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10.1
The Group 2 metals · โลหะกลุ่ม 2
Syllabus · หลักสูตร
English
describe, and write equations for, the reactions of the elements with oxygen, water and dilute hydrochloric and sulfuric acids
describe, and write equations for, the reactions of the oxides, hydroxides and carbonates with water and dilute hydrochloric and sulfuric acids
describe, and write equations for, the thermal decomposition of the nitrates and carbonates, to include the trend in thermal stabilities
describe, and make predictions from, the trends in physical and chemical properties of the elements involved in the reactions in 10.1.1 and the compounds involved in 10.1.2, 10.1.3 and 10.1.5
state the variation in the solubilities of the hydroxides and sulfates
Source: Cambridge International syllabus · แหล่งที่มา: หลักสูตร Cambridge International
English
Group 族 2 holds the metals magnesium, calcium, strontium and barium. They all have two outer electrons, which they lose to form $2+$ ions. Going down the group, the atoms get larger and the outer electrons are easier to lose, so the metals get more reactive — their reactivity 反应活性 increases down the group.
The thermal stability 热稳定性 of both the carbonates and the nitrates increases down the group. A larger metal ion pulls less on the carbonate or nitrate ion, so the compound is harder to break apart — it needs a higher temperature. So magnesium carbonate decomposes most easily, and barium carbonate is the hardest.
Trends in solubility
Compound
Trend in solubility 溶解度 down the group
hydroxides
increase (Mg(OH)$_2$ almost insoluble; Ba(OH)$_2$ soluble)
sulfates
decrease (MgSO$_4$ soluble; BaSO$_4$ insoluble)
From these trends you can predict the properties of the next element down, radium, and of its compounds.
Worked example.$\text{MgCO}_3$ decomposes at about $540\ °\text{C}$ and $\text{BaCO}_3$ at about $1360\ °\text{C}$. Explain the trend and predict where $\text{CaCO}_3$ sits. Going down Group 2 the cation gets larger, so its charge is spread over a bigger surface and its polarising power falls. A less polarising cation distorts the carbonate ion less, so the $\text{C-O}$ bond is weakened less and more heat is needed to break it. Thermal stability therefore increases down the group, and $\text{CaCO}_3$, lying between Mg and Ba, decomposes at an intermediate temperature of about $900\ °\text{C}$. Argue the whole chain - cation size, then polarising power, then distortion of the anion; "it is more reactive" explains nothing here.
ความเสถียรต่อความร้อนเพิ่มขึ้นตามกลุ่ม:แคทไอออนขนาดเล็กทำให้ニयามคาร์บอเนตเกิดการโพลาไรซ์ (บิดเบี้ยว) มากกว่า ทำให้ weakened sehingga it decomposes more easily
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