Magnetic flux 磁通量 measures how much magnetic field passes through a surface. For a uniform field through a flat loop it is the dot product $\Phi_B=\vec{B}\cdot\vec{A}=BA\cos\theta$; in general it is the surface integral 面积分
$$\Phi_B=\int \vec{B}\cdot d\vec{A}.$$
The area vector 面积矢量 is perpendicular to the surface (outward from a closed one), and the sign of the flux comes from the dot product. Flux changes if $B$ changes, the area changes, or the loop turns – keep all three routes in mind, because each one is an exam question.
A changing flux induces an emf 电动势 – Faraday's law 法拉第定律:
$$\varepsilon=-\frac{d\Phi_B}{dt}.$$
With constant area, $\varepsilon=-A\,\dfrac{dB_\perp}{dt}$; with constant field, $\varepsilon=-B\,\dfrac{dA_\perp}{dt}$. A coil of $N$ turns multiplies the single-loop emf: $|\varepsilon_{\text{sol}}|=N\left|\dfrac{d\Phi_B}{dt}\right|$.
Lenz's law 楞次定律 is the minus sign: the induced current 感应电流 flows so that its own magnetic field opposes the change in flux that created it. Push a magnet toward a loop and the loop pushes back; pull it away and the loop pulls it in. Use the right-hand rule 右手定则 to turn "oppose the change" into a current direction.
Moving a magnet into a coil induces an e.m.f. that drives a current
A rod of length $L$ sliding at speed $v$, with the rod, velocity and magnetic field mutually perpendicular, is the special case worth memorising – the motional emf 动生电动势$\varepsilon=BLv$.
Worked example. A $0.20\ \text{m}$ rod slides at $3.0\ \text{m/s}$ across a $0.50\ \text{T}$ field: $\varepsilon=BLv=0.50(0.20)(3.0)=0.30\ \text{V}$. Equivalently, if a single loop's flux drops from $0.020\ \text{Wb}$ to $0.008\ \text{Wb}$ in $0.030\ \text{s}$, the average emf is $\varepsilon=\dfrac{0.012}{0.030}=0.40\ \text{V}$.
Faraday's law is also the third of Maxwell's equations 麦克斯韦方程组, in a deeper form: a changing magnetic flux creates a circulating electric field, $\oint\vec{E}\cdot d\vec{l}=-\dfrac{d\Phi_B}{dt}$ – that field is what pushes the charges around the loop. Together, Maxwell's equations predict electromagnetic waves 电磁波 travelling at $c=1/\sqrt{\varepsilon_0\mu_0}$ (you should know this connection, but AP will not ask you to derive it).
Coils of wire spinning in a magnetic field: moving them past the field induces a current, the basis of a generatorA substation transformer: changing magnetic flux in coils induces the voltages that power the grid
Once an induced current flows, the external field exerts forces on it ($\vec{F}=\int I\,d\vec{l}\times\vec{B}$) – and by Lenz's law those forces always resist the motion that causes the induction. Only the segments of the loop actually inside the field feel a force, which can make a loop accelerate, rotate, or brake. This is the origin of eddy currents 涡电流 braking, and you can apply Newton's second law to a moving loop or rod like any other mechanics problem.
Induced eddy currents oppose motion, quickly damping a metal plate swinging in a field
The classic setup is a rod sliding on conducting rails connected by a resistor:
A rod sliding on rails: the induced current feels a force opposing the motion
Worked example (the full chain). Rails $L=0.20\ \text{m}$ apart with resistance $R=0.60\ \Omega$ sit in a $0.50\ \text{T}$ field into the page. The rod is pushed at a constant $3.0\ \text{m/s}$. Then: $\varepsilon=BLv=0.30\ \text{V}$; $I=\varepsilon/R=0.50\ \text{A}$; the field pushes back on the rod with $F=BIL=0.50(0.50)(0.20)=0.050\ \text{N}$. The pushing force does work at $P=Fv=0.15\ \text{W}$ – exactly the $P=I^2R=0.15\ \text{W}$ dissipated in the resistor. Mechanical work becomes electrical energy: that is a generator 发电机, and energy is conserved. Released with no push, the rod slows exponentially: $ma=-\dfrac{B^2L^2}{R}v$.
Exam skill. FRQs walk this exact chain: flux $\to$ emf $\to$ current $\to$ force $\to$ Newton's second law. Write each link separately and check the direction with Lenz's law at the end.
Inductance 电感 is a conductor's tendency to oppose a change in its own current: changing current changes its own flux, which self-induces an emf. From Faraday's law,
$$\varepsilon=-L\frac{dI}{dt}.$$
An inductor 电感器 is a circuit element built to have large inductance – usually a solenoid 螺线管, where geometry gives
with $N$ total turns, area $A$, length $\ell$, and the magnetic permeability 磁导率 of the core. (Straight wires are modelled as having zero inductance.) An inductor carrying current $I$ stores energy in its magnetic field:
$$U_L=\tfrac{1}{2}LI^2,$$
which can later be dissipated in a resistor or moved into a capacitor – conservation of energy applies as usual.
In an RL circuit RL电路 starting with zero current, Kirchhoff's loop rule for a battery $\varepsilon$, resistor $R$, and inductor $L$ in series gives a differential equation 微分方程:
The time constant 时间常数$\tau$ sets the pace: after one $\tau$ a rising current reaches about $63\%$ of its final value (a decaying one falls to $37\%$); it is also how long the change would take at the initial rate. Learn the two limits – they answer most conceptual questions:
Just after the switch closes ($t=0$): current cannot jump, so the inductor momentarily blocks it, self-inducing an emf equal and opposite to the applied potential difference.
Long after ($t\gg\tau$): the current is steady, $dI/dt=0$, and the inductor behaves as a plain wire – the exact opposite of a capacitor.
The current in an RL circuit rises exponentially, reaching 63% at one time constant
Worked example.$\varepsilon=12\ \text{V}$, $R=6.0\ \Omega$, $L=3.0\ \text{H}$: final current $\varepsilon/R=2.0\ \text{A}$, $\tau=L/R=0.50\ \text{s}$. At $t=0.50\ \text{s}$ the current is $2.0(1-e^{-1})\approx1.3\ \text{A}$. At $t=0$ the inductor's potential difference is the full $12\ \text{V}$; as $t\to\infty$ it falls to zero. The current approaches its final value exponentially, and the inductor voltage decays exponentially. Stored magnetic energy follows $U_B=\tfrac12 L[I(t)]^2$, so it is not a single exponential during this current growth.
An LC circuit LC电路 has no resistance, so nothing dissipates energy: it oscillates 振荡, sloshing energy between the capacitor's electric field and the inductor's magnetic field. The loop rule gives
$$\frac{d^2q}{dt^2}=-\frac{1}{LC}\,q,$$
the same equation as a mass on a spring – simple harmonic motion 简谐运动 with charge playing the role of displacement and
$$\omega=\frac{1}{\sqrt{LC}}.$$
The total energy $\dfrac{q^2}{2C}+\tfrac12LI^2$ stays constant: all in the capacitor at maximum charge, all in the inductor at maximum current.
Worked example.$L=2.0\ \text{H}$, $C=8.0\ \mu\text{F}$: $\omega=\dfrac{1}{\sqrt{2.0(8.0\times10^{-6})}}=250\ \text{rad/s}$, period $T=2\pi/\omega\approx0.025\ \text{s}$. If the capacitor starts charged to $12\ \text{V}$, then $U=\tfrac12CV^2=5.8\times10^{-4}\ \text{J}$, and the maximum current follows from $\tfrac12LI_{\max}^2=U$: $I_{\max}=\sqrt{2U/L}=0.024\ \text{A}$ – conservation of energy 能量守恒, no calculus needed.
Compute flux$\Phi_B=\int \vec B\cdot d\vec A$ and get the induced EMF from Faraday's law$\varepsilon=-\tfrac{d\Phi_B}{dt}$.
Use Lenz's law (the minus sign) to fix the direction: the induced current opposes the change in flux.
Flux changes three ways — changing $B$, changing area, or changing angle — identify which and differentiate.
For a rod of length $L$ moving at speed $v$ with the rod, motion and field mutually perpendicular, the motional EMF is $BLv$.
An inductor stores energy $\tfrac12 LI^2$ and resists changes in current (RL time constant $\tau=L/R$).
Common mistakes
Using the full $B$ in the flux when the field is at an angle. $\Phi_B = BA\cos\theta$, with $\theta$ between $\vec B$ and the normal to the loop.
Saying the induced current opposes the field. It opposes the change in flux: if the flux falls, the induced field points the same way as the original.
Treating an inductor like a capacitor at $t = 0$. Just after switching on from zero current, an inductor carries no current (like a break); after a long time it acts as a plain wire.
Forgetting energy in an $LC$ circuit swaps between $\tfrac12 CV^2$ and $\tfrac12 LI^2$ with the total constant.