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生命的化学

AP 生物 · 知识点 1

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9:24

生命化学

把冰块放进玻璃杯,它会浮起来。这听起来很普通,但其实很奇怪。几乎所有其他固体都会沉入自己的液体中,因为冻结会使……

英语旁白 · 英中内嵌字幕

1.1

水的结构与氢键

教学大纲

核心概念4 — 系统相互作用: 生物系统之间相互作用,这些系统及其相互作用表现出复杂的特性。

学习目标 1.1.A: 解释由于极性和氢键而形成的水的性质如何影响其生物学功能。

  • 1.1.A.1 生命系统依赖于水的性质来维持生命。
    • 1.1.A.1.i 水具有极性,这是由于在水分子内部氢与氧之间形成极性共价键所致。这种极性促进了生物分子之间及内部的氢键形成。
    • 1.1.A.1.ii 水具有较高的比热容,这使得生物体能够维持恒定的体温(内环境稳态)。
    • 1.1.A.1.iii 水具有较高的汽化热,这允许通过蒸发冷却周围环境。在生物体内,这一特性使得体温得以维持。
  • 1.1.A.2 相邻极性水分子之间的氢键产生了内聚力、附着力和表面张力。

来源:College Board AP 课程与考试说明

English

Ice floats, so lakes freeze from the top and fish survive the winter underneath. A single wrong amino acid among hundreds in haemoglobin causes sickle cell disease. Both start at the scale of atoms and bonds, which is where this unit begins.

Ice floats on water because hydrogen bonding makes solid water less dense than liquid water
Ice floats on water because hydrogen bonding makes solid water less dense than liquid water

Water is polar 极性: its oxygen pulls electrons more strongly than its hydrogens, giving a slightly negative O and slightly positive H. This lets water molecules form hydrogen bonds 氢键 with each other, which explains water's life-supporting properties:

  • Cohesion 内聚力 and adhesion 附着力 (surface tension, capillary action, water rising in plants),
  • high specific heat 比热容 (resists temperature change, stabilizing organisms),
  • high heat of vaporization (evaporative cooling),
  • ice floating (less dense solid), and being a great solvent for polar and ionic substances.
A hydrogen bond between two polar water molecules
A hydrogen bond between two polar water molecules
探索

探索共价键如何共享电子

逐步观察两个原子重叠以共享一对电子,从而使每个原子达到满壳层。在 $\text{H}_2$ 中,两个原子平等地拉拽,因此键是非极性的——这种对比使得水的不平等共享(及其 $\delta^+/\delta^-$ 偶极矩)如此重要。

词汇 训练
English 中文 拼音
polar/ˈpəʊlə/ 极性 jí xìng
hydrogen bonds/ˈhaɪdrədʒn bɒndz/ 氢键 qīng jiàn
Cohesion/kəʊˈhiːʒn/ 内聚力 nèi jù lì
adhesion/ədˈhiːʒn/ 附着力 fù zhuó lì
specific heat/spəˈsɪfɪk hiːt/ 比热容 bǐ rè róng
1.2

生命元素

教学大纲

核心概念 2 — 能量代谢: 生物体利用能量和分子构建单元来生长、繁殖并维持动态稳态。

学习目标 1.2.A: 描述生物体所需大分子的组成。

  • 1.2.A.1 来自环境的原子和分子是构建新分子所必需的。碳、氢和氧是用于构建碳水化合物、蛋白质、脂类和核酸等生物分子中最普遍的元素。此外:
    • 1.2.A.1.i 硫用于蛋白质的构建。
    • 1.2.A.1.ii 磷用于磷脂(一种脂类)和核酸的构建。
    • 1.2.A.1.iii 氮用于核酸的构建。

来源:College Board AP 课程与考试说明

English

Living matter is built mostly from a few elements – carbon, hydrogen, oxygen, nitrogen, phosphorus, and sulfur. Carbon 碳 is central because it forms four stable covalent bonds, building long chains, branches, and rings – the skeletons of organic biological molecules.

Carbohydrates and fats contain carbon, hydrogen, and oxygen; proteins also contain nitrogen
Carbohydrates and fats contain carbon, hydrogen, and oxygen; proteins also contain nitrogen
Which elements each macromolecule contains: proteins need N and S, nucleic acids N and P
Which elements each macromolecule contains: proteins need N and S, nucleic acids N and P
探索

主要元素还是微量元素?

按照元素在生物体中占比多少来分类。少数几种元素占主导;其他的在极微量下也至关重要。

词汇 训练
English 中文 拼音
Carbon/ˈkɑːbən/ 碳 tàn
1.3

大分子导论

教学大纲

核心概念4 — 系统相互作用: 生物系统之间存在相互作用,这些系统及其相互作用表现出复杂的特性。

学习目标 1.3.A: 描述构建和分解生物大分子的化学反应。

  • 1.3.A.1 水解是一种涉及共价键断裂的化学反应。这种反应将分子分解为更小的分子。当向聚合物中单体之间的键加入水时,该键便会断裂。水分子中的氢离子被添加到其中一个单体上,而水分子的羟基则被添加到另一个单体上,从而完成反应。
  • 1.3.A.2 脱水缩合是指两个较小的分子通过共价键结合的过程。一个氢离子从一个单体上脱去,一个羟基从另一个单体上脱去。这导致反应物失去相当于一分子水的部分,并使剩余的两个单体连接起来。许多单体的连接过程称为聚合。

来源:College Board AP 课程与考试说明

English

Many large biological molecules – macromolecules 大分子 – are polymers 聚合物 built from repeating monomers 单体. Lipids are also studied among the major biological molecule classes, but are not generally repeating-unit polymers. Cells join monomers by dehydration synthesis 脱水缩合 (removing water to form a bond) and break polymers by hydrolysis 水解 (adding water). Four classes: carbohydrates, lipids, nucleic acids, and proteins.

Dehydration synthesis builds polymers and releases water; hydrolysis reverses it
Dehydration synthesis builds polymers and releases water; hydrolysis reverses it
探索

通过单体探索四大类生物大分子

通过将构建它的单体(糖、核苷酸或氨基酸)与每个线索匹配,将其分类到正确的生物大分子类别中——并注意脂质是那个不是真正聚合物的例外。

词汇 训练
English 中文 拼音
macromolecules/ˈmækrəmɒlɪkjuːlz/ 大分子 dà fēn zǐ
polymers/ˈpɒlɪməz/ 聚合物 jù hé wù
monomers/ˈmɒnəʊməz/ 单体 dān tǐ
dehydration synthesis/ˌdiːhaɪˈdreɪʃn ˈsɪnθəsɪs/ 脱水缩合 tuō shuǐ suō hé
hydrolysis/haɪˈdrɒləsɪs/ 水解 shuǐ jiě
1.4

碳水化合物

教学大纲

核心概念 4 — 系统相互作用: 生物系统之间存在相互作用,这些系统及其相互作用表现出复杂的特性。

学习目标 1.4.A: 描述碳水化合物的结构与功能。

  • 1.4.A.1 单糖(简单糖)是多糖(复杂碳水化合物)的单体。这些单体通过共价键连接形成聚合物(如复杂碳水化合物),其结构可以是线性的或分支的。
    • 示例(适用于 1.4.A.1):
      • 纤维素
      • 淀粉
      • 糖原
    • 排除说明: 特定碳水化合物聚合物的分子结构不在 AP 考试范围内。

来源:College Board AP 课程与考试说明

English

Carbohydrates 碳水化合物 are made of sugar monomers (monosaccharides 单糖 like glucose). They store energy (starch, glycogen) and provide structure (cellulose 纤维素 in plant walls). Many small sugars are polar and dissolve readily in water. Large carbohydrate polymers differ: cellulose, for example, does not dissolve readily in water.

The shapes of storage polysaccharides (starch, glycogen) and structural cellulose
The shapes of storage polysaccharides (starch, glycogen) and structural cellulose
探索

给糖分类

按照含有多少个糖单元,给每种碳水化合物分组。

词汇 训练
English 中文 拼音
Carbohydrates/ˌkɑːbəʊˈhaɪdreɪts/ 碳水化合物 tàn shuǐ huà hé wù
monosaccharides/ˈmɒnəʊsækɑːraɪdz/ 单糖 dān táng
cellulose/ˈseljuːləʊs/ 纤维素 xiān wéi sù
1.5

脂质

教学大纲

核心概念4 — 系统相互作用: 生物系统之间存在相互作用,这些系统及其相互作用表现出复杂的特性。

学习目标 1.5.A: 描述脂质的结构与功能。

  • 1.5.A.1 脂质通常是非极性、疏水性分子,其结构和功能源于其亚组分的组装方式。脂肪酸可分为饱和脂肪酸和不饱和脂肪酸。
    • 1.5.A.1.i 饱和脂肪酸中碳原子之间仅含单键。
    • 1.5.A.1.ii 不饱和脂肪酸在碳原子之间至少含有一个双键,这会导致碳链发生弯曲。
    • 1.5.A.1.iii 脂肪酸尾部含有的双键越多,该脂质就越不饱和。
    • 1.5.A.1.iv 脂质的不饱和程度越高,其在室温下越呈液态。
  • 1.5.A.2 脂质为生物体提供多种功能。脂质的例子包括脂肪、类固醇(包括胆固醇)和磷脂。
    • 1.5.A.2.i 脂肪提供能量储存并支持细胞功能。在某些情况下,它们还能提供隔热作用以帮助哺乳动物保持体温。
    • 1.5.A.2.ii 类固醇是激素,支持包括生长发育、能量代谢和稳态在内的生理功能。
    • 1.5.A.2.iii 胆固醇为动物细胞膜提供必要的结构稳定性。
    • 1.5.A.2.iv 磷脂聚集形成血浆膜和细胞膜中的脂双层。
    • 排除说明: 特定脂质的分子结构不在AP考试范围内。

来源:College Board AP 课程与考试说明

English

Lipids 脂质 contain large nonpolar, water-repelling (hydrophobic 疏水) regions. Some also have polar regions, so they are not uniformly nonpolar. They include fats (long-term energy storage), phospholipids 磷脂 (which build membranes), and steroids. A phospholipid has a polar "head" and nonpolar "tails," the key to the cell membrane.

A phospholipid has a polar head and two nonpolar tails, so phospholipids form a bilayer
A phospholipid has a polar head and two nonpolar tails, so phospholipids form a bilayer
A triglyceride: glycerol joined to three fatty acids
A triglyceride: glycerol joined to three fatty acids
探索

给脂质分类

按照结构和在身体里的主要作用,给每种脂质分组。

词汇 训练
English 中文 拼音
Lipids/ˈlɪpɪdz/ 脂质 zhī zhì
hydrophobic/ˌhaɪdrəˈfəʊbɪk/ 疏水 shū shuǐ
phospholipids/ˈfɒsfəlɪpɪdz/ 磷脂 lín zhī
1.6

核酸

教学大纲

核心概念3 — 信息的存储与传递: 生命系统能够存储、检索、传递并对维持生命过程所需的信息作出响应。

学习目标 1.6.A: 描述 DNA 和 RNA 的结构与功能。

  • 1.6.A.1 在核酸(DNA 和 RNA)中,生物信息以核苷酸单体的序列形式编码。每个核苷酸包含以下结构组分:一个五碳糖(脱氧核糖或核糖)、一个磷酸基团和一个含氮碱基(腺嘌呤、胸腺嘧啶、鸟嘌呤、胞嘧啶或尿嘧啶)。
  • 1.6.A.2 核酸具有线性的核苷酸序列,其两端由核苷酸中糖的 3'(三 prime)羟基和 5'(五 prime)磷酸基团定义。在核酸合成过程中,核苷酸被添加到生长链的 3' 端,从而在核苷酸之间形成共价键。
    • 排除声明: 特定核苷酸的分子结构超出了 AP 考试的范围。
  • 1.6.A.3 DNA 的结构为反向平行的双螺旋,两条核苷酸链沿相反的 5' 至 3' 方向排列。在 DNA 中,腺嘌呤核苷酸通过氢键与胸腺嘧啶核苷酸配对(A-T),胞嘧啶核苷酸通过氢键与鸟嘌呤核苷酸配对(C-G)。在 RNA 中,腺嘌呤与尿嘧啶配对(A-U)。
  • 1.6.A.4 DNA 和 RNA 之间的结构差异包括:
    • 1.6.A.4.i DNA 含有脱氧核糖,而 RNA 含有核糖。
    • 1.6.A.4.ii DNA 含有含氮碱基胸腺嘧啶,而 RNA 含有含氮碱基尿嘧啶。
    • 1.6.A.4.iii DNA 通常为双链,而 RNA 通常为单链。

来源:College Board AP 课程与考试说明

English
Space-filling model of the DNA double helix (NHGRI)
Space-filling model of the DNA double helix (NHGRI)

Nucleic acids 核酸 (DNA and RNA) store and carry genetic information. Their monomers are nucleotides 核苷酸, each a sugar, a phosphate, and a nitrogen base. The base sequence encodes instructions; cellular DNA is usually double-stranded, while RNA is usually single-stranded and can fold into paired regions.

Complementary base pairing holds the two antiparallel strands of DNA together
Complementary base pairing holds the two antiparallel strands of DNA together
探索

探索互补碱基配对

沿 DNA 模板逐步操作,观察每个碱基通过互补碱基配对与其伙伴配对($A$ 与 $T$,$G$ 与 $C$)——这条规则使得任意一条链都能作为模板重建另一条链。

词汇 训练
English 中文 拼音
Nucleic acids/njuːˈklɪɪk ˈæsɪdz/ 核酸 hé suān
nucleotides/ˈnjuːklɪɒtaɪdz/ 核苷酸 hé gān suān
1.7

蛋白质

教学大纲

核心概念 3 — 信息的存储与传递: 生命系统存储、检索、传递和响应对生命过程至关重要的信息。

学习目标 1.7.A: 描述蛋白质的结构和功能。

  • 1.7.A.1 蛋白质由通过共价(肽)键连接而成的氨基酸线性链组成,该键形成于一个氨基酸的羧基($-\text{COOH}$)与下一个氨基酸的氨基($-\text{NH}_2$)之间,从而产生不断增长的肽链。
  • 1.7.A.2 氨基酸由一个中心碳原子组成,该碳原子上共价结合有一个氢原子、一个羧基、一个氨基和一个可变的 R 基团。氨基酸的 R 基团可以根据三种可能的化学性质进行分类:疏水性/非极性、亲水性/极性或离子性。这些 R 基团的相互作用决定了蛋白质该区域的结构和功能。
  • 1.7.A.3 蛋白质中氨基酸的特定序列决定了多肽的一级结构以及蛋白质的整体形状。
    • 排除声明: 氨基酸的分子结构不在 AP 考试的范围内。
  • 1.7.A.4 蛋白质的二级结构是通过氨基酸链的多肽骨架原子之间的相互作用形成的局部折叠而产生的。氢键形成了如 α-螺旋和 β-折叠片等形状。
  • 1.7.A.5 蛋白质三级结构的三维形状源于氢键、疏水相互作用、离子相互作用或二硫键的形成。
  • 1.7.A.6 四级结构源于多个多肽之间的相互作用。蛋白质的所有四个结构水平决定了其功能。

来源:College Board AP 课程与考试说明

English
Haemoglobin quaternary structure: four folded polypeptide chains, each holding a haem group
Haemoglobin quaternary structure: four folded polypeptide chains, each holding a haem group

Proteins 蛋白质 are polymers of amino acids 氨基酸 joined by peptide bonds 肽键. Their amino-acid sequence contributes to their 3-D shape (primary, secondary and tertiary structure; quaternary structure applies when multiple polypeptide chains assemble), and shape determines function – as enzymes, transporters, receptors, and structural parts. Changing the environment (heat, pH) can denature 变性 a protein, unfolding it and stopping its function.

An amino acid, and the peptide bond formed by condensation
An amino acid, and the peptide bond formed by condensation
The four levels of protein structure
The four levels of protein structure

Worked example. Building a polymer from 10 monomers by dehydration synthesis forms 9 bonds and releases 9 water molecules — one per bond, so $N$ monomers release $N-1$ waters. Hydrolysis reverses this exactly: adding those 9 waters breaks the polymer back into 10 monomers. This is why biosynthesis (dehydration) and digestion (hydrolysis) are chemical opposites.

Worked example (Chargaff's rule). In double-stranded DNA, A pairs with T and C pairs with G, so the amount of A equals the amount of T, and C equals G. A sample is $30\%$ adenine. Then thymine is also $30\%$, which leaves $40\%$ for C and G together: $20\%$ each. The rule fails for single-stranded RNA, which has no partner strand.

Worked example (tracing elements). Which molecules would take up a radioactive label?

  • Sulfur ($^{35}\text{S}$) is found in some amino acids, so it labels proteins, not DNA.
  • Phosphorus ($^{32}\text{P}$) is in every nucleotide's phosphate group, so it labels nucleic acids, and also phospholipids, but not most proteins.
  • Nitrogen is in amino acids and in nucleotide bases, so it labels both proteins and nucleic acids, but not carbohydrates or fats.

This logic is how Hershey and Chase showed that DNA, not protein, enters a cell to carry the genes.

Worked example (predicting a change in shape). A protein's interior is packed with nonpolar R groups, away from water. A mutation replaces one interior nonpolar amino acid with a charged one. Predict the effect: the charged group is attracted to water and disrupts the hydrophobic core, so the tertiary structure is likely to change. Because shape determines function, the protein may work less well, or not at all.

Common mistakes.

  • Calling the O–H bond inside a water molecule a hydrogen bond. That bond is covalent; hydrogen bonds are the weaker attractions between neighbouring water molecules.
  • Saying dehydration synthesis adds water. Dehydration synthesis removes a water molecule for each bond; hydrolysis adds one to break it.
  • Calling lipids polymers. Fats and phospholipids are not chains of repeating monomers, though they are major biological molecules.
  • Saying DNA's two strands run the same way. They are antiparallel 反向平行: one runs 5′→3′, the other 3′→5′.
  • Saying a protein's shape comes from its peptide bonds alone. The R groups and their interactions (hydrogen bonds, ionic bonds, hydrophobic clustering, disulfide bridges) fold the chain into its tertiary shape.
  • Labelling DNA with $^{35}\text{S}$. DNA contains no sulfur; sulfur labels proteins and phosphorus labels nucleic acids.
词汇 训练
English 中文 拼音
Proteins/ˈprəʊtiːnz/ 蛋白质 dàn bái zhì
amino acids/əˈmiːnəʊ ˈæsɪdz/ 氨基酸 ān jī suān
peptide bonds/ˈpeptaɪd bɒndz/ 肽键 tài jiàn
denature/ˈdenətʃə/ 变性 biàn xìng
antiparallel/ˌæntɪˈpærəlel/ 反向平行 fǎn xiàng píng xíng
1.7

Practice

English

Answer each before reading the answers below.

  1. Explain, using hydrogen bonds, why sweating cools the body.
  2. A DNA sample contains $18\%$ guanine. Find the percentages of the other three bases.
  3. How many water molecules are released when 25 amino acids join into one polypeptide?
  4. A cell is grown with radioactive $^{32}\text{P}$. Which two kinds of molecule become radioactive?
  5. A student says: "Boiling an egg breaks the peptide bonds in its proteins." Correct the student.
1.7

答案

English
  1. Evaporating water must break many hydrogen bonds, which takes a large amount of energy (a high heat of vaporization). That energy is taken from the skin as the sweat evaporates, cooling it.
  2. C $=18\%$, so G and C together are $36\%$, leaving $64\%$ for A and T: A $=32\%$ and T $=32\%$.
  3. $25-1=24$ water molecules, one per peptide bond.
  4. Nucleic acids (DNA and RNA) and phospholipids, the two kinds containing phosphate groups.
  5. Heat denatures the protein: it breaks the weak bonds (such as hydrogen bonds) that hold the folded shape. The peptide bonds, and so the primary structure, stay intact.
1.7

考试技巧

English
  • Trace every property of water back to its polarity and hydrogen bonding (cohesion, high specific heat, solvent power).
  • Know the four macromolecule classes and their monomers; polymers are built by dehydration synthesis and broken by hydrolysis.
  • For proteins, structure (shape) determines function — heat or a pH change denatures them and stops them working.
  • In DNA the bases pair A–T and C–G on antiparallel strands; RNA is single-stranded and uses U.
  • Link each molecule to its role (carbohydrates: energy/structure; lipids: membranes/storage; nucleic acids: information).

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