- describe the formation of polyesters: (a) the reaction between a diol and a dicarboxylic acid or dioyl chloride (b) the reaction of a hydroxycarboxylic acid
- describe the formation of polyamides: (a) the reaction between a diamine and a dicarboxylic acid or dioyl chloride (b) the reaction of an aminocarboxylic acid (c) the reaction between amino acids
- deduce the repeat unit of a condensation polymer obtained from a given monomer or pair of monomers
- identify the monomer(s) present in a given section of a condensation polymer molecule
Polymerisation
A-Level Chemistry · Topic 35
35.1
Condensation polymerisation
Syllabus
Source: Cambridge International syllabus
In condensation polymerisation 缩合聚合, monomers join into a long chain and a small molecule (such as water or $\text{HCl}$) is lost each time a new bond forms. Each monomer needs two reactive groups, so the chain can grow at both ends.
Condensation links: a polyester forms ester links and a polyamide forms amide links; each new link releases a small molecule (here water)
Polyesters
A polyester 聚酯 has many ester links along its chain. You can make one from:
- a diol 二醇 (two $\text{–OH}$ groups) and a dicarboxylic acid 二羧酸 (two $\text{–COOH}$ groups), or a dioyl chloride.
- a single hydroxycarboxylic acid, which has both an $\text{–OH}$ and a $\text{–COOH}$.
PET drinks bottles are made of a polyester — a condensation polymer, collected here for recycling
Polyamides
A polyamide 聚酰胺 has many amide links. You can make one from:
- a diamine 二胺 (two $\text{–NH}_2$ groups) and a dicarboxylic acid or a dioyl chloride.
- a single aminocarboxylic acid, or from amino acids 氨基酸 joining together (proteins are natural polyamides).
The "nylon rope trick": nylon (a polyamide) forms where two reactant solutions meet, so a single long thread can be pulled out (it is pink here from an added indicator)
Repeat units and monomers
The repeat unit 重复单元 of a condensation polymer contains parts of both monomers, minus the atoms lost as the small molecule. To find the monomers 单体 from a section of polymer, break the chain at each ester or amide link, then add back $\text{–OH}$ and $\text{–H}$ (or $\text{–Cl}$).
To find the monomers, break the chain at each link and add back –OH and –H to the cut ends — here giving the diol and the dicarboxylic acid
Worked example. A polymer chain contains repeating $\text{–CONH–}$ links. Name the type of polymer, identify the monomers, and give the small molecule lost. A $\text{–CONH–}$ link is an amide, so this is a polyamide made by condensation polymerisation. To find the monomers, break the chain at each amide link and give the cut ends their atoms back: the carbon side takes $\text{–OH}$, making a dicarboxylic acid, and the nitrogen side takes $\text{–H}$, making a diamine. The small molecule lost at each link is water (or $\text{HCl}$, if an acyl dichloride was used in place of the acid). Each monomer must have two functional groups, or the chain could never keep growing - if the monomer you propose has only one, you have broken the chain in the wrong place.
Condensation polymer route
Watch monomers join while a small molecule leaves each time.
| English | Chinese | Pinyin |
|---|---|---|
| condensation polymerisation | 缩合聚合 | suō hé jù hé |
| polyester | 聚酯 | jù zhǐ |
| diol | 二醇 | èr chún |
| dicarboxylic acid | 二羧酸 | èr suō suān |
| polyamide | 聚酰胺 | jù xiān àn |
| diamine | 二胺 | èr àn |
| amino acid | 氨基酸 | ān jī suān |
| repeat unit | 重复单元 | chóng fù dān yuán |
| monomer | 单体 | dān tǐ |
35.2
Predicting the type of polymerisation
Syllabus
- predict the type of polymerisation reaction for a given monomer or pair of monomers
- deduce the type of polymerisation reaction which produces a given section of a polymer molecule
Source: Cambridge International syllabus
| Clue | Type |
|---|---|
| the monomer has a C=C double bond, and nothing else is lost | addition polymerisation 加成聚合 |
| each monomer has two functional groups, and a small molecule is lost; the chain has ester or amide links | condensation polymerisation |
The two kinds of polymerisation: addition opens a C=C and loses nothing; condensation joins two-group monomers and loses a small molecule
Polymerisation type lab
Classify monomers by whether they form addition or condensation polymers.
| English | Chinese | Pinyin |
|---|---|---|
| addition polymerisation | 加成聚合 | jiā chéng jù hé |
35.3
Degradable polymers
Syllabus
- recognise that poly(alkenes) are chemically inert and can therefore be difficult to biodegrade
- recognise that some polymers can be degraded by the action of light
- recognise that polyesters and polyamides are biodegradable by acidic and alkaline hydrolysis
Source: Cambridge International syllabus
- poly(alkene)s 聚烯烃 are chemically inert — they have only strong, non-polar C–C and C–H bonds, so they are hard to biodegrade 可生物降解 and last a long time.
- some polymers are made so that light can break them down (they are photodegradable).
- polyesters and polyamides are biodegradable, because their ester and amide links can be broken by acidic or alkaline hydrolysis 水解.
Degradable polymer route
Follow how polymer structure controls breakdown.
| English | Chinese | Pinyin |
|---|---|---|
| poly(alkene) | 聚烯烃 | jù xī tīng |
| biodegradable | 可生物降解 | kě shēng wù jiàng jiě |
| hydrolysis | 水解 | shuǐ jiě |
35.3
Exam tips
- Condensation polymers (polyesters, polyamides) form with loss of a small molecule ($\text{H}_2\text{O}$ or HCl) — draw the repeat unit and the lost molecule.
- Identify the monomers from the polymer by breaking the ester or amide link — a common question.
- Predict the type from the monomers: a $\text{C}=\text{C}$ gives addition; two functional groups give condensation.
- Polyesters and polyamides are hydrolysable (more degradable); addition polymers are not.