- explain the origin of pressure in a gas in terms of collisions between gas molecules and the wall of the container
- understand that ideal gases have zero particle volume and no intermolecular forces of attraction
- state and use the ideal gas equation $pV = nRT$ in calculations, including in the determination of $M_r$
States of matter
A-Level Chemistry · Topic 4
4.1
The gaseous state
Syllabus
Source: Cambridge International syllabus
Boiling turns liquid water into steam — a change between states of matter.
Where gas pressure comes from
Gas molecules move fast in all directions. They keep hitting — colliding 碰撞 with — the walls of their container. Each hit gives the wall a tiny push. The pressure 压强 of the gas is the overall result of these many collisions on the walls.
Gas pressure: fast molecules move in all directions and collide with the walls; the many tiny pushes add up to the pressure
Ideal gases
An ideal gas 理想气体 is a simple model. We assume two things:
- the particles themselves take up zero volume.
- there are no intermolecular forces 分子间作用力 of attraction between the particles.
A real gas 实际气体 follows this model closely at low pressure and high temperature. It behaves least like an ideal gas at high pressure and low temperature, when the particles are squeezed close together and the forces between them start to matter.
An ideal gas is a model: point particles with no forces between them. A real gas behaves least like this at high pressure and low temperature, when the particles are crowded and their real size and attractions start to matter
The ideal gas equation
The ideal gas equation 理想气体方程 links pressure, volume, amount and temperature:
where $p$ is the pressure in Pa, $V$ is the volume in $\text{m}^3$, $n$ is the amount in moles, $T$ is the temperature in kelvin 开尔文 (K), and $R$ is the gas constant 气体常量 ($8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$).
Always change the units first: °C to K (add 273), and $\text{cm}^3$ or $\text{dm}^3$ to $\text{m}^3$.
Worked example. Find the volume of $0.50\ \text{mol}$ of an ideal gas at $27\ ^{\circ}\text{C}$ and $100\ \text{kPa}$. ($R = 8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$.)
Convert first: $T = 300\ \text{K}$, $p = 1.00 \times 10^{5}\ \text{Pa}$. Then
You can also use the equation to find a molar mass 摩尔质量. Since $n = m/M$:
This lets you work out $M_r$ from the mass (or the density) of a gas.
Worked example. A flask holds $0.96\ \text{g}$ of a gas in $600\ \text{cm}^3$ at $100\ \text{kPa}$ and $27\ ^{\circ}\text{C}$. Find the molar mass of the gas. ($R = 8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$.)
Convert: $V = 6.00 \times 10^{-4}\ \text{m}^3$, $T = 300\ \text{K}$. Then
The gaseous state
p = k / V
Boyle's law: at constant temperature pressure ∝ 1/volume.
| English | Chinese | Pinyin |
|---|---|---|
| collide | 碰撞 | pèng zhuàng |
| pressure | 压强 | yā qiáng |
| ideal gas | 理想气体 | lǐ xiǎng qì tǐ |
| intermolecular forces | 分子间作用力 | fèn zǐ jiàn zuò yòng lì |
| real gas | 实际气体 | shí jì qì tǐ |
| ideal gas equation | 理想气体方程 | lǐ xiǎng qì tǐ fāng chéng |
| kelvin | 开尔文 | kāi ěr wén |
| gas constant | 气体常量 | qì tǐ cháng liàng |
| molar mass | 摩尔质量 | mó ěr zhì liàng |
4.2
Bonding and structure
Syllabus
- describe, in simple terms, the lattice structure of a crystalline solid which is: (a) giant ionic, including sodium chloride and magnesium oxide (b) simple molecular, including iodine, buckminsterfullerene $\text{C}_{60}$ and ice (c) giant molecular, including silicon(IV) oxide, graphite and diamond (d) giant metallic, including copper
- describe, interpret and predict the effect of different types of structure and bonding on the physical properties of substances, including melting point, boiling point, electrical conductivity and solubility
- deduce the type of structure and bonding present in a substance from given information
Source: Cambridge International syllabus
Quartz is a giant covalent structure of silicon and oxygen.
How a substance behaves depends on how its particles are joined. There are four main structures of a crystalline solid 晶体.
The four structures of a crystalline solid — the structure decides the melting point, conductivity and solubility
Giant ionic
A giant ionic 离子晶体 structure is a huge regular lattice 晶格 of positive and negative ions 离子, held together by strong attraction in every direction. Examples are sodium chloride and magnesium oxide.
Simple molecular
A simple molecular 分子晶体 structure is made of small molecules 分子. The bonds inside each molecule are strong, but the intermolecular forces between the molecules are weak. Examples are iodine ($\text{I}_2$), fullerene 富勒烯 ($\text{C}_{60}$) and ice.
Giant molecular
A giant molecular 原子晶体 structure (also called giant covalent) is a huge network of atoms joined by strong covalent bonds 共价键. Examples are silicon(IV) oxide 二氧化硅, graphite 石墨 and diamond 金刚石.
Two giant covalent forms of carbon: diamond is a rigid 3D network (very hard); graphite has sliding layers and spare electrons that conduct
A real diamond in the rock it grew in. That whole crystal is one giant molecule — a single unbroken network of carbon atoms, each bonded to four others. Breaking it means breaking countless strong covalent bonds, which is why diamond is the hardest natural material
Giant metallic
A giant metallic 金属晶体 structure is a lattice of positive metal ions in a "sea" of delocalised electrons 离域电子. An example is copper.
A piece of pure copper metal. The shine, and the way metals conduct and bend, all come from that giant lattice of copper ions sitting in a shared sea of delocalised electrons
Physical properties
The structure decides the physical properties:
| Structure | Melting/boiling point | Conducts electricity? | Solubility in water |
|---|---|---|---|
| giant ionic | high | only when molten or dissolved | usually soluble |
| simple molecular | low | no | usually low |
| giant molecular | very high | no (except graphite) | insoluble |
| giant metallic | high | yes (solid and molten) | insoluble |
- melting point 熔点 and boiling point 沸点 are high when strong forces (ionic, covalent or metallic) must be broken, and low when only weak intermolecular forces break.
- electrical conductivity 导电性 needs charged particles that can move — ions that are free (when molten or dissolved) or delocalised electrons. Graphite conducts because some of its electrons are delocalised.
- solubility 溶解度 in water is usually high for ionic solids and low for molecular and giant covalent solids.
You can work backwards too: from the melting point, conductivity and solubility of an unknown substance, deduce the type of structure and bonding it has.
Giant structure lab
Compare giant structures by particles and bonding.
| English | Chinese | Pinyin |
|---|---|---|
| crystalline solid | 晶体 | jīng tǐ |
| giant ionic | 离子晶体 | lí zi jīng tǐ |
| lattice | 晶格 | jīng gé |
| ion | 离子 | lí zi |
| simple molecular | 分子晶体 | fēn zǐ jīng tǐ |
| molecule | 分子 | fèn zǐ |
| fullerene | 富勒烯 | fù lēi xī |
| giant molecular | 原子晶体 | yuán zi jīng tǐ |
| covalent bonds | 共价键 | gòng jià jiàn |
| silicon(IV) oxide | 二氧化硅 | èr yǎng huà guī |
| graphite | 石墨 | shí mò |
| diamond | 金刚石 | jīn gāng shí |
| giant metallic | 金属晶体 | jīn shǔ jīng tǐ |
| delocalised electrons | 离域电子 | lí yù diàn zi |
| melting point | 熔点 | róng diǎn |
| boiling point | 沸点 | fèi diǎn |
| electrical conductivity | 导电性 | dǎo diàn xìng |
| solubility | 溶解度 | róng jiě dù |
4.2
Exam tips
- Use SI units in $pV = nRT$: pressure in Pa, volume in $\text{m}^3$ ($\text{cm}^3 \times 10^{-6}$), temperature in K ($^\circ\text{C} + 273$).
- State the ideal-gas assumptions (negligible molecular volume, no intermolecular forces) and when real gases deviate (high pressure, low temperature).
- Link each property to structure: giant ionic (high m.p., conducts molten), giant covalent (very high m.p.), simple molecular (low m.p.), giant metallic (conducts, malleable).
- Graphite conducts because each carbon has a delocalised electron; diamond does not — a favourite comparison.