跳到主要内容

含氮化合物

A-Level 化学 · 知识点 34

本主题的视频课程 打开视频页面
7:49

氮化合物

看看三件截然不同的东西。一种甜的、染成亮橙色的东西。一片止痛药片。以及你肌肉中的蛋白质。它们几乎没有共同点——除了一个……

英语旁白 · 英中内嵌字幕

34.1

伯胺与仲胺

教学大纲
  1. 回忆通过以下反应(包括试剂和条件)制备伯胺和仲胺的方法:(a) 卤代烷与乙醇中的 $\text{NH}_3$ 在加压下加热反应;(b) 卤代烷与伯胺在乙醇中于密封管/加压条件下加热反应;(c) 用 $\text{LiAlH}_4$ 还原酰胺;(d) 用 $\text{LiAlH}_4$ 或 $\text{H}_2/\text{Ni}$ 还原腈。
  2. 描述氨或胺在室温下与酰氯发生的缩合反应,生成酰胺。
  3. 描述并解释胺的水溶液的碱性。

来源:Cambridge International 教学大纲

English

An amine 胺 has an $\text{–NH}_2$ (primary) or $\text{–NH}$ (secondary) group.

A primary amine has -NH2; a secondary amine has -NH between two carbons
A primary amine has -NH2; a secondary amine has -NH-

Making amines

  • a halogenoalkane 卤代烷 with $\text{NH}_3$ in ethanol, heated under pressure → a primary amine.
  • a halogenoalkane with a primary amine, heated under pressure → a secondary amine.
  • reduction 还原 of an amide 酰胺 with $\text{LiAlH}_4$.
  • reduction of a nitrile 腈 with $\text{LiAlH}_4$ or $\text{H}_2/\text{Ni}$.
Two routes: a halogenoalkane with ammonia, or reducing a nitrile
Two routes to an amine: from a halogenoalkane, or by reducing a nitrile

An amine (or ammonia 氨) reacts with an acyl chloride in a condensation 缩合 reaction to give an amide. The reagent is an acyl chloride 酰氯.

Basicity of amines

The basicity 碱性 of an amine comes from the lone pair on its nitrogen, which can accept an $\text{H}^+$ from water.

探索

胺类型实验室

按氮上的取代和碱性行为分类胺。

词汇 训练
English 中文 拼音
amine/ˈæmaɪn/ 胺 àn
halogenoalkane/ˈheɪləʊdʒnəʊlkeɪn/ 卤代烷 lǔ dài wán
reduction/rɪˈdʌkʃn/ 还原 huán yuán
amide/əˈmaɪd/ 酰胺 xiān àn
nitrile/ˈnaɪtraɪl/ 腈 jīng
ammonia/æˈməʊnɪə/ 氨 ān
condensation/kɒndenˈseɪʃn/ 缩合 suō hé
acyl chloride/əˈkɪl ˈklɔːraɪd/ 酰氯 xiān lǜ
basicity/beɪˈsɪsɪti/ 碱性 jiǎn xìng
34.2

苯胺与偶氮化合物

教学大纲
  1. 描述通过以下步骤制备苯胺:苯经硝化生成硝基苯,随后用热的 Sn/浓 $\text{HCl}$ 还原,最后加入 $\text{NaOH(aq)}$。
  2. 描述以下内容:(a) 苯胺在室温下与 $\text{Br}_2\text{(aq)}$ 的反应;(b) 苯胺在低于 $10\text{ }^\circ\text{C}$ 的条件下与 $\text{HNO}_2$ 或 $\text{NaNO}_2$ 及稀酸反应生成重氮盐;将重氮盐进一步加热并与 $\text{H}_2\text{O}$ 反应生成苯酚。
  3. 描述并解释水合氨、乙胺和苯胺的相对碱性。
  4. 回顾关于偶氮化合物的以下知识:(a) 描述氯化苯重氮盐在 $\text{NaOH(aq)}$ 中与苯酚发生偶联反应生成偶氮化合物的过程;(b) 识别偶氮基团;(c) 说明偶氮化合物常被用作染料;(d) 其他偶氮染料也可通过类似的途径制得。

来源:Cambridge International 教学大纲

English

Making phenylamine

Make phenylamine 苯胺 from benzene in two steps: nitrate benzene to nitrobenzene, then reduce it with hot $\text{Sn}$ and concentrated $\text{HCl}$, followed by $\text{NaOH(aq)}$.

Reactions

  • with bromine water at room temperature → 2,4,6-tribromophenylamine (a white precipitate). The ring is activated, like phenol.
  • with $\text{HNO}_2$ (from $\text{NaNO}_2$ and dilute acid) below $10\,°\text{C}$ → a diazonium salt; warming this with water gives phenol.

Relative basicity

$$\text{phenylamine} < \text{ammonia} < \text{ethylamine}$$

Ethylamine is the strongest base: its alkyl group pushes electron density onto the nitrogen, making the lone pair more available. Phenylamine is the weakest, because its lone pair is delocalised 离域 into the benzene ring, so it is less available to accept an $\text{H}^+$.

Phenylamine, ammonia and ethylamine along a basicity scale, with the ring pulling the lone pair away in phenylamine and the alkyl group pushing electrons in ethylamine
Basicity depends on the nitrogen lone pair: an alkyl group makes it more available (ethylamine strongest), a benzene ring pulls it away (phenylamine weakest)

Azo compounds

A diazonium salt 重氮盐 (benzenediazonium chloride) couples with phenol 苯酚 in $\text{NaOH(aq)}$ to form an azo compound 偶氮化合物. The azo group is $\text{–N=N–}$. Azo compounds are brightly coloured and are often used as dyes 染料; many other azo dyes are made the same way.

A small pile of bright orange methyl orange dye powder on a pale background
Methyl orange, a bright orange azo dye; the strong colour comes from the $\text{–N=N–}$ azo group, which is why azo compounds are so widely used as dyes

Worked example. An amino acid has an isoelectric point of pH 6.0. Give its charge, and the electrode it moves towards in electrophoresis, at pH 2, at pH 6.0 and at pH 11. Compare the solution's pH with the isoelectric point each time. At pH 2, well below it, the solution is acidic, so the $\text{–NH}_2$ gains an $\text{H}^{+}$: the amino acid is positive and moves to the cathode (negative electrode). At pH 6.0, exactly its isoelectric point, it is the zwitterion with no net charge, so it does not move. At pH 11, well above it, the $\text{–COOH}$ loses its $\text{H}^{+}$: the amino acid is negative and moves to the anode. Compare the pH with the isoelectric point, never with 7 - and note the zwitterion still carries both charges, it simply has no net charge.

探索

苯胺到偶氮染料途径

跟随苯胺从重氮化到有色偶氮化合物。

词汇 训练
English 中文 拼音
phenylamine/ˌfiːˈnaɪləmiːn/ 苯胺 běn àn
delocalised/dɪˈlɒkəlaɪzd/ 离域 lí yù
diazonium salt/ˌdaɪəˈzəʊnɪəm sɒlt/ 重氮盐 zhòng dàn yán
phenol/ˈfenɒl/ 苯酚 běn fēn
azo compound/ˈɑːzəʊ ˈkɒmpaʊnd/ 偶氮化合物 ǒu dàn huà hé wù
dye/daɪ/ 染料 rǎn liào
34.3

酰胺

教学大纲
  1. 回忆制备酰胺的反应(试剂和条件):(a) 氨与酰氯在室温下的反应;(b) 伯胺与酰氯在室温下的反应
  2. 描述酰胺的反应:(a) 用氢氧化水溶液或酸水溶液进行水解;(b) 使用 $\text{LiAlH}_4$ 还原酰胺中的 CO 基团以生成胺
  3. 陈述并解释为什么酰胺是比胺弱得多的碱

来源:Cambridge International 教学大纲

English

An amide is made from ammonia or a primary amine with an acyl chloride at room temperature.

A bottle of paracetamol tablets
Paracetamol is a common painkiller that contains the amide group (–CONH–)

Its reactions:

  • hydrolysis with aqueous acid or alkali, giving the carboxylic acid (or its salt) and the amine (or ammonium).
  • reduction of the C=O group with $\text{LiAlH}_4$ to give an amine.

An amide is a much weaker base than an amine, because the nitrogen lone pair is delocalised onto the neighbouring C=O group, so it is not available to accept an $\text{H}^+$.

探索

酰胺形成途径

跟随酰氯或酸衍生物到一个酰胺。

34.4

氨基酸

教学大纲
  1. 描述氨基酸的酸/碱性质及两性离子的形成,包括等电点
  2. 描述氨基酸之间形成酰胺(肽)键以生成二肽和三肽的过程
  3. 解释和预测不同pH值下氨基酸和二肽混合物的电泳结果(不测试装置的组装)

来源:Cambridge International 教学大纲

English

An amino acid 氨基酸 has both a basic $\text{–NH}_2$ group and an acidic $\text{–COOH}$ group.

Zwitterions and the isoelectric point

The $\text{–COOH}$ can give its $\text{H}^+$ to the $\text{–NH}_2$ in the same molecule, forming a zwitterion 两性离子 ($\text{H}_3\text{N}^+\text{–CHR–COO}^-$) — an ion with both a positive and a negative end but no overall charge.

  • in acid (low pH), the amino acid gains $\text{H}^+$ and becomes positive.
  • in alkali (high pH), it loses $\text{H}^+$ and becomes negative.
  • at one special pH, the isoelectric point 等电点, it is mostly the zwitterion with no net charge.
An amino acid drawn three ways: positively charged in acid, a neutral zwitterion at the isoelectric point, and negatively charged in alkali
An amino acid's charge depends on pH: positive in acid, the neutral zwitterion at the isoelectric point, negative in alkali

Peptide bonds

Two amino acids join in a condensation reaction: the $\text{–COOH}$ of one and the $\text{–NH}_2$ of the other react, losing water and forming a peptide bond 肽键 (an amide link). Two amino acids give a dipeptide 二肽, three give a tripeptide.

Two amino acids condensing: the OH from one carboxyl and the H from the other amino group leave as water, forming a peptide bond
Two amino acids condense: the –OH from one –COOH and the –H from the other –NH$_2$ leave as water, forming the peptide (amide) bond

Electrophoresis

In electrophoresis 电泳, a mixture is placed in an electric field at a chosen pH:

  • above its isoelectric point, an amino acid is negative and moves to the positive electrode.
  • below its isoelectric point, it is positive and moves to the negative electrode.
  • at its isoelectric point, it does not move. So different amino acids separate.
A gel strip with a negative and a positive electrode: a positive amino acid moves towards the negative electrode, a negative one towards the positive, and a neutral one stays put
Electrophoresis at a chosen pH: a positive amino acid moves to the negative electrode, a negative one to the positive, and a neutral one stays — so they separate

Common mistakes.

  • Saying phenylamine is a stronger base than ethylamine because "the ring donates electrons". The opposite is true: the nitrogen lone pair is delocalised into the ring, so it is less available for $\text{H}^+$, and phenylamine is the weakest of the three.
  • Calling an amide basic like an amine. In an amide the lone pair is delocalised onto the C=O group, so amides are essentially neutral.
  • Making the diazonium salt above $10\,°\text{C}$. The diazonium ion decomposes on warming, giving phenol and nitrogen gas, so keep it below $10\,°\text{C}$ until it is coupled.
  • Coupling with phenol in acid. The coupling is done in alkaline solution ($\text{NaOH(aq)}$), where the phenoxide ion is more strongly activated.
  • Using ammonia alone to make a pure primary amine. The primary amine formed is itself a nucleophile and reacts further, so a large excess of ammonia is needed to favour the primary amine.
  • Sending an amino acid the wrong way in electrophoresis. Below its isoelectric point it is positive and moves to the cathode; above it, negative, it moves to the anode.
  • Drawing a zwitterion as an uncharged amino acid. The zwitterion is $\text{H}_3\text{N}^+\text{–CHR–COO}^-$: both groups are ionised, but the overall charge is zero.
探索

氨基酸实验室

按反应的基团分类氨基酸的行为。

词汇 训练
English 中文 拼音
amino acid/əˈmiːnəʊ ˈæsɪd/ 氨基酸 ān jī suān
zwitterion/zwɪˈtɪərɪən/ 两性离子 liǎng xìng lí zi
isoelectric point/ˌaɪsəʊˈlektrɪk pɔɪnt/ 等电点 děng diàn diǎn
peptide bond/ˈpeptaɪd bɒnd/ 肽键 tài jiàn
dipeptide/ˈdaɪpptaɪd/ 二肽 èr tài
electrophoresis/ɪˌlektrəʊfɔːˈriːsɪs/ 电泳 diàn yǒng
34.4

考试技巧

English
  • Phenylamine is a weaker base than aliphatic amines because the N lone pair delocalises into the ring.
  • Diazotisation ($\text{NaNO}_2$/HCl, below $10\ ^\circ\text{C}$) then coupling gives azo dyes — learn the conditions and the coloured product.
  • Amino acids are zwitterions (both $-\text{NH}_2$ and $-\text{COOH}$), so they are amphoteric; describe behaviour either side of the isoelectric point.

该知识点的互动课程

逐步完成,配合即时检查练习。

历年真题

更多 A-Level 化学 知识点

登录或创建账户

IGCSE, A-Level & AP