| Learning Objective | Essential Knowledge |
|---|---|
8.1.A |
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Fluids
AP Physics 1 · Topic 8
8.1
Internal Structure and Density
Syllabus
Source: College Board AP Course and Exam Description
The differences between solids, liquids, and gases come from how strongly their particles interact. A fluid 流体 (liquid or gas) has no fixed shape – it flows because its particles move past one another. Density 密度 is mass per unit volume:
Float or sink by density
An object floats if it is less dense than the fluid. Change the density and watch it ride higher or sink, displacing its own weight of fluid.
| English | Chinese | Pinyin |
|---|---|---|
| fluid | 流体 | liú tǐ |
| Density | 密度 | mì dù |
| ideal fluid | 理想流体 | lǐ xiǎng liú tǐ |
| incompressible | 不可压缩 | bù kě yā suō |
| viscosity | 黏度 | nián dù |
8.2
Pressure
Syllabus
| Learning Objective | Essential Knowledge |
|---|---|
8.2.A |
|
8.2.B |
|
Source: College Board AP Course and Exam Description
Pressure 压强 is the perpendicular force per unit area, a scalar 标量 measured in pascals (Pa):
Distinguish the two pressures AP asks about: the gauge pressure 表压 is the extra pressure the fluid column adds, $P_{\text{gauge}}=\rho g h$, while the absolute pressure 绝对压强 is the total, $P=P_0+P_{\text{gauge}}$ (with $P_0$ usually atmospheric). A tyre gauge reading "$200\ \text{kPa}$" is gauge pressure; the air inside is really at about $300\ \text{kPa}$ absolute.
The weight of a liquid column sets the extra pressure at a depth
Worked example. Find the total pressure on a diver $10\ \text{m}$ below the surface of water ($\rho=1000\ \text{kg/m}^3$, surface pressure $P_0=1.0\times10^{5}\ \text{Pa}$):
An aneroid barometer measures air pressure with a sealed metal box that flexes as the pressure outside changes
| English | Chinese | Pinyin |
|---|---|---|
| Pressure | 压强 | yā qiáng |
| scalar | 标量 | biāo liàng |
| depth | 深度 | shēn dù |
| gauge pressure | 表压 | biǎo yā |
| absolute pressure | 绝对压强 | jué duì yā qiáng |
8.3
Fluids and Newton's Laws
Syllabus
| Learning Objective | Essential Knowledge |
|---|---|
8.3.A |
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8.3.B |
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Source: College Board AP Course and Exam Description
An object in a fluid feels an upward buoyant force 浮力 equal to the weight of the fluid it displaces – Archimedes' principle 阿基米德原理:
Worked example. A block of density $600\ \text{kg/m}^3$ floats in water ($1000\ \text{kg/m}^3$). What fraction is under the surface? For floating, the buoyant force equals the weight, so $\rho_{\text{fluid}}\,g\,V_{\text{sub}}=\rho_{\text{object}}\,g\,V$:
| English | Chinese | Pinyin |
|---|---|---|
| buoyant force | 浮力 | fú lì |
| Archimedes' principle | 阿基米德原理 | ā jī mǐ dé yuán lǐ |
8.4
Fluids and Conservation Laws
Syllabus
| Learning Objective | Essential Knowledge |
|---|---|
8.4.A |
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Source: College Board AP Course and Exam Description
For an ideal fluid flowing steadily, two conservation ideas apply:
Upthrust arises because the pressure on the bottom of an object exceeds that on the top
- Continuity 连续性 (conservation of mass): the volume flow rate is constant, so $A_1 v_1 = A_2 v_2$. A narrower pipe forces faster flow.
- Bernoulli's equation 伯努利方程 (conservation of energy per volume): along a streamline,
$$P+\tfrac{1}{2}\rho v^2+\rho g y = \text{constant}.$$
Together they explain why fluid speeds up and its pressure drops where a pipe narrows or where flow is fastest.
Where the pipe narrows the fluid speeds up (continuity) and its pressure drops (Bernoulli)
Worked example. Water flows at $2.0\ \text{m/s}$ through a pipe of cross-section $0.010\ \text{m}^2$, then enters a narrower section of $0.0040\ \text{m}^2$. By continuity the speed there is
Exam skill. Choose the right law by what changes. If the pipe changes width, start with continuity ($A_1v_1=A_2v_2$) to get the speeds; if you then need a pressure, feed those speeds into Bernoulli. Watch the height term $\rho g y$ only when the pipe also changes level.
| English | Chinese | Pinyin |
|---|---|---|
| Continuity | 连续性 | lián xù xìng |
| Bernoulli's equation | 伯努利方程 | bó nǔ lì fāng chéng |
8.4
Exam tips
- Pressure with depth is $P=P_0+\rho g h$ — it depends on depth only, not the container's shape or width.
- Buoyant force = weight of fluid displaced ($\rho_{\text{fluid}}\,gV_{\text{disp}}$); a floating object displaces its own weight, so the fraction submerged is $\rho_{\text{object}}/\rho_{\text{fluid}}$.
- Compare densities to predict floating vs sinking; a floating object is in equilibrium (buoyancy = weight), not weightless.
- Use continuity $A_1v_1=A_2v_2$: a narrower pipe means faster flow.
- Bernoulli: where a fluid flows faster its pressure is lower (wing lift, spray).