Skip to content

Sampling Distributions

AP Statistics · Topic 5

Train
5.1

Why Two Samples Never Match: Sampling Variability

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

VAR-1
Given that variation may be random or not, conclusions are uncertain.

VAR-1.G
Identify questions suggested by variation in statistics for samples collected from the same population. [Skill 1.A]

  • VAR-1.G.1 Variation in statistics for samples taken from the same population may be random or not.

Source: College Board AP Course and Exam Description

A statistic 统计量 (like a sample mean $\bar{x}$ or sample proportion $\hat{p}$) is computed from a sample and varies from sample to sample – this is sampling variability 抽样变异. A parameter 参数 ($\mu$ or $p$) is the fixed truth about the population. The sampling distribution 抽样分布 is the distribution of a statistic over all possible samples of a given size – it is the bridge from one sample to inference.

Vocabulary Train
English Chinese Pinyin
statistic 统计量 tǒng jì liàng
sampling variability 抽样变异 chōu yàng biàn yì
parameter 参数 cān shù
sampling distribution 抽样分布 chōu yàng fēn bù
5.2

The Normal Curve as a Model for a Statistic

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

VAR-6
The normal distribution may be used to model variation.

VAR-6.A
Calculate the probability that a particular value lies in a given interval of a normal distribution. [Skill 3.A]

  • VAR-6.A.1 A continuous random variable is a variable that can take on any value within a specified domain. Every interval within the domain has a probability associated with it.
  • VAR-6.A.2 A continuous random variable with a normal distribution is commonly used to describe populations. The distribution of a normal random variable can be described by a normal, or "bell-shaped," curve.
  • VAR-6.A.3 The area under a normal curve over a given interval represents the probability that a particular value lies in that interval.
    • Illustrative examples for VAR-6.A: Continuous random variable: If one looks at a clock at a random time, the probability that the minute hand is between the 3 and the 6 is one fourth.

VAR-6.B
Determine the interval associated with a given area in a normal distribution. [Skill 3.A]

  • VAR-6.B.1 The boundaries of an interval associated with a given area in a normal distribution can be determined using $z$-scores or technology, such as a calculator, a standard normal table, or computer-generated output.
  • VAR-6.B.2 Intervals associated with a given area in a normal distribution can be determined by assigning appropriate inequalities to the boundaries of the intervals:
    • a. $P(X < x_a) = \dfrac{p}{100}$ means that the lowest $p\%$ of values lie to the left of $x_a$.
    • b. $P(x_a < X < x_b) = \dfrac{p}{100}$ means that $p\%$ of values lie between $x_a$ and $x_b$.
    • c. $P(X > x_b) = \dfrac{p}{100}$ means that the highest $p\%$ of values lie to the right of $x_b$.
    • d. To determine the most extreme $p\%$ of values requires dividing the area associated with $p\%$ into two equal areas on either extreme of the distribution: $P(X < x_a) = \dfrac{1}{2}\dfrac{p}{100}$ and $P(X > x_b) = \dfrac{1}{2}\dfrac{p}{100}$ means that half of the $p\%$ most extreme values lie to the left of $x_a$ and half of the $p\%$ most extreme values lie to the right of $x_b$.

VAR-6.C
Determine the appropriateness of using the normal distribution to approximate probabilities for unknown distributions. [Skill 3.C]

  • VAR-6.C.1 Normal distributions are symmetrical and "bell-shaped." As a result, normal distributions can be used to approximate distributions with similar characteristics.

Source: College Board AP Course and Exam Description

The normal distribution

For large enough samples, many sampling distributions are approximately normal. That lets us describe a statistic by a center (its mean), a spread (its standard error 标准误), and a normal shape – and then compute how likely a given sample result is.

Explore

Use the normal curve to find a proportion

A normal model turns a range of values into an area = a proportion. Shade a band to read off the fraction of samples falling within it (the 68-95-99.7 rule).

Vocabulary Train
English Chinese Pinyin
standard error 标准误 biāo zhǔn wù
5.3

The Central Limit Theorem

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.H
Estimate sampling distributions using simulation. [Skill 3.C]

  • UNC-3.H.1 A sampling distribution of a statistic is the distribution of values for the statistic for all possible samples of a given size from a given population.
  • UNC-3.H.2 The central limit theorem (CLT) states that when the sample size is sufficiently large, a sampling distribution of the mean of a random variable will be approximately normally distributed.
  • UNC-3.H.3 The central limit theorem requires that the sample values are independent of each other and that $n$ is sufficiently large.
  • UNC-3.H.4 A randomization distribution is a collection of statistics generated by simulation assuming known values for the parameters. For a randomized experiment, this means repeatedly randomly reallocating/reassigning the response values to treatment groups.
  • UNC-3.H.5 The sampling distribution of a statistic can be simulated by generating repeated random samples from a population.

Source: College Board AP Course and Exam Description

The Central Limit Theorem

The Central Limit Theorem 中心极限定理 (CLT): for a sample mean, if the sample size $n$ is large enough (a common rule is $n\ge 30$), the sampling distribution of $\bar{x}$ is approximately normal, regardless of the population's shape. The larger $n$, the more normal and the tighter the distribution.

The sample mean is nearly normal whatever the shape of the population The sample mean is nearly normal whatever the shape of the population

Explore

Watch a sampling distribution turn normal

The Central Limit Theorem: for a large enough sample, the distribution of the sample mean is approximately normal — whatever the shape of the population.

Vocabulary Train
English Chinese Pinyin
Central Limit Theorem 中心极限定理 zhōng xīn jí xiàn dìng lǐ
Exercise sheet
5.4

Good Guesses and Bad Guesses: Bias

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.I
Explain why an estimator is or is not unbiased. [Skill 4.B]

  • UNC-3.I.1 When estimating a population parameter, an estimator is unbiased if, on average, the value of the estimator is equal to the population parameter.

UNC-3.J
Calculate estimates for a population parameter. [Skill 3.B]

  • UNC-3.J.1 When estimating a population parameter, an estimator exhibits variability that can be modeled using probability.
  • UNC-3.J.2 A sample statistic is a point estimator of the corresponding population parameter.

Source: College Board AP Course and Exam Description

A statistic is unbiased 无偏 if the mean of its sampling distribution equals the parameter – it is correct on average. Bias is about the center being off; variability is about the spread. A good estimator is both unbiased (centered right) and low-variability (precise); larger samples reduce variability but do not fix bias from bad sampling.

Vocabulary Train
English Chinese Pinyin
unbiased 无偏 wú piān
5.5

The Sampling Distribution of a Sample Proportion

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.K
Determine parameters of a sampling distribution for sample proportions. [Skill 3.B]

  • UNC-3.K.1 For independent samples (sampling with replacement) of a categorical variable from a population with population proportion, $p$, the sampling distribution of the sample proportion, $\hat{p}$, has a mean, $\mu_{\hat{p}} = p$ and a standard deviation, $\sigma_{\hat{p}} = \sqrt{\dfrac{p(1-p)}{n}}$.
  • UNC-3.K.2 If sampling without replacement, the standard deviation of the sample proportion is smaller than what is given by the formula above. If the sample size is less than 10% of the population size, the difference is negligible.

UNC-3.L
Determine whether a sampling distribution for a sample proportion can be described as approximately normal. [Skill 3.C]

  • UNC-3.L.1 For a categorical variable, the sampling distribution of the sample proportion, $\hat{p}$, will have an approximate normal distribution, provided the sample size is large enough: $np \geq 10$ and $n(1-p) \geq 10$

UNC-3.M
Interpret probabilities and parameters for a sampling distribution for a sample proportion. [Skill 4.B]

  • UNC-3.M.1 Probabilities and parameters for a sampling distribution for a sample proportion should be interpreted using appropriate units and within the context of a specific population.

Source: College Board AP Course and Exam Description

For a sample proportion $\hat{p}$ from an SRS: the mean is $p$ (unbiased), and the standard deviation is

$$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}.$$
It is approximately normal when $np\ge 10$ and $n(1-p)\ge 10$ (the Large Counts condition), and the $10\%$ condition ($n\le 0.10N$) keeps the observations near-independent.

Worked example. Suppose $40\%$ of voters favor a measure ($p=0.4$) and you sample $n=100$. The standard error is $\sigma_{\hat p}=\sqrt{\dfrac{0.4(0.6)}{100}}=0.049$. The chance a sample gives $\hat{p}>0.5$ is $z=\dfrac{0.5-0.4}{0.049}=2.04$, so $P(\hat p>0.5)\approx0.02$ – a majority in the sample would be surprising.

5.6

Comparing Two Groups: Difference of Sample Proportions

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.N
Determine parameters of a sampling distribution for a difference in sample proportions. [Skill 3.B]

  • UNC-3.N.1 For a categorical variable, when randomly sampling with replacement from two independent populations with population proportions $p_1$ and $p_2$, the sampling distribution of the difference in sample proportions $\hat{p}_1 - \hat{p}_2$ has mean, $\mu_{\hat{p}_1 - \hat{p}_2} = p_1 - p_2$ and standard deviation, $\sigma_{\hat{p}_1 - \hat{p}_2} = \sqrt{\dfrac{p_1(1-p_1)}{n_1} + \dfrac{p_2(1-p_2)}{n_2}}$.
  • UNC-3.N.2 If sampling without replacement, the standard deviation of the difference in sample proportions is smaller than what is given by the formula above. If the sample sizes are less than 10% of the population sizes, the difference is negligible.

UNC-3.O
Determine whether a sampling distribution for a difference of sample proportions can be described as approximately normal. [Skill 3.C]

  • UNC-3.O.1 The sampling distribution of the difference in sample proportions $\hat{p}_1 - \hat{p}_2$ will have an approximate normal distribution provided the sample sizes are large enough: $n_1 p_1 \geq 10, n_1(1-p_1) \geq 10, n_2 p_2 \geq 10, n_2(1-p_2) \geq 10$.

UNC-3.P
Interpret probabilities and parameters for a sampling distribution for a difference in proportions. [Skill 4.B]

  • UNC-3.P.1 Parameters for a sampling distribution for a difference of proportions should be interpreted using appropriate units and within the context of a specific populations.

Source: College Board AP Course and Exam Description

For $\hat{p}_1-\hat{p}_2$ from two independent samples: the mean is $p_1-p_2$, and because the samples are independent the variances add:

$$\sigma_{\hat p_1-\hat p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2}}.$$
It is approximately normal when the Large Counts condition holds in both samples.

5.7

The Sampling Distribution of a Sample Mean

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.Q
Determine parameters for a sampling distribution for sample means. [Skill 3.B]

  • UNC-3.Q.1 For a numerical variable, when random sampling with replacement from a population with mean $\mu$ and standard deviation, $\sigma$, the sampling distribution of the sample mean has mean $\mu_{\bar{x}} = \mu$ and standard deviation $\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}}$.
  • UNC-3.Q.2 If sampling without replacement, the standard deviation of the sample mean is smaller than what is given by the formula above. If the sample size is less than 10% of the population size, the difference is negligible.

UNC-3.R
Determine whether a sampling distribution of a sample mean can be described as approximately normal. [Skill 3.C]

  • UNC-3.R.1 For a numerical variable, if the population distribution can be modeled with a normal distribution, the sampling distribution of the sample mean, $\bar{x}$, can be modeled with a normal distribution.
  • UNC-3.R.2 For a numerical variable, if the population distribution cannot be modeled with a normal distribution, the sampling distribution of the sample mean, $\bar{x}$, can be modeled approximately by a normal distribution, provided the sample size is large enough, e.g., greater than or equal to 30.

UNC-3.S
Interpret probabilities and parameters for a sampling distribution for a sample mean. [Skill 4.B]

  • UNC-3.S.1 Probabilities and parameters for a sampling distribution for a sample mean should be interpreted using appropriate units and within the context of a specific population.

Source: College Board AP Course and Exam Description

For a sample mean $\bar{x}$ from an SRS: the mean is $\mu$ (unbiased), and the standard deviation is

$$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}.$$
Its shape is normal if the population is normal, or approximately normal for large $n$ by the CLT. Note the spread shrinks like $\sqrt{n}$ – quadrupling the sample halves the standard error.

Worked example. A population has $\mu=70$ and $\sigma=12$. For samples of $n=36$, the sampling distribution of $\bar{x}$ is centered at $70$ with standard error $\dfrac{12}{\sqrt{36}}=2$. The chance a sample mean exceeds $73$ is $z=\dfrac{73-70}{2}=1.5$, so $P(\bar x>73)\approx0.067$.

The sampling distribution of the mean narrows and becomes more normal as n grows All three sampling distributions are centered at $\mu$, but a larger $n$ makes the standard error $\sigma/\sqrt{n}$ smaller, so the distribution of $\bar{x}$ is taller and narrower.

Exercise sheet
5.8

Comparing Two Groups: Difference of Sample Means

Syllabus
Enduring UnderstandingLearning ObjectiveEssential Knowledge

UNC-3
Probabilistic reasoning allows us to anticipate patterns in data.

UNC-3.T
Determine parameters of a sampling distribution for a difference in sample means. [Skill 3.B]

  • UNC-3.T.1 For a numerical variable, when randomly sampling with replacement from two independent populations with population means $\mu_1$ and $\mu_2$ and population standard deviations $\sigma_1$ and $\sigma_2$, the sampling distribution of the difference in sample means $\bar{x}_1 - \bar{x}_2$ has mean $\mu_{(\bar{x}_1 - \bar{x}_2)} = \mu_1 - \mu_2$ and standard deviation, $\sigma_{(\bar{x}_1 - \bar{x}_2)} = \sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}$.
  • UNC-3.T.2 If sampling without replacement, the standard deviation of the difference in sample means is smaller than what is given by the formula above. If the sample sizes are less than 10% of the population sizes, the difference is negligible.

UNC-3.U
Determine whether a sampling distribution of a difference in sample means can be described as approximately normal. [Skill 3.C]

  • UNC-3.U.1 The sampling distribution of the difference in sample means $\bar{x}_1 - \bar{x}_2$ can be modeled with a normal distribution if the two population distributions can be modeled with a normal distribution.
  • UNC-3.U.2 The sampling distribution of the difference in sample means $\bar{x}_1 - \bar{x}_2$ can be modeled approximately by a normal distribution if the two population distributions cannot be modeled with a normal distribution but both sample sizes are greater than or equal to 30.

UNC-3.V
Interpret probabilities and parameters for a sampling distribution for a difference in sample means. [Skill 4.B]

  • UNC-3.V.1 Probabilities and parameters for a sampling distribution for a difference of sample means should be interpreted using appropriate units and within the context of a specific populations.

Source: College Board AP Course and Exam Description

For $\bar{x}_1-\bar{x}_2$ from two independent samples: the mean is $\mu_1-\mu_2$, and (independent, so variances add)

$$\sigma_{\bar x_1-\bar x_2}=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}.$$
This is the foundation for two-sample inference in the next units.

5.8

Exam tips

  • A sampling distribution is the distribution of a statistic over many samples, centered on the true parameter.
  • The Central Limit Theorem: for a large enough sample the sample mean is approximately normal, even if the population is not.
  • Larger samples give less variability (a smaller standard error).
  • Check the conditions (random, independent/10%, large enough) before using a normal model.
  • Keep straight what varies — the statistic — versus the fixed parameter.

Log in or create account

IGCSE & A-Level