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线动量

AP 物理 1 · 第 4 主题

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讲义 词汇表
4.1

线动量

大纲
Learning ObjectiveEssential Knowledge

4.1.A
Describe the linear momentum of an object or system.

  • 4.1.A.1 Linear momentum is defined by the equation $\vec{p} = m\vec{v}$.
    • Equation: $\vec{p} = m\vec{v}$
  • 4.1.A.2 Momentum is a vector quantity and has the same direction as the velocity.
  • 4.1.A.3 Momentum can be used to analyze collisions and explosions.
    • 4.1.A.3.i A collision is a model for an interaction where the forces exerted between the involved objects in the system are much larger than the net external force exerted on those objects during the interaction.
    • 4.1.A.3.ii As only the initial and final states of a collision are analyzed, the object model may be used to analyze collisions.
    • 4.1.A.3.iii An explosion is a model for an interaction in which forces internal to the system move objects within that system apart.

Boundary statement: Unless otherwise stated, the general term "momentum" will refer specifically to linear momentum.

来源:美国大学理事会 AP 课程与考试说明

动量(linear momentum)是质量乘速度——一个指向与速度相同方向的矢量:

$$\vec{p}=m\vec{v}.$$
它测量"停止一个移动物体有多难"。一辆重的慢卡车和一个轻的快球能有相同的动量。它的单位是 $\text{kg m/s}$,与 $\text{N s}$ 相同。

词汇表 训练
英文 中文 拼音
Linear momentum 动量 dòng liàng
4.2

动量变化与冲量

大纲
Learning ObjectiveEssential Knowledge

4.2.A
Describe the impulse delivered to an object or system.

  • 4.2.A.1 The rate of change of momentum is equal to the net external force exerted on an object or system.
    • Equation: $\vec{F}_{\text{net}} = \dfrac{\Delta \vec{p}}{\Delta t}$
  • 4.2.A.2 Impulse is defined as the product of the average force exerted on a system and the time interval during which that force is exerted on the system.
    • Equation: $\vec{J} = \vec{F}_{\text{avg}} \Delta t$
  • 4.2.A.3 Impulse is a vector quantity and has the same direction as the net force exerted on the system.
  • 4.2.A.4 The impulse delivered to a system by a net external force is equal to the area under the curve of a graph of the net external force exerted on the system as a function of time.
  • 4.2.A.5 The net external force exerted on a system is equal to the slope of a graph of the momentum of the system as a function of time.

4.2.B
Describe the relationship between the impulse exerted on an object or a system and the change in momentum of the object or system.

  • 4.2.B.1 Change in momentum is the difference between a system's final momentum and its initial momentum.
    • Equation: $\Delta \vec{p} = \vec{p} - \vec{p}_0$
  • 4.2.B.2 The impulse–momentum theorem relates the impulse exerted on a system and the system's change in momentum.
    • Equation: $\vec{J} = \vec{F}_{\text{avg}} \Delta t = \Delta \vec{p}$
  • 4.2.B.3 Newton's second law of motion is a direct result of the impulse–momentum theorem applied to systems with constant mass.
    • Equation: $\vec{F}_{\text{net}} = \dfrac{\Delta \vec{p}}{\Delta t} = m\dfrac{\Delta \vec{v}}{\Delta t} = m\vec{a}$

Boundary statement: AP Physics 1 does not require students to quantitatively analyze systems in which the mass of the system changes with respect to time.

来源:美国大学理事会 AP 课程与考试说明

一个合力随时间作用改变动量。传递的冲量(impulse)是

$$\vec{J}=\vec{F}\,\Delta t=\Delta\vec{p}.$$
这是冲量-动量定理(impulse–momentum theorem):冲量等于动量的变化。在一个力-时间图上,冲量是曲线下的面积。它解释为什么气囊和随挥有帮助——把同样的动量变化分散到一个更长的时间减少力。

冲量是力-时间曲线下的面积,等于平均力乘接触时间
冲量是力-时间曲线下的面积,等于平均力乘接触时间

Worked example. 一个 $0.15\ \text{kg}$ 的球以 $20\ \text{m/s}$ 撞墙并以 $15\ \text{m/s}$ 直接弹回。接触持续 $0.020\ \text{s}$。求球上的平均力。取反弹方向为正,所以 $u=-20\ \text{m/s}$$v=+15\ \text{m/s}$:

$$\Delta p=m(v-u)=0.15\big(15-(-20)\big)=5.25\ \text{kg m/s},\qquad F=\frac{\Delta p}{\Delta t}=\frac{5.25}{0.020}=260\ \text{N}.$$
符号工作重要:忘记速度反转是这里最常见的错误。

词汇表 训练
英文 中文 拼音
impulse 冲量 chōng liàng
4.3

线动量守恒

大纲
Learning ObjectiveEssential Knowledge

4.3.A
Describe the behavior of a system using conservation of linear momentum.

  • 4.3.A.1 A collection of objects with individual momenta can be described as one system with one center-of-mass velocity.
    • 4.3.A.1.i For a collection of objects, the velocity of a system's center of mass can be calculated using the equation $\vec{v}_{\text{cm}} = \dfrac{\sum \vec{p}_i}{\sum m_i} = \dfrac{\sum m_i \vec{v}_i}{\sum m_i}$.
    • 4.3.A.1.ii The velocity of a system's center of mass is constant in the absence of a net external force.
  • 4.3.A.2 The total momentum of a system is the sum of the momenta of the system's constituent parts.
  • 4.3.A.3 In the absence of net external forces, any change to the momentum of an object within a system must be balanced by an equivalent and opposite change of momentum elsewhere within the system. Any change to the momentum of a system is due to a transfer of momentum between the system and its surroundings.
    • 4.3.A.3.i The impulse exerted by one object on a second object is equal and opposite to the impulse exerted by the second object on the first. This is a direct result of Newton's third law.
    • 4.3.A.3.ii A system may be selected so that the total momentum of that system is constant.
    • 4.3.A.3.iii If the total momentum of a system changes, that change will be equivalent to the impulse exerted on the system.
      • Equation: $\vec{J} = \Delta \vec{p}$
  • 4.3.A.4 Correct application of conservation of momentum can be used to determine the velocity of a system immediately before and immediately after collisions or explosions.

Boundary statement: AP Physics 1 includes a quantitative and qualitative treatment of conservation of momentum in one dimension and a semiquantitative treatment of conservation of momentum in two dimensions. Exam questions involving solution of simultaneous equations are not included in AP Physics 1, but the AP Physics 1 Exam may include questions that assess whether students can set up the equations properly and reason about how changing a given mass, speed, or angle would affect other quantities. AP Physics 2 includes a full treatment of conservation of momentum in two dimensions for problems that include one unknown final velocity.

4.3.B
Describe how the selection of a system determines whether the momentum of that system changes.

  • 4.3.B.1 Momentum is conserved in all interactions.
  • 4.3.B.2 If the net external force on the selected system is zero, the total momentum of the system is constant.
  • 4.3.B.3 If the net external force on the selected system is nonzero, momentum is transferred between the system and the environment.

来源:美国大学理事会 AP 课程与考试说明

若一个系统上的合外力是零,它的总动量守恒(conserved):

$$\sum \vec{p}_{\text{before}}=\sum \vec{p}_{\text{after}}.$$
内力(像两个碰撞的小车之间的推力)成第三定律对而抵消,所以它们不能改变总动量。这是碰撞(collisions)和爆炸的关键工具——在 $x$$y$ 方向分别应用它。

一个正面碰撞:之前的总动量等于之后的总动量
一个正面碰撞:之前的总动量等于之后的总动量

Worked example (recoil 反冲). 一个 $60\ \text{kg}$ 的滑冰者,最初在无摩擦冰上静止,以 $8.0\ \text{m/s}$ 抛一个 $2.0\ \text{kg}$ 的球。求她的反冲速率。总动量从零开始并保持零:

$$0=(60)v+(2.0)(8.0)\;\Rightarrow\;v=-\frac{16}{60}=-0.27\ \text{m/s},$$
所以她以 $0.27\ \text{m/s}$ 向球相反的方向移动——火箭和枪背后的原理。

一整个物体集合能用单一的质心速度(center-of-mass velocity)描述:

$$\vec{v}_{\text{cm}}=\frac{\sum m_i\vec{v}_i}{\sum m_i}=\frac{\vec{p}_{\text{total}}}{M_{\text{total}}}.$$
因为在没有净外力作用时总动量守恒,$\vec{v}_{\text{cm}}$ 于是保持恒定——一张 $v_{\text{cm}}$ 对时间的图是平的,除非有外部力作用。一次内部碰撞或爆炸从不改变它,无论碎片飞得多猛烈。

探索

Collide two carts and conserve momentum

In any collision the total momentum $\sum mv$ before equals the total after. Set the masses and speeds and check the momentum bookkeeping.

词汇表 训练
英文 中文 拼音
conserved 守恒 shǒu héng
collisions 碰撞 pèng zhuàng
center-of-mass velocity 质心速度 zhì xīn sù dù
recoil 反冲 fǎn chōng
4.4

弹性碰撞与非弹性碰撞

大纲
Learning ObjectiveEssential Knowledge

4.4.A
Describe whether an interaction between objects is elastic or inelastic.

  • 4.4.A.1 An elastic collision between objects is one in which the initial kinetic energy of the system is equal to the final kinetic energy of the system.
  • 4.4.A.2 In an elastic collision, the final kinetic energies of each of the objects within the system may be different from their initial kinetic energies.
  • 4.4.A.3 An inelastic collision between objects is one in which the total kinetic energy of the system decreases.
  • 4.4.A.4 In an inelastic collision, some of the initial kinetic energy is not restored to kinetic energy but is transformed by nonconservative forces into other forms of energy.
  • 4.4.A.5 In a perfectly inelastic collision, the objects stick together and move with the same velocity after the collision.

来源:美国大学理事会 AP 课程与考试说明

碰撞中的动量守恒

动量在每个碰撞里守恒(没有外力)。动能不守恒:

一个掠射碰撞,沿两个垂直坐标轴分解
一个掠射碰撞,沿两个垂直坐标轴分解
  • 在一个弹性碰撞(elastic collision)里,动能守恒(物体干净地弹开)。
  • 在一个非弹性碰撞(inelastic collision)里,一些动能变成热或形变。在一个完全非弹性碰撞里物体粘在一起并之后以一个共同速度移动。

策略:总是写动量守恒;只在碰撞被陈述为弹性时加能量守恒。一个值得记住的弹性事实:在相等质量之间的一个一维弹性碰撞里,这两个物体简单地交换速度(一个移动的球撞一个相同的静止的停死,而目标以进入的速率飞走)。

Worked example. 一辆 $1000\ \text{kg}$$20\ \text{m/s}$ 移动的车撞进一辆静止的 $1500\ \text{kg}$ 的车而它们锁在一起。求它们的共同速率,和损失的动能。动量守恒给出

$$1000\times20=(1000+1500)\,v\;\Rightarrow\;v=\frac{20000}{2500}=8.0\ \text{m/s}.$$
之前的动能是 $\tfrac12(1000)(20^2)=2.0\times10^{5}\ \text{J}$;之后是 $\tfrac12(2500)(8.0^2)=8.0\times10^{4}\ \text{J}$。所以 $1.2\times10^{5}\ \text{J}$(约 $60\%$)损失给撞皱和热——动量仍然守恒,但动能不守恒。

探索

Compare elastic and inelastic collisions

Momentum is always conserved, but kinetic energy is only conserved in an elastic collision. In an inelastic one the carts stick and some energy becomes heat.

词汇表 训练
英文 中文 拼音
elastic collision 弹性碰撞 tán xìng pèng zhuàng
inelastic collision 非弹性碰撞 fēi tán xìng pèng zhuàng
练习卷
4.4

考试技巧

  • 动量是一个矢量——在相加之前分配 $+$/$-$ 符号;一个反弹的球反转它的速度,给出一个大的 $\Delta p$
  • 动量在每个碰撞里守恒(没有外力);动能在碰撞被陈述为弹性时守恒。
  • 在一个完全非弹性碰撞里物体粘住并以一个共同速度移动。
  • 冲量 $=F\,\Delta t=\Delta p$ = 一个力-时间图下的面积;把一个碰撞分散到一个更长的时间减少力(气囊、弯膝)。
  • 对反冲/爆炸,把之前和之后的总动量设为相等(之前常常是零)。

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