$, not $[\text{Ar}]\,4s^2\,3d^4$.
Saying ionization energy falls down a group because the nucleus has less charge. The nuclear charge rises, but the outer electron is further away and more shielded, so it is held less tightly.
Use the mole as the hub: convert grams↔moles with $n=m/M$ and moles↔particles with Avogadro's number.
Relative atomic mass is the abundance-weighted average of the isotopes — it lies closer to the more abundant one, not halfway.
For an empirical formula, turn each element's mass into moles and divide by the smallest; scale up to whole numbers.
Read periodic trends from nuclear charge and shielding: atomic radius decreases across a period, ionisation energy and electronegativity increase across (and up).
Fill electron configurations in energy order; the outer valence electrons control the chemistry.