跳到主要内容

元素周期表:化学周期性

A-Level 化学 · 知识点 9

本主题的视频课程 打开视频页面
8:43

元素周期表:化学周期性

钠和氩坐在元素周期表的同一行,中间只有六个元素。将钠投入冷水中,它会熔化成闪亮的球体……

英语旁白 · 英中内嵌字幕

9.1

第三周期元素物理性质的周期性

教学大纲
  1. 描述(并指出其周期性变化)原子半径、离子半径、熔点和导电性的定性变化
  2. 从元素的结构和键合角度解释熔点和导电性的变化

来源:Cambridge International 教学大纲

English
A periodic table display
Properties repeat in a regular pattern across each period of the table.

Periodicity 周期性 means that properties repeat in a regular pattern as you go across each period 周期 of the Periodic Table. Period 3 (Na to Ar) is the standard example.

A row of atoms from sodium to chlorine shrinking from left to right, with nuclear charge rising from +11 to +17
Atomic radius decreases across Period 3: the rising nuclear charge pulls the same outer shell inwards
Property Trend across Period 3
atomic radius 原子半径 gets smaller (more nuclear charge pulls the same shell in)
ionic radius 离子半径 positive ions are small; from $\text{P}^{3-}$ onwards the negative ions are larger
melting point 熔点 rises to a peak at silicon, then falls sharply
electrical conductivity 导电性 high for Na, Mg, Al; almost zero from Si onwards

The melting point and conductivity follow from the structure and bonding:

  • Na, Mg, Al are giant metallic 金属晶体. Melting points rise (Na → Al) because each atom gives more delocalised electrons and the ions get smaller, so the bonding is stronger. They conduct well.
  • Si is giant molecular 原子晶体 (giant covalent). It has the highest melting point, because strong covalent bonds must be broken. It barely conducts.
  • P, S, Cl, Ar are simple molecular 分子晶体 (or single atoms). Their melting points are low, because the only forces that break are the weak van der Waals' forces 范德华力 between the molecules - the strong covalent bonds inside each molecule are never broken at all. They do not conduct.

Name van der Waals' forces when you explain that drop: it is the marking point, and "the covalent bonds are weak" is the error that loses it. Melting $\text{S}_8$ pulls whole molecules apart from each other; it does not touch a single $\text{S–S}$ bond. Their sizes still follow the molecule: $\text{S}_8$ melts higher than $\text{P}_4$ because it is bigger, with more electrons and so stronger van der Waals' forces, while $\text{Ar}$ (a single atom) is lowest of all.

A graph of melting point across Period 3 rising through the metals to a sharp peak at silicon, then dropping to the simple molecular elements
Melting point across Period 3 peaks at silicon (giant covalent); it is high for the metals and low for the simple molecular elements
探索

第3周期的趋势

在原子半径、电离能和熔点之间切换,并跨越第3周期,以观察每种周期性趋势。

词汇 训练
English 中文 拼音
periodicity/ˌpɪərɪˌɒˈdɪsɪti/ 周期性 zhōu qī xìng
period/ˈpɪərɪəd/ 周期 zhōu qī
atomic radius/əˈtɒmɪk ˈreɪdɪəs/ 原子半径 yuán zi bàn jìng
ionic radius/aɪˈɒnɪk ˈreɪdɪəs/ 离子半径 lí zi bàn jìng
melting point/ˈmeltɪŋ pɔɪnt/ 熔点 róng diǎn
electrical conductivity/ɪˈlektrɪkl kɒndəkˈtɪvɪti/ 导电性 dǎo diàn xìng
giant metallic/ˈdʒaɪənt məˈtælɪk/ 金属晶体 jīn shǔ jīng tǐ
giant molecular/ˈdʒaɪənt məˈlekjʊlə/ 原子晶体 yuán zi jīng tǐ
simple molecular/ˈsɪmpl məˈlekjʊlə/ 分子晶体 fēn zǐ jīng tǐ
van der Waals' forces/ˈvændɜː wɑːlz ˈfɔːsɪz/ 范德华力 fàn dé huá lì
9.2

第三周期元素化学性质的周期性

教学大纲
  1. 描述并写出各元素与氧气(生成 $\text{Na}_2\text{O}$、$\text{MgO}$、$\text{Al}_2\text{O}_3$、$\text{P}_4\text{O}_{10}$、$\text{SO}_2$)、氯气(生成 $\text{NaCl}$、$\text{MgCl}_2$、$\text{AlCl}_3$、$\text{SiCl}_4$、$\text{PCl}_5$)以及水(仅限 $\text{Na}$ 和 $\text{Mg}$)反应的方程式。
  2. 阐述并解释氧化物(仅限 $\text{Na}_2\text{O}$、$\text{MgO}$、$\text{Al}_2\text{O}_3$、$\text{P}_4\text{O}_{10}$、$\text{SO}_2$ 和 $\text{SO}_3$)及氯化物(仅限 $\text{NaCl}$、$\text{MgCl}_2$、$\text{AlCl}_3$、$\text{SiCl}_4$、$\text{PCl}_5$)中氧化数的变化规律,并结合其最外层(价层)电子进行说明。
  3. 描述并写出氧化物 $\text{Na}_2\text{O}$、$\text{MgO}$、$\text{Al}_2\text{O}_3$、$\text{SiO}_2$、$\text{P}_4\text{O}_{10}$、$\text{SO}_2$ 和 $\text{SO}_3$ 与水发生的反应(如有),包括所得溶液的大致 pH 值。
  4. 描述、解释并写出氧化物 $\text{Na}_2\text{O}$、$\text{MgO}$、$\text{Al}_2\text{O}_3$、$\text{P}_4\text{O}_{10}$、$\text{SO}_2$ 和 $\text{SO}_3$ 以及氢氧化物 $\text{NaOH}$、$\text{Mg(OH)}_2$ 和 $\text{Al(OH)}_3$ 的酸碱性质;在相关情况下,需涉及两性行为及其与酸和碱的反应(仅限氢氧化钠)。
  5. 描述、解释并写出氯化物 $\text{NaCl}$、$\text{MgCl}_2$、$\text{AlCl}_3$、$\text{SiCl}_4$、$\text{PCl}_5$ 与水的反应,包括所得溶液的大致 pH 值。
  6. 从化学键合和电负性的角度,解释 9.2.2、9.2.3、9.2.4 和 9.2.5 中的变化与趋势。
  7. 根据化学和物理性质的观察结果,推断氯化物和氧化物中可能存在的化学键类型。

来源:Cambridge International 教学大纲

English

Reactions with oxygen, chlorine and water

With oxygen:

$$4\text{Na} + \text{O}_2 \rightarrow 2\text{Na}_2\text{O} \qquad 2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO} \qquad 4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3$$
$$\text{P}_4 + 5\text{O}_2 \rightarrow \text{P}_4\text{O}_{10} \qquad \text{S} + \text{O}_2 \rightarrow \text{SO}_2$$

With chlorine:

$$2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl} \qquad \text{Mg} + \text{Cl}_2 \rightarrow \text{MgCl}_2 \qquad 2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3$$
$$\text{Si} + 2\text{Cl}_2 \rightarrow \text{SiCl}_4 \qquad 2\text{P} + 5\text{Cl}_2 \rightarrow 2\text{PCl}_5$$

With water (only Na and Mg react):

$$2\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2 \qquad \text{Mg} + 2\text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2 + \text{H}_2$$

Sodium reacts fast; magnesium reacts only very slowly with cold water.

Oxidation number of the oxides and chlorides

The oxidation number 氧化数 of the Period 3 element in its oxide or chloride rises across the period, because it equals the number of outer-shell (valence shell 价层) electrons 电子 the atom uses in bonding:

Oxides $\text{Na}_2\text{O}$ $\text{MgO}$ $\text{Al}_2\text{O}_3$ $\text{P}_4\text{O}_{10}$ $\text{SO}_2$ / $\text{SO}_3$
oxidation number $+1$ $+2$ $+3$ $+5$ $+4$ / $+6$

The chlorides $\text{NaCl}$, $\text{MgCl}_2$, $\text{AlCl}_3$, $\text{SiCl}_4$, $\text{PCl}_5$ show oxidation numbers $+1$ to $+5$ in the same way.

Oxides with water, and acid–base behaviour

Across the period the oxides 氧化物 change from basic to acidic:

A coloured bar split into basic, amphoteric and acidic regions, with the Period 3 oxides placed along it from Na2O to SO3 and approximate pH values
The Period 3 oxides change from basic (the metals) through amphoteric (Al$_2$O$_3$) to acidic (the non-metals)
Oxide With water Acid–base nature Approximate pH
$\text{Na}_2\text{O}$ $\text{Na}_2\text{O} + \text{H}_2\text{O} \rightarrow 2\text{NaOH}$ basic 13–14
$\text{MgO}$ $\text{MgO} + \text{H}_2\text{O} \rightarrow \text{Mg(OH)}_2$ basic 9–10
$\text{Al}_2\text{O}_3$ insoluble amphoteric 两性 7
$\text{SiO}_2$ insoluble weakly acidic 7
$\text{P}_4\text{O}_{10}$ $\text{P}_4\text{O}_{10} + 6\text{H}_2\text{O} \rightarrow 4\text{H}_3\text{PO}_4$ acidic 1–2
$\text{SO}_3$ $\text{SO}_3 + \text{H}_2\text{O} \rightarrow \text{H}_2\text{SO}_4$ strongly acidic 0–1

Metal oxides (left) are basic; non-metal oxides (right) are acidic. $\text{Al}_2\text{O}_3$ and its hydroxide 氢氧化物 $\text{Al(OH)}_3$ are amphoteric — they react with both acids and bases:

$$\text{Al}_2\text{O}_3 + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2\text{O}$$
$$\text{Al}_2\text{O}_3 + 2\text{NaOH} + 3\text{H}_2\text{O} \rightarrow 2\text{NaAl(OH)}_4$$
Aluminium oxide in the centre reacting to the left with acid and to the right with base
Aluminium oxide is amphoteric — it reacts with acids (behaving as a base) and with bases (behaving as an acid)

Chlorides with water

  • $\text{NaCl}$ and $\text{MgCl}_2$ are ionic. They simply dissolve, giving a near-neutral solution.
  • $\text{SiCl}_4$ and $\text{PCl}_5$ are covalent. They undergo hydrolysis 水解 (react with water) to make acidic solutions and fumes of $\text{HCl}$:
$$\text{SiCl}_4 + 2\text{H}_2\text{O} \rightarrow \text{SiO}_2 + 4\text{HCl} \qquad \text{PCl}_5 + 4\text{H}_2\text{O} \rightarrow \text{H}_3\text{PO}_4 + 5\text{HCl}$$
Two routes: the ionic chlorides dissolve to a neutral solution, while the covalent chlorides hydrolyse to an acidic solution and HCl fumes
The ionic chlorides just dissolve (neutral); the covalent chlorides react with water (hydrolyse) to give an acidic solution and HCl fumes

Explaining the trends

These trends follow from the change in bonding and electronegativity 电负性. On the left, the elements are metals with low electronegativity, so their oxides and chlorides are ionic and basic (or neutral). On the right, the elements are non-metals with high electronegativity, so their oxides and chlorides are covalent and acidic. You can use a chloride's or oxide's properties (melting point, conductivity, effect on water) to suggest whether its bonding is ionic or covalent.

Worked example. Predict the pH when $\text{Na}_2\text{O}$, $\text{Al}_2\text{O}_3$ and $\text{SO}_3$ are each added to water. Acid-base character follows the metal to non-metal change across Period 3. $\text{Na}_2\text{O}$ is ionic and basic: it dissolves to give $\text{NaOH}$, so the pH is about 13. $\text{SO}_3$ is covalent and acidic: it reacts to give $\text{H}_2\text{SO}_4$, so the pH is about 1. $\text{Al}_2\text{O}_3$ sits at the changeover - it is amphoteric and essentially insoluble in water, so the pH stays about 7. The trap is that last one: amphoteric does not mean neutral, it means the oxide reacts with acids and with alkalis - it simply does not react with water.

探索

3 周期反应实验

根据3反应揭示的成键和酸性特征对其进行分类。

探索

氧化物和氯化物水解途径

观察第3周期元素的氧化物和氯化物在水中如何改变pH值。

词汇 训练
English 中文 拼音
oxidation number/ˌɒksɪˈdeɪʃn ˈnʌmbə/ 氧化数 yǎng huà shù
valence shell/ˈveɪləns ʃel/ 价层 jià céng
electron/ɪˈlektrɒn/ 电子 diàn zi
oxide/ˈɒksaɪd/ 氧化物 yǎng huà wù
amphoteric/ˌæmfəʊˈterɪk/ 两性 liǎng xìng
hydroxide/haɪˈdrɒksaɪd/ 氢氧化物 qīng yǎng huà wù
hydrolysis/haɪˈdrɒləsɪs/ 水解 shuǐ jiě
electronegativity/ɪˌlektrəʊŋɡəˈtɪvɪti/ 电负性 diàn fù xìng
9.3

其他元素的化学周期性

教学大纲
  1. 利用化学周期性知识,预测给定族中某元素的特征性质
  2. 根据给定的物理和化学性质信息,推断未知元素的性质、在元素周期表中的可能位置及其身份

来源:Cambridge International 教学大纲

English

The same idea works for any group. If you know the pattern down a group and across a period, you can:

  • predict the properties of an element from its position (for example, a Group 1 element will be a reactive metal forming a $+1$ ion).
  • deduce the likely position and identity of an unknown element from its physical and chemical properties.

Common mistakes.

  • Explaining the atomic-radius trend by "more electrons". Across the period the electrons go into the same shell with similar shielding, while the nuclear charge rises, so the outer electrons are pulled closer.
  • Explaining silicon's high melting point with intermolecular forces. Silicon is a giant covalent lattice: melting means breaking many strong covalent bonds.
  • Saying $\text{Al}_2\text{O}_3$ gives a neutral solution because it is amphoteric. It is insoluble, so the pH stays 7; "amphoteric" means it reacts with both acids and bases.
  • Saying $\text{SiO}_2$ is basic because it does not dissolve. $\text{SiO}_2$ is weakly acidic: it reacts with hot, concentrated $\text{NaOH}$ but not with acids.
  • Saying $\text{SiCl}_4$ dissolves in water like $\text{NaCl}$. Covalent chlorides are hydrolysed, giving steamy fumes of HCl and an acidic solution.
  • Giving the same oxidation number to sulfur in both of its oxides. Sulfur is $+4$ in $\text{SO}_2$ and $+6$ in $\text{SO}_3$.
探索

周期性趋势

沿第 3 周期一步步看一个性质升或降,然后在下一周期重复——这种反复出现的规律就是周期性。

9.3

考试技巧

English
  • Always pair the trend with its reason: atomic radius falls across Period 3 (rising nuclear charge, similar shielding).
  • Explain the melting-point pattern by structure: giant metallic (Na→Al), giant covalent (Si, highest), then simple molecular ($\text{P}_4$, $\text{S}_8$, $\text{Cl}_2$) and monatomic (Ar).
  • Oxides go basic → amphoteric ($\text{Al}_2\text{O}_3$) → acidic across the period; link to ionic-to-covalent bonding.
  • For reactions of oxides/chlorides with water, give the products and the resulting pH.

该知识点的互动课程

逐步完成,配合即时检查练习。

历年真题

更多 A-Level 化学 知识点

登录或创建账户

IGCSE, A-Level & AP