Vmax, Km and inhibitors · Vmax、Km 和抑制剂
| English | 中文 | Pinyin · 拼音 |
|---|---|---|
| maximum rate/ˈmæksɪməm reɪt/ | 最大速率 | zuì dà sù lǜ |
| Michaelis–Menten constant/ˈmaɪkəliz ˈmentn ˈkɒnstənt/ | 米氏常数 | mǐ shì cháng shù |
| affinity/əˈfɪnɪti/ | 亲和力 | qīn hé lì |
| competitive/kəmˈpetɪtɪv/ | 竞争性 | jìng zhēng xìng |
| non-competitive/nɒn kəmˈpetɪtɪv/ | 非竞争性 | fēi jìng zhēng xìng |
| immobilised enzyme/ɪˈməʊbəlaɪzd ˈenzaɪm/ | 固定化酶 | gù dìng huà méi |
Vmax and Km
- When every active site is full, the reaction hits a top speed — the maximum rate 最大速率, $V_{max}$.
- The curve of rate against substrate concentration climbs and then flattens at $V_{max}$.
Vmax 和 Km
- 当每个活性位点都满了,反应达到一个最高速度——最大速率(maximum rate),$V_{max}$。
- 速率对底物浓度的曲线攀升,然后在 $V_{max}$ 处变平。

What does V_max represent? · V_max 代表什么?
V_max is the top rate; the curve flattens there because every active site is busy. · V_max 是最高速率;曲线在那里变平,因为每个活性位点都忙着。
What Km tells you
- The Michaelis–Menten constant 米氏常数, $K_m$, is the substrate concentration that gives half of $V_{max}$.
- It measures the enzyme's affinity 亲和力 (pulling power) for its substrate:
- low $K_m$ → reaches half-speed at low substrate → high affinity.
- high $K_m$ → needs lots of substrate → low affinity.
- So $K_m$ lets you compare how strongly different enzymes hold their substrates.
Both reach the same $V_{max}$, but the low-$K_m$ enzyme gets to half-speed on far less substrate — it grips its substrate more tightly.
Km 告诉你什么
- 米氏常数(Michaelis–Menten constant),$K_m$,是给出 $V_{max}$ 一半 的底物浓度。
- 它衡量酶对它的底物的 亲和力(affinity)(吸引力):
- 低 $K_m$ → 在低底物处达到半速 → 高 亲和力。
- 高 $K_m$ → 需要大量底物 → 低 亲和力。
- 所以 $K_m$ 让你比较不同的酶抓住它们底物有多紧。

两者都达到相同的 $V_{max}$,但低 $K_m$ 的酶在少得多的底物上就达到半速——它抓住它的底物更紧。
Vmax and Km · Vmax 和 Km
rate = Vmax·[S] / (Km + [S]) · 速率 = Vmax·[S] / (Km + [S])
Drag the substrate. The rate approaches Vmax; the substrate that gives half · 一半 of Vmax is Km — a measure of how tightly the enzyme binds. · 拖动底物。速率接近 Vmax;给出 Vmax 一半 的底物是 Km——衡量酶结合有多紧。
An enzyme has V_max = 80 units. At a substrate concentration equal to its Km, what is the rate? · 一个酶有 V_max = 80 单位。在等于它的 Km 的底物浓度下,速率是多少?
By definition Km is the substrate concentration that gives half · 一半 of V_max, so the rate is 80 ÷ 2 = 40 units. · 根据定义,Km 是给出 V_max 一半 的底物浓度,所以速率是 80 ÷ 2 = 40 单位。
A LOW Km means the enzyme only reaches half its maximum rate at a HIGH substrate concentration. · 一个低 Km 意味着酶只在高底物浓度下才达到它最大速率的一半。
The opposite: low Km means half-speed is reached at LOW substrate — a high affinity, gripping the substrate tightly. · 相反:低 Km 意味着在低底物处就达到半速——一个高亲和力,紧紧抓住底物。
Reversible inhibitors
- An inhibitor slows an enzyme; a reversible one can leave again. Two types:
| Type | Binds | Add more substrate? | $V_{max}$ | $K_m$ |
|---|---|---|---|---|
| competitive 竞争性 | the active site (similar shape to substrate) | out-competes it — effect drops | unchanged | rises |
| non-competitive 非竞争性 | a different site (changes the active site) | does not help | falls | unchanged |
可逆抑制剂
- 抑制剂(inhibitor) 减慢一个酶;一个 可逆的(reversible) 抑制剂能再次离开。两种类型:
| 类型 | 结合 | 加更多底物? | $V_{max}$ | $K_m$ |
|---|---|---|---|---|
| 竞争性 | 活性位点(形状与底物相似) | 胜过它——效应下降 | 不变 | 上升 |
| 非竞争性 | 一个不同的位点(改变活性位点) | 没有 帮助 | 下降 | 不变 |

Match each inhibitor effect to the right outcome. · 把每个抑制剂效应与正确的结果配对。
A competitive inhibitor blocks the active site (raises Km, same Vmax); a non-competitive one binds elsewhere and lowers Vmax (Km unchanged). · 一个竞争性抑制剂阻塞活性位点(提高 Km,相同 Vmax);一个非竞争性的结合在别处并降低 Vmax(Km 不变)。
Adding more substrate overcomes a competitive inhibitor but not a non-competitive one. Why? · 加更多底物克服一个竞争性抑制剂,但不克服一个非竞争性的。为什么?
A competitive inhibitor blocks the active site, so flooding with substrate wins the competition. A non-competitive inhibitor binds elsewhere, so substrate cannot displace it. · 一个竞争性抑制剂阻塞活性位点,所以用底物淹没赢得竞争。一个非竞争性抑制剂结合在别处,所以底物不能取代它。
Immobilised enzymes 固定化酶
- An immobilised enzyme is fixed in place — e.g. trapped in alginate beads — while substrate flows past.
- A free enzyme works a little faster, but immobilising it brings big practical wins:
- it is not washed away, so it can be reused.
- the product is pure (not mixed with enzyme).
- it is more stable to changes in temperature and pH.
- the process can run continuously.
- Used industrially — e.g. lactase beads make lactose-free milk.
固定化酶
- 固定化酶(immobilised enzyme) 被固定在原地——例如困在 海藻酸盐(alginate) 珠中——而底物流过。
- 自由的酶工作快一点,但固定化它带来很大的实际好处:
- 它 不被冲走,所以它能被 重复使用。
- 产物纯净(不与酶混合)。
- 它对温度和 pH 的变化 更稳定。
- 过程能 连续 运行。
- 工业上使用——例如 乳糖酶(lactase) 珠制造无乳糖牛奶。
Select all · 所有 the advantages of immobilising an enzyme (e.g. in alginate beads). · 选出固定化一个酶(例如在海藻酸盐珠中)的所有优点。
Immobilised enzymes are reusable, give a pure product and are more stable — but a free enzyme actually works a little faster. · 固定化酶可重复使用、给出纯净产物且更稳定——但自由的酶实际上工作快一点。
An enzyme fixed in place (e.g. trapped in alginate beads) so it can be reused is described as ______. · 一个被固定在原地(例如困在海藻酸盐珠中)以便能被重复使用的酶被描述为 ______。
Immobilising the enzyme lets it be recovered and reused, and keeps the product enzyme-free. · 固定化酶让它能被回收和重复使用,并使产物不含酶。
You've got it
- $V_{max}$ = top rate (all active sites full); $K_m$ = substrate concentration giving half $V_{max}$
- low $K_m$ = high affinity; high $K_m$ = low affinity
- competitive inhibitor: active site, raises $K_m$, $V_{max}$ unchanged (more substrate overcomes it)
- non-competitive inhibitor: other site, lowers $V_{max}$, $K_m$ unchanged
- immobilised enzymes: reusable, pure product, more stable, continuous
你掌握了
- $V_{max}$ = 最高速率(所有活性位点满);$K_m$ = 给出 一半 $V_{max}$ 的底物浓度
- 低 $K_m$ = 高亲和力;高 $K_m$ = 低亲和力
- 竞争性 抑制剂:活性位点,提高 $K_m$,$V_{max}$ 不变(更多底物克服它)
- 非竞争性 抑制剂:其他位点,降低 $V_{max}$,$K_m$ 不变
- 固定化酶:可重复使用、产物纯净、更稳定、连续