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IGCSE Chemistry

  • 1 States of matter
    1.1

    The three states of matter

    Syllabus
    Core Supplement
    1 State the distinguishing properties of solids, liquids and gases
    2 Describe the structures of solids, liquids and gases in terms of particle separation, arrangement and motion
    3 Describe changes of state in terms of melting, boiling, evaporating, freezing and condensing 5 Explain changes of state in terms of kinetic particle theory, including the interpretation of heating and cooling curves
    4 Describe the effects of temperature and pressure on the volume of a gas 6 Explain, in terms of kinetic particle theory, the effects of temperature and pressure on the volume of a gas

    Source: Cambridge International syllabus

    Solid, liquid, gas: particle motion

    Everything around you is made of tiny particles 粒子 — these can be atoms 原子, molecules 分子, or ions 离子. The kinetic particle theory 粒子动理论 says these particles are always moving. How close the particles are, how they are arranged, and how they move decides whether matter is a solid 固体, a liquid 液体, or a gas 气体.

    Properties you can observe

    You do not need a microscope to tell the three states apart. They behave in different ways:

    • A solid has a fixed shape and a fixed volume 体积. It does not flow and you cannot compress 压缩 it (squeeze it smaller).
    • A liquid has a fixed volume but no fixed shape. It flows and takes the shape of its container. It is almost impossible to compress.
    • A gas has no fixed shape and no fixed volume. It flows and spreads out to fill the whole container. A gas is easy to compress.

    The table below sums up these properties. Density 密度 means how much mass 质量 is packed into a given volume.

    Property Solid Liquid Gas
    Shape fixed takes the shape of the container fills the whole container
    Volume fixed fixed fills the whole container
    Can it be compressed? no almost none yes, easily
    Does it flow? no yes yes
    Density high high low

    The particle picture

    The kinetic particle theory explains these properties by looking at three things: the separation 间距 of the particles (how far apart they are), their arrangement 排列 (the pattern), and their motion 运动 (how they move).

    Solid Liquid Gas
    Separation touching, very close close together far apart
    Arrangement regular 规则 pattern random, no pattern random, no pattern
    Motion vibrate 振动 about fixed positions move and slide past each other move quickly in all directions

    Strong forces of attraction 引力 hold the particles together. In a solid these forces are strong enough to hold every particle in place, so a solid keeps its shape. In a liquid the forces are weaker, so particles can move around. In a gas the particles move so fast that the forces hardly act at all, so the gas spreads out.

    Particle diagrams of a solid, a liquid and a gas: the solid is a regular packed grid, the liquid is close but random, the gas is sparse and spread out
    Particles are packed and regular in a solid, close and random in a liquid, and far apart in a gas
    Explore

    States of matter

    Heat the box and watch the particles break free: a vibrating solid melts to a flowing liquid, then spreads out as a gas. Same particles — just more energy.

    Vocabulary Train
    English Chinese Pinyin
    particles 粒子 lì zi
    atoms 原子 yuán zi
    molecules 分子 fèn zǐ
    ions 离子 lí zi
    kinetic particle theory 粒子动理论 lì zi dòng lǐ lùn
    solid 固体 gù tǐ
    liquid 液体 yè tǐ
    gas 气体 qì tǐ
    volume 体积 tǐ jī
    compress 压缩 yā suō
    density 密度 mì dù
    mass 质量 zhì liàng
    separation 间距 jiān jù
    arrangement 排列 pái liè
    motion 运动 yùn dòng
    regular 规则 guī zé
    vibrate 振动 zhèn dòng
    forces of attraction 引力 yǐn lì
    Exercise sheet
    1.1

    Changes of state

    Ice cubes melting in a glass
    Ice melting to water: a change of state as the solid warms.

    When you heat or cool a substance, it can change from one state to another. You must know the name of each change.

    Change What happens Name
    solid → liquid melting 熔化 melting
    liquid → solid freezing 凝固 freezing
    liquid → gas (at the surface, below the boiling point) evaporating 蒸发 evaporation
    liquid → gas (all through the liquid) boiling 沸腾 boiling
    gas → liquid condensing 凝结 condensation

    A pure solid melts at one fixed temperature, the melting point 熔点. A pure liquid boils at one fixed temperature, the boiling point 沸点. The same substance freezes at its melting point and condenses at its boiling point.

    Solid, liquid and gas linked by arrows: melting and boiling go one way, freezing and condensing go back
    Heating: solid → liquid → gas; cooling reverses each change

    A few substances change straight from solid to gas without melting first. This is called sublimation 升华. In the photo below, warmed solid iodine in a beaker turns directly into a purple gas; the gas then cools on the round flask of ice above and turns back into a solid.

    A beaker of solid iodine on a hotplate filled with bright purple iodine gas, with a flask of ice resting on top where the gas turns back to a solid
    Warmed solid iodine turns straight into a purple gas (sublimation)

    Explaining changes of state with the particle theory

    Each change of state is really a change in the energy 能量 of the particles.

    • When you heat a solid, the particles gain energy and vibrate faster. At the melting point the particles have enough energy to break away from their fixed places and slide around — the solid melts.
    • When you heat a liquid, the particles move faster. At the boiling point they have enough energy to fully escape the forces of attraction and become a gas.
    • Cooling does the opposite. The particles lose energy, move more slowly, and the forces of attraction pull them back together.

    During a change of state the energy goes into breaking the forces of attraction, not into making the particles move faster. This is why the temperature stays the same while a substance is melting or boiling.

    Heating and cooling curves

    A heating curve 加热曲线 is a graph of temperature against time as you heat a substance steadily. A cooling curve 冷却曲线 is the same graph as the substance cools.

    On a heating curve there are two flat (level) parts:

    • The first flat part is at the melting point. Here solid and liquid are both present. The heat energy breaks the forces holding the solid together, so the temperature does not rise.
    • The second flat part is at the boiling point. Here liquid and gas are both present, and the temperature again stays constant.

    A cooling curve is the reverse. It has a flat part at the boiling point (the gas condenses) and a flat part at the melting point (the liquid freezes). As the particles slow down, thermal energy 热能 is released to the surroundings.

    A heating curve of temperature against time, rising then flat at the melting point, rising then flat at the boiling point, then rising again
    Temperature stays constant at the melting and boiling points while forces of attraction are broken
    Explore

    Heating a substance through its states

    Step up the temperature. Adding heat gives the particles more energy until they break free — and the temperature pauses at each change of state while the energy does that work.

    Vocabulary Train
    English Chinese Pinyin
    melting 熔化 róng huà
    freezing 凝固 níng gù
    evaporating 蒸发 zhēng fā
    boiling 沸腾 fèi téng
    condensing 凝结 níng jié
    melting point 熔点 róng diǎn
    boiling point 沸点 fèi diǎn
    sublimation 升华 shēng huá
    energy 能量 néng liàng
    heating curve 加热曲线 jiā rè qū xiàn
    cooling curve 冷却曲线 lěng què qū xiàn
    thermal energy 热能 rè néng
    1.1

    Gases: temperature, pressure and volume

    A gas pushes on the walls of its container. This push, spread over the area of the wall, is the pressure 压强 of the gas. Pressure comes from the gas particles hitting the walls.

    Effect of temperature

    If you heat a fixed mass of gas while keeping the pressure the same, its volume increases.

    A heated gas: faster particles take up more space at constant pressure
    A heated gas: faster particles spread out and take up more space

    Using the particle theory: heating gives the particles more kinetic energy 动能, so they move faster. They hit the walls harder and more often. To keep the pressure the same, the gas must take up more space, so the volume gets bigger.

    If instead the volume is fixed (a sealed, rigid container), heating the gas makes the pressure rise, because the faster particles collide 碰撞 with the walls harder and more often.

    Effect of pressure

    If you increase the pressure on a fixed mass of gas while keeping the temperature the same, its volume decreases. Squeezing the gas into a smaller space means the particles hit the walls more often, which is what a higher pressure means.

    At the same temperature, squeezing a gas into a smaller volume packs the particles closer so they hit the walls more often, which is a higher pressure
    Squeezing a gas into a smaller volume makes the particles hit the walls more often, so the pressure rises
    Explore

    Gases, pressure & volume

    p = k / V

    Squeeze the volume and the pressure rises (Boyle's law).

    Vocabulary Train
    English Chinese Pinyin
    pressure 压强 yā qiáng
    kinetic energy 动能 dòng néng
    collide 碰撞 pèng zhuàng
    1.2

    Diffusion

    Syllabus
    Core Supplement
    1 Describe and explain diffusion in terms of kinetic particle theory 2 Describe and explain the effect of relative molecular mass on the rate of diffusion of gases

    Source: Cambridge International syllabus

    Diffusion: random motion, one-way flow

    Diffusion 扩散 is the spreading of particles from a region where they are crowded to a region where they are spread out — that is, from high concentration 浓度 to low concentration. It happens because particles are always moving in random directions.

    Particles crowded on one side of a box spread out over time until they fill the box evenly, moving from high to low concentration
    Particles diffuse from high to low concentration until they are spread out evenly

    Diffusion explains why you can smell food from across a room: the smell particles move and mix with the air until they reach your nose. Diffusion happens in gases and in liquids, but not in solids, because solid particles cannot move from place to place.

    Rate of diffusion and molecular mass

    Lighter gas particles move faster than heavier ones at the same temperature. So a gas with a smaller relative molecular mass 相对分子质量 (a smaller mass for each molecule) has a faster rate 速率 of diffusion.

    A classic experiment shows this. Cotton wool soaked in ammonia 氨气 ($\text{NH}_3$) is put at one end of a long glass tube. Cotton wool soaked in hydrogen chloride 氯化氢 ($\text{HCl}$) is put at the other end. Both gases diffuse along the tube and meet to form a white ring of ammonium chloride 氯化铵 ($\text{NH}_4\text{Cl}$).

    $$\text{NH}_3 + \text{HCl} \rightarrow \text{NH}_4\text{Cl}$$

    Ammonia has $M_r = 17$ and hydrogen chloride has $M_r = 36.5$. Ammonia is lighter, so it diffuses faster and travels further along the tube. The white ring forms nearer the hydrogen chloride end.

    A long glass tube with ammonia diffusing in from the left and hydrogen chloride from the right; they meet to form a white ring closer to the hydrogen chloride end
    Ammonia ($M_r=17$) is lighter, so it diffuses faster and further; the white ring forms nearer the HCl end

    Worked example. Bromine ($M_r = 160$) and ammonia ($M_r = 17$) are released at the same moment from opposite ends of a long tube. Which travels further before they meet? Compare the relative molecular masses. Ammonia's $M_r$ is far smaller, so its molecules move faster at the same temperature and it diffuses more quickly. Ammonia therefore travels the greater distance, and the two gases meet nearer the bromine end. The rule is always "lighter means faster" - argue from $M_r$, never from how big the formula looks on paper.

    Explore

    Diffusion

    Release the cloud and the particles spread on their own from the crowded corner until they fill the box evenly — diffusion, sped up by heat.

    Explore

    Diffusion

    Set the concentration on each side. Particles spread from high to low concentration until evenly mixed.

    Vocabulary Train
    English Chinese Pinyin
    diffusion 扩散 kuò sàn
    concentration 浓度 nóng dù
    relative molecular mass 相对分子质量 xiāng duì fèn zǐ zhì liàng
    rate 速率 sù lǜ
    ammonia 氨气 ān qì
    hydrogen chloride 氯化氢 lǜ huà qīng
    ammonium chloride 氯化铵 lǜ huà ǎn
    Exercise sheet
    1.2

    Exam tips

    • During melting and boiling the temperature stays constant (the flat parts of a heating curve), because the energy breaks the forces between particles instead of making them move faster.
    • Evaporation happens only at the surface and at any temperature; boiling happens throughout the liquid at one fixed temperature.
    • Explain gas behaviour with the particle theory: heating a gas at fixed volume raises the pressure because the particles hit the walls harder and more often — the particles themselves do not get bigger.
    • Diffusion is faster for lighter particles (smaller $M_r$) and cannot happen in solids. In the ammonia/hydrogen chloride tube the lighter ammonia travels further, so the white ring forms nearer the HCl end.
  • 2 Atoms, elements and compounds
    2.1

    Elements, compounds and mixtures

    Syllabus
    Core Supplement
    1 Describe the differences between elements, compounds and mixtures

    Source: Cambridge International syllabus

    A pure vanadium crystal bar and cube
    A pure element (vanadium): elements are the simplest substances.

    All substances are made from about 100 simple building blocks. Knowing how they are joined lets you sort every substance into one of three groups.

    • An element 元素 is a substance made of only one type of atom 原子. You cannot break it into anything simpler by a chemical reaction. Examples: copper, oxygen, carbon.
    • A compound 化合物 is two or more elements chemically joined (bonded) together. The atoms are joined in a fixed ratio. Examples: water, carbon dioxide. A compound has different properties from the elements in it.
    • A mixture 混合物 is two or more substances that are just mixed, not chemically joined. The parts keep their own properties and can be separated by physical methods. Example: air.

    The key difference: in a compound the elements are bonded and can only be separated by chemical reactions; in a mixture they are not bonded and are easy to separate.

    Three boxes of particles: an element with one type of atom, a compound with two atom types bonded in a fixed ratio, and a mixture of unbonded atoms
    An element has one type of atom; a compound has different atoms bonded in a fixed ratio; a mixture is not bonded
    Explore

    Elements, compounds and mixtures lab

    Classify everyday particle examples by composition.

    Vocabulary Train
    English Chinese Pinyin
    element 元素 yuán sù
    atom 原子 yuán zi
    compound 化合物 huà hé wù
    mixture 混合物 hùn hé wù
    2.2

    Atomic structure

    Syllabus
    Core Supplement
    1 Describe the structure of the atom as a central nucleus containing neutrons and protons surrounded by electrons in shells
    2 State the relative charges and relative masses of a proton, a neutron and an electron
    3 Define proton number/atomic number as the number of protons in the nucleus of an atom
    4 Define mass number/nucleon number as the total number of protons and neutrons in the nucleus of an atom
    5 Determine the electronic configuration of elements and their ions with proton number 1 to 20, e.g. 2,8,3
    6 State that: (a) Group VIII noble gases have a full outer electron shell (b) the number of outer shell electrons is equal to the group number in Groups I to VII (c) the number of occupied electron shells is equal to the period number

    Source: Cambridge International syllabus

    Inside the atom

    Every atom has a small, dense centre called the nucleus 原子核. Around it, electrons 电子 move in shells 电子层 (energy levels). The nucleus contains two kinds of particle: protons 质子 and neutrons 中子.

    A lithium atom: an orange nucleus of protons and neutrons, with two electron shells holding 2 then 1 electrons
    An atom has a tiny nucleus of protons and neutrons, with electrons in shells around it

    Each particle has a relative mass and a relative charge 电荷. You must learn these values:

    Particle Relative mass Relative charge
    proton 1 $+1$
    neutron 1 $0$
    electron $\frac{1}{1840}$ (almost 0) $-1$

    An atom has no overall charge because it has equal numbers of protons ($+1$ each) and electrons ($-1$ each).

    Proton number and mass number

    Two numbers describe an atom:

    • The proton number 质子数 (also called the atomic number 原子序数) is the number of protons in the nucleus. It tells you which element the atom is.
    • The mass number 质量数 (also called the nucleon number 核子数) is the total number of protons and neutrons in the nucleus.

    So the number of neutrons $=$ mass number $-$ proton number.

    Electronic configuration

    The electrons fill the shells from the inside out. The first shell holds up to 2 electrons; the next shells hold up to 8 each (for the first 20 elements). The electronic configuration 电子排布 lists how many electrons are in each shell, starting from the inside.

    For example, an atom with 13 electrons has the configuration $2,8,3$. Sodium (proton number 11) is $2,8,1$. Calcium (proton number 20) is $2,8,8,2$.

    The configuration links to the Periodic Table 周期表:

    • A Group number (Groups I to VII) equals the number of electrons in the outer shell. So $2,8,1$ is in Group I.
    • A Period 周期 number equals the number of shells that hold electrons. So $2,8,1$ has three shells, so it is in Period 3.
    • The noble gases 稀有气体 in Group VIII (or 0) have a full outer shell, which makes them very unreactive.
    A sodium atom with electrons drawn in three shells as 2, 8, 1; the one outer electron means Group I and the three shells in use mean Period 3
    Sodium's configuration 2,8,1 links to the Periodic Table: one outer electron means Group I, three shells means Period 3
    Explore

    Electron shells

    Change the atomic number and watch the shells fill (2, 8, 8) — the electron arrangement of the first 20 elements.

    Vocabulary Train
    English Chinese Pinyin
    nucleus 原子核 yuán zǐ hé
    electrons 电子 diàn zi
    shells 电子层 diàn zi céng
    protons 质子 zhì zi
    neutrons 中子 zhōng zi
    charge 电荷 diàn hè
    proton number 质子数 zhì zi shù
    atomic number 原子序数 yuán zi xù shù
    mass number 质量数 zhì liàng shù
    nucleon number 核子数 hé zǐ shù
    electronic configuration 电子排布 diàn zi pái bù
    Periodic Table 周期表 zhōu qī biǎo
    Group
    Period 周期 zhōu qī
    noble gases 稀有气体 xī yǒu qì tǐ
    Exercise sheet
    2.3

    Isotopes

    Syllabus
    Core Supplement
    1 Define isotopes as different atoms of the same element that have the same number of protons but different numbers of neutrons 3 State that isotopes of the same element have the same chemical properties because they have the same number of electrons and therefore the same electronic configuration
    2 Interpret and use symbols for atoms, e.g. $^{12}_{6}\text{C}$, and ions, e.g. $^{35}_{17}\text{Cl}^-$ 4 Calculate the relative atomic mass of an element from the relative masses and abundances of its isotopes

    Source: Cambridge International syllabus

    Isotopes 同位素 are atoms of the same element that have the same number of protons but different numbers of neutrons. Because the proton number is the same, they are the same element. Because the neutron number is different, they have different mass numbers.

    You write an atom with its mass number on top and proton number below, like $^{12}_{6}\text{C}$. For an ion you add the charge, like $^{35}_{17}\text{Cl}^{-}$.

    Isotopes of an element have the same chemical properties. This is because chemical reactions only involve electrons, and isotopes have the same number of electrons and the same electronic configuration. (The extra neutrons change only the mass.)

    Calculating relative atomic mass

    The relative atomic mass 相对原子质量 ($A_r$) of an element is the average mass of its atoms, taking into account how common each isotope is. The abundance 丰度 is the percentage of each isotope.

    $$A_r = \frac{\sum (\text{isotope mass} \times \text{abundance})}{100}$$

    For example, chlorine is 75% $^{35}\text{Cl}$ and 25% $^{37}\text{Cl}$:

    $$A_r = \frac{(35 \times 75) + (37 \times 25)}{100} = 35.5$$
    Chlorine's two isotopes drawn as circles sized by abundance, 75 percent Cl-35 and 25 percent Cl-37, so the weighted-average relative atomic mass 35.5 sits closer to 35
    Relative atomic mass is a weighted average: chlorine is 75 percent Cl-35 and 25 percent Cl-37, so A_r is 35.5

    Worked example. Boron has two isotopes, $^{10}\text{B}$ and $^{11}\text{B}$, and its $A_r$ is 10.8. Find the percentage of each. Let the abundance of $^{11}\text{B}$ be $x$, so the abundance of $^{10}\text{B}$ is $(100 - x)$. Then

    $$\frac{11x + 10(100 - x)}{100} = 10.8$$

    so $11x + 1000 - 10x = 1080$, giving $x = 80$. Boron is 80% $^{11}\text{B}$ and 20% $^{10}\text{B}$. Check it against common sense: 10.8 lies closer to 11, so the heavier isotope must be the more common one. If your answer gives the majority to the isotope further from $A_r$, you have them the wrong way round.

    Explore

    Protons, neutrons & isotopes

    Change the neutrons to make isotopes (same element, different mass number); change the electrons to make ions.

    Explore

    Isotope lab

    Classify isotope facts by proton, neutron and mass number.

    Vocabulary Train
    English Chinese Pinyin
    isotopes 同位素 tóng wèi sù
    relative atomic mass 相对原子质量 xiāng duì yuán zi zhì liàng
    abundance 丰度 fēng dù
    2.4

    Ions and ionic bonds

    Syllabus
    Core Supplement
    1 Describe the formation of positive ions, known as cations, and negative ions, known as anions 5 Describe the giant lattice structure of ionic compounds as a regular arrangement of alternating positive and negative ions
    2 State that an ionic bond is a strong electrostatic attraction between oppositely charged ions 6 Describe the formation of ionic bonds between ions of metallic and non-metallic elements, including the use of dot-and-cross diagrams
    3 Describe the formation of ionic bonds between elements from Group I and Group VII, including the use of dot-and-cross diagrams 7 Explain in terms of structure and bonding the properties of ionic compounds: (a) high melting points and boiling points (b) good electrical conductivity when aqueous or molten and poor when solid
    4 Describe the properties of ionic compounds: (a) high melting points and boiling points (b) good electrical conductivity when aqueous or molten and poor when solid

    Source: Cambridge International syllabus

    Ionic bonding: electron transfer

    An ion 离子 is an atom (or group of atoms) that has lost or gained electrons, so it has an electric charge.

    • A metal atom loses electrons to form a positive ion, called a cation 阳离子.
    • A non-metal atom gains electrons to form a negative ion, called an anion 阴离子.

    Atoms do this to get a full outer shell, like a noble gas.

    How an ionic bond forms

    An ionic bond 离子键 is a strong electrostatic attraction 静电引力 between oppositely charged ions (a $+$ ion and a $-$ ion pull together).

    Ionic bonds form between a metal 金属 and a non-metal 非金属. Take sodium chloride, $\text{NaCl}$. Sodium ($2,8,1$) gives its one outer electron to chlorine ($2,8,7$). Now sodium is $\text{Na}^{+}$ ($2,8$) and chlorine is $\text{Cl}^{-}$ ($2,8,8$). Both have full outer shells, and the opposite charges attract.

    You can show this with a dot-and-cross diagram: draw each atom's outer-shell electrons as dots for one element and crosses for the other, then show the electron moving from the metal to the non-metal.

    Sodium's single outer electron transfers to chlorine; sodium becomes Na+ (2,8) and chlorine becomes Cl- (2,8,8)
    Sodium gives its outer electron to chlorine; both reach full outer shells and the opposite charges attract (the blue electron came from sodium)

    The structure and properties of ionic compounds

    An ionic compound 离子化合物 is not made of separate molecules 分子. The ions pack together into a giant lattice 晶格 — a regular pattern of huge numbers of alternating 交替 positive and negative ions.

    A grid of alternating small blue Na+ ions and larger orange Cl- ions, repeating in a regular pattern
    Ions pack into a giant lattice: a regular, repeating pattern of alternating positive and negative ions

    This structure explains the properties:

    Property Reason
    high melting point 熔点 and boiling point 沸点 the strong electrostatic attraction between ions needs a lot of energy to break
    poor electrical conductivity 导电性 when solid the ions are fixed in place and cannot move
    good conductor when molten 熔融 or aqueous 水溶液 the ions are now free to move and carry charge
    Explore

    Forming an ionic bond (NaCl)

    Step through it. A metal hands its outer electron to a non-metal; the oppositely charged ions then attract and pack into a giant lattice.

    Explore

    Ionic bonding (electron transfer)

    Step through it: the metal hands its outer electron(s) to the non-metal, both reach full shells, and the resulting + and − ions attract — an ionic bond.

    Vocabulary Train
    English Chinese Pinyin
    ion 离子 lí zi
    cation 阳离子 yáng lí zi
    anion 阴离子 yīn lí zi
    ionic bond 离子键 lí zi jiàn
    electrostatic attraction 静电引力 jìng diàn yǐn lì
    metal 金属 jīn shǔ
    non-metal 非金属 fēi jīn shǔ
    ionic compound 离子化合物 lí zi huà hé wù
    molecules 分子 fèn zǐ
    lattice 晶格 jīng gé
    alternating 交替 jiāo tì
    melting point 熔点 róng diǎn
    boiling point 沸点 fèi diǎn
    electrical conductivity 导电性 dǎo diàn xìng
    molten 熔融 róng róng
    aqueous 水溶液 shuǐ róng yè
    Exercise sheet
    2.5

    Simple molecules and covalent bonds

    Syllabus
    Core Supplement
    1 State that a covalent bond is formed when a pair of electrons is shared between two atoms leading to noble gas electronic configurations
    2 Describe the formation of covalent bonds in simple molecules, including $\text{H}_2$, $\text{Cl}_2$, $\text{H}_2\text{O}$, $\text{CH}_4$, $\text{NH}_3$ and $\text{HCl}$. Use dot-and-cross diagrams to show the electronic configurations in these and similar molecules 4 Describe the formation of covalent bonds in simple molecules, including $\text{CH}_3\text{OH}$, $\text{C}_2\text{H}_4$, $\text{O}_2$, $\text{CO}_2$ and $\text{N}_2$. Use dot-and-cross diagrams to show the electronic configurations in these and similar molecules
    3 Describe in terms of structure and bonding the properties of simple molecular compounds: (a) low melting points and boiling points (b) poor electrical conductivity 5 Explain in terms of structure and bonding the properties of simple molecular compounds: (a) low melting points and boiling points in terms of weak intermolecular forces (specific types of intermolecular forces are not required) (b) poor electrical conductivity

    Source: Cambridge International syllabus

    Covalent bonding: a shared pair
    A ball-and-stick model of a water molecule
    A model of a water molecule: atoms share electrons in covalent bonds.

    A covalent bond 共价键 forms when two atoms share a pair of electrons. By sharing, each atom gets a full outer shell (a noble gas configuration). Covalent bonds form between non-metal atoms.

    Some molecules to know:

    • $\text{H}_2$ — two hydrogen atoms share one pair of electrons (a single bond).
    • $\text{Cl}_2$, $\text{HCl}$ — one shared pair each.
    • $\text{H}_2\text{O}$ — oxygen shares one pair with each of two hydrogen atoms.
    • $\text{NH}_3$ — nitrogen shares a pair with each of three hydrogen atoms.
    • $\text{CH}_4$ — carbon shares a pair with each of four hydrogen atoms.
    • $\text{O}_2$ and $\text{CO}_2$ have double bonds (two shared pairs); $\text{N}_2$ has a triple bond (three shared pairs); $\text{C}_2\text{H}_4$ and $\text{CH}_3\text{OH}$ also use shared pairs.

    In a dot-and-cross diagram for a molecule, you draw the outer electrons of each atom and show which pairs are shared in the overlap between the atoms.

    Dot-and-cross diagrams for hydrogen (one shared pair), water (two shared pairs and lone pairs) and methane (four shared pairs)
    In a covalent bond, atoms share pairs of electrons so each reaches a full outer shell

    Properties of simple molecular compounds

    These substances are made of small, separate molecules.

    • They have low melting points and boiling points. The covalent bonds inside each molecule are strong, but the intermolecular forces 分子间作用力 (the forces between one molecule and the next) are weak, so little energy is needed to separate the molecules.
    • They are poor conductors of electricity, because the molecules have no overall charge and no free electrons or ions to carry charge.
    Explore

    Why a molecule has its shape

    Shared electron pairs repel one another and spread out as far apart as they can. Four bonding pairs and no lone pairs gives a tetrahedral shape, like methane (CH4).

    Explore

    Covalent bonding (sharing)

    Step through it: two non-metal atoms overlap and share a pair of electrons — counting for both — so each reaches a full outer shell. That shared pair is the covalent bond; O₂ shares two pairs (a double bond).

    Vocabulary Train
    English Chinese Pinyin
    covalent bond 共价键 gòng jià jiàn
    intermolecular forces 分子间作用力 fèn zǐ jiàn zuò yòng lì
    Exercise sheet
    2.6

    Giant covalent structures

    Syllabus
    Core Supplement
    1 Describe the giant covalent structures of graphite and diamond 3 Describe the giant covalent structure of silicon(IV) oxide, $\text{SiO}_2$
    2 Relate the structures and bonding of graphite and diamond to their uses, limited to: (a) graphite as a lubricant and as an electrode (b) diamond in cutting tools 4 Describe the similarity in properties between diamond and silicon(IV) oxide, related to their structures

    Source: Cambridge International syllabus

    Some covalent substances are not small molecules. Instead, millions of atoms are joined by covalent bonds into one giant covalent structure 巨型共价结构. The two you must know are both forms of carbon.

    Diamond 金刚石: each carbon atom is bonded to four other carbon atoms. This makes a very strong, rigid 3-D network. Diamond is extremely hard, so it is used in cutting tools 切割工具.

    Graphite 石墨: each carbon atom is bonded to only three others, forming flat layers. There are weak forces between the layers, so the layers can slide over each other — this makes graphite a good lubricant 润滑剂. The fourth outer electron of each carbon is free; these delocalised electrons 离域电子 can move, so graphite conducts electricity and is used as an electrode 电极.

    Diamond with each carbon bonded to four others in a network, beside graphite's flat hexagonal layers held by weak forces
    Diamond bonds each carbon to four others (hard); graphite forms flat layers with weak forces between them (slippery)

    Silicon(IV) oxide 二氧化硅 ($\text{SiO}_2$) has a giant covalent structure like diamond, so it is also very hard and has a very high melting point.

    Explore

    Giant covalent lab

    Compare giant covalent structures by bonding and properties.

    Vocabulary Train
    English Chinese Pinyin
    giant covalent structure 巨型共价结构 jù xíng gòng jià jié gòu
    diamond 金刚石 jīn gāng shí
    cutting tools 切割工具 qiē gē gōng jù
    graphite 石墨 shí mò
    layers céng
    lubricant 润滑剂 rùn huá jì
    delocalised electrons 离域电子 lí yù diàn zi
    electrode 电极 diàn jí
    silicon(IV) oxide 二氧化硅 èr yǎng huà guī
    2.7

    Metallic bonding

    Syllabus
    Core Supplement
    1 Describe metallic bonding as the electrostatic attraction between the positive ions in a giant metallic lattice and a ‘sea’ of delocalised electrons
    2 Explain in terms of structure and bonding the properties of metals: (a) good electrical conductivity (b) malleability and ductility

    Source: Cambridge International syllabus

    A metal is a giant structure of positive ions surrounded by a 'sea' of delocalised electrons that are free to move through the whole metal. Metallic bonding 金属键 is the strong electrostatic attraction between these positive ions and the sea of electrons.

    A regular lattice of positive metal ions with free electrons scattered in the gaps between them
    A metal is positive ions in a 'sea' of delocalised electrons that are free to move and carry charge

    This explains two key properties of metals:

    • Good electrical conductivity: the delocalised electrons are free to move and carry charge through the metal.
    • Malleability 展性 (can be hammered into sheets) and ductility 延性 (can be pulled into wires): the layers of positive ions can slide over each other without breaking the metallic bond, so the metal changes shape instead of shattering.
    Explore

    Inside a metal — and why it behaves that way

    Step through it. Positive ions sit in a shared sea of delocalised electrons — that one picture explains conduction and why metals bend instead of snapping.

    Vocabulary Train
    English Chinese Pinyin
    metallic bonding 金属键 jīn shǔ jiàn
    malleability 展性 zhǎn xìng
    ductility 延性 yán xìng
    2.7

    Exam tips

    • Number of neutrons = mass number − proton number. The proton number is what decides which element an atom is.
    • Isotopes have the same chemical properties because reactions involve only electrons, and isotopes share the same electron configuration; only the mass differs.
    • Match structure to properties: ionic = giant lattice (high melting point; conducts only when molten or aqueous); simple molecular = weak forces between molecules (low melting point; no conduction); giant covalent = very hard, very high melting point.
    • Graphite conducts and is slippery (one free electron per carbon; layers slide); diamond does neither (all four electrons bonded, so hard and non-conducting). Metals conduct and bend thanks to the sea of delocalised electrons.
    • For relative atomic mass, take the weighted average: $A_r = \dfrac{\sum(\text{isotope mass} \times \text{abundance})}{100}$.
  • 3 Stoichiometry

    Stoichiometry 化学计量 is the study of the amounts of substances in a reaction — how much reacts and how much is made. This topic is mostly about counting atoms and doing calculations.

    3.1

    Chemical formulae

    Syllabus
    Core Supplement
    1 State the formulae of the elements and compounds named in the subject content
    2 Define the molecular formula of a compound as the number and type of different atoms in one molecule 5 Define the empirical formula of a compound as the simplest whole number ratio of the different atoms or ions in a compound
    3 Deduce the formula of a simple compound from the relative numbers of atoms present in a model or a diagrammatic representation 6 Deduce the formula of an ionic compound from the relative numbers of the ions present in a model or a diagrammatic representation or from the charges on the ions
    4 Construct word equations and symbol equations to show how reactants form products, including state symbols 7 Construct symbol equations with state symbols, including ionic equations
    8 Deduce the symbol equation with state symbols for a chemical reaction, given relevant information

    Source: Cambridge International syllabus

    A formula 化学式 shows which atoms 原子 are in a substance, and how many of each. There are two kinds of formula you must know.

    • The molecular formula 分子式 is the actual number of each atom in one molecule 分子. For glucose it is $\text{C}_6\text{H}_{12}\text{O}_6$.
    • The empirical formula 实验式 is the simplest whole-number ratio 比例 of the atoms or ions 离子 in a compound 化合物. For glucose it is $\text{CH}_2\text{O}$.

    Working out a formula

    If you are given a model or diagram, just count the atoms of each element and write them as a formula.

    For an ionic compound 离子化合物 you can work out the formula from the charges on the ions. The total positive charge must balance the total negative charge, because the compound has no overall charge. Some common ions:

    Positive ions Negative ions
    $\text{Na}^{+}$, $\text{K}^{+}$, $\text{H}^{+}$ $\text{Cl}^{-}$, $\text{OH}^{-}$, $\text{NO}_3^{-}$
    $\text{Mg}^{2+}$, $\text{Ca}^{2+}$, $\text{Cu}^{2+}$ $\text{O}^{2-}$, $\text{SO}_4^{2-}$, $\text{CO}_3^{2-}$
    $\text{Al}^{3+}$ $\text{N}^{3-}$

    For example, $\text{Na}^{+}$ and $\text{O}^{2-}$: you need two $\text{Na}^{+}$ to balance one $\text{O}^{2-}$, so the formula is $\text{Na}_2\text{O}$.

    Aluminium 3+ and oxygen 2- ions with their charge numbers crossing over to become the subscripts in Al2O3
    For an ionic compound, the ion charges cross over to give the formula (here $\text{Al}_2\text{O}_3$)
    Explore

    Formula writing route

    Follow charges or valencies to a neutral chemical formula.

    Vocabulary Train
    English Chinese Pinyin
    stoichiometry 化学计量 huà xué jì liàng
    formula 化学式 huà xué shì
    atoms 原子 yuán zi
    molecular formula 分子式 fēn zǐ shì
    molecule 分子 fèn zǐ
    empirical formula 实验式 shí yàn shì
    ratio 比例 bǐ lì
    ions 离子 lí zi
    compound 化合物 huà hé wù
    ionic compound 离子化合物 lí zi huà hé wù
    3.1

    Writing equations

    An equation shows how reactants 反应物 (the starting substances) change into products 生成物 (the substances made).

    • A word equation 文字方程式 uses names: magnesium + oxygen → magnesium oxide.
    • A symbol equation 化学方程式 uses formulae and must be balanced 配平 — the same number of each atom on both sides.
    $$2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}$$
    Two magnesium atoms plus an oxygen molecule react to form two units of magnesium oxide, with two Mg and two O on each side
    A balanced symbol equation has the same number of each atom on both sides

    You add state symbols 状态符号 in brackets to show the physical state: $(s)$ solid, $(l)$ liquid, $(g)$ gas, and $(aq)$ for aqueous 水溶液 (dissolved in water).

    $$\text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g)$$

    Ionic equations

    An ionic equation 离子方程式 shows only the ions that actually change. Ions that are the same on both sides are spectator ions 旁观离子 and are left out. For example, when an acid reacts with an alkali:

    $$\text{H}^{+}(aq) + \text{OH}^{-}(aq) \rightarrow \text{H}_2\text{O}(l)$$
    Explore

    Balance the equation

    Step the coefficients until every element has the same number of atoms on both sides.

    Vocabulary Train
    English Chinese Pinyin
    reactants 反应物 fǎn yìng wù
    products 生成物 shēng chéng wù
    word equation 文字方程式 wén zì fāng chéng shì
    symbol equation 化学方程式 huà xué fāng chéng shì
    balanced 配平 pèi píng
    state symbols 状态符号 zhuàng tài fú hào
    aqueous 水溶液 shuǐ róng yè
    ionic equation 离子方程式 lí zi fāng chéng shì
    spectator ions 旁观离子 páng guān lí zi
    3.2

    Relative masses

    Syllabus
    Core Supplement
    1 Describe relative atomic mass, $A_r$, as the average mass of the isotopes of an element compared to 1/12th of the mass of an atom of $^{12}\text{C}$
    2 Define relative molecular mass, $M_r$, as the sum of the relative atomic masses. Relative formula mass, $M_r$, will be used for ionic compounds
    3 Calculate reacting masses in simple proportions. Calculations will not involve the mole concept

    Source: Cambridge International syllabus

    A laboratory analytical balance
    A laboratory balance measures mass — the basis of mole calculations.

    The relative atomic mass 相对原子质量 ($A_r$) of an element 元素 is the average mass 质量 of its atoms compared to $\tfrac{1}{12}$ of the mass of one $^{12}\text{C}$ atom.

    The relative molecular mass 相对分子质量 ($M_r$) is the sum of the relative atomic masses of all the atoms in the molecule. For ionic compounds we use the relative formula mass 相对式量, found the same way from the formula.

    $$M_r(\text{H}_2\text{O}) = (2 \times 1) + 16 = 18$$

    Reacting masses by simple proportion

    You can sometimes find a reacting mass without the mole. If 24 g of magnesium makes 40 g of magnesium oxide, then 12 g of magnesium (half as much) makes 20 g of magnesium oxide.

    Explore

    Formula mass lab

    mass = moles x Mr

    Change number of formula units and see total mass scale.

    Vocabulary Train
    English Chinese Pinyin
    relative atomic mass 相对原子质量 xiāng duì yuán zi zhì liàng
    element 元素 yuán sù
    mass 质量 zhì liàng
    relative molecular mass 相对分子质量 xiāng duì fèn zǐ zhì liàng
    relative formula mass 相对式量 xiāng duì shì liàng
    3.3

    The mole

    Syllabus
    Core Supplement
    2 State that the mole, mol, is the unit of amount of substance and that one mole contains $6.02 \times 10^{23}$ particles, e.g. atoms, ions, molecules; this number is the Avogadro constant
    3 Use the relationship $\text{amount of substance (mol)} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}$ to calculate: (a) amount of substance (b) mass (c) molar mass (d) relative atomic mass or relative molecular/formula mass (e) number of particles, using the value of the Avogadro constant
    4 Use the molar gas volume, taken as $24\text{ dm}^3$ at room temperature and pressure, r.t.p., in calculations involving gases
    1 State that concentration can be measured in $\text{g/dm}^3$ or $\text{mol/dm}^3$ 5 Calculate stoichiometric reacting masses, limiting reactants, volumes of gases at r.t.p., volumes of solutions and concentrations of solutions expressed in $\text{g/dm}^3$ and $\text{mol/dm}^3$, including conversion between $\text{cm}^3$ and $\text{dm}^3$
    6 Use experimental data from a titration to calculate the moles of solute, or the concentration or volume of a solution
    7 Calculate empirical formulae and molecular formulae, given appropriate data
    8 Calculate percentage yield, percentage composition by mass and percentage purity, given appropriate data

    Source: Cambridge International syllabus

    The mole 摩尔 (symbol mol) is the unit for the amount of substance 物质的量. One mole of any substance contains $6.02 \times 10^{23}$ particles 粒子 (atoms, ions or molecules). This number is the Avogadro constant 阿伏伽德罗常数.

    The molar mass 摩尔质量 is the mass of one mole, in grams per mole (g/mol). Its number is the same as the $A_r$ or $M_r$. The key relationship is:

    $$\text{amount (mol)} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}}$$

    Worked example. How many moles are in 36 g of water? Molar mass of water $= 18$ g/mol.

    $$n = \frac{36}{18} = 2 \text{ mol}$$

    To find the number of particles, multiply the moles by the Avogadro constant.

    Volumes of gases

    At room temperature and pressure (r.t.p.), one mole of any gas takes up the same volume 体积. This molar gas volume 摩尔气体体积 is $24 \text{ dm}^3$.

    Three balloons of the same size holding one mole of hydrogen, oxygen and carbon dioxide: different masses but the same 24 cubic decimetres
    One mole of any gas fills 24 cubic decimetres at room temperature and pressure
    $$\text{volume of gas (dm}^3) = \text{amount (mol)} \times 24$$

    Worked example. What volume does $0.25$ mol of carbon dioxide occupy at r.t.p.?

    $$\text{volume} = 0.25 \times 24 = 6 \text{ dm}^3$$

    Concentration of solutions

    The concentration 浓度 of a solution 溶液 can be given in $\text{g/dm}^3$ or in $\text{mol/dm}^3$.

    $$\text{concentration (mol/dm}^3) = \frac{\text{amount of solute (mol)}}{\text{volume (dm}^3)}$$

    Remember to convert volume: $1 \text{ dm}^3 = 1000 \text{ cm}^3$, so divide a volume in $\text{cm}^3$ by 1000.

    A mole map with moles in the centre, linked to mass, gas volume, concentration and number of particles by their conversion factors
    Moles sit at the centre: multiply going outwards, divide coming back (concentration is moles ÷ volume)
    Explore

    Mole particle lab

    particles = n x Avogadro constant

    Change moles and see particle number scale with Avogadro constant.

    Vocabulary Train
    English Chinese Pinyin
    mole 摩尔 mó ěr
    amount of substance 物质的量 wù zhì dì liàng
    particles 粒子 lì zi
    Avogadro constant 阿伏伽德罗常数 ā fú gā dé luó cháng shù
    molar mass 摩尔质量 mó ěr zhì liàng
    volume 体积 tǐ jī
    molar gas volume 摩尔气体体积 mó ěr qì tǐ tǐ jī
    concentration 浓度 nóng dù
    solution 溶液 róng yè
    3.3

    Doing reaction calculations

    A titration being carried out in a laboratory
    A titration measures exactly how much acid reacts with a base.

    Most calculations follow the same steps: change the known amount into moles, use the balanced equation to find the moles of what you want, then change back into mass, volume or concentration.

    Worked example. What mass of magnesium oxide forms when 12 g of magnesium burns completely? $2\text{Mg} + \text{O}_2 \rightarrow 2\text{MgO}$. ($A_r$: Mg $= 24$, O $= 16$.)

    Moles of Mg $= 12 / 24 = 0.5$ mol. The ratio Mg : MgO is $1 : 1$, so $0.5$ mol of MgO forms. Its molar mass is $24 + 16 = 40$ g/mol, so the mass is $0.5 \times 40 = 20$ g — the same answer as the simple-proportion method above.

    Limiting reactant

    When two reactants are mixed, often one runs out first. This is the limiting reactant 限量反应物. It decides how much product can form; any other reactant is in excess (left over).

    Four A particles and two B particles react to make two products, leaving two A particles unreacted
    B runs out first, so it is the limiting reactant and sets how much product forms; the spare A is left over in excess

    Worked example. 8 g of hydrogen reacts with 8 g of oxygen: $2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}$. Which is the limiting reactant, and what mass of water forms? ($A_r$: H $= 1$, O $= 16$.)

    Moles of $\text{H}_2 = 8 / 2 = 4$ mol; moles of $\text{O}_2 = 8 / 32 = 0.25$ mol. The equation needs $2\text{H}_2$ for every one $\text{O}_2$, so $0.25$ mol of $\text{O}_2$ reacts with only $0.5$ mol of $\text{H}_2$. There is far more hydrogen than that, so oxygen is the limiting reactant and the hydrogen is in excess. The oxygen makes $2 \times 0.25 = 0.5$ mol of water, so the mass is $0.5 \times 18 = 9$ g. Always work in moles, not masses — the reactant with the smaller mass is not always the one that runs out.

    Titration calculation

    In a titration 滴定 you measure the volume of one solution that reacts with another. From the volume and concentration you find the moles of one solute 溶质, then use the equation ratio to find the moles, concentration or volume of the other.

    Worked example. $25.0 \text{ cm}^3$ of sodium hydroxide solution is exactly neutralised by $20.0 \text{ cm}^3$ of $0.10 \text{ mol/dm}^3$ hydrochloric acid. $\text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O}$. Find the concentration of the sodium hydroxide.

    Moles of HCl $= 0.10 \times \dfrac{20.0}{1000} = 0.0020$ mol. The ratio is $1 : 1$, so there are $0.0020$ mol of NaOH in $25.0 \text{ cm}^3$:

    $$\text{concentration} = \frac{0.0020}{25.0 / 1000} = 0.08 \text{ mol/dm}^3$$
    The titration calculation as a flow: the known acid gives its moles, the equation's 1 to 1 ratio gives the moles of sodium hydroxide, and dividing by its volume gives the concentration
    The titration calculation: known solution to moles, ratio, then the unknown concentration

    Empirical and molecular formulae from data

    To find an empirical formula from masses or percentages:

    1. Divide each element's mass (or %) by its $A_r$.
    2. Divide all the answers by the smallest one to get the simplest ratio.

    To find the molecular formula, compare the empirical formula mass with the real $M_r$ and multiply up.

    Worked example. A compound contains $40\%$ calcium, $12\%$ carbon and $48\%$ oxygen by mass. Find its empirical formula. ($A_r$: Ca $= 40$, C $= 12$, O $= 16$.)

    Divide each percentage by its $A_r$: Ca $= 40/40 = 1$, C $= 12/12 = 1$, O $= 48/16 = 3$. The ratio is $1 : 1 : 3$, so the empirical formula is $\text{CaCO}_3$.

    Percentages

    • Percentage yield 产率 compares how much product you actually got with the most you could get: $\dfrac{\text{actual}}{\text{theoretical}} \times 100$.
    • Percentage composition by mass 质量分数 of an element $= \dfrac{\text{mass of the element}}{M_r} \times 100$.
    • Percentage purity 纯度 $= \dfrac{\text{mass of pure substance}}{\text{mass of impure sample}} \times 100$.

    Worked example. Find the percentage by mass of nitrogen in ammonium nitrate, $\text{NH}_4\text{NO}_3$. ($A_r$: N $= 14$, H $= 1$, O $= 16$.)

    $M_r = (2 \times 14) + (4 \times 1) + (3 \times 16) = 80$. The mass of nitrogen is $2 \times 14 = 28$, so

    $$\% \text{ nitrogen} = \frac{28}{80} \times 100 = 35\%$$

    Worked example. A reaction could make at most 5.0 g of product, but only 4.0 g is actually collected. Find the percentage yield.

    $$\% \text{ yield} = \frac{4.0}{5.0} \times 100 = 80\%$$

    Some product is always lost — left behind in the apparatus, or used up in side reactions — so the yield is almost never $100\%$.

    Worked example. A 50 g sample of impure calcium carbonate contains 45 g of pure calcium carbonate. Find its percentage purity.

    $$\% \text{ purity} = \frac{45}{50} \times 100 = 90\%$$
    Explore

    Reaction calculation route

    Follow a known mass through a balanced equation to the answer.

    Vocabulary Train
    English Chinese Pinyin
    limiting reactant 限量反应物 xiàn liàng fǎn yìng wù
    titration 滴定 dī dìng
    solute 溶质 róng zhì
    percentage yield 产率 chǎn lǜ
    percentage composition by mass 质量分数 zhì liàng fēn shù
    percentage purity 纯度 chún dù
    3.3

    Exam tips

    • Always turn masses, gas volumes and concentrations into moles first, use the balanced equation's ratio, then convert back. Never compare masses directly across an equation.
    • Key formulas: $n = \dfrac{\text{mass}}{M_r}$, gas volume $= n \times 24\ \text{dm}^3$ at r.t.p., and concentration $= \dfrac{n}{\text{volume in dm}^3}$. Change cm³ to dm³ by dividing by 1000.
    • To balance a symbol equation you may only change the big numbers in front of a formula, never the small subscripts inside it.
    • The limiting reactant is the one that runs out (fewest moles once you allow for the ratio); it sets how much product forms. The other reactant is in excess.
    • Percentage yield = actual ÷ theoretical × 100; percentage purity = mass of pure substance ÷ mass of sample × 100. Both are always 100% or less.
  • 4 Electrochemistry
    4.1

    Electrolysis

    Syllabus
    Core Supplement
    1 Define electrolysis as the decomposition of an ionic compound, when molten or in aqueous solution, by the passage of an electric current 8 Describe the transfer of charge during electrolysis to include: (a) the movement of electrons in the external circuit (b) the loss or gain of electrons at the electrodes (c) the movement of ions in the electrolyte
    2 Identify in simple electrolytic cells: (a) the anode as the positive electrode (b) the cathode as the negative electrode (c) the electrolyte as the molten or aqueous substance that undergoes electrolysis
    3 Identify the products formed at the electrodes and describe the observations made during the electrolysis of: (a) molten lead(II) bromide (b) concentrated aqueous sodium chloride (c) dilute sulfuric acid using inert electrodes made of platinum or carbon/graphite 9 Identify the products formed at the electrodes and describe the observations made during the electrolysis of aqueous copper(II) sulfate using inert carbon/graphite electrodes and when using copper electrodes
    4 State that metals or hydrogen are formed at the cathode and that non-metals (other than hydrogen) are formed at the anode
    5 Predict the identity of the products at each electrode for the electrolysis of a binary compound in the molten state 10 Predict the identity of the products at each electrode for the electrolysis of a halide compound in dilute or concentrated aqueous solution
    11 Construct ionic half-equations for reactions at the anode (to show oxidation) and at the cathode (to show reduction)
    6 State that metal objects are electroplated to improve their appearance and resistance to corrosion
    7 Describe how metals are electroplated

    Source: Cambridge International syllabus

    Electrolysis: ions discharge at the electrodes

    Electrolysis 电解 is the breaking down (decomposition 分解) of an ionic compound 离子化合物 — when it is molten 熔融 or in aqueous 水溶液 solution — by passing an electric current 电流 through it.

    A water electrolysis unit
    An electrolysis cell splits a compound using an electric current.

    It only works when the substance is molten or dissolved, because then the ions 离子 are free to move and carry the charge. A solid ionic compound cannot be electrolysed because its ions are locked in place.

    A small electrolysis demonstration: two upturned graduated tubes stand in a beaker of water, wired to a 9-volt battery, with gas collected at the top of each tube and about twice as much gas in one tube as the other
    Electrolysis of water: gas bubbles off at each electrode and collects in the tubes above, with about twice as much hydrogen as oxygen

    The electrolytic cell

    The set-up is called an electrolytic cell 电解池. Two electrodes 电极 (solid conductors) dip into the electrolyte 电解质 — the molten or aqueous substance being broken down.

    • The anode 阳极 is the positive ($+$) electrode.
    • The cathode 阴极 is the negative ($-$) electrode.

    The electrodes are often inert 惰性 (they do not react), such as platinum or carbon/graphite 石墨.

    What is formed at each electrode

    There is a simple rule:

    Metals/hydrogen form at the cathode; non-metals form at the anode
    Metals and hydrogen form at the cathode; non-metals at the anode
    • Metals 金属 or hydrogen 氢气 are formed at the cathode.
    • Non-metals 非金属 (other than hydrogen) are formed at the anode.

    For aqueous solutions, the product can depend on whether the solution is dilute or concentrated. Here are the three Core examples:

    Electrolyte At the cathode ($-$) At the anode ($+$)
    molten lead(II) bromide, $\text{PbBr}_2$ lead (silvery liquid) bromine (red-brown vapour)
    concentrated aqueous sodium chloride hydrogen (bubbles of gas) chlorine 氯气 (pale green gas)
    dilute sulfuric acid 硫酸 hydrogen (bubbles of gas) oxygen 氧气 (bubbles of gas)

    Worked example. Predict the products of electrolysing molten zinc chloride, $\text{ZnCl}_2$. Because it is molten, only zinc ions and chloride ions are present - there is no water to complicate things. Zinc is a metal, so it forms at the cathode: $\text{Zn}^{2+}$ ions gain electrons and silvery zinc appears. Chlorine is a non-metal, so it forms at the anode: pale green chlorine gas bubbles off. Always check the state first. A molten compound simply gives you its own two elements, while an aqueous one brings water into the competition - which is why concentrated sodium chloride solution gives hydrogen at the cathode rather than sodium.

    How the charge moves

    During electrolysis:

    • Electrons 电子 move through the wires (the external circuit 外电路) from the power supply.
    • At the cathode, positive ions gain electrons. Gaining electrons is reduction 还原.
    • At the anode, negative ions lose electrons. Losing electrons is oxidation 氧化.
    • Inside the electrolyte, the ions move: positive ions go to the cathode and negative ions go to the anode.

    You can write a half-equation 半反应式 for each electrode. For molten lead(II) bromide:

    $$\text{Pb}^{2+} + 2e^{-} \rightarrow \text{Pb} \quad (\text{cathode, reduction})$$
    $$2\text{Br}^{-} \rightarrow \text{Br}_2 + 2e^{-} \quad (\text{anode, oxidation})$$
    An electrolysis cell for molten lead bromide: a d.c. supply connected to a cathode and anode dipping into the melt, with lead ions moving to the cathode and bromide ions to the anode
    In molten lead(II) bromide, $\text{Pb}^{2+}$ moves to the cathode and $\text{Br}^-$ to the anode, where each is discharged

    Electrolysis of copper(II) sulfate

    The product at the anode depends on the electrode:

    • With inert carbon electrodes: copper forms at the cathode and oxygen forms at the anode. The blue colour of the solution slowly fades as copper is removed.
    • With copper electrodes: copper forms at the cathode, while the anode itself dissolves into the solution. The blue colour stays the same. This is used to purify copper.

    Electroplating

    Electroplating 电镀 means covering a metal object with a thin layer of another metal. This improves its appearance and its resistance to corrosion 腐蚀 (rusting and wearing away).

    To electroplate an object:

    • the object to be coated is made the cathode;
    • the plating metal is made the anode;
    • the electrolyte is a solution containing ions of the plating metal.
    An electroplating cell with the object as the cathode and a bar of pure copper as the anode in copper(II) sulfate solution
    To electroplate, make the object the cathode and the plating metal the anode, in a solution of the plating-metal ions
    Explore

    Inside an electrolysis cell

    Pick an electrolyte and watch ions move: positive ions to the cathode, negative ions to the anode.

    Vocabulary Train
    English Chinese Pinyin
    electrolysis 电解 diàn jiě
    decomposition 分解 fēn jiě
    ionic compound 离子化合物 lí zi huà hé wù
    molten 熔融 róng róng
    aqueous 水溶液 shuǐ róng yè
    electric current 电流 diàn liú
    ions 离子 lí zi
    electrolytic cell 电解池 diàn jiě chí
    electrodes 电极 diàn jí
    electrolyte 电解质 diàn jiě zhì
    anode 阳极 yáng jí
    cathode 阴极 yīn jí
    inert 惰性 duò xìng
    platinum
    graphite 石墨 shí mò
    metals 金属 jīn shǔ
    hydrogen 氢气 qīng qì
    non-metals 非金属 fēi jīn shǔ
    dilute
    concentrated nóng
    lead qiān
    bromine xiù
    chlorine 氯气 lǜ qì
    sulfuric acid 硫酸 liú suān
    oxygen 氧气 yǎng qì
    electrons 电子 diàn zi
    external circuit 外电路 wài diàn lù
    reduction 还原 huán yuán
    oxidation 氧化 yǎng huà
    half-equation 半反应式 bàn fǎn yìng shì
    copper tóng
    electroplating 电镀 diàn dù
    corrosion 腐蚀 fǔ shí
    4.2

    Hydrogen–oxygen fuel cells

    Syllabus
    Core Supplement
    1 State that a hydrogen–oxygen fuel cell uses hydrogen and oxygen to produce electricity with water as the only chemical product 2 Describe the advantages and disadvantages of using hydrogen–oxygen fuel cells in comparison with gasoline/petrol engines in vehicles

    Source: Cambridge International syllabus

    A fuel cell 燃料电池 uses hydrogen and oxygen to make electricity directly. The only chemical product is water.

    $$2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}$$
    A hydrogen-oxygen fuel cell with hydrogen and oxygen fed to two electrodes, an external circuit running a motor, and water leaving as the only product
    A hydrogen–oxygen fuel cell turns chemical energy straight into electricity, with water as the only product

    It is useful to compare a fuel cell with a normal petrol (gasoline) engine in a vehicle.

    Hydrogen–oxygen fuel cell Petrol engine
    Main product water only carbon dioxide and pollutants 污染物
    Effect on air clean adds to air pollution
    Fuel storage hydrogen is hard and dangerous to store (flammable, needs high pressure) petrol is easy to store
    Source hydrogen may be made using fossil fuels made from crude oil

    Advantages of the fuel cell: the only product is water, so it does not pollute the air, and it changes chemical energy into electricity efficiently. Disadvantages: hydrogen is hard to store and transport safely, and producing the hydrogen can still use energy from fossil fuels.

    Explore

    Inside a hydrogen–oxygen fuel cell

    Step through a fuel cell. Hydrogen and oxygen combine to make water, and the energy of that reaction is released as electricity — with no carbon dioxide.

    Vocabulary Train
    English Chinese Pinyin
    fuel cell 燃料电池 rán liào diàn chí
    pollutants 污染物 wū rǎn wù
    4.2

    Exam tips

    • At the cathode (negative) you get a metal or hydrogen; at the anode (positive) you get a non-metal. Positive ions move to the cathode, negative ions to the anode.
    • A molten compound just gives its two elements. An aqueous solution can give something different (concentrated sodium chloride gives hydrogen and chlorine, not sodium).
    • Reduction is gain of electrons (at the cathode); oxidation is loss of electrons (at the anode). Remember OIL RIG.
    • In a half-equation the atoms and the charges must balance, with the electrons on the correct side: $\text{Pb}^{2+} + 2e^- \rightarrow \text{Pb}$ (cathode).
    • To electroplate an object, make it the cathode, make the plating metal the anode, and use a solution containing ions of the plating metal.
  • 5 Chemical energetics
    5.1

    Exothermic and endothermic reactions

    Syllabus
    Core Supplement
    1 State that an exothermic reaction transfers thermal energy to the surroundings leading to an increase in the temperature of the surroundings 4 State that the transfer of thermal energy during a reaction is called the enthalpy change, $\Delta H$, of the reaction. $\Delta H$ is negative for exothermic reactions and positive for endothermic reactions
    2 State that an endothermic reaction takes in thermal energy from the surroundings leading to a decrease in the temperature of the surroundings
    5 Define activation energy, $E_a$, as the minimum energy that colliding particles must have to react
    3 Interpret reaction pathway diagrams showing exothermic and endothermic reactions 6 Draw and label reaction pathway diagrams for exothermic and endothermic reactions using information provided, to include: (a) reactants (b) products (c) enthalpy change of the reaction, $\Delta H$ (d) activation energy, $E_a$
    7 State that bond breaking is an endothermic process and bond making is an exothermic process and explain the enthalpy change of a reaction in terms of bond breaking and bond making
    8 Calculate the enthalpy change of a reaction using bond energies

    Source: Cambridge International syllabus

    Reaction profile: exothermic energy change
    A campfire burning wood
    Burning wood is exothermic, releasing heat to the surroundings.

    In every chemical reaction, energy is transferred. The reaction is either exothermic or endothermic, depending on which way the energy moves.

    • An exothermic reaction 放热反应 gives out thermal energy 热能 to the surroundings 环境. So the temperature of the surroundings goes up.
    • An endothermic reaction 吸热反应 takes in thermal energy from the surroundings. So the temperature of the surroundings goes down.

    Examples of exothermic reactions are combustion 燃烧 (burning a fuel) and neutralisation 中和 (an acid reacting with an alkali). An example of an endothermic reaction is the thermal decomposition 分解 of a compound (breaking it down using heat).

    Two thermometers: in an exothermic reaction the reading rises, in an endothermic reaction it falls
    An exothermic reaction warms the surroundings; an endothermic reaction cools them
    Explore

    Exothermic & endothermic

    ΔH = products − reactants

    Exothermic drops to lower-energy products (releases heat); endothermic climbs to higher.

    Vocabulary Train
    English Chinese Pinyin
    exothermic reaction 放热反应 fàng rè fǎn yìng
    thermal energy 热能 rè néng
    surroundings 环境 huán jìng
    endothermic reaction 吸热反应 xī rè fǎn yìng
    combustion 燃烧 rán shāo
    neutralisation 中和 zhōng hé
    decomposition 分解 fēn jiě
    5.1

    Enthalpy change, ΔH

    The amount of thermal energy transferred in a reaction is called the enthalpy change 焓变. It is written as $\Delta H$ and has these signs:

    • $\Delta H$ is negative for an exothermic reaction, because energy leaves the chemicals.
    • $\Delta H$ is positive for an endothermic reaction, because energy is taken in.
    A Bunsen flame supplies energy: enthalpy change ΔH is the heat transferred at constant pressure
    A Bunsen flame supplies energy: enthalpy change ΔH is the heat transferred at constant pressure
    Vocabulary Train
    English Chinese Pinyin
    enthalpy change 焓变 hán biàn
    5.1

    Activation energy

    Particles do not react every time they meet. The activation energy 活化能 ($E_a$) is the smallest amount of energy that colliding 碰撞 particles 粒子 must have before they can react. It is like a hill the particles must get over before the reaction can happen.

    Explore

    Activation energy

    Ea = the energy barrier

    Every reaction must climb the activation-energy barrier before products can form.

    Vocabulary Train
    English Chinese Pinyin
    activation energy 活化能 huó huà néng
    colliding 碰撞 pèng zhuàng
    particles 粒子 lì zi
    5.1

    Reaction pathway diagrams

    A reaction pathway diagram 反应进程图 shows how the energy changes as a reaction happens. Energy is on the vertical axis, and the progress of the reaction is on the horizontal axis.

    • The line starts at the energy level of the reactants 反应物.
    • It rises over a 'hill' — the height of this hill is the activation energy $E_a$.
    • It then falls or rises to the energy level of the products 生成物.
    • The gap between the reactant level and the product level is the enthalpy change $\Delta H$.

    For an exothermic reaction, the products are lower than the reactants, so energy is given out and $\Delta H$ is negative.

    For an endothermic reaction, the products are higher than the reactants, so energy is taken in and $\Delta H$ is positive.

    Two reaction pathway diagrams: an exothermic one with products below the reactants and an endothermic one with products above
    Exothermic reactions end lower than they start ($\Delta H<0$); endothermic reactions end higher ($\Delta H>0$)
    Explore

    Reaction pathway diagrams

    Drag ΔH and the activation energy. Exothermic releases energy; endothermic takes it in; the hump is the energy barrier.

    Vocabulary Train
    English Chinese Pinyin
    reaction pathway diagram 反应进程图 fǎn yìng jìn chéng tú
    reactants 反应物 fǎn yìng wù
    products 生成物 shēng chéng wù
    5.1

    Bonds and energy

    A Bunsen burner with a blue flame
    Breaking and making bonds transfers energy — the flame supplies it here.

    A reaction involves breaking the bonds in the reactants and making new bonds in the products.

    • Bond breaking 断键 takes in energy, so it is an endothermic step.
    • Bond making 成键 gives out energy, so it is an exothermic step.

    The bond energy 键能 is the energy needed to break one mole of a particular bond. You can use bond energies to find the enthalpy change:

    $$\Delta H = (\text{energy to break all bonds}) - (\text{energy released making all bonds})$$

    If more energy is given out making bonds than is taken in breaking bonds, the reaction is exothermic ($\Delta H$ negative). If less energy is given out, it is endothermic ($\Delta H$ positive).

    Worked example

    For the reaction $\text{H}_2 + \text{Cl}_2 \rightarrow 2\text{HCl}$, use these bond energies (in kJ/mol): H–H $= 436$, Cl–Cl $= 242$, H–Cl $= 431$.

    Bonds broken: one H–H and one Cl–Cl $= 436 + 242 = 678$.

    Bonds made: two H–Cl $= 2 \times 431 = 862$.

    $$\Delta H = 678 - 862 = -184 \text{ kJ/mol}$$

    The answer is negative, so this reaction is exothermic.

    An energy level diagram for hydrogen plus chlorine forming hydrogen chloride: a rise to break bonds, then a larger fall to make bonds, ending below the start
    Breaking bonds takes energy in ($+678$); making bonds gives more out ($-862$); so $\Delta H = -184$ kJ/mol
    Vocabulary Train
    English Chinese Pinyin
    bond breaking 断键 duàn jiàn
    bond making 成键 chéng jiàn
    bond energy 键能 jiàn néng
    5.1

    Exam tips

    • Exothermic gives out heat, so the surroundings warm up and $\Delta H$ is negative; endothermic takes in heat, so the surroundings cool and $\Delta H$ is positive.
    • Bond breaking takes energy in (endothermic); bond making gives energy out (exothermic). Use $\Delta H = (\text{energy to break bonds}) - (\text{energy released making bonds})$.
    • If more energy is released making bonds than is used breaking them, the reaction is exothermic. Always check the sign of your final answer.
    • On a reaction pathway diagram, an exothermic reaction ends lower than it starts; an endothermic one ends higher. The height of the hill is the activation energy.
  • 6 Chemical reactions
    6.1

    Physical and chemical changes

    Syllabus
    Core Supplement
    1 Identify physical and chemical changes, and describe the differences between them

    Source: Cambridge International syllabus

    Rust on an iron surface
    Iron rusting is a chemical change — it forms a new substance.

    A physical change 物理变化 does not make a new substance. The substance only changes its state or shape, and the change can usually be reversed. Melting ice and dissolving sugar are physical changes.

    A chemical change 化学变化 (a chemical reaction) makes one or more new substances and is usually hard to reverse. Signs of a chemical change include a colour change, a gas being given off, an energy change, or a precipitate 沉淀 (a solid) forming.

    Physical change Chemical change
    no new substance made new substance(s) made
    easy to reverse usually hard to reverse
    e.g. melting, boiling, dissolving e.g. burning, rusting
    Explore

    Physical change vs chemical change

    Step through the difference. A physical change makes no new substance and is usually easy to reverse; a chemical change makes a new substance and is hard to undo.

    Vocabulary Train
    English Chinese Pinyin
    physical change 物理变化 wù lǐ biàn huà
    chemical change 化学变化 huà xué biàn huà
    precipitate 沉淀 chén diàn
    6.2

    Rate of reaction

    Syllabus
    Core Supplement
    5 Describe collision theory in terms of: (a) number of particles per unit volume (b) frequency of collisions between particles (c) kinetic energy of particles (d) activation energy, $E_a$
    1 Describe the effect on the rate of reaction of: (a) changing the concentration of solutions (b) changing the pressure of gases (c) changing the surface area of solids (d) changing the temperature (e) adding or removing a catalyst, including enzymes 6 Describe and explain the effect on the rate of reaction of: (a) changing the concentration of solutions (b) changing the pressure of gases (c) changing the surface area of solids (d) changing the temperature (e) adding or removing a catalyst, including enzymes using collision theory
    2 State that a catalyst increases the rate of a reaction and is unchanged at the end of a reaction 7 State that a catalyst decreases the activation energy, $E_a$, of a reaction
    3 Describe practical methods for investigating the rate of a reaction including change in mass of a reactant or a product and the formation of a gas 8 Evaluate practical methods for investigating the rate of a reaction including change in mass of a reactant or a product and the formation of a gas
    4 Interpret data, including graphs, from rate of reaction experiments

    Source: Cambridge International syllabus

    Collision theory: energy and orientation

    The rate of reaction 反应速率 tells you how fast the reactants 反应物 change into products 生成物.

    Collision theory

    Collision theory 碰撞理论 explains what controls the rate. For a reaction to happen, the particles 粒子 must collide 碰撞, and they must collide with enough energy. The least energy they need is the activation energy 活化能 ($E_a$). A faster rate happens when the particles have successful collisions more often.

    What changes the rate

    Change Effect Reason (collision theory)
    increase concentration 浓度 of a solution faster more particles in the same volume, so collisions happen more often
    increase pressure 压强 of gases faster particles are pushed closer, so collisions happen more often
    increase surface area 表面积 of a solid faster more particles are exposed, so collisions happen more often
    increase temperature faster particles gain kinetic energy 动能 and move faster, so collisions are more frequent and more of them have enough energy
    add a catalyst 催化剂 faster the catalyst lowers the activation energy, so more collisions are successful
    Two boxes of particles: the higher-concentration box holds more particles, so collisions happen more often
    More particles in the same volume collide more often, so the rate is faster
    A big lump touched by acid only on its outside, beside the same solid as a powder that acid can touch all over
    Breaking a solid into a powder exposes much more surface, so the rate is faster

    Catalysts

    A catalyst speeds up a reaction but is not used up — it is unchanged at the end. It works by lowering the activation energy. Enzymes are biological catalysts (catalysts that work in living things).

    A reaction pathway with a high hill without a catalyst and a lower hill with a catalyst, both ending at the same products
    A catalyst gives a lower activation energy so more collisions succeed; $\Delta H$ is unchanged

    Measuring the rate

    You can follow a reaction over time in these ways:

    • Change in mass: stand the flask on a balance. If a gas escapes, the mass falls. Record the mass at regular times.
    • Volume of gas: collect the gas in a gas syringe 注射器 and read its volume at regular times.
    • Formation of a precipitate: in a reaction that turns cloudy, time how long it takes for a mark under the flask to disappear.
    A conical flask of reaction mixture connected by a delivery tube to a gas syringe that fills with gas
    A gas syringe collects the gas given off; read its volume at regular times to follow the rate

    On a graph of product against time, the line is steepest at the start (fastest rate), becomes less steep as reactants are used up, and goes flat when the reaction has finished.

    A graph of gas volume against time: steep at first then levelling off, with a faster and a slower curve reaching the same final amount
    The rate is fastest at the start (steepest) and the line levels off when the reaction finishes
    Explore

    Rate from a gas-volume graph

    The gradient of the volume–time curve is the rate; it is steepest at the start and flattens as reactants run out.

    Explore

    Rate of reaction

    conc = c₀·b

    Concentration falls over time — fast at first, then slower.

    Explore

    Collision theory in action

    Watch the particles collide. Heat speeds them up so they collide more often and harder; more particles or a catalyst give more successful collisions — the rate climbs.

    Vocabulary Train
    English Chinese Pinyin
    rate of reaction 反应速率 fǎn yìng sù lǜ
    reactants 反应物 fǎn yìng wù
    products 生成物 shēng chéng wù
    collision theory 碰撞理论 pèng zhuàng lǐ lùn
    particles 粒子 lì zi
    collide 碰撞 pèng zhuàng
    activation energy 活化能 huó huà néng
    concentration 浓度 nóng dù
    pressure 压强 yā qiáng
    surface area 表面积 biǎo miàn jī
    kinetic energy 动能 dòng néng
    catalyst 催化剂 cuī huà jì
    enzymes méi
    syringe 注射器 zhù shè qì
    6.3

    Reversible reactions and equilibrium

    Syllabus
    Core Supplement
    1 State that some chemical reactions are reversible as shown by the symbol $\rightleftharpoons$ 3 State that a reversible reaction in a closed system is at equilibrium when: (a) the rate of the forward reaction is equal to the rate of the reverse reaction (b) the concentrations of reactants and products are no longer changing
    2 Describe how changing the conditions can change the direction of a reversible reaction for: (a) the effect of heat on hydrated compounds (b) the addition of water to anhydrous compounds limited to copper(II) sulfate and cobalt(II) chloride 4 Predict and explain, for a reversible reaction, how the position of equilibrium is affected by: (a) changing temperature (b) changing pressure (c) changing concentration (d) using a catalyst using information provided
    5 State the symbol equation for the production of ammonia in the Haber process, $\text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)}$
    6 State the sources of the hydrogen (methane) and nitrogen (air) in the Haber process
    7 State the typical conditions in the Haber process as $450\text{ }^{\circ}\text{C}$, $20\,000\text{ kPa}/200\text{ atm}$ and an iron catalyst
    8 State the symbol equation for the conversion of sulfur dioxide to sulfur trioxide in the Contact process, $2\text{SO}_2\text{(g)} + \text{O}_2\text{(g)} \rightleftharpoons 2\text{SO}_3\text{(g)}$
    9 State the sources of the sulfur dioxide (burning sulfur or roasting sulfide ores) and oxygen (air) in the Contact process
    10 State the typical conditions for the conversion of sulfur dioxide to sulfur trioxide in the Contact process as $450\text{ }^{\circ}\text{C}$, $200\text{ kPa}/2\text{ atm}$ and a vanadium(V) oxide catalyst
    11 Explain, in terms of rate of reaction and position of equilibrium, why the typical conditions stated are used in the Haber process and in the Contact process, including safety considerations and economics

    Source: Cambridge International syllabus

    Le Chatelier's principle
    Dynamic equilibrium: the rates converge

    Some reactions are reversible 可逆反应: the products can react to form the reactants again. We show this with the symbol $\rightleftharpoons$.

    Blue hydrated copper sulfate loses water on heating to white anhydrous; adding water turns it blue again
    Heating blue copper sulfate drives off water; adding water turns it blue again

    Changing the direction

    A clear example uses hydrated 水合 and anhydrous 无水 compounds:

    • Blue hydrated copper(II) sulfate, when heated, loses its water to become white anhydrous copper(II) sulfate. Adding water turns it blue again.
    • Pink hydrated cobalt(II) chloride loses water when heated to become blue anhydrous cobalt(II) chloride. Adding water turns it pink again.

    Adding water to the anhydrous solid (and seeing the colour return) is used as a test for water.

    Equilibrium

    In a closed system 密闭系统 (where nothing enters or leaves), a reversible reaction reaches equilibrium 平衡 when:

    • the rate of the forward reaction 正反应 equals the rate of the reverse reaction 逆反应, and
    • the concentrations of the reactants and products are no longer changing.

    Changing the position of equilibrium

    The position of equilibrium 平衡位置 tells you whether there are more reactants or more products. You can move it:

    • Temperature: heating moves the equilibrium in the direction that takes in heat (the endothermic 吸热反应 direction); cooling moves it in the direction that gives out heat (the exothermic 放热反应 direction).
    • Pressure (gases): more pressure moves the equilibrium to the side with fewer gas molecules.
    • Concentration: adding more of a substance moves the equilibrium to the other side, to use it up.
    • A catalyst does not move the position of equilibrium. It only helps the reaction reach equilibrium faster.

    The Haber process

    The Haber process 哈伯法 makes ammonia:

    $$\text{N}_2(g) + 3\text{H}_2(g) \rightleftharpoons 2\text{NH}_3(g)$$
    • The hydrogen 氢气 comes from methane 甲烷 (natural gas); the nitrogen 氮气 comes from the air.
    • Typical conditions: a temperature of $450\,{}^{\circ}\text{C}$, a pressure of about $200$ atm ($20\,000$ kPa), and an iron catalyst.

    The Contact process

    The Contact process 接触法 turns sulfur dioxide into sulfur trioxide:

    $$2\text{SO}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{SO}_3(g)$$
    • The sulfur dioxide comes from burning sulfur (or roasting sulfide ores); the oxygen 氧气 comes from the air.
    • Typical conditions: a temperature of $450\,{}^{\circ}\text{C}$, a pressure of about $2$ atm ($200$ kPa), and a vanadium(V) oxide 五氧化二钒 catalyst.

    Why these conditions are chosen

    The conditions are a compromise 折中:

    • A higher pressure would give more product, but very high pressure is dangerous and expensive, so a medium pressure is used.
    • A lower temperature would give more product (both forward reactions are exothermic), but the reaction would be too slow, so a fairly high temperature is used to keep a good rate.
    • The catalyst speeds up the reaction without changing the position of equilibrium, which lowers cost.
    Explore

    Shifting an equilibrium

    Change temperature, pressure or concentration and watch a reversible reaction shift to a new balance.

    Vocabulary Train
    English Chinese Pinyin
    reversible reaction 可逆反应 kě nì fǎn yìng
    hydrated 水合 shuǐ hé
    anhydrous 无水 wú shuǐ
    closed system 密闭系统 mì bì xì tǒng
    equilibrium 平衡 píng héng
    forward reaction 正反应 zhèng fǎn yìng
    reverse reaction 逆反应 nì fǎn yìng
    position of equilibrium 平衡位置 píng héng wèi zhì
    endothermic 吸热反应 xī rè fǎn yìng
    exothermic 放热反应 fàng rè fǎn yìng
    Haber process 哈伯法 hā bó fǎ
    hydrogen 氢气 qīng qì
    methane 甲烷 jiǎ wán
    nitrogen 氮气 dàn qì
    iron tiě
    Contact process 接触法 jiē chù fǎ
    sulfur liú
    oxygen 氧气 yǎng qì
    vanadium(V) oxide 五氧化二钒 wǔ yǎng huà èr fán
    compromise 折中 zhé zhōng
    6.4

    Redox

    Syllabus
    Core Supplement
    1 Use a Roman numeral to indicate the oxidation number of an element in a compound
    2 Define redox reactions as involving simultaneous oxidation and reduction
    3 Define oxidation as gain of oxygen and reduction as loss of oxygen 6 Define oxidation in terms of: (a) loss of electrons (b) an increase in oxidation number
    7 Define reduction in terms of: (a) gain of electrons (b) a decrease in oxidation number
    4 Identify redox reactions as reactions involving gain and loss of oxygen 8 Identify redox reactions as reactions involving gain and loss of electrons
    5 Identify oxidation and reduction in redox reactions 9 Identify redox reactions by changes in oxidation number using: (a) the oxidation number of elements in their uncombined state is zero (b) the oxidation number of a monatomic ion is the same as the charge on the ion (c) the sum of the oxidation numbers in a compound is zero (d) the sum of the oxidation numbers in an ion is equal to the charge on the ion
    10 Identify redox reactions by the colour changes involved when using acidified aqueous potassium manganate(VII) or aqueous potassium iodide
    11 Define an oxidising agent as a substance that oxidises another substance and is itself reduced
    12 Define a reducing agent as a substance that reduces another substance and is itself oxidised
    13 Identify oxidising agents and reducing agents in redox reactions

    Source: Cambridge International syllabus

    Oxidation 氧化 and reduction 还原 always happen at the same time, in what is called a redox reaction 氧化还原反应. ('Redox' is short for reduction–oxidation.)

    There are three ways to describe oxidation and reduction:

    • Oxygen: oxidation is the gain of oxygen; reduction is the loss of oxygen.
    • Electrons 电子: oxidation is the loss of electrons; reduction is the gain of electrons.
    • Oxidation number 氧化数: in oxidation the oxidation number goes up; in reduction it goes down.

    A useful memory aid is OIL RIG: Oxidation Is Loss, Reduction Is Gain — of electrons.

    One substance passing electrons to another, the first oxidised and the second reduced
    Electrons pass from the substance that is oxidised (loses them) to the one that is reduced (gains them) — the two always happen together

    Oxidation number rules

    The oxidation number is shown by a Roman numeral, as in iron(II) and iron(III). The rules are:

    • An element that is not combined has an oxidation number of $0$.
    • A single-atom ion has an oxidation number equal to its charge (so $\text{Na}^{+}$ is $+1$).
    • The oxidation numbers in a compound add up to $0$.
    • The oxidation numbers in an ion add up to the charge on the ion.

    Worked example. Find the oxidation number of manganese in the manganate(VII) ion, $\text{MnO}_4^{-}$. Each oxygen is $-2$, and there are four of them, giving $4 \times (-2) = -8$. The oxidation numbers in an ion must add up to the charge on the ion, which here is $-1$. So if manganese is $x$, then $x + (-8) = -1$, giving $x = +7$ - exactly what the (VII) in the name tells you. Set the total to the ion's charge, not to zero: zero is only for a neutral compound.

    Oxidising and reducing agents

    • An oxidising agent 氧化剂 oxidises another substance, and is itself reduced.
    • A reducing agent 还原剂 reduces another substance, and is itself oxidised.

    Some redox reactions show clear colour changes:

    • Acidified potassium manganate(VII) 高锰酸钾 is purple. When it acts as an oxidising agent it is reduced, and the purple colour fades to colourless.
    • Potassium iodide 碘化钾 is colourless. When it is oxidised, red-brown iodine is formed.
    A rack of test tubes of potassium manganate(VII), going from deep purple on the right to colourless on the left as it gets more dilute
    Potassium manganate(VII) is deep purple; as it is reduced (or diluted) the purple fades to colourless
    Explore

    Oxidation and reduction happen together

    Step through a redox reaction. One substance loses electrons while another gains them — you can never have one without the other.

    Vocabulary Train
    English Chinese Pinyin
    oxidation 氧化 yǎng huà
    reduction 还原 huán yuán
    redox reaction 氧化还原反应 yǎng huà huán yuán fǎn yìng
    electrons 电子 diàn zi
    oxidation number 氧化数 yǎng huà shù
    oxidising agent 氧化剂 yǎng huà jì
    reducing agent 还原剂 huán yuán jì
    potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ
    potassium iodide 碘化钾 diǎn huà jiǎ
    iodine diǎn
    6.4

    Exam tips

    • Explain a faster rate with collision theory: successful collisions happen more often. Concentration, pressure and surface area all raise how often particles collide; a higher temperature does that and gives more particles enough energy.
    • A catalyst lowers the activation energy and speeds the reaction up, but is not used up and does not change $\Delta H$ or the position of equilibrium.
    • At equilibrium the forward and reverse rates are equal and the concentrations stop changing — it does not mean the amounts of reactant and product are equal.
    • Use Le Chatelier's principle: raising temperature favours the endothermic direction; raising pressure favours the side with fewer gas molecules; adding a substance shifts the equilibrium away from it.
    • Redox — OIL RIG: Oxidation Is Loss, Reduction Is Gain of electrons. They always happen together, and an oxidising agent is itself reduced.
  • 7 Acids, bases and salts
    7.1

    Acids

    Syllabus
    Core Supplement
    1 Describe the characteristic properties of acids in terms of their reactions with: (a) metals (b) bases (c) carbonates
    2 Describe acids in terms of their effect on: (a) litmus (b) thymolphthalein (c) methyl orange
    3 State that bases are oxides or hydroxides of metals and that alkalis are soluble bases
    4 Describe the characteristic properties of bases in terms of their reactions with: (a) acids (b) ammonium salts
    5 Describe alkalis in terms of their effect on: (a) litmus (b) thymolphthalein (c) methyl orange
    6 State that aqueous solutions of acids contain $\text{H}^+$ ions and aqueous solutions of alkalis contain $\text{OH}^-$ ions 9 Define acids as proton donors and bases as proton acceptors
    10 Define a strong acid as an acid that is completely dissociated in aqueous solution and a weak acid as an acid that is partially dissociated in aqueous solution
    11 State that hydrochloric acid is a strong acid, as shown by the symbol equation, $\text{HCl}(\text{aq}) \rightarrow \text{H}^+(\text{aq}) + \text{Cl}^-(\text{aq})$
    12 State that ethanoic acid is a weak acid, as shown by the symbol equation, $\text{CH}_3\text{COOH}(\text{aq}) \rightleftharpoons \text{H}^+(\text{aq}) + \text{CH}_3\text{COO}^-(\text{aq})$
    7 Describe how to compare hydrogen ion concentration, neutrality, relative acidity and relative alkalinity in terms of colour and pH using universal indicator paper
    8 Describe the neutralisation reaction between an acid and an alkali to produce water, $\text{H}^+(\text{aq}) + \text{OH}^-(\text{aq}) \rightarrow \text{H}_2\text{O}(l)$

    Source: Cambridge International syllabus

    An acid is a substance that forms hydrogen ions ($\text{H}^{+}$) when dissolved in water. Acids have three typical reactions:

    An acid reacts with a metal, a base and a carbonate to give different products
    Acids react with metals, bases and carbonates to give different products
    • with metals 金属: acid + metal → a salt + hydrogen 氢气
    • with bases: acid + base → a salt + water (this is neutralisation 中和)
    • with carbonates 碳酸盐: acid + carbonate → a salt + water + carbon dioxide 二氧化碳

    Describing what you see

    Naming the products is only half of what the exam wants. "State the observations" asks what you would see with your eyes, and it carries its own marks - so learn the words:

    You see Say
    bubbles of gas coming off effervescence 泡腾 (also accepted: fizzing, bubbling)
    the solid getting smaller and vanishing the solid dissolves / disappears
    the colour of the solution changing name the colour, e.g. turns blue (copper salts)
    bubbling that stops no more effervescence - the acid is used up

    So for magnesium added to hydrochloric acid, a full answer is: effervescence, and the solid dissolves (and the tube gets warm). For copper(II) oxide added to warm sulfuric acid: the black solid dissolves and the solution turns blue.

    Two rules save most of the lost marks. Never write "hydrogen is given off" as an observation - you cannot see hydrogen, you can only see the bubbles, so write effervescence. And do not write a name you cannot see: "a salt forms" is a conclusion, not an observation.

    Indicators

    An indicator 指示剂 is a dye that changes colour to show whether a solution is acidic or alkaline.

    Indicator In acid In alkali
    litmus 石蕊 red blue
    thymolphthalein 百里酚酞 colourless blue
    methyl orange 甲基橙 red yellow

    Aqueous solutions of acids contain hydrogen ions 离子 ($\text{H}^{+}$). Aqueous solutions of alkalis contain hydroxide ions ($\text{OH}^{-}$).

    Blue litmus paper strips and a booklet of red litmus paper on a white background
    Litmus paper: blue litmus turns red in an acid, and red litmus turns blue in an alkali
    Vocabulary Train
    English Chinese Pinyin
    acid suān
    metals 金属 jīn shǔ
    salt yán
    hydrogen 氢气 qīng qì
    base jiǎn
    neutralisation 中和 zhōng hé
    carbonates 碳酸盐 tàn suān yán
    carbon dioxide 二氧化碳 èr yǎng huà tàn
    indicator 指示剂 zhǐ shì jì
    litmus 石蕊 shí ruǐ
    thymolphthalein 百里酚酞 bǎi lǐ fēn tài
    methyl orange 甲基橙 jiǎ jī chéng
    ions 离子 lí zi
    effervescence 泡腾 pào téng
    Exercise sheet
    7.1

    Bases and alkalis

    Bases are oxides 氧化物 or hydroxides 氢氧化物 of metals. An alkali 可溶性碱 is a base that dissolves in water (a soluble base).

    Bases have two typical reactions:

    • with acids: base + acid → a salt + water (neutralisation again)
    • with ammonium salts 铵盐: this releases ammonia gas.
    pH strips: alkalis turn universal indicator purple or blue (pH > 7)
    pH strips: alkalis turn universal indicator purple or blue (pH > 7)
    Explore

    Watch the pH during neutralisation

    Adding alkali to acid raises the pH. Near the end point the pH leaps up sharply — that steep jump is where the acid has just been neutralised.

    Vocabulary Train
    English Chinese Pinyin
    oxides 氧化物 yǎng huà wù
    hydroxides 氢氧化物 qīng yǎng huà wù
    alkali 可溶性碱 kě róng xìng jiǎn
    ammonium salts 铵盐 ǎn yán
    7.1

    Strong and weak acids

    An acid is a proton 质子 donor — it gives away $\text{H}^{+}$ ions (a hydrogen ion is just a proton). A base is a proton acceptor.

    How strong an acid is depends on how much of it splits into ions in water:

    • A strong acid 强酸 is completely dissociated 电离 (fully split into ions) in water. Hydrochloric acid 盐酸 is strong:
    $$\text{HCl}(aq) \rightarrow \text{H}^{+}(aq) + \text{Cl}^{-}(aq)$$
    • A weak acid 弱酸 is only partly dissociated. Ethanoic acid 乙酸 is weak, so the equation uses the reversible arrow:
    $$\text{CH}_3\text{COOH}(aq) \rightleftharpoons \text{H}^{+}(aq) + \text{CH}_3\text{COO}^{-}(aq)$$

    Note: 'strong' and 'weak' are about dissociation, not about being dilute or concentrated.

    Two beakers: a strong acid full of separate positive and negative ions, and a weak acid that is mostly intact molecules with only a few ions
    A strong acid is fully split into ions; a weak acid stays mostly as molecules (only partly dissociated)
    Vocabulary Train
    English Chinese Pinyin
    proton 质子 zhì zi
    strong acid 强酸 qiáng suān
    dissociated 电离 diàn lí
    hydrochloric acid 盐酸 yán suān
    weak acid 弱酸 ruò suān
    ethanoic acid 乙酸 yǐ suān
    7.1

    The pH scale

    The pH scale runs from 0 to 14 and tells you how acidic or alkaline a solution is. A higher hydrogen ion concentration means a lower pH.

    You can find pH using universal indicator 通用指示剂, which turns different colours:

    pH Type Colour of universal indicator
    below 7 acidic 酸性 red / orange / yellow
    exactly 7 neutral 中性 green
    above 7 alkaline 碱性 blue / purple
    The pH scale from 0 to 14 coloured like universal indicator: red at the acidic end, green at neutral, purple at the alkaline end
    Universal indicator turns red in a strong acid, green at neutral (pH 7), and purple in a strong alkali

    When an acid and an alkali react, the $\text{H}^{+}$ and $\text{OH}^{-}$ ions join to make water:

    $$\text{H}^{+}(aq) + \text{OH}^{-}(aq) \rightarrow \text{H}_2\text{O}(l)$$
    Explore

    The pH scale

    Slide the pH or tap a substance — lemon, water, soap, bleach. The indicator goes red→green→purple, and each step down in pH is ten times more H⁺ ions.

    Explore

    A titration curve

    Add alkali to acid and watch the pH rise. The steep jump is where the acid is just neutralised.

    Vocabulary Train
    English Chinese Pinyin
    universal indicator 通用指示剂 tōng yòng zhǐ shì jì
    acidic 酸性 suān xìng
    neutral 中性 zhōng xìng
    alkaline 碱性 jiǎn xìng
    7.2

    Oxides

    Syllabus
    Core Supplement
    1 Classify oxides as acidic, including $\text{SO}_2$ and $\text{CO}_2$, or basic, including $\text{CuO}$ and $\text{CaO}$, related to metallic and non-metallic character 2 Describe amphoteric oxides as oxides that react with acids and with bases to produce a salt and water
    3 Classify $\text{Al}_2\text{O}_3$ and $\text{ZnO}$ as amphoteric oxides

    Source: Cambridge International syllabus

    Oxides can be sorted by how they behave:

    • Acidic oxides are oxides of non-metals, such as $\text{SO}_2$ and $\text{CO}_2$.
    • Basic oxides are oxides of metals, such as $\text{CuO}$ and $\text{CaO}$.
    • Amphoteric 两性 oxides react with both acids and bases to make a salt and water. $\text{Al}_2\text{O}_3$ and $\text{ZnO}$ are amphoteric.

    So metal oxides tend to be basic and non-metal oxides tend to be acidic.

    Limestone is mostly calcium carbonate — a metal carbonate that acts as a base and neutralises acids
    Limestone is mostly calcium carbonate — a metal carbonate that acts as a base and neutralises acids
    Explore

    Oxide type lab

    Classify oxides by how they behave with acids and bases.

    Vocabulary Train
    English Chinese Pinyin
    amphoteric 两性 liǎng xìng
    7.3

    Preparing salts

    Syllabus
    Core Supplement
    1 Describe the preparation, separation and purification of soluble salts by reaction of an acid with: (a) an alkali by titration (b) excess metal (c) excess insoluble base (d) excess insoluble carbonate 4 Describe the preparation of insoluble salts by precipitation
    2 Describe the general solubility rules for salts: (a) sodium, potassium and ammonium salts are soluble (b) nitrates are soluble (c) chlorides are soluble, except lead and silver (d) sulfates are soluble, except barium, calcium and lead (e) carbonates are insoluble, except sodium, potassium and ammonium (f) hydroxides are insoluble, except sodium, potassium, ammonium and calcium (partially)
    3 Define a hydrated substance as a substance that is chemically combined with water and an anhydrous substance as a substance containing no water 5 Define the term water of crystallisation as the water molecules present in hydrated crystals, including $\text{CuSO}_4\bullet5\text{H}_2\text{O}$ and $\text{CoCl}_2\bullet6\text{H}_2\text{O}$

    Source: Cambridge International syllabus

    Whether a salt can be made by a certain method depends on whether it is soluble 可溶 (dissolves) or insoluble 不溶 (does not dissolve).

    Solubility rules

    Salt type Rule
    sodium, potassium, ammonium salts all soluble
    nitrates 硝酸盐 all soluble
    chlorides 氯化物 soluble, except lead and silver
    sulfates 硫酸盐 soluble, except barium, calcium and lead
    carbonates insoluble, except sodium, potassium and ammonium
    hydroxides insoluble, except sodium, potassium, ammonium and (partly) calcium

    Making a soluble salt

    You react an acid with one of these:

    • an alkali, using titration 滴定 (since both are solutions, you must measure the exact volumes);
    • an excess 过量 of a metal, an insoluble base, or an insoluble carbonate.

    When you use an excess of a solid, you then filter 过滤 to remove the leftover solid. Finally you evaporate 蒸发 some water and let the solution crystallise 结晶 to get the salt.

    A four-step flowchart: add excess solid to the acid, filter, evaporate some water, then leave to crystallise
    Making a soluble salt from an insoluble solid: react with excess, filter off the excess, evaporate, then crystallise
    Bright blue geometric crystals of copper(II) sulfate against a white background
    Letting the solution crystallise slowly gives well-shaped crystals — here, the blue crystals of copper(II) sulfate

    Worked example. Which method would you use to prepare (a) copper(II) sulfate and (b) barium sulfate? Check the solubility rules first. (a) Copper(II) sulfate is soluble (only barium, calcium and lead sulfates are not), so make it from an insoluble solid and an acid: add excess copper(II) oxide to warm dilute sulfuric acid, filter off the leftover solid, then evaporate some water and crystallise. (b) Barium sulfate is insoluble, so make it by precipitation: mix two solutions that each carry one of the needed ions, then filter, wash and dry the solid. The solubility of the salt you want is what decides the method - consult the rules before you choose.

    Making an insoluble salt

    An insoluble salt is made by precipitation 沉淀: mix two solutions that each contain one of the needed ions, and the insoluble salt forms as a solid. You then filter, wash and dry it.

    Two clear solutions poured together to give a beaker with a solid forming at the bottom
    Mixing two solutions that each carry one of the needed ions makes the insoluble salt appear as a solid precipitate, which you then filter off

    Water in salts

    • A hydrated 水合 substance is chemically joined with water.
    • An anhydrous 无水 substance contains no water.

    The water molecules inside hydrated crystals are called the water of crystallisation 结晶水. For example, $\text{CuSO}_4 \bullet 5\text{H}_2\text{O}$ has five water molecules for each formula unit.

    Explore

    Preparing a soluble salt

    Step through the method. React an acid with excess insoluble base, filter off what's left over, then evaporate and crystallise to get pure salt crystals.

    Vocabulary Train
    English Chinese Pinyin
    soluble 可溶 kě róng
    insoluble 不溶 bù róng
    nitrates 硝酸盐 xiāo suān yán
    chlorides 氯化物 lǜ huà wù
    sulfates 硫酸盐 liú suān yán
    titration 滴定 dī dìng
    excess 过量 guò liàng
    filter 过滤 guò lǜ
    evaporate 蒸发 zhēng fā
    crystallise 结晶 jié jīng
    precipitation 沉淀 chén diàn
    hydrated 水合 shuǐ hé
    anhydrous 无水 wú shuǐ
    water of crystallisation 结晶水 jié jīng shuǐ
    7.3

    Exam tips

    • Learn the three acid reactions: acid + metal → salt + hydrogen; acid + base → salt + water (neutralisation); acid + carbonate → salt + water + carbon dioxide.
    • Strong and weak describe how much the acid splits into ions (dissociation), not how concentrated it is. A strong acid is fully dissociated; a weak acid only partly.
    • A lower pH means a higher hydrogen-ion concentration. pH 7 is neutral, below 7 is acidic, above 7 is alkaline.
    • Choose the salt method by solubility: a soluble salt is made from an acid + excess solid (then filter, evaporate, crystallise), or by titration with an alkali; an insoluble salt is made by precipitation (mix two solutions, then filter).
    • Learn the solubility rules — all sodium, potassium, ammonium and nitrate salts are soluble.
  • 8 The Periodic Table
    8.1

    Arrangement of the elements

    Syllabus
    Core Supplement
    1 Describe the Periodic Table as an arrangement of elements in periods and groups and in order of increasing proton number/atomic number
    2 Describe the change from metallic to non‑metallic character across a period
    3 Describe the relationship between group number and the charge of the ions formed from elements in that group
    4 Explain similarities in the chemical properties of elements in the same group of the Periodic Table in terms of their electronic configuration
    5 Explain how the position of an element in the Periodic Table can be used to predict its properties 6 Identify trends in groups, given information about the elements

    Source: Cambridge International syllabus

    A periodic table display with element samples
    The periodic table arranges the elements in order of atomic number.

    The Periodic Table 周期表 arranges all the elements 元素 in order of increasing proton number 质子数 (the atomic number 原子序数). The horizontal rows are called periods 周期 and the vertical columns are called groups.

    A few key patterns:

    • Across a period, the elements change from metals 金属 on the left to non-metals 非金属 on the right.
    • The group number tells you the charge of the ions 离子 that the elements form. Group I forms $+1$ ions, Group II forms $+2$ ions, and Group VII forms $-1$ ions.
    • Elements in the same group have similar chemical properties. This is because they have the same number of outer-shell electrons 电子 (the same outer electronic configuration 电子排布).

    Because of these patterns, you can use an element's position to predict its properties.

    A schematic periodic table: groups as numbered columns and periods as rows, with metals shaded on the left and non-metals on the right, split by a staircase line
    Groups are the columns and periods are the rows; metals lie to the left of the staircase, non-metals to the right
    Explore

    Spot a trend across a period

    Reading across a period, properties change in a regular, repeating pattern. Switch the trend to watch atomic radius, ionisation energy or melting point change element by element.

    Vocabulary Train
    English Chinese Pinyin
    Periodic Table 周期表 zhōu qī biǎo
    elements 元素 yuán sù
    proton number 质子数 zhì zi shù
    atomic number 原子序数 yuán zi xù shù
    periods 周期 zhōu qī
    groups
    metals 金属 jīn shǔ
    non-metals 非金属 fēi jīn shǔ
    ions 离子 lí zi
    electrons 电子 diàn zi
    electronic configuration 电子排布 diàn zi pái bù
    8.2

    Group I — the alkali metals

    Syllabus
    Core Supplement
    1 Describe the Group I alkali metals, lithium, sodium and potassium, as relatively soft metals with general trends down the group, limited to: (a) decreasing melting point (b) increasing density (c) increasing reactivity
    2 Predict the properties of other elements in Group I, given information about the elements

    Source: Cambridge International syllabus

    Group I elements are the alkali metals 碱金属: lithium, sodium and potassium. They are soft 柔软 metals (you can cut them with a knife).

    A small piece of potassium burns with a bright burst of sparks and a lilac flame on the surface of a dish of water
    Potassium reacts violently with water, giving off hydrogen that burns with a lilac flame — reactivity increases down Group I
    Electron-shell diagrams of lithium, sodium and potassium, each with a single highlighted outer electron
    Every Group I atom has one electron in its outer shell, which is why they react in similar ways

    Going down the group, there are clear trends 趋势:

    Property Trend going down the group
    melting point 熔点 decreases
    density 密度 increases
    reactivity 活泼性 increases

    You can use these trends to predict the properties of other Group I elements. For example, rubidium (below potassium) would be even more reactive and have an even lower melting point.

    Reaction with water, and what you see

    This is the reaction the exam asks about most. Every Group I metal reacts with water to give an alkali (the metal hydroxide) plus hydrogen - which is exactly why they are called the alkali metals:

    $$2\text{Na} + 2\text{H}_2\text{O} \rightarrow 2\text{NaOH} + \text{H}_2$$

    "Describe what you see" is worth marks of its own, so learn the list for sodium on water:

    • it floats - the metal is less dense than water.
    • it melts into a ball - the reaction gives out heat, and the metal's melting point is low.
    • it moves about on the surface - the hydrogen jetting off pushes it around.
    • there is effervescence 泡腾 (fizzing) - the hydrogen gas escaping.
    • it gets smaller and disappears as it is used up.
    • the solution turns alkaline, so universal indicator goes purple (it is now $\text{NaOH}$).

    The trend shows up in how violent this is: lithium fizzes steadily but does not melt; sodium melts into a ball and darts around; potassium is fast enough to ignite its own hydrogen, burning with a lilac flame. Two answers to avoid: "hydrogen is given off" is not an observation (you cannot see it - say effervescence), and the metal melts because the reaction is exothermic, not because "water is hot".

    Explore

    Group I trend lab

    Follow Group I metals down the group and watch reactivity increase.

    Vocabulary Train
    English Chinese Pinyin
    alkali metals 碱金属 jiǎn jīn shǔ
    lithium
    sodium
    potassium jiǎ
    soft 柔软 róu ruǎn
    trends 趋势 qū shì
    melting point 熔点 róng diǎn
    density 密度 mì dù
    reactivity 活泼性 huó pō xìng
    effervescence 泡腾 pào téng
    8.3

    Group VII — the halogens

    Syllabus
    Core Supplement
    1 Describe the Group VII halogens, chlorine, bromine and iodine, as diatomic non-metals with general trends down the group, limited to: (a) increasing density (b) decreasing reactivity
    2 State the appearance of the halogens at r.t.p. as: (a) chlorine, a pale yellow-green gas (b) bromine, a red-brown liquid (c) iodine, a grey-black solid
    3 Describe and explain the displacement reactions of halogens with other halide ions
    4 Predict the properties of other elements in Group VII, given information about the elements

    Source: Cambridge International syllabus

    Group VII elements are the halogens 卤素: chlorine 氯气, bromine and iodine. They are diatomic 双原子 non-metals (each molecule is made of two atoms, such as $\text{Cl}_2$).

    Their appearance at room temperature and pressure:

    Halogen Appearance
    chlorine a pale yellow-green gas
    bromine a red-brown liquid
    iodine a grey-black solid

    Going down the group, the density increases but the reactivity decreases (the opposite trend to Group I).

    Group I with a downward reactivity arrow next to Group VII with an upward reactivity arrow
    Group I gets more reactive down the group, while Group VII gets less reactive down — opposite trends

    Displacement reactions

    A more reactive halogen pushes out (displaces) a less reactive halide 卤化物 ion from its solution. This is a displacement reaction 置换反应.

    For example, chlorine is more reactive than bromine, so chlorine displaces bromine from potassium bromide:

    $$\text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2$$
    Colourless potassium bromide solution turning orange when chlorine is added
    Chlorine is more reactive, so it displaces bromine from the solution; the released bromine turns the colourless solution orange

    Worked example. Aqueous chlorine is added to potassium iodide solution; then aqueous iodine is added to potassium bromide solution. What happens in each? Reactivity falls down Group VII: chlorine, then bromine, then iodine. (a) Chlorine is above iodine, so it is more reactive and displaces it: $\text{Cl}_2 + 2\text{KI} \rightarrow 2\text{KCl} + \text{I}_2$, and the solution turns red-brown as iodine is released. (b) Iodine is below bromine, so it is less reactive and cannot displace it - there is no reaction and no colour change. "No reaction" is a complete answer worth marks: check the order in the group before you write any equation.

    Explore

    Group VII trend lab

    Follow halogens down the group and watch reactivity decrease.

    Vocabulary Train
    English Chinese Pinyin
    halogens 卤素 lǔ sù
    chlorine 氯气 lǜ qì
    bromine xiù
    iodine diǎn
    diatomic 双原子 shuāng yuán zi
    halide 卤化物 lǔ huà wù
    displacement reaction 置换反应 zhì huàn fǎn yìng
    8.4

    Transition elements

    Syllabus
    Core Supplement
    1 Describe the transition elements as metals that: (a) have high densities (b) have high melting points (c) form coloured compounds (d) often act as catalysts as elements and in compounds 2 Describe transition elements as having ions with variable oxidation numbers, including iron(II) and iron(III)

    Source: Cambridge International syllabus

    The transition elements 过渡元素 are the block of metals in the middle of the Periodic Table. Compared with Group I metals, they:

    • have high densities;
    • have high melting points;
    • form coloured 有色 compounds 化合物;
    • often act as catalysts, both as elements and in compounds.

    They can also have variable 可变 oxidation numbers 氧化数. For example, iron forms both iron(II) and iron(III) compounds.

    Six beakers of brightly coloured solutions — red, orange, yellow, green, blue and purple
    Transition metals form coloured compounds: each of these solutions contains a different transition-metal ion
    Explore

    Transition element lab

    Match transition-metal properties to real examples.

    Vocabulary Train
    English Chinese Pinyin
    transition elements 过渡元素 guò dù yuán sù
    coloured 有色 yǒu sè
    compounds 化合物 huà hé wù
    variable 可变 kě biàn
    oxidation numbers 氧化数 yǎng huà shù
    iron tiě
    8.5

    Group VIII — the noble gases

    Syllabus
    Core Supplement
    1 Describe the Group VIII noble gases as unreactive, monatomic gases and explain this in terms of electronic configuration

    Source: Cambridge International syllabus

    The Group VIII noble gases 稀有气体 are unreactive 不活泼, monatomic 单原子 gases (they exist as single atoms, not as molecules).

    They are unreactive because they already have a full outer shell of electrons. This makes them stable, so they do not need to gain, lose or share electrons.

    Five discharge tubes labelled He, Ne, Ar, Kr and Xe, each glowing a different colour
    Passing electricity through each noble gas makes it glow a characteristic colour — this is how neon signs and other lights work
    Explore

    Noble gas lab

    Classify noble gas uses by the property that makes them useful.

    Vocabulary Train
    English Chinese Pinyin
    noble gases 稀有气体 xī yǒu qì tǐ
    unreactive 不活泼 bù huó pō
    monatomic 单原子 dān yuán zi
    8.5

    Exam tips

    • The Periodic Table is ordered by proton number. Elements in the same group (column) have the same number of outer electrons, so they react in similar ways; periods are the rows.
    • Group I (alkali metals) get more reactive going down; Group VII (halogens) get less reactive going down — opposite trends.
    • A more reactive halogen displaces a less reactive one from a solution of its salt — for example chlorine displaces bromine.
    • Noble gases are unreactive because they have a full outer shell. Transition elements are hard and dense, form coloured compounds, act as catalysts and have variable oxidation numbers.
  • 9 Metals
    9.1

    Properties of metals

    Syllabus
    Core Supplement
    1 Compare the general physical properties of metals and non-metals, including: (a) thermal conductivity (b) electrical conductivity (c) malleability and ductility (d) melting points and boiling points
    2 Describe the general chemical properties of metals, limited to their reactions with: (a) dilute acids (b) cold water and steam (c) oxygen

    Source: Cambridge International syllabus

    Physical properties

    Metals 金属 and non-metals 非金属 behave very differently:

    Property Metals Non-metals
    thermal conductivity 导热性 (conducting heat) good poor
    electrical conductivity 导电性 good poor (except graphite)
    malleability 展性 and ductility 延性 malleable and ductile brittle 易碎 (they snap)
    melting point 熔点 and boiling point 沸点 usually high usually low

    Chemical properties

    Metals react in three main ways:

    • with dilute acids → a salt + hydrogen 氢气
    • with cold water or steam 蒸汽 → a metal hydroxide (or oxide) + hydrogen
    • with oxygen 氧气 → a metal oxide 氧化物
    Native copper: metals are shiny, dense, malleable conductors of heat and electricity
    Native copper: metals are shiny, dense, malleable conductors of heat and electricity
    Explore

    Metallic bonding

    Positive ions sit in a sea of delocalised electrons — that is why metals conduct and bend. Push the layers and the bond holds.

    Explore

    Metal property lab

    Link metal properties to the particle model.

    Vocabulary Train
    English Chinese Pinyin
    metals 金属 jīn shǔ
    non-metals 非金属 fēi jīn shǔ
    thermal conductivity 导热性 dǎo rè xìng
    electrical conductivity 导电性 dǎo diàn xìng
    malleability 展性 zhǎn xìng
    ductility 延性 yán xìng
    brittle 易碎 yì suì
    melting point 熔点 róng diǎn
    boiling point 沸点 fèi diǎn
    acids suān
    salt yán
    hydrogen 氢气 qīng qì
    steam 蒸汽 zhēng qì
    oxygen 氧气 yǎng qì
    oxide 氧化物 yǎng huà wù
    9.2

    Uses of metals

    Syllabus
    Core Supplement
    1 Describe the uses of metals in terms of their physical properties, including: (a) aluminium in the manufacture of aircraft because of its low density (b) aluminium in the manufacture of overhead electrical cables because of its low density and good electrical conductivity (c) aluminium in food containers because of its resistance to corrosion (d) copper in electrical wiring because of its good electrical conductivity and ductility

    Source: Cambridge International syllabus

    A metal is chosen for a job because of its physical properties.

    • Aluminium is used to make aircraft because of its low density 密度 (it is light).
    • Aluminium is used for overhead electrical cables because of its low density and good electrical conductivity.
    • Aluminium is used for food containers because it resists corrosion 腐蚀.
    • Copper is used for electrical wiring because of its good electrical conductivity and its ductility (it can be drawn into wires).
    A large passenger jet on an airport runway with hills behind
    Aircraft bodies use a lot of aluminium: it is strong but has a low density, so the plane stays light
    Explore

    Metal use lab

    Choose the property that explains each metal use.

    Vocabulary Train
    English Chinese Pinyin
    aluminium
    density 密度 mì dù
    corrosion 腐蚀 fǔ shí
    copper tóng
    9.3

    Alloys

    Syllabus
    Core Supplement
    1 Describe an alloy as a mixture of a metal with other elements, including: (a) brass as a mixture of copper and zinc (b) stainless steel as a mixture of iron and other elements such as chromium, nickel and carbon
    2 State that alloys can be harder and stronger than the pure metals and are more useful 5 Explain in terms of structure how alloys can be harder and stronger than the pure metals because the different sized atoms in alloys mean the layers can no longer slide over each other
    3 Describe the uses of alloys in terms of their physical properties, including stainless steel in cutlery because of its hardness and resistance to rusting
    4 Identify representations of alloys from diagrams of structure

    Source: Cambridge International syllabus

    An alloy 合金 is a mixture 混合物 of a metal with one or more other elements.

    • Brass 黄铜 is a mixture of copper and zinc.
    • Stainless steel 不锈钢 is a mixture of iron with other elements such as chromium, nickel and carbon.

    Alloys are usually harder and stronger than the pure metals, which makes them more useful. For example, stainless steel is used for cutlery because it is hard and does not rust.

    Why alloys are harder. In a pure metal, the atoms 原子 are all the same size, so the layers can slide over each other easily. In an alloy, the different-sized atoms stop the layers from sliding, so the alloy is harder and stronger.

    A neat grid of same-size atoms whose layers can slide, beside an alloy where larger atoms distort the rows and block sliding
    In an alloy, different-sized atoms stop the layers sliding past each other, so the alloy is harder than the pure metal
    Explore

    Alloy property lab

    See why mixing atoms changes metal properties.

    Vocabulary Train
    English Chinese Pinyin
    alloy 合金 hé jīn
    mixture 混合物 hùn hé wù
    brass 黄铜 huáng tóng
    zinc xīn
    stainless steel 不锈钢 bù xiù gāng
    iron tiě
    chromium
    nickel niè
    carbon tàn
    atoms 原子 yuán zi
    layers céng
    9.4

    The reactivity series

    Syllabus
    Core Supplement
    1 State the order of the reactivity series as: potassium, sodium, calcium, magnesium, aluminium, carbon, zinc, iron, hydrogen, copper, silver, gold 4 Describe the relative reactivities of metals in terms of their tendency to form positive ions, by displacement reactions, if any, with the aqueous ions of magnesium, zinc, iron, copper and silver
    2 Describe the reactions, if any, of: (a) potassium, sodium and calcium with cold water (b) magnesium with steam (c) magnesium, zinc, iron, copper, silver and gold with dilute hydrochloric acid and explain these reactions in terms of the position of the metals in the reactivity series
    5 Explain the apparent unreactivity of aluminium in terms of its oxide layer
    3 Deduce an order of reactivity from a given set of experimental results

    Source: Cambridge International syllabus

    The reactivity series 金属活动性顺序 lists metals in order of how reactive they are. Carbon and hydrogen are included for comparison:

    potassium, sodium, calcium, magnesium, aluminium, carbon, zinc, iron, hydrogen, copper, silver, gold

    (most reactive at the top, least reactive at the bottom)

    The reactivity series from potassium down to gold, with carbon and hydrogen marked, and the extraction method shown on each side of carbon
    Metals above carbon are extracted by electrolysis; those below carbon can be extracted by heating with carbon

    The higher a metal is, the more easily it forms positive ions 离子. This explains its reactions:

    • potassium, sodium and calcium react with cold water.
    • magnesium reacts with steam (but only very slowly with cold water).
    • magnesium, zinc and iron react with dilute hydrochloric acid; copper, silver and gold do not.

    Displacement reactions

    A more reactive metal will displace a less reactive metal from a solution of its ions (a displacement reaction 置换反应). For example, zinc displaces copper from copper(II) sulfate solution, because zinc is more reactive than copper:

    $$\text{Zn} + \text{CuSO}_4 \rightarrow \text{ZnSO}_4 + \text{Cu}$$

    Be ready to say what you would see, because those are separate marks:

    • the blue colour of the solution fades - the blue $\text{Cu}^{2+}$ ions are being used up (zinc sulfate is colourless).
    • a pink-brown solid coats the zinc - that is the displaced copper.
    • the grey zinc dissolves and gets smaller.
    • the mixture warms up - displacement is exothermic.

    Metal-and-acid reactions have their own list: effervescence 泡腾 (the hydrogen escaping) and the solid dissolves. With copper(II) oxide or carbonate and acid, add that the solution turns blue. Never write "hydrogen is given off" as an observation - you cannot see the gas, only the bubbles, so write effervescence.

    Worked example. Zinc and aluminium are both found as oxides. Which can be extracted by heating with carbon, and why? Find each metal's place relative to carbon in the reactivity series. Zinc sits below carbon, so carbon is the more reactive of the two and can take the oxygen away from it: zinc oxide is reduced by heating with carbon. Aluminium sits above carbon, so carbon is not reactive enough to displace it, and aluminium must be extracted by electrolysis instead - which is why aluminium costs far more to extract. The line in the series that decides the method is carbon's, not the top of the list.

    The special case of aluminium

    Aluminium seems less reactive than its position suggests. This is because it is covered by a thin, strong oxide layer 氧化层 that stops other substances reaching the metal underneath.

    Explore

    Displacement and the reactivity series

    Step through a displacement. A more reactive metal pushes a less reactive one out of its compound — which is exactly what the reactivity series predicts.

    Vocabulary Train
    English Chinese Pinyin
    reactivity series 金属活动性顺序 jīn shǔ huó dòng xìng shùn xù
    potassium jiǎ
    sodium
    calcium gài
    magnesium měi
    ions 离子 lí zi
    displacement reaction 置换反应 zhì huàn fǎn yìng
    oxide layer 氧化层 yǎng huà céng
    effervescence 泡腾 pào téng
    9.5

    Corrosion of metals

    Syllabus
    Core Supplement
    1 State the conditions required for the rusting of iron and steel to form hydrated iron(III) oxide
    2 State some common barrier methods, including painting, greasing and coating with plastic 4 Describe the use of zinc in galvanising as an example of a barrier method and sacrificial protection
    3 Describe how barrier methods prevent rusting by excluding oxygen or water 5 Explain sacrificial protection in terms of the reactivity series and in terms of electron loss

    Source: Cambridge International syllabus

    A heavily corroded metal post
    Corrosion slowly eats away unprotected metal.

    Rusting 生锈 is the corrosion of iron and steel. Two things are needed for rusting: oxygen (from the air) and water. The rust 铁锈 formed is hydrated iron(III) oxide.

    A heavy iron chain on coastal rocks, deeply covered in orange-brown rust
    Sea water and air have badly rusted this iron chain — the rust is hydrated iron(III) oxide
    Three test tubes: an iron nail in water and air, a nail in boiled water sealed under oil, and a nail in dry air with a drying agent
    Rusting needs both water and oxygen — the nail only rusts in the tube that has both

    Stopping rust

    Barrier methods 隔离法 keep oxygen and water away from the iron:

    • painting, greasing (covering with oil), and coating with plastic.

    Galvanising 镀锌 means coating iron with a layer of zinc. This works in two ways:

    • it is a barrier (the zinc keeps out air and water);
    • it gives sacrificial protection 牺牲保护. Because zinc is more reactive than iron, the zinc loses electrons 电子 and corrodes instead of the iron — even if the surface is scratched.
    A block of zinc attached to an iron bar, with electrons flowing from the zinc into the iron
    The more reactive zinc corrodes and gives its electrons to the iron, so the iron is protected even where the surface is scratched
    Explore

    Why iron rusts — and how to stop it

    Step through rusting. Iron needs BOTH water and oxygen, and once it starts the rust flakes off to expose fresh metal — which is why we protect iron.

    Vocabulary Train
    English Chinese Pinyin
    rusting 生锈 shēng xiù
    rust 铁锈 tiě xiù
    barrier methods 隔离法 gé lí fǎ
    galvanising 镀锌 dù xīn
    sacrificial protection 牺牲保护 xī shēng bǎo hù
    electrons 电子 diàn zi
    9.6

    Extraction of metals

    Syllabus
    Core Supplement
    1 Describe the ease in obtaining metals from their ores, related to the position of the metal in the reactivity series
    2 Describe the extraction of iron from hematite in the blast furnace, limited to: (a) the burning of carbon (coke) to provide heat and produce carbon dioxide (b) the reduction of carbon dioxide to carbon monoxide (c) the reduction of iron(III) oxide by carbon monoxide (d) the thermal decomposition of calcium carbonate/limestone to produce calcium oxide (e) the formation of slag Symbol equations are not required 4 State the symbol equations for the extraction of iron from hematite (a) $\text{C} + \text{O}_2 \rightarrow \text{CO}_2$ (b) $\text{C} + \text{CO}_2 \rightarrow 2\text{CO}$ (c) $\text{Fe}_2\text{O}_3 + 3\text{CO} \rightarrow 2\text{Fe} + 3\text{CO}_2$ (d) $\text{CaCO}_3 \rightarrow \text{CaO} + \text{CO}_2$ (e) $\text{CaO} + \text{SiO}_2 \rightarrow \text{CaSiO}_3$
    3 State that the main ore of aluminium is bauxite and that aluminium is extracted by electrolysis 5 Describe the extraction of aluminium from purified bauxite/aluminium oxide, including: (a) the role of cryolite (b) why the carbon anodes need to be regularly replaced (c) the reactions at the electrodes, including ionic half-equations Details of the purification of bauxite are not required

    Source: Cambridge International syllabus

    How a metal is taken from its ore 矿石 depends on its place in the reactivity series. Metals below carbon can be extracted by heating with carbon (which removes the oxygen). Metals above carbon are too reactive for this and must be extracted by electrolysis 电解.

    Metals above carbon are extracted by electrolysis; those below carbon by heating with carbon
    Metals above carbon need electrolysis; those below are heated with carbon

    Iron from the blast furnace

    Iron is extracted from its ore hematite 赤铁矿 (iron(III) oxide) in a blast furnace 高炉:

    • Carbon (coke) burns in hot air to give carbon dioxide and lots of heat.
    • This carbon dioxide 二氧化碳 reacts with more carbon to form carbon monoxide 一氧化碳.
    • The carbon monoxide reduces the iron(III) oxide to iron (this is reduction 还原).
    • Limestone 石灰石 (calcium carbonate) breaks down in the heat to form calcium oxide 氧化钙.
    • The calcium oxide reacts with sandy impurities to form slag 炉渣, which is removed.
    A labelled blast furnace: the charge enters at the top, hot air is blasted in low down, and molten iron and slag are tapped from the bottom
    In the blast furnace, carbon monoxide reduces the iron ore, and limestone removes sandy impurities as slag

    Aluminium by electrolysis

    Aluminium is extracted from its ore bauxite 铝土矿 (purified to aluminium oxide) by electrolysis:

    • The aluminium oxide is dissolved in molten cryolite 冰晶石 to lower its melting point and save energy.
    • At the cathode 阴极, aluminium ions gain electrons to form aluminium metal.
    • At the anode 阳极, oxygen is formed. This oxygen reacts with the hot carbon anodes and burns them away, so they must be replaced regularly.
    Explore

    Extracting iron in the blast furnace

    Iron is below carbon in reactivity, so carbon can reduce its ore to the metal.

    Vocabulary Train
    English Chinese Pinyin
    ore 矿石 kuàng shí
    electrolysis 电解 diàn jiě
    hematite 赤铁矿 chì tiě kuàng
    blast furnace 高炉 gāo lú
    carbon dioxide 二氧化碳 èr yǎng huà tàn
    carbon monoxide 一氧化碳 yī yǎng huà tàn
    reduction 还原 huán yuán
    limestone 石灰石 shí huī shí
    calcium oxide 氧化钙 yǎng huà gài
    slag 炉渣 lú zhā
    bauxite 铝土矿 lǚ tǔ kuàng
    cryolite 冰晶石 bīng jīng shí
    cathode 阴极 yīn jí
    anode 阳极 yáng jí
    9.6

    Exam tips

    • Learn the reactivity series (potassium → gold). A more reactive metal displaces a less reactive one from a solution of its ions.
    • Metals above carbon are extracted by electrolysis; those below carbon (like iron) can be extracted by heating with carbon.
    • Rusting needs both water and oxygen. Barrier methods (paint, oil) keep them out; galvanising also gives sacrificial protection, because the more reactive zinc corrodes instead of the iron.
    • Alloys are harder than pure metals because the different-sized atoms stop the layers of ions sliding over each other.
  • 10 Chemistry of the environment
    10.1

    Water

    Syllabus
    Core Supplement
    1 Describe chemical tests for the presence of water using anhydrous cobalt(II) chloride and anhydrous copper(II) sulfate
    2 Describe how to test for the purity of water using melting point and boiling point
    3 Explain that distilled water is used in practical chemistry rather than tap water because it contains fewer chemical impurities
    4 State that water from natural sources may contain substances, including: (a) dissolved oxygen (b) metal compounds (c) plastics (d) sewage (e) harmful microbes (f) nitrates from fertilisers (g) phosphates from fertilisers and detergents
    5 State that some of these substances are beneficial, including: (a) dissolved oxygen for aquatic life (b) some metal compounds provide essential minerals for life
    6 State that some of these substances are potentially harmful, including: (a) some metal compounds are toxic (b) some plastics harm aquatic life (c) sewage contains harmful microbes which cause disease (d) nitrates and phosphates lead to deoxygenation of water and damage to aquatic life Details of the eutrophication process are not required
    7 Describe the treatment of the domestic water supply in terms of: (a) sedimentation and filtration to remove solids (b) use of carbon to remove tastes and odours (c) chlorination to kill microbes

    Source: Cambridge International syllabus

    Testing for water

    Two chemical tests show that water is present:

    • Anhydrous 无水 cobalt(II) chloride turns from blue to pink when water is added.
    • Anhydrous copper(II) sulfate turns from white to blue when water is added.

    These tests only show that water is there. To show that water is pure, you test its melting point 熔点 and boiling point 沸点: pure water melts at exactly $0\,{}^{\circ}\text{C}$ and boils at exactly $100\,{}^{\circ}\text{C}$. Any dissolved substance changes these values.

    Two colour-change tests show water is present: cobalt chloride blue to pink and copper sulfate white to blue; fixed melting and boiling points of 0 and 100 degrees show it is pure
    Colour-change tests show water is present; fixed melting and boiling points show it is pure

    This is why distilled water 蒸馏水 is used in chemistry instead of tap water — it has far fewer chemical impurities 杂质.

    What is in natural water

    Water from rivers, lakes and the sea is not pure. It may contain dissolved oxygen 氧气, metal compounds, plastics, sewage 污水, harmful microbes 微生物, and nitrates 硝酸盐 and phosphates 磷酸盐 (which come from fertilisers and detergents).

    Some of these are helpful:

    • dissolved oxygen lets aquatic life 水生生物 (fish and plants) breathe;
    • some metal compounds give essential minerals 矿物质.

    Others are harmful:

    • some metal compounds are toxic 有毒 (poisonous);
    • some plastics harm aquatic life;
    • sewage carries microbes that cause disease;
    • nitrates and phosphates cause deoxygenation 缺氧 (loss of oxygen) in the water, which harms aquatic life.

    Treating drinking water

    To make water safe to drink, the water supply is treated in steps:

    • sedimentation 沉降 and filtration 过滤 remove solid bits;
    • passing it through carbon removes bad tastes and smells;
    • chlorination 氯消毒 (adding chlorine) kills harmful microbes.
    A flowchart: sedimentation, then filtration, then passing through carbon, then chlorination, giving safe drinking water
    Water is made safe to drink in steps: settle out big bits, filter, remove tastes with carbon, then chlorinate
    Explore

    Water treatment lab

    Classify water processes by what they remove or change.

    Vocabulary Train
    English Chinese Pinyin
    anhydrous 无水 wú shuǐ
    melting point 熔点 róng diǎn
    boiling point 沸点 fèi diǎn
    distilled water 蒸馏水 zhēng liú shuǐ
    impurities 杂质 zá zhì
    oxygen 氧气 yǎng qì
    sewage 污水 wū shuǐ
    microbes 微生物 wēi shēng wù
    nitrates 硝酸盐 xiāo suān yán
    phosphates 磷酸盐 lín suān yán
    aquatic life 水生生物 shuǐ shēng shēng wù
    minerals 矿物质 kuàng wù zhì
    toxic 有毒 yǒu dú
    deoxygenation 缺氧 quē yǎng
    sedimentation 沉降 chén jiàng
    filtration 过滤 guò lǜ
    carbon tàn
    chlorination 氯消毒 lǜ xiāo dú
    10.2

    Fertilisers

    Syllabus
    Core Supplement
    1 State that ammonium salts and nitrates are used as fertilisers
    2 Describe the use of NPK fertilisers to provide the elements nitrogen, phosphorus and potassium for improved plant growth

    Source: Cambridge International syllabus

    Fertilisers 肥料 are added to soil to help plants grow. Ammonium salts and nitrates are common fertilisers.

    NPK fertilisers contain the three elements plants need most: nitrogen 氮气, phosphorus and potassium.

    Three cards for NPK: N nitrogen for leaf and stem growth, P phosphorus for strong roots, K potassium for flowers and fruit
    NPK fertilisers supply the three elements plants need most: nitrogen, phosphorus and potassium
    Explore

    Fertiliser route lab

    Follow nitrogen from raw materials to crop growth.

    Vocabulary Train
    English Chinese Pinyin
    fertilisers 肥料 féi liào
    nitrogen 氮气 dàn qì
    phosphorus lín
    potassium jiǎ
    10.3

    Air quality and climate

    Syllabus
    Core Supplement
    1 State the composition of clean, dry air as approximately 78% nitrogen, $\text{N}_2$, 21% oxygen, $\text{O}_2$ and the remainder as a mixture of noble gases and carbon dioxide, $\text{CO}_2$
    2 State the source of each of these air pollutants, limited to: (a) carbon dioxide from the complete combustion of carbon-containing fuels (b) carbon monoxide and particulates from the incomplete combustion of carbon-containing fuels (c) methane from the decomposition of vegetation and waste gases from digestion in animals (d) oxides of nitrogen from car engines (e) sulfur dioxide from the combustion of fossil fuels which contain sulfur compounds
    3 State the adverse effect of these air pollutants, limited to: (a) carbon dioxide: higher levels of carbon dioxide leading to increased global warming, which leads to climate change (b) carbon monoxide: toxic gas (c) particulates: increased risk of respiratory problems and cancer (d) methane: higher levels of methane leading to increased global warming, which leads to climate change (e) oxides of nitrogen: acid rain, photochemical smog and respiratory problems (f) sulfur dioxide: acid rain 7 Describe how the greenhouse gases carbon dioxide and methane cause global warming, limited to: (a) the absorption, reflection and emission of thermal energy (b) reducing thermal energy loss to space
    4 State and explain strategies to reduce the effects of these environmental issues, limited to: (a) climate change: planting trees, reduction in livestock farming, decreasing use of fossil fuels, increasing use of hydrogen and renewable energy, e.g. wind, solar (b) acid rain: use of catalytic converters in vehicles, reducing emissions of sulfur dioxide by using low-sulfur fuels and flue gas desulfurisation with calcium oxide 8 Explain how oxides of nitrogen form in car engines and describe their removal by catalytic converters, e.g. $2\text{CO} + 2\text{NO} \rightarrow 2\text{CO}_2 + \text{N}_2$
    5 Describe photosynthesis as the reaction between carbon dioxide and water to produce glucose and oxygen in the presence of chlorophyll and using energy from light
    6 State the word equation for photosynthesis, carbon dioxide + water $\rightarrow$ glucose + oxygen 9 State the symbol equation for photosynthesis, $6\text{CO}_2 + 6\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2$

    Source: Cambridge International syllabus

    A power station releasing emissions
    Burning fossil fuels pollutes the air and changes the climate.

    Clean, dry air is approximately:

    • 78% nitrogen ($\text{N}_2$)
    • 21% oxygen ($\text{O}_2$)
    • the rest is a mixture of noble gases 稀有气体 and carbon dioxide ($\text{CO}_2$).
    A pie chart of clean dry air: a large nitrogen slice (78%), an oxygen slice (21%) and a thin slice for the rest (1%)
    Clean, dry air is about 78% nitrogen, 21% oxygen, and 1% other gases (noble gases and carbon dioxide)

    Air pollutants and their sources

    Pollutant Main source
    carbon dioxide ($\text{CO}_2$) complete combustion 完全燃烧 of carbon-containing fuels
    carbon monoxide 一氧化碳 and particulates 颗粒物 incomplete combustion 不完全燃烧 of carbon-containing fuels
    methane 甲烷 rotting plants and waste gases from animal digestion
    oxides of nitrogen 氮氧化物 car engines
    sulfur dioxide burning fossil fuels 化石燃料 that contain sulfur

    Effects of these pollutants

    • Carbon dioxide 二氧化碳 and methane are greenhouse gases 温室气体: more of them causes global warming 全球变暖, which leads to climate change 气候变化.
    • Carbon monoxide is a toxic gas.
    • Particulates increase the risk of respiratory 呼吸 (breathing) problems and cancer 癌症.
    • Oxides of nitrogen cause acid rain 酸雨, photochemical smog 光化学烟雾 and breathing problems.
    • Sulfur dioxide causes acid rain.

    Worked example. A power station burns coal containing sulfur, and a lake downwind slowly turns acidic. Name the pollutant, explain the link, and give one way to stop it. Burning a fossil fuel that contains sulfur releases sulfur dioxide, which causes acid rain, so the rain falling on the lake is acidic. To stop it at the source, use flue gas desulfurisation, where calcium oxide removes the sulfur dioxide from the waste gases before they leave the chimney, or switch to a low-sulfur fuel. Match the fix to the pollutant: a catalytic converter treats a car's oxides of nitrogen and would do nothing about a coal-fired power station's sulfur dioxide.

    Reducing these problems

    To slow climate change: plant trees, farm fewer animals, burn fewer fossil fuels, and use more hydrogen and renewable energy 可再生能源 such as wind and solar power.

    To reduce acid rain: fit catalytic converters 催化转化器 in cars, use low-sulfur fuels, and use flue gas desulfurisation 烟气脱硫 with calcium oxide 氧化钙 to remove sulfur dioxide from waste gases.

    The ceramic honeycomb core taken out of a catalytic converter, showing thousands of tiny channels
    Inside a catalytic converter is a honeycomb coated with catalyst metals; the many tiny channels give a huge surface area

    How greenhouse gases warm the Earth

    Greenhouse gases such as carbon dioxide and methane let sunlight through, but they absorb the thermal energy 热能 given off by the warm Earth, and send some of it back down. This reduces the thermal energy lost to space, so the Earth gets warmer.

    Sunlight passes through the atmosphere to warm the Earth, which gives off heat; greenhouse gases absorb some of that heat and send it back down
    Greenhouse gases let sunlight through but trap some of the heat the Earth gives off, so the Earth warms up

    In a car engine, the high temperature makes nitrogen and oxygen from the air react to form oxides of nitrogen. A catalytic converter removes them, for example:

    $$2\text{CO} + 2\text{NO} \rightarrow 2\text{CO}_2 + \text{N}_2$$

    Photosynthesis

    Photosynthesis 光合作用 is the opposite of combustion — it removes carbon dioxide from the air. Plants use light energy and chlorophyll 叶绿素 to turn carbon dioxide and water into glucose 葡萄糖 and oxygen:

    $$6\text{CO}_2 + 6\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + 6\text{O}_2$$
    Explore

    Air pollutant lab

    Classify air gases by source and environmental effect.

    Explore

    Climate and air quality route

    Trace emissions from combustion to atmospheric effects.

    Vocabulary Train
    English Chinese Pinyin
    noble gases 稀有气体 xī yǒu qì tǐ
    complete combustion 完全燃烧 wán quán rán shāo
    carbon monoxide 一氧化碳 yī yǎng huà tàn
    particulates 颗粒物 kē lì wù
    incomplete combustion 不完全燃烧 bù wán quán rán shāo
    methane 甲烷 jiǎ wán
    oxides of nitrogen 氮氧化物 dàn yǎng huà wù
    fossil fuels 化石燃料 huà shí rán liào
    sulfur liú
    carbon dioxide 二氧化碳 èr yǎng huà tàn
    greenhouse gases 温室气体 wēn shì qì tǐ
    global warming 全球变暖 quán qiú biàn nuǎn
    climate change 气候变化 qì hòu biàn huà
    respiratory 呼吸 hū xī
    cancer 癌症 ái zhèng
    acid rain 酸雨 suān yǔ
    photochemical smog 光化学烟雾 guāng huà xué yān wù
    renewable energy 可再生能源 kě zài shēng néng yuán
    catalytic converters 催化转化器 cuī huà zhuǎn huà qì
    flue gas desulfurisation 烟气脱硫 yān qì tuō liú
    calcium oxide 氧化钙 yǎng huà gài
    thermal energy 热能 rè néng
    photosynthesis 光合作用 guāng hé zuò yòng
    chlorophyll 叶绿素 yè lǜ sù
    glucose 葡萄糖 pú táo táng
    10.3

    Exam tips

    • Two tests show water is present (cobalt(II) chloride blue → pink; copper(II) sulfate white → blue), but only fixed melting and boiling points (0 °C and 100 °C) show it is pure.
    • Clean, dry air is about 78% nitrogen, 21% oxygen and 1% other gases (mostly noble gases and carbon dioxide).
    • Match each pollutant to its source and effect: carbon monoxide (incomplete combustion; toxic); sulfur dioxide and oxides of nitrogen (acid rain); carbon dioxide and methane (greenhouse gases → global warming).
    • Greenhouse gases let sunlight through but absorb the heat the warm Earth gives off and send some back down, so the Earth warms up.
  • 11 Organic chemistry

    Organic chemistry is the chemistry of carbon compounds. Carbon is special because it can join to other carbon atoms to make long chains and rings.

    11.1

    Formulae and key words

    Syllabus
    Core Supplement
    1 Draw and interpret the displayed formula of a molecule to show all the atoms and all the bonds
    2 Write and interpret general formulae of compounds in the same homologous series, limited to: (a) alkanes, $\text{C}_n\text{H}_{2n+2}$ (b) alkenes, $\text{C}_n\text{H}_{2n}$ (c) alcohols, $\text{C}_n\text{H}_{2n+1}\text{OH}$ (d) carboxylic acids, $\text{C}_n\text{H}_{2n+1}\text{COOH}$
    3 Identify a functional group as an atom or group of atoms that determine the chemical properties of a homologous series
    7 State that a structural formula is an unambiguous description of the way the atoms in a molecule are arranged, including $\text{CH}_2=\text{CH}_2$, $\text{CH}_3\text{CH}_2\text{OH}$, $\text{CH}_3\text{COOCH}_3$
    8 Define structural isomers as compounds with the same molecular formula, but different structural formulae, including $\text{C}_4\text{H}_{10}$ as $\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3$ and $\text{CH}_3\text{CH}(\text{CH}_3)\text{CH}_3$ and $\text{C}_4\text{H}_8$ as $\text{CH}_3\text{CH}_2\text{CH}=\text{CH}_2$ and $\text{CH}_3\text{CH}=\text{CHCH}_3$
    4 State that a homologous series is a family of similar compounds with similar chemical properties due to the presence of the same functional group 9 Describe the general characteristics of a homologous series as: (a) having the same functional group (b) having the same general formula (c) differing from one member to the next by a –CH2– unit (d) displaying a trend in physical properties (e) sharing similar chemical properties
    5 State that a saturated compound has molecules in which all carbon–carbon bonds are single bonds
    6 State that an unsaturated compound has molecules in which one or more carbon–carbon bonds are not single bonds

    Source: Cambridge International syllabus

    There are several ways to write an organic molecule:

    • The molecular formula 分子式 shows how many of each atom there are, for example $\text{C}_2\text{H}_6$.
    • The displayed formula 结构式 shows every atom and every bond drawn out in full.
    • The structural formula 结构简式 shows how the atoms are arranged without drawing every bond, for example $\text{CH}_3\text{CH}_2\text{OH}$.
    • The general formula 通式 works for a whole family, for example $\text{C}_n\text{H}_{2n+2}$ for alkanes.

    A homologous series 同系物 is a family of compounds with the same functional group 官能团 — the atom or group of atoms that gives the family its chemical properties. Members of a series have the same general formula, differ by a $\text{CH}_2$ unit each step, and have similar chemical properties with a gradual change in physical properties.

    Series Functional group General formula
    alkanes C–C single bonds only $\text{C}_n\text{H}_{2n+2}$
    alkenes C=C double bond $\text{C}_n\text{H}_{2n}$
    alcohols –OH $\text{C}_n\text{H}_{2n+1}\text{OH}$
    carboxylic acids –COOH $\text{C}_n\text{H}_{2n+1}\text{COOH}$
    Displayed formulae of methane, ethane and propane, each one CH2 unit longer than the last
    The alkanes are a homologous series: each member has one more $\text{CH}_2$ unit (general formula $\text{C}_n\text{H}_{2n+2}$)

    A saturated 饱和 compound has only single carbon–carbon bonds. An unsaturated 不饱和 compound has one or more carbon–carbon bonds that are not single (such as a C=C double bond).

    Ethane with a single carbon-carbon bond next to ethene with a carbon-carbon double bond
    A saturated compound has only single C–C bonds; an unsaturated one has a C=C double bond

    Structural isomers 同分异构体 are compounds with the same molecular formula but different structural formulae. For example, $\text{C}_4\text{H}_{10}$ can be a straight chain or a branched chain.

    Butane drawn as a straight chain of four carbons beside 2-methylpropane drawn as a branched structure
    Structural isomers: butane and 2-methylpropane share the formula $\text{C}_4\text{H}_{10}$ but have different structures
    Explore

    Functional group lab

    Classify organic molecules by the group that controls their reactions.

    Vocabulary Train
    English Chinese Pinyin
    molecular formula 分子式 fēn zǐ shì
    displayed formula 结构式 jié gòu shì
    structural formula 结构简式 jié gòu jiǎn shì
    general formula 通式 tōng shì
    homologous series 同系物 tóng xì wù
    functional group 官能团 guān néng tuán
    saturated 饱和 bǎo hé
    unsaturated 不饱和 bù bǎo hé
    Structural isomers 同分异构体 tóng fēn yì gòu tǐ
    11.2

    Naming organic compounds

    Syllabus
    Core Supplement
    1 Name and draw the displayed formulae of: (a) methane and ethane (b) ethene (c) ethanol (d) ethanoic acid (e) the products of the reactions stated in sections 11.4–11.7 3 Name and draw the structural and displayed formulae of unbranched: (a) alkanes (b) alkenes, including but-1-ene and but-2-ene (c) alcohols, including propan-1-ol, propan-2-ol, butan-1-ol and butan-2-ol (d) carboxylic acids containing up to four carbon atoms per molecule
    2 State the type of compound present, given a chemical name ending in -ane, -ene, -ol, or -oic acid or from a molecular formula or displayed formula 4 Name and draw the displayed formulae of the unbranched esters which can be made from unbranched alcohols and carboxylic acids, each containing up to four carbon atoms

    Source: Cambridge International syllabus

    The end of the name tells you the family:

    Ending Family Example
    -ane alkane methane, ethane
    -ene alkene ethene
    -ol alcohol ethanol
    -oic acid carboxylic acid ethanoic acid

    The start of the name tells you the number of carbon atoms: meth- = 1, eth- = 2, prop- = 3, but- = 4. For longer alkenes and alcohols, a number shows where the functional group is, for example but-1-ene and but-2-ene, or propan-1-ol and propan-2-ol.

    Explore

    Organic naming route

    Follow the route from structure to systematic name.

    11.3

    Fuels

    Syllabus
    Core Supplement
    1 Name the fossil fuels: coal, natural gas and petroleum
    2 Name methane as the main constituent of natural gas
    3 State that hydrocarbons are compounds that contain hydrogen and carbon only
    4 State that petroleum is a mixture of hydrocarbons
    5 Describe the separation of petroleum into useful fractions by fractional distillation
    6 Describe how the properties of fractions obtained from petroleum change from the bottom to the top of the fractionating column, limited to: (a) decreasing chain length (b) higher volatility (c) lower boiling points (d) lower viscosity
    7 Name the uses of the fractions as: (a) refinery gas fraction for gas used in heating and cooking (b) gasoline/petrol fraction for fuel used in cars (c) naphtha fraction as a chemical feedstock (d) kerosene/paraffin fraction for jet fuel (e) diesel oil/gas oil fraction for fuel used in diesel engines (f) fuel oil fraction for fuel used in ships and home heating systems (g) lubricating oil fraction for lubricants, waxes and polishes (h) bitumen fraction for making roads

    Source: Cambridge International syllabus

    Fractional distillation of crude oil
    An oil refinery at dusk
    An oil refinery separates crude oil into useful fuels by fractional distillation.

    The three fossil fuels 化石燃料 are coal, natural gas 天然气 and petroleum 石油 (crude oil). Methane 甲烷 is the main part of natural gas.

    A hydrocarbon 碳氢化合物 is a compound made of hydrogen and carbon only. Petroleum is a mixture of many different hydrocarbons.

    Fractional distillation

    Petroleum is separated into useful fractions 馏分 by fractional distillation 分馏. The mixture is heated, and the different hydrocarbons turn to gas and rise up a tall fractionating column 分馏塔. The column is hot at the bottom and cool at the top, so each fraction turns back to liquid at a different height.

    A fractionating column with fractions drawn off at different heights, hottest at the bottom and coolest at the top
    Fractions separate by boiling point: small molecules leave the cool top, thick bitumen stays at the hot bottom

    Going from the bottom to the top of the column, the fractions have:

    • shorter chain length 链长 (smaller molecules);
    • higher volatility 挥发性 (they turn to gas more easily);
    • lower boiling points;
    • lower viscosity 黏度 (they flow more easily).
    Fraction Use
    refinery gas gas for heating and cooking
    gasoline / petrol fuel for cars
    naphtha raw material for making chemicals
    kerosene / paraffin jet fuel
    diesel oil fuel for diesel engines
    fuel oil fuel for ships and home heating
    lubricating oil lubricants, waxes and polishes
    bitumen 沥青 making roads
    Explore

    Fuel chain lab

    Follow a fuel from source to combustion products.

    Vocabulary Train
    English Chinese Pinyin
    fossil fuels 化石燃料 huà shí rán liào
    coal méi
    natural gas 天然气 tiān rán qì
    petroleum 石油 shí yóu
    Methane 甲烷 jiǎ wán
    hydrocarbon 碳氢化合物 tàn qīng huà hé wù
    fractions 馏分 liú fèn
    fractional distillation 分馏 fēn liú
    fractionating column 分馏塔 fēn liú tǎ
    chain length 链长 liàn zhǎng
    volatility 挥发性 huī fā xìng
    viscosity 黏度 nián dù
    bitumen 沥青 lì qīng
    11.4

    Alkanes

    Syllabus
    Core Supplement
    1 State that the bonding in alkanes is single covalent and that alkanes are saturated hydrocarbons
    2 Describe the properties of alkanes as being generally unreactive, except in terms of combustion and substitution by chlorine 3 State that in a substitution reaction one atom or group of atoms is replaced by another atom or group of atoms
    4 Describe the substitution reaction of alkanes with chlorine as a photochemical reaction, with ultraviolet light providing the activation energy, $E_a$, and draw the structural or displayed formulae of the products, limited to monosubstitution

    Source: Cambridge International syllabus

    Alkanes 烷烃 have only single covalent bonds, so they are saturated hydrocarbons. They are generally unreactive. Their two important reactions are:

    • Combustion 燃烧: they burn in plenty of oxygen to give carbon dioxide and water.
    • Substitution with chlorine.

    In a substitution reaction 取代反应, one atom (or group of atoms) is replaced by another. Alkanes react with chlorine only in ultraviolet light 紫外线 — this is a photochemical reaction 光化学反应, where the light provides the activation energy 活化能. For example:

    $$\text{CH}_4 + \text{Cl}_2 \rightarrow \text{CH}_3\text{Cl} + \text{HCl}$$
    Explore

    Burning an alkane

    Step through combustion. With plenty of oxygen an alkane burns cleanly; starve it of oxygen and you get toxic carbon monoxide and soot instead.

    Vocabulary Train
    English Chinese Pinyin
    Alkanes 烷烃 wán tīng
    Combustion 燃烧 rán shāo
    substitution reaction 取代反应 qǔ dài fǎn yìng
    ultraviolet light 紫外线 zǐ wài xiàn
    photochemical reaction 光化学反应 guāng huà xué fǎn yìng
    activation energy 活化能 huó huà néng
    11.5

    Alkenes

    Syllabus
    Core Supplement
    1 State that the bonding in alkenes includes a double carbon–carbon covalent bond and that alkenes are unsaturated hydrocarbons
    2 Describe the manufacture of alkenes and hydrogen by the cracking of larger alkane molecules using a high temperature and a catalyst
    3 Describe the reasons for the cracking of larger alkane molecules
    5 State that in an addition reaction only one product is formed
    4 Describe the test to distinguish between saturated and unsaturated hydrocarbons by their reaction with aqueous bromine 6 Describe the properties of alkenes in terms of addition reactions with: (a) bromine or aqueous bromine (b) hydrogen in the presence of a nickel catalyst (c) steam in the presence of an acid catalyst and draw the structural or displayed formulae of the products

    Source: Cambridge International syllabus

    Alkenes 烯烃 have a carbon–carbon double bond (C=C), so they are unsaturated hydrocarbons.

    Cracking

    Large alkane molecules are not very useful. Cracking 裂化 breaks them into smaller, more useful molecules — smaller alkanes and alkenes — using a high temperature and a catalyst 催化剂. Cracking also makes hydrogen 氢气 and provides alkenes for making plastics.

    A long alkane chain breaking into a shorter alkane and an alkene with a double bond
    Cracking breaks one large alkane into a smaller alkane plus an alkene (with a C=C), using heat and a catalyst

    Worked example. Cracking one molecule of decane, $\text{C}_{10}\text{H}_{22}$, gives octane, $\text{C}_8\text{H}_{18}$, and one other product. Identify it, and say how you would tell the two products apart. Atoms are conserved, so subtract: carbon $10 - 8 = 2$, hydrogen $22 - 18 = 4$. The other product is $\text{C}_2\text{H}_4$, ethene - an alkene, because it fits $\text{C}_n\text{H}_{2n}$. To tell them apart, shake each with orange bromine water: ethene has a C=C, so it decolourises the bromine water, while octane is saturated and leaves it orange. Balance a cracking equation by counting atoms on each side; the alkene is whatever is left over.

    Reactions of alkenes

    The C=C double bond makes alkenes reactive. They take part in addition reactions 加成反应, where two molecules join to form a single product.

    • Test for unsaturation: shake the compound with bromine water (which is orange). An alkene turns the bromine water colourless; an alkane does not change it.
    Two test tubes of orange bromine water: the alkene one has gone colourless, the alkane one is still orange
    The bromine water test: an alkene decolourises the orange bromine water (its C=C reacts), while an alkane leaves it orange
    • With hydrogen and a nickel catalyst, an alkene becomes an alkane.
    • With steam 蒸汽 and an acid catalyst, an alkene becomes an alcohol.
    Explore

    Addition across the C=C double bond

    Step through an addition reaction. The C=C double bond is an alkene's reactive spot — molecules add right across it, which also gives the bromine-water test.

    Vocabulary Train
    English Chinese Pinyin
    Alkenes 烯烃 xī tīng
    Cracking 裂化 liè huà
    catalyst 催化剂 cuī huà jì
    hydrogen 氢气 qīng qì
    addition reactions 加成反应 jiā chéng fǎn yìng
    bromine xiù
    nickel niè
    steam 蒸汽 zhēng qì
    11.6

    Alcohols

    Syllabus
    Core Supplement
    1 Describe the manufacture of ethanol by: (a) fermentation of aqueous glucose at 25–35 °C in the presence of yeast and in the absence of oxygen (b) catalytic addition of steam to ethene at 300 °C and 6000 kPa / 60 atm in the presence of an acid catalyst 4 Describe the advantages and disadvantages of the manufacture of ethanol by: (a) fermentation (b) catalytic addition of steam to ethene
    2 Describe the combustion of ethanol
    3 State the uses of ethanol as: (a) a solvent (b) a fuel

    Source: Cambridge International syllabus

    Alcohols contain the –OH functional group. The most important one is ethanol 乙醇. There are two ways to make ethanol.

    Two routes to ethanol: fermentation of glucose, and hydration of ethene with steam
    Two routes to ethanol: fermentation, and hydration of ethene
    Method Conditions Notes
    fermentation 发酵 of glucose yeast, 25–35 °C, no oxygen uses renewable sugar, but slow and gives impure ethanol
    addition of steam to ethene 乙烯 300 °C, 60 atm, acid catalyst fast and pure, but uses petroleum (non-renewable)

    In fermentation, yeast 酵母 turns glucose 葡萄糖 into ethanol and carbon dioxide.

    Ethanol burns well (combustion), so it is used as a fuel. It also dissolves many substances, so it is used as a solvent 溶剂.

    Explore

    Making ethanol by fermentation

    Step through fermentation. Yeast turns sugar into ethanol with no air — the same alcohol can then be oxidised to vinegar.

    Vocabulary Train
    English Chinese Pinyin
    Alcohols chún
    ethanol 乙醇 yǐ chún
    fermentation 发酵 fā jiào
    ethene 乙烯 yǐ xī
    yeast 酵母 jiào mǔ
    glucose 葡萄糖 pú táo táng
    solvent 溶剂 róng jì
    11.7

    Carboxylic acids

    Syllabus
    Core Supplement
    1 Describe the reaction of ethanoic acid with: (a) metals (b) bases (c) carbonates including names and formulae of the salts produced 2 Describe the formation of ethanoic acid by the oxidation of ethanol: (a) with acidified aqueous potassium manganate(VII) (b) by bacterial oxidation during vinegar production
    3 Describe the reaction of a carboxylic acid with an alcohol using an acid catalyst to form an ester

    Source: Cambridge International syllabus

    Carboxylic acids 羧酸 contain the –COOH functional group. Ethanoic acid 乙酸 is the one to know. Like other acids, it reacts with:

    Carboxylic acid plus alcohol reacting to form an ester plus water
    A carboxylic acid and an alcohol react to make an ester and water
    • metals 金属 → a salt + hydrogen;
    • bases → a salt + water;
    • carbonates 碳酸盐 → a salt + water + carbon dioxide.

    The salts formed are called ethanoates.

    Ethanoic acid can be made by the oxidation 氧化 of ethanol, either using acidified potassium manganate(VII) 高锰酸钾, or by bacteria during the making of vinegar.

    When a carboxylic acid reacts with an alcohol (using an acid catalyst), it forms an ester. For example, ethanol + ethanoic acid → ethyl ethanoate + water. The ester's functional group is $-\text{COO}-$, and you name it from its two parents: the alcohol gives the first part with an -yl ending (ethyl), the acid gives the second part with an -oate ending (ethanoate). Its displayed formula is $\text{CH}_3\text{-COO-CH}_2\text{-CH}_3$.

    Explore

    A weak acid's pH

    Carboxylic acids are weak acids — they only partly ionise, so they sit just below pH 7. Slide the scale to see where they fall.

    Vocabulary Train
    English Chinese Pinyin
    Carboxylic acids 羧酸 suō suān
    Ethanoic acid 乙酸 yǐ suān
    metals 金属 jīn shǔ
    bases jiǎn
    salt yán
    carbonates 碳酸盐 tàn suān yán
    oxidation 氧化 yǎng huà
    potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ
    vinegar
    ester zhǐ
    11.8

    Polymers

    Syllabus
    Core Supplement
    1 Define polymers as large molecules built up from many smaller molecules called monomers 6 Identify the repeat units and/or linkages in addition polymers and in condensation polymers
    2 Describe the formation of poly(ethene) as an example of addition polymerisation using ethene monomers 7 Deduce the structure or repeat unit of an addition polymer from a given alkene and vice versa
    8 Deduce the structure or repeat unit of a condensation polymer from given monomers and vice versa, limited to: (a) polyamides from a dicarboxylic acid and a diamine (b) polyesters from a dicarboxylic acid and a diol
    9 Describe the differences between addition and condensation polymerisation
    10 Describe and draw the structure of: (a) nylon, a polyamide [image] (b) PET, a polyester [image] The full name for PET, polyethylene terephthalate, is not required
    3 State that plastics are made from polymers
    4 Describe how the properties of plastics have implications for their disposal 11 State that PET can be converted back into monomers and re-polymerised
    5 Describe the environmental challenges caused by plastics, limited to: (a) disposal in landfill sites (b) accumulation in oceans (c) formation of toxic gases from burning
    12 Describe proteins as natural polyamides and that they are formed from amino acid monomers with the general structure: [image] where R represents different types of side-chain
    13 Describe and draw the structure of proteins as: [image]

    Source: Cambridge International syllabus

    A polymer 聚合物 is a very large molecule built from many small molecules called monomers 单体.

    Addition polymerisation

    In addition polymerisation 加聚, many unsaturated monomers join together with no other product. For example, many ethene monomers join to make poly(ethene). The small part that repeats along the chain is the repeat unit 重复单元.

    Many ethene monomers with C=C double bonds joining into a poly(ethene) chain with single bonds, shown as a repeat unit in brackets
    In addition polymerisation the C=C bonds open up and many ethene monomers join into a long poly(ethene) chain

    Condensation polymerisation

    In condensation polymerisation 缩聚, monomers join and a small molecule (usually water) is lost each time a bond forms. This makes two important types:

    • Polyamides 聚酰胺 are made from a dicarboxylic acid and a diamine. Nylon 尼龙 is a polyamide.
    • Polyesters 聚酯 are made from a dicarboxylic acid and a diol. PET is a polyester, and it can be broken back into its monomers and re-made.

    The new bond joining the monomers is the linkage: an amide linkage 酰胺键 (written $-\text{CO-NH}-$) in a polyamide such as nylon, and an ester linkage 酯键 (written $-\text{CO-O}-$) in a polyester such as PET. A repeat unit is drawn in brackets, e.g. nylon as $-[\text{CO-}(\text{CH}_2)_4\text{-CO-NH-}(\text{CH}_2)_6\text{-NH}]-$; in an exam you may be asked to circle the linkage in a drawn repeat unit.

    Plastics and the environment

    Plastics 塑料 are made from polymers. Because many plastics do not break down, getting rid of them is a problem:

    • they build up in landfill 填埋 sites;
    • they collect in the oceans and harm sea life;
    • burning them can make toxic gases.
    A pebble beach covered in washed-up plastic bottles, cups and broken plastic fragments
    Most plastics are non-biodegradable, so waste plastic collects on beaches and in the oceans for hundreds of years

    Proteins

    Proteins 蛋白质 are natural polyamides. They are made from amino acid 氨基酸 monomers joined in long chains.

    Explore

    Making a polymer

    Small monomers join into a long chain — the basis of all plastics.

    Vocabulary Train
    English Chinese Pinyin
    polymer 聚合物 jù hé wù
    monomers 单体 dān tǐ
    addition polymerisation 加聚 jiā jù
    repeat unit 重复单元 chóng fù dān yuán
    condensation polymerisation 缩聚 suō jù
    Polyamides 聚酰胺 jù xiān àn
    Nylon 尼龙 ní lóng
    Polyesters 聚酯 jù zhǐ
    amide linkage 酰胺键 xiān àn jiàn
    ester linkage 酯键 zhǐ jiàn
    Plastics 塑料 sù liào
    landfill 填埋 tián mái
    Proteins 蛋白质 dàn bái zhì
    amino acid 氨基酸 ān jī suān
    11.8

    Exam tips

    • Learn each homologous series by its functional group and general formula: alkanes $\text{C}_n\text{H}_{2n+2}$, alkenes $\text{C}_n\text{H}_{2n}$, alcohols $-\text{OH}$, carboxylic acids $-\text{COOH}$.
    • The bromine water test for unsaturation: an alkene (with its C=C) turns orange bromine water colourless; an alkane leaves it orange.
    • Cracking breaks large, less useful alkanes into smaller alkanes and alkenes, using heat and a catalyst.
    • Two routes to ethanol: fermentation of glucose (renewable but slow and impure) and adding steam to ethene (fast and pure, but from petroleum).
    • Addition polymerisation joins unsaturated monomers with no other product; condensation polymerisation joins monomers and loses a small molecule (usually water) each time.
  • 12 Experimental techniques and chemical analysis
    12.1

    Experimental design

    Syllabus
    Core Supplement
    1 Name appropriate apparatus for the measurement of time, temperature, mass and volume, including: (a) stop-watches (b) thermometers (c) balances (d) burettes (e) volumetric pipettes (f) measuring cylinders (g) gas syringes
    2 Suggest advantages and disadvantages of experimental methods and apparatus
    3 Describe a: (a) solvent as a substance that dissolves a solute (b) solute as a substance that is dissolved in a solvent (c) solution as a mixture of one or more solutes dissolved in a solvent (d) saturated solution as a solution containing the maximum concentration of a solute dissolved in the solvent at a specified temperature (e) residue as a substance that remains after evaporation, distillation, filtration or any similar process (f) filtrate as a liquid or solution that has passed through a filter

    Source: Cambridge International syllabus

    Apparatus

    You should know which piece of apparatus to use for each measurement:

    Measurement Apparatus
    time stop-watch 秒表
    temperature thermometer 温度计
    mass balance 天平
    volume (accurate) burette 滴定管 or volumetric pipette 移液管
    volume (rough) measuring cylinder 量筒
    volume of a gas gas syringe 注射器

    Key words

    These words are used throughout practical chemistry:

    • A solvent 溶剂 is a substance that dissolves a solute.
    • A solute 溶质 is the substance that dissolves in the solvent.
    • A solution 溶液 is a mixture of one or more solutes dissolved in a solvent.
    • A saturated solution 饱和溶液 holds the maximum amount of solute that will dissolve at a given temperature.
    • A residue 残渣 is the substance left behind after evaporation, distillation or filtration.
    • A filtrate 滤液 is the liquid that has passed through a filter.
    Explore

    Experiment design route

    Follow a fair test from question to reliable conclusion.

    Vocabulary Train
    English Chinese Pinyin
    stop-watch 秒表 miǎo biǎo
    thermometer 温度计 wēn dù jì
    balance 天平 tiān píng
    burette 滴定管 dī dìng guǎn
    volumetric pipette 移液管 yí yè guǎn
    measuring cylinder 量筒 liáng tǒng
    gas syringe 注射器 zhù shè qì
    solvent 溶剂 róng jì
    solute 溶质 róng zhì
    solution 溶液 róng yè
    saturated solution 饱和溶液 bǎo hé róng yè
    residue 残渣 cán zhā
    filtrate 滤液 lǜ yè
    12.2

    Acid–base titrations

    Syllabus
    Core Supplement
    1 Describe an acid–base titration to include the use of a: (a) burette (b) volumetric pipette (c) suitable indicator
    2 Describe how to identify the end-point of a titration using an indicator

    Source: Cambridge International syllabus

    Titration curve and equivalence point

    A titration 滴定 finds the exact volume of one solution that reacts with another.

    • Use a volumetric pipette to measure a fixed volume of one solution into a flask.
    • Add a few drops of a suitable indicator 指示剂.
    • Add the other solution from a burette, slowly, until the colour just changes.

    The end-point 终点 is the moment the indicator changes colour, which shows the reaction is exactly complete. You read the burette to find the volume added.

    A burette of solution clamped above a conical flask of solution and indicator standing on a white tile
    Solution is run from the burette into the flask until the indicator just changes colour (the end-point)
    A real titration set-up: burettes above conical flasks holding an orange indicator solution
    A real titration: solution from the burette is added to the flask, where the indicator has turned orange
    Explore

    Acid–base titrations

    pH jumps at the equivalence point

    Track the pH as base is added — it leaps through neutral at the equivalence point.

    Vocabulary Train
    English Chinese Pinyin
    titration 滴定 dī dìng
    indicator 指示剂 zhǐ shì jì
    end-point 终点 zhōng diǎn
    Exercise sheet
    12.3

    Chromatography

    Syllabus
    Core Supplement
    1 Describe how paper chromatography is used to separate mixtures of soluble coloured substances, using a suitable solvent 3 Describe how paper chromatography is used to separate mixtures of soluble colourless substances, using a suitable solvent and a locating agent Knowledge of specific locating agents is not required
    2 Interpret simple chromatograms to identify: (a) unknown substances by comparison with known substances (b) pure and impure substances 4 State and use the equation for $R_{\text{f}}$:
    $$R_{\text{f}} = \frac{\text{distance travelled by substance}}{\text{distance travelled by solvent}}$$

    Source: Cambridge International syllabus

    Paper chromatography 纸色谱法 separates a mixture of soluble substances. You put a spot of the mixture near the bottom of the paper, then stand the paper in a solvent. As the solvent rises up the paper, the substances move different distances, so they separate.

    Chromatography paper standing in solvent, with a mixture on the baseline separating into spots that rise to different heights below the solvent front
    As the solvent rises, the substances travel different distances and separate; $R_f$ is the spot distance ($a$) divided by the solvent distance ($b$)
    Real chromatography paper strips with coloured spots that have risen to different heights up each strip
    On real chromatograms, each substance in the mixture rises a different distance, leaving a separate coloured spot
    • For coloured substances you can see the spots directly.
    • For colourless substances you must spray a locating agent 显色剂 to make the spots show up.

    The finished paper is a chromatogram 色谱图. You can use it to:

    • identify an unknown substance by comparing it with known substances;
    • tell if a substance is pure (a pure substance gives only one spot).

    You can also calculate the $R_{\text{f}}$ value of a spot:

    $$R_{\text{f}} = \frac{\text{distance moved by the substance}}{\text{distance moved by the solvent}}$$

    Worked example. On a chromatogram the solvent front has risen 8.0 cm from the baseline, and a spot has moved 6.0 cm. Find its $R_{\text{f}}$ value.

    $$R_{\text{f}} = \frac{6.0}{8.0} = 0.75$$

    Both distances are measured from the baseline (the pencil line), and the spot's distance is taken to the centre of the spot. An $R_{\text{f}}$ has no unit, and it is always less than 1, because a spot can never travel further than the solvent carrying it - an answer above 1 means the two distances have been divided the wrong way round.

    Explore

    Chromatography route

    Watch a mixture separate as the solvent front moves.

    Vocabulary Train
    English Chinese Pinyin
    paper chromatography 纸色谱法 zhǐ sè pǔ fǎ
    locating agent 显色剂 xiǎn sè jì
    chromatogram 色谱图 sè pǔ tú
    12.4

    Separation and purification

    Syllabus
    Core Supplement
    1 Describe and explain methods of separation and purification using: (a) a suitable solvent (b) filtration (c) crystallisation (d) simple distillation (e) fractional distillation
    2 Suggest suitable separation and purification techniques, given information about the substances involved
    3 Identify substances and assess their purity using melting point and boiling point information

    Source: Cambridge International syllabus

    You choose a method based on the mixture:

    Method Used to separate
    dissolving in a suitable solvent, then filtration 过滤 an insoluble solid from a liquid
    crystallisation 结晶 a soluble solid from its solution
    simple distillation 蒸馏 a solvent (the liquid) from a solution
    fractional distillation 分馏 two or more liquids with different boiling points
    A filter funnel lined with filter paper catching insoluble residue while the filtrate drips into a beaker below
    Filtration: the insoluble solid stays on the filter paper (residue) and the liquid passes through (filtrate)
    A heated flask of solution with a thermometer, a water-cooled condenser, and a beaker collecting the distillate
    Simple distillation: the solvent boils off, the condenser cools it back to a liquid, and the pure distillate is collected
    Like simple distillation but with a glass-bead fractionating column and a thermometer at the top of the column
    Fractional distillation adds a fractionating column, so liquids with different boiling points separate cleanly

    You can check the purity of a substance using its melting point 熔点 and boiling point 沸点: a pure substance melts and boils at sharp, fixed temperatures, while impurities lower the melting point and raise the boiling point.

    Explore

    Separation method lab

    Choose the method that matches the mixture.

    Vocabulary Train
    English Chinese Pinyin
    filtration 过滤 guò lǜ
    crystallisation 结晶 jié jīng
    simple distillation 蒸馏 zhēng liú
    fractional distillation 分馏 fēn liú
    melting point 熔点 róng diǎn
    boiling point 沸点 fèi diǎn
    12.5

    Identifying ions and gases

    Syllabus
    Core Supplement
    1 Describe tests to identify the anions: (a) carbonate, $\text{CO}_3^{2-}$, by reaction with dilute acid and then testing for carbon dioxide gas (b) chloride, $\text{Cl}^-$, bromide, $\text{Br}^-$, and iodide, $\text{I}^-$, by acidifying with dilute nitric acid then adding aqueous silver nitrate (c) nitrate, $\text{NO}_3^-$, reduction with aluminium foil and aqueous sodium hydroxide and then testing for ammonia gas (d) sulfate, $\text{SO}_4^{2-}$, by acidifying with dilute nitric acid and then adding aqueous barium nitrate (e) sulfite, $\text{SO}_3^{2-}$, by reaction with acidified aqueous potassium manganate(VII)
    2 Describe tests using aqueous sodium hydroxide and aqueous ammonia to identify the aqueous cations: (a) aluminium, $Al^{3+}$ (b) ammonium, $NH_4^+$ (c) calcium, $Ca^{2+}$ (d) chromium(III), $Cr^{3+}$ (e) copper(II), $Cu^{2+}$ (f) iron(II), $Fe^{2+}$ (g) iron(III), $Fe^{3+}$ (h) zinc, $Zn^{2+}$
    3 Describe tests to identify the gases: (a) ammonia, $NH_3$, using damp red litmus paper (b) carbon dioxide, $CO_2$, using limewater (c) chlorine, $Cl_2$, using damp litmus paper (d) hydrogen, $H_2$, using a lighted splint (e) oxygen, $O_2$, using a glowing splint (f) sulfur dioxide, $SO_2$, using acidified aqueous potassium manganate(VII)
    4 Describe the use of a flame test to identify the cations: (a) lithium, $Li^+$ (b) sodium, $Na^+$ (c) potassium, $K^+$ (d) calcium, $Ca^{2+}$ (e) barium, $Ba^{2+}$ (f) copper(II), $Cu^{2+}$

    Source: Cambridge International syllabus

    Tests for anions

    An anion 阴离子 is a negative ion.

    Anion Test Result
    carbonate 碳酸盐 ($\text{CO}_3^{2-}$) add dilute acid fizzes; the gas turns limewater milky (carbon dioxide 二氧化碳)
    chloride 氯化物 ($\text{Cl}^-$) add dilute nitric acid 硝酸, then silver nitrate 硝酸银 white precipitate
    bromide 溴化物 ($\text{Br}^-$) add dilute nitric acid, then silver nitrate cream precipitate
    iodide 碘化物 ($\text{I}^-$) add dilute nitric acid, then silver nitrate yellow precipitate
    nitrate 硝酸盐 ($\text{NO}_3^-$) add aluminium foil and sodium hydroxide 氢氧化钠, warm ammonia 氨气 gas given off
    sulfate 硫酸盐 ($\text{SO}_4^{2-}$) add dilute nitric acid, then barium nitrate 硝酸钡 white precipitate
    sulfite 亚硫酸盐 ($\text{SO}_3^{2-}$) add acidified potassium manganate(VII) 高锰酸钾 purple colour fades

    Tests for cations

    A cation 阳离子 is a positive ion. Add aqueous sodium hydroxide, or aqueous ammonia, and look at the precipitate 沉淀 formed.

    A dropper adds sodium hydroxide to a solution in a test tube, forming a coloured precipitate at the bottom
    Adding sodium hydroxide forms a coloured precipitate for some metal ions
    Cation With sodium hydroxide With aqueous ammonia
    aluminium ($\text{Al}^{3+}$) white, dissolves in excess white, stays
    ammonium ($\text{NH}_4^+$) ammonia gas when warmed
    calcium ($\text{Ca}^{2+}$) white, stays no precipitate
    chromium(III) ($\text{Cr}^{3+}$) green, dissolves in excess green, stays
    copper(II) ($\text{Cu}^{2+}$) light blue, stays light blue, dissolves to deep blue
    iron(II) ($\text{Fe}^{2+}$) green, stays green, stays
    iron(III) ($\text{Fe}^{3+}$) red-brown, stays red-brown, stays
    zinc ($\text{Zn}^{2+}$) white, dissolves in excess white, dissolves in excess

    Tests for gases

    Gas Test Result
    ammonia ($\text{NH}_3$) damp red litmus 石蕊 paper turns blue
    carbon dioxide ($\text{CO}_2$) bubble through limewater 石灰水 turns milky
    chlorine 氯气 ($\text{Cl}_2$) damp litmus paper bleached white
    hydrogen 氢气 ($\text{H}_2$) a lighted splint burns with a squeaky pop
    oxygen 氧气 ($\text{O}_2$) a glowing splint relights
    sulfur dioxide ($\text{SO}_2$) acidified potassium manganate(VII) purple colour fades
    Two test tubes: a lit splint gives a squeaky pop with hydrogen; a glowing splint relights in oxygen
    Testing gases: hydrogen pops, oxygen relights a glowing splint

    Flame tests

    A flame test 焰色试验 identifies some metal cations by the colour they give to a flame:

    A clean wire holding a sample in a Bunsen flame, giving a coloured flame
    A flame test: the metal ion gives the flame a colour
    Cation Flame colour
    lithium ($\text{Li}^+$) red
    sodium ($\text{Na}^+$) yellow
    potassium ($\text{K}^+$) lilac (purple)
    calcium ($\text{Ca}^{2+}$) orange-red
    barium ($\text{Ba}^{2+}$) light green
    copper(II) ($\text{Cu}^{2+}$) blue-green
    Explore

    Ion and gas test lab

    Match test observations to the ion or gas present.

    Vocabulary Train
    English Chinese Pinyin
    anion 阴离子 yīn lí zi
    carbonate 碳酸盐 tàn suān yán
    carbon dioxide 二氧化碳 èr yǎng huà tàn
    chloride 氯化物 lǜ huà wù
    nitric acid 硝酸 xiāo suān
    silver nitrate 硝酸银 xiāo suān yín
    bromide 溴化物 xiù huà wù
    iodide 碘化物 diǎn huà wù
    nitrate 硝酸盐 xiāo suān yán
    aluminium
    sodium hydroxide 氢氧化钠 qīng yǎng huà nà
    ammonia 氨气 ān qì
    sulfate 硫酸盐 liú suān yán
    barium nitrate 硝酸钡 xiāo suān bèi
    sulfite 亚硫酸盐 yà liú suān yán
    potassium manganate(VII) 高锰酸钾 gāo měng suān jiǎ
    cation 阳离子 yáng lí zi
    precipitate 沉淀 chén diàn
    ammonium ǎn
    calcium gài
    chromium
    copper tóng
    iron tiě
    zinc xīn
    litmus 石蕊 shí ruǐ
    limewater 石灰水 shí huī shuǐ
    chlorine 氯气 lǜ qì
    hydrogen 氢气 qīng qì
    oxygen 氧气 yǎng qì
    flame test 焰色试验 yàn sè shì yàn
    lithium
    sodium
    potassium jiǎ
    barium bèi
    12.5

    Exam tips

    • Pick apparatus by the measurement: a burette or pipette for accurate volumes, a measuring cylinder for a rough volume, a gas syringe for a gas volume, a balance for mass.
    • $R_f = \dfrac{\text{distance moved by the substance}}{\text{distance moved by the solvent}}$, so it is always less than 1. A pure substance gives a single spot.
    • Learn the anion tests: a carbonate fizzes and the gas turns limewater milky; halides with silver nitrate give a chloride white, bromide cream, iodide yellow precipitate; a sulfate gives a white precipitate with barium nitrate.
    • Learn the gas tests: hydrogen gives a squeaky pop, oxygen relights a glowing splint, carbon dioxide turns limewater milky, chlorine bleaches damp litmus, ammonia turns damp red litmus blue.
    • For cations, add sodium hydroxide and read the precipitate colour: copper(II) light blue, iron(II) green, iron(III) red-brown.

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