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Organic synthesis

A-Level Chemistry · Topic 36

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Organic synthesis (A2)

Three very different things: a bright orange dye, a painkiller, and a tough plastic. All three begin as the same colourless liquid — benzene. But no single…

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36.1

Organic synthesis

Syllabus
  1. for an organic molecule containing several functional groups: (a) identify organic functional groups using the reactions in the syllabus (b) predict properties and reactions
  2. devise multi-step synthetic routes for preparing organic molecules using the reactions in the syllabus
  3. analyse a given synthetic route in terms of type of reaction and reagents used for each step of it, and possible by-products

Source: Cambridge International syllabus

Like the AS synthesis topic, this asks you to join up known reactions to build a target molecule. Now you also have the A Level reactions of arenes, phenol, amines, amides and acyl chlorides.

Identifying functional groups

A molecule may carry several functional group 官能团 types. Use the test reactions to spot each one, then predict its behaviour. For example:

  • decolourises bromine water with no catalyst, giving a white precipitate → a phenol or a phenylamine (the ring is activated).
  • reacts violently with cold water, giving fumes of $\text{HCl}$ → an acyl chloride 酰氯.
  • gives a purple colour with neutral $\text{FeCl}_3$ → a phenol 苯酚.
A three-column table of A Level tests: bromine water with no catalyst, cold water, and neutral iron(III) chloride, with the observation and functional group for each
Identification tests added at A Level: each reagent gives a characteristic result that points to a functional group

A map of the A Level reactions

Start Reagent and conditions Product
benzene (an arene 芳烃) $\text{HNO}_3$ / $\text{H}_2\text{SO}_4$ (electrophilic substitution 亲电取代) nitrobenzene
nitrobenzene $\text{Sn}$ / conc $\text{HCl}$, then $\text{NaOH}$ (reduction 还原) phenylamine
phenylamine $\text{HNO}_2$, below $10\,°\text{C}$ a diazonium salt
diazonium salt warm water phenol; or couple with phenol → azo dye
methylbenzene hot $\text{KMnO}_4$ (oxidation 氧化) benzoic acid
carboxylic acid 羧酸 $\text{SOCl}_2$ or $\text{PCl}_5$ acyl chloride
acyl chloride alcohol / phenol an ester 酯
acyl chloride ammonia / amine 胺 an amide 酰胺
amide or nitrile 腈 $\text{LiAlH}_4$ an amine
halogenoalkane $\text{KCN}$ a nitrile (adds one carbon)
A network of A Level reactions: benzene to nitrobenzene to phenylamine to a diazonium salt to phenol or an azo dye, and a carboxylic acid to an acyl chloride to esters and amides
A map of the A Level reactions: the aromatic chain (top) and the acyl-chloride chain (bottom), with their feed-ins. Work backwards from your target

Planning and analysing a route

To devise a synthetic route 合成路线, work backwards from the target: which single reaction makes it, and from what? Repeat until you reach the starting material, then write each step with its reagent 试剂 and conditions.

A synthesis chain from benzene to an azo dye, with the reagent on each forward step, and a large backward arrow above showing that the planning runs from the target back to the start
Plan a route by working backwards from the target, one reaction at a time, until you reach the starting material

When you analyse a route, state the type of reaction for each step (for example electrophilic substitution, addition–elimination 加成消去, oxidation or reduction) and watch for likely by-products 副产物 — for example, making an amine from a halogenoalkane also gives over-substituted amines, lowering the yield.

Worked example. Devise a route from benzene to phenylamine, $\text{C}_6\text{H}_5\text{NH}_2$. Work backwards: phenylamine comes from reducing nitrobenzene, and nitrobenzene comes from nitrating benzene - so the route is two steps. Step 1: benzene with concentrated $\text{HNO}_3$ and concentrated $\text{H}_2\text{SO}_4$ at $55\ °\text{C}$; electrophilic substitution gives nitrobenzene (keep below $55\ °\text{C}$, or further substitution follows). Step 2: reduce the nitrobenzene with tin and concentrated $\text{HCl}$, then add $\text{NaOH}$ to free the amine from its salt. There is no direct route - you cannot put an $\text{–NH}_2$ straight onto a ring, which is exactly why this nitrate-then-reduce pair is worth knowing by heart.

Explore

A-Level synthesis planner

Build a route by matching functional-group changes to reagents.

Vocabulary Train
English
functional group/ˈfʌŋkʃənl ɡruːp/
acyl chloride/əˈkɪl ˈklɔːraɪd/
phenol/ˈfenɒl/
arene/ˈæren/
electrophilic substitution/ɪˌlektrəʊˈfɪlɪk ˌsʌbstɪˈtjuːʃn/
reduction/rɪˈdʌkʃn/
oxidation/ˌɒksɪˈdeɪʃn/
carboxylic acid/ˌkɑːbəkˈsɪlɪk ˈæsɪd/
ester/ˈestə/
amine/ˈæmaɪn/
amide/əˈmaɪd/
nitrile/ˈnaɪtraɪl/
synthetic route/sɪnˈθetɪk ruːt/
reagent/rɪˈeɪdʒənt/
addition–elimination/əˈdɪʃn ɪˌlɪmɪˈneɪʃn/
by-product/baɪ ˈprɒdʌkt/
36.1

Exam tips

  • Combine AS and A-level steps and watch for benzene-ring reactions and carbon-count changes.
  • State every reagent and condition, and note when a step produces a racemic mixture.
  • Choose the shortest route that reaches the target functional group.

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