学习目标 9.1.A: 描述系统的电势能。
- 9.1.A.1 两个点电荷组成的系统的电势能等于外力将这两个点电荷从无穷远处移至当前位置所做的功。
- 9.1.A.2 两个带电物体之间的电势能的一般形式由以下方程给出:
- 公式: $U_E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{q_1 q_2}{r} = k\dfrac{q_1 q_2}{r}$。
- 9.1.A.3 系统的总电势能可以通过求系统中每对带电物体之间相互作用的电势能之和来确定。
AP 物理 C:电磁学 · 知识点 9
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电势
看看这些数字。一节小电池标着一点五伏。汽车电池标着十二伏。高压输电线承载四十万伏。一…
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学习目标 9.1.A: 描述系统的电势能。
来源:College Board AP 课程与考试说明
When you push two like charges together, you do work 功 against the electric force. That work is stored by the pair as electric potential energy 电势能:
$U_E$ is defined as the work an external force must do to bring the charges from infinitely far away to a distance $r$ apart. The signs carry the physics:
The electric force is a conservative force 保守力: the work it does depends only on the start and end points, not the path, and equals $-\Delta U_E$.
For a system 系统 of several charges, add the potential energy of every distinct pair:
Worked example. Three $+2.0\ \mu\text{C}$ charges sit at the corners of an equilateral triangle with sides $0.30\ \text{m}$. Each pair stores $U=\dfrac{kq^2}{r}=\dfrac{(9.0\times10^{9})(2.0\times10^{-6})^2}{0.30}=0.12\ \text{J}$. There are three pairs, so $U_{\text{total}}=3\times0.12\ \text{J}=0.36\ \text{J}$. This is the work needed to assemble the triangle from infinity – and the kinetic energy the charges would share if all three were released.
两个电荷的电势能随它们之间距离的倒数而衰减。
| English | 中文 | 拼音 |
|---|---|---|
| work/wɜːk/ | 功 | gōng |
| electric potential energy/ɪˈlektrɪk pəˈtenʃl ˈenədʒi/ | 电势能 | diàn shì néng |
| kinetic energy/kɪˈnetɪk ˈenədʒi/ | 动能 | dòng néng |
| conservative force/kənˈsɜːvətɪv fɔːs/ | 保守力 | bǎo shǒu lì |
| system/ˈsɪstəm/ | 系统 | xì tǒng |
学习目标 9.2.A: 描述带电物体系统产生的电势。
边界说明: AP物理C:电磁学仅要求学生使用微积分计算以下电荷分布及位置所产生的电势:距无限长均匀带电导线或圆柱体中心轴一定距离处的点、位于圆环轴线上某点的薄带电圆环、半圆弧或其一部分圆心处的点,以及与线电荷共线的点或位于其垂直平分线上的有限长导线或线电荷。
学习目标 9.2.B: 描述电势与电场之间的关系。
来源:College Board AP 课程与考试说明
Electric potential 电势 is electric potential energy per unit charge at a point in space. It is measured in volts ($1\ \text{V}=1\ \text{J/C}$):
Potential is a scalar 标量: it has a sign but no direction. This makes $V$ far easier to work with than the field $\vec{E}$. For several point charges 点电荷, use scalar superposition 叠加 – add the potentials with their signs:
Worked example. The potential $0.10\ \text{m}$ from a $+3.0\ \text{nC}$ point charge is $V=\dfrac{kq}{r}=\dfrac{9.0\times10^{9}(3.0\times10^{-9})}{0.10}=270\ \text{V}$. Now add a $-3.0\ \text{nC}$ charge $0.30\ \text{m}$ from the same point: it contributes $\dfrac{9.0\times10^{9}(-3.0\times10^{-9})}{0.30}=-90\ \text{V}$, so the total is $270-90=180\ \text{V}$. Just a signed sum – no vector components to resolve.
For a continuous charge distribution 连续电荷分布, cut it into small pieces $dq$, treat each piece as a point charge, and integrate 积分:
This is a scalar integral, so it is usually much easier than the field integral. AP expects you to handle four shapes with calculus: a thin ring (at a point on its axis), an arc (at its centre), a finite line or wire (collinear, or on its perpendicular bisector), and an infinitely long wire or cylinder (at a distance from its axis).

Worked example (ring of charge). A thin ring of radius $R$ carries total charge $Q$. For a point $P$ on the axis a distance $z$ from the centre, every element $dq$ sits at the same distance $r=\sqrt{R^2+z^2}$ from $P$. The distance is constant, so it comes out of the integral:
On an FRQ, say that $r$ is the same for every element – that statement is the marked step. The same idea gives $V=kQ/R$ at the centre of any arc, whatever its angle.
Potential and field contain the same information, linked by a derivative in each direction and by a path integral:
The field is the negative gradient 梯度 of the potential: $\vec{E}$ points from high potential to low potential, "downhill". Where $V$ changes quickly, the field is strong.
Worked example. Along the $x$-axis, $V(x)=3x^{2}-2x$ (volts, with $x$ in metres). Then $E_x=-\dfrac{dV}{dx}=2-6x\ \text{V/m}$. At $x=0.50\ \text{m}$, $E_x=-1.0\ \text{V/m}$: the field there points in the $-x$ direction.

The potential difference 电势差 between two points is the change in potential energy per unit charge moved between them: $\Delta V=\Delta U_E/q$. A battery makes a potential difference chemically: reactions inside separate positive from negative charge and hold the terminals a fixed $\Delta V$ apart.

An equipotential 等势面 surface contains points that share the same potential; its intersection with a map appears as an isoline 等值线. Four rules let you read any map:

Exam skill. Given a map with isolines every $10\ \text{V}$ spaced about $2\ \text{cm}$ apart, estimate $E\approx\dfrac{10}{0.02}=500\ \text{V/m}$, pointing from the higher-value line to the lower one. The work an external agent does moving a charge $q$ slowly from $A$ to $B$ is $W=q(V_B-V_A)$ – the path taken does not matter.

电势是单位电荷的能量。它随距正电荷的距离增加而降低;电场线从高电势指向低电势。
| English | 中文 | 拼音 |
|---|---|---|
| Electric potential/ɪˈlektrɪk pəˈtenʃl/ | 电势 | diàn shì |
| scalar/ˈskeɪlə/ | 标量 | biāo liàng |
| point charges/pɔɪnt ˈtʃɑːdʒɪz/ | 点电荷 | diǎn diàn hè |
| superposition/ˌsuːpəpəˈzɪʃn/ | 叠加 | dié jiā |
| continuous charge distribution/kənˈtɪnjuːəs tʃɑːdʒ ˌdɪstrɪˈbjuːʃn/ | 连续电荷分布 | lián xù diàn hè fēn bù |
| integrate/ˈɪntɪɡreɪt/ | 积分 | jī fēn |
| gradient/ˈɡreɪdɪənt/ | 梯度 | tī dù |
| potential difference/pəˈtenʃl ˈdɪfrəns/ | 电势差 | diàn shì chā |
| equipotential/ˌiːkwɪpəˈtenʃl/ | 等势面 | děng shì miàn |
| isoline/ˈaɪsəliːn/ | 等值线 | děng zhí xiàn |
| perpendicular/ˌpɜːpənˈdɪkjʊlə/ | 垂直 | chuí zhí |
| field lines/fiːld laɪnz/ | 电场线 | diàn chǎng xiàn |
学习目标 9.3.A: 描述由于两个位置之间电势差而引起的系统变化。
来源:College Board AP 课程与考试说明
When a charge $q$ moves between two points that differ in potential by $\Delta V$, the potential energy of the charge–field system changes by
If only the electric force acts, total energy is conserved, so the kinetic energy changes by the opposite amount:
Watch the two signs together: a positive charge speeds up when it moves to lower potential, while a negative charge speeds up when it moves to higher potential. Both are just the system trading potential energy for kinetic energy. This is how particle accelerators give charged particles their energy, and it underlies energy analysis in circuits.
Worked example. A proton ($q=1.6\times10^{-19}\ \text{C}$, $m=1.67\times10^{-27}\ \text{kg}$) starts at rest and is accelerated through a potential drop of $500\ \text{V}$ (it moves to lower potential, so $\Delta V=-500\ \text{V}$ and $\Delta K=-q\,\Delta V=+8.0\times10^{-17}\ \text{J}$). Setting $\Delta K=\tfrac12 mv^2$:
Exam skill. Choose energy methods, not kinematics, whenever the field is non-uniform or the path curves: only the end-point potentials matter. A typical FRQ chain is $q\,\Delta V \to \Delta K \to v$, with one line of justification: "the electric force is conservative, so energy is conserved."
电荷在电场中运动时,能量在动能和势能之间转换。对每种情况进行分类。
逐步完成,配合即时检查练习。
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