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States of matter

A-Level Chemistry · Topic 4

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4.1

The gaseous state

Syllabus
  1. explain the origin of pressure in a gas in terms of collisions between gas molecules and the wall of the container
  2. understand that ideal gases have zero particle volume and no intermolecular forces of attraction
  3. state and use the ideal gas equation $pV = nRT$ in calculations, including in the determination of $M_r$

Source: Cambridge International syllabus

Steam rising from boiling water Boiling turns liquid water into steam — a change between states of matter.

Where gas pressure comes from

Gas molecules move fast in all directions. They keep hitting — colliding 碰撞 with — the walls of their container. Each hit gives the wall a tiny push. The pressure 压强 of the gas is the overall result of these many collisions on the walls.

Fast-moving particles inside a box, each with a velocity arrow, some striking the walls and marked with an impact star Gas pressure: fast molecules move in all directions and collide with the walls; the many tiny pushes add up to the pressure

Ideal gases

An ideal gas 理想气体 is a simple model. We assume two things:

  • the particles themselves take up zero volume.
  • there are no intermolecular forces 分子间作用力 of attraction between the particles.

A real gas 实际气体 follows this model closely at low pressure and high temperature. It behaves least like an ideal gas at high pressure and low temperature, when the particles are squeezed close together and the forces between them start to matter.

Two boxes: on the left an ideal gas of tiny point particles with velocity arrows and no forces; on the right a real gas at high pressure and low temperature with larger crowded particles joined by dashed attraction lines An ideal gas is a model: point particles with no forces between them. A real gas behaves least like this at high pressure and low temperature, when the particles are crowded and their real size and attractions start to matter

The ideal gas equation

The ideal gas equation 理想气体方程 links pressure, volume, amount and temperature:

$$pV = nRT$$

where $p$ is the pressure in Pa, $V$ is the volume in $\text{m}^3$, $n$ is the amount in moles, $T$ is the temperature in kelvin 开尔文 (K), and $R$ is the gas constant 气体常量 ($8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$).

Always change the units first: °C to K (add 273), and $\text{cm}^3$ or $\text{dm}^3$ to $\text{m}^3$.

Worked example. Find the volume of $0.50\ \text{mol}$ of an ideal gas at $27\ ^{\circ}\text{C}$ and $100\ \text{kPa}$. ($R = 8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$.)

Convert first: $T = 300\ \text{K}$, $p = 1.00 \times 10^{5}\ \text{Pa}$. Then

$$V = \frac{nRT}{p} = \frac{0.50 \times 8.31 \times 300}{1.00 \times 10^{5}} = 0.0125\ \text{m}^3\ (= 12.5\ \text{dm}^3).$$

You can also use the equation to find a molar mass 摩尔质量. Since $n = m/M$:

$$pV = \frac{m}{M}RT \qquad\Rightarrow\qquad M = \frac{mRT}{pV}$$

This lets you work out $M_r$ from the mass (or the density) of a gas.

Worked example. A flask holds $0.96\ \text{g}$ of a gas in $600\ \text{cm}^3$ at $100\ \text{kPa}$ and $27\ ^{\circ}\text{C}$. Find the molar mass of the gas. ($R = 8.31\ \text{J K}^{-1}\,\text{mol}^{-1}$.)

Convert: $V = 6.00 \times 10^{-4}\ \text{m}^3$, $T = 300\ \text{K}$. Then

$$M = \frac{mRT}{pV} = \frac{0.96 \times 8.31 \times 300}{(1.00 \times 10^{5})(6.00 \times 10^{-4})} \approx 40\ \text{g mol}^{-1}.$$
Explore

The gaseous state

p = k / V

Boyle's law: at constant temperature pressure ∝ 1/volume.

Vocabulary Train
English Chinese Pinyin
collide 碰撞 pèng zhuàng
pressure 压强 yā qiáng
ideal gas 理想气体 lǐ xiǎng qì tǐ
intermolecular forces 分子间作用力 fèn zǐ jiàn zuò yòng lì
real gas 实际气体 shí jì qì tǐ
ideal gas equation 理想气体方程 lǐ xiǎng qì tǐ fāng chéng
kelvin 开尔文 kāi ěr wén
gas constant 气体常量 qì tǐ cháng liàng
molar mass 摩尔质量 mó ěr zhì liàng
Exercise sheet
4.2

Bonding and structure

Syllabus
  1. describe, in simple terms, the lattice structure of a crystalline solid which is: (a) giant ionic, including sodium chloride and magnesium oxide (b) simple molecular, including iodine, buckminsterfullerene $\text{C}_{60}$ and ice (c) giant molecular, including silicon(IV) oxide, graphite and diamond (d) giant metallic, including copper
  2. describe, interpret and predict the effect of different types of structure and bonding on the physical properties of substances, including melting point, boiling point, electrical conductivity and solubility
  3. deduce the type of structure and bonding present in a substance from given information

Source: Cambridge International syllabus

A cluster of quartz crystals Quartz is a giant covalent structure of silicon and oxygen.

How a substance behaves depends on how its particles are joined. There are four main structures of a crystalline solid 晶体.

Four panels: a giant ionic lattice of alternating positive and negative ions, separate small molecules, a bonded covalent network, and metal ions in an electron sea The four structures of a crystalline solid — the structure decides the melting point, conductivity and solubility

Giant ionic

A giant ionic 离子晶体 structure is a huge regular lattice 晶格 of positive and negative ions 离子, held together by strong attraction in every direction. Examples are sodium chloride and magnesium oxide.

Simple molecular

A simple molecular 分子晶体 structure is made of small molecules 分子. The bonds inside each molecule are strong, but the intermolecular forces between the molecules are weak. Examples are iodine ($\text{I}_2$), fullerene 富勒烯 ($\text{C}_{60}$) and ice.

Giant molecular

A giant molecular 原子晶体 structure (also called giant covalent) is a huge network of atoms joined by strong covalent bonds 共价键. Examples are silicon(IV) oxide 二氧化硅, graphite 石墨 and diamond 金刚石.

On the left a diamond node with each carbon bonded to four others; on the right graphite as stacked hexagonal layers held by weak forces Two giant covalent forms of carbon: diamond is a rigid 3D network (very hard); graphite has sliding layers and spare electrons that conduct

A rough octahedral diamond crystal A real diamond in the rock it grew in. That whole crystal is one giant molecule — a single unbroken network of carbon atoms, each bonded to four others. Breaking it means breaking countless strong covalent bonds, which is why diamond is the hardest natural material

Giant metallic

A giant metallic 金属晶体 structure is a lattice of positive metal ions in a "sea" of delocalised electrons 离域电子. An example is copper.

A rounded nugget of copper with a bright reddish metallic shine and small green spots of tarnish A piece of pure copper metal. The shine, and the way metals conduct and bend, all come from that giant lattice of copper ions sitting in a shared sea of delocalised electrons

Physical properties

The structure decides the physical properties:

Structure Melting/boiling point Conducts electricity? Solubility in water
giant ionic high only when molten or dissolved usually soluble
simple molecular low no usually low
giant molecular very high no (except graphite) insoluble
giant metallic high yes (solid and molten) insoluble
  • melting point 熔点 and boiling point 沸点 are high when strong forces (ionic, covalent or metallic) must be broken, and low when only weak intermolecular forces break.
  • electrical conductivity 导电性 needs charged particles that can move — ions that are free (when molten or dissolved) or delocalised electrons. Graphite conducts because some of its electrons are delocalised.
  • solubility 溶解度 in water is usually high for ionic solids and low for molecular and giant covalent solids.

You can work backwards too: from the melting point, conductivity and solubility of an unknown substance, deduce the type of structure and bonding it has.

Explore

Giant structure lab

Compare giant structures by particles and bonding.

Vocabulary Train
English Chinese Pinyin
crystalline solid 晶体 jīng tǐ
giant ionic 离子晶体 lí zi jīng tǐ
lattice 晶格 jīng gé
ion 离子 lí zi
simple molecular 分子晶体 fēn zǐ jīng tǐ
molecule 分子 fèn zǐ
fullerene 富勒烯 fù lēi xī
giant molecular 原子晶体 yuán zi jīng tǐ
covalent bonds 共价键 gòng jià jiàn
silicon(IV) oxide 二氧化硅 èr yǎng huà guī
graphite 石墨 shí mò
diamond 金刚石 jīn gāng shí
giant metallic 金属晶体 jīn shǔ jīng tǐ
delocalised electrons 离域电子 lí yù diàn zi
melting point 熔点 róng diǎn
boiling point 沸点 fèi diǎn
electrical conductivity 导电性 dǎo diàn xìng
solubility 溶解度 róng jiě dù
4.2

Exam tips

  • Use SI units in $pV = nRT$: pressure in Pa, volume in $\text{m}^3$ ($\text{cm}^3 \times 10^{-6}$), temperature in K ($^\circ\text{C} + 273$).
  • State the ideal-gas assumptions (negligible molecular volume, no intermolecular forces) and when real gases deviate (high pressure, low temperature).
  • Link each property to structure: giant ionic (high m.p., conducts molten), giant covalent (very high m.p.), simple molecular (low m.p.), giant metallic (conducts, malleable).
  • Graphite conducts because each carbon has a delocalised electron; diamond does not — a favourite comparison.

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