Skip to content

Compound Structure and Properties

AP Chemistry · Topic 2

Train
2.1

Types of Chemical Bonds

Syllabus
Learning ObjectiveEssential Knowledge

2.1.A
Explain the relationship between the type of bonding and the properties of the elements participating in the bond.

  • 2.1.A.1 Electronegativity values for the representative elements increase going from left to right across a period and decrease going down a group. These trends can be understood qualitatively through the electronic structure of the atoms, the shell model, and Coulomb's law.
  • 2.1.A.2 Valence electrons shared between atoms of similar electronegativity constitute a nonpolar covalent bond. For example, bonds between carbon and hydrogen are effectively nonpolar even though carbon is slightly more electronegative than hydrogen.
  • 2.1.A.3 Valence electrons shared between atoms of unequal electronegativity constitute a polar covalent bond.
    • i. The atom with a higher electronegativity will develop a partial negative charge relative to the other atom in the bond.
    • ii. In single bonds, greater differences in electronegativity lead to greater bond dipoles.
    • iii. All polar bonds have some ionic character, and the difference between ionic and covalent bonding is not distinct but rather a continuum.
  • 2.1.A.4 The difference in electronegativity is not the only factor in determining if a bond should be designated as ionic or covalent. Generally, bonds between a metal and nonmetal are ionic, and bonds between two nonmetals are covalent. Examination of the properties of a compound is the best way to characterize the type of bonding.
  • 2.1.A.5 In a metallic solid, the valence electrons from the metal atoms are considered to be delocalized and not associated with any individual atom.

Source: College Board AP Course and Exam Description

A chemical bond 化学键 is an attraction that holds atoms together. Which type forms depends on the atoms' electronegativities:

Ionic bonding: a metal transfers its outer electrons to a non-metal Ionic bonding: a metal transfers its outer electrons to a non-metal

  • Ionic bond 离子键: electrons transfer from a metal to a nonmetal (large electronegativity difference).
  • Covalent bond 共价键: nonmetals share electrons (small difference). A big-but-not-huge difference gives a polar covalent 极性共价 bond.
  • Metallic bond 金属键: metal atoms share a "sea" of mobile electrons.
Explore

Form an ionic bond by electron transfer

An ionic bond forms when a metal gives electrons to a non-metal, making oppositely charged ions that attract; a covalent bond shares electrons instead.

Vocabulary Train
English Chinese Pinyin
chemical bond 化学键 huà xué jiàn
Ionic bond 离子键 lí zi jiàn
Covalent bond 共价键 gòng jià jiàn
polar covalent 极性共价 jí xìng gòng jià
Metallic bond 金属键 jīn shǔ jiàn
2.2

Intramolecular Force and Potential Energy

Syllabus
Learning ObjectiveEssential Knowledge

2.2.A
Represent the relationship between potential energy and distance between atoms, based on factors that influence the interaction strength.

  • 2.2.A.1 A graph of potential energy versus the distance between atoms (internuclear distance) is a useful representation for describing the interactions between atoms. Such graphs illustrate both the equilibrium bond length (the separation between atoms at which the potential energy is lowest) and the bond energy (the energy required to separate the atoms).
  • 2.2.A.2 In a covalent bond, the bond length is influenced by both the size of the atom's core and the bond order (i.e., single, double, triple). Bonds with a higher order are shorter and have larger bond energies.
  • 2.2.A.3 Coulomb's law can be used to understand the strength of interactions between cations and anions.
    • i. Because the interaction strength is proportional to the charge on each ion, larger charges lead to stronger interactions.
    • ii. Because the interaction strength increases as the distance between the centers of the ions (nuclei) decreases, smaller ions lead to stronger interactions.

Source: College Board AP Course and Exam Description

As two atoms approach, a potential energy 势能 curve captures the balance of attraction and repulsion. It dips to a minimum at the bond length 键长 (the stable separation) whose depth is the bond energy 键能. Shorter, stronger bonds sit in deeper, tighter wells; more shared pairs (double, triple bonds) give shorter, stronger bonds.

Vocabulary Train
English Chinese Pinyin
potential energy 势能 shì néng
bond length 键长 jiàn zhǎng
bond energy 键能 jiàn néng
2.3

Structure of Ionic Solids

Syllabus
Learning ObjectiveEssential Knowledge

2.3.A
Represent an ionic solid with a particulate model that is consistent with Coulomb's law and the properties of the constituent ions.

  • 2.3.A.1 The cations and anions in an ionic crystal are arranged in a systematic, periodic 3-D array that maximizes the attractive forces among cations and anions while minimizing the repulsive forces.
    • Exclusion statement: Knowledge of specific crystal structures is not essential to an understanding of the learning objective and will not be assessed on the AP Exam.

Source: College Board AP Course and Exam Description

An ionic solid 离子固体 is a repeating 3-D lattice 晶格 of alternating cations and anions, held by strong electrostatic attraction. This explains their high melting points, brittleness, and why they conduct only when molten or dissolved (ions freed to move). The lattice energy rises with larger ion charges and smaller ions, so MgO (both $2+/2-$) melts far higher than NaCl (both $1+/1-$).

Ions pack into a giant lattice of alternating positive and negative ions Ions pack into a giant lattice of alternating positive and negative ions

Vocabulary Train
English Chinese Pinyin
ionic solid 离子固体 lí zi gù tǐ
lattice 晶格 jīng gé
2.4

Structure of Metals and Alloys

Syllabus
Learning ObjectiveEssential Knowledge

2.4.A
Represent a metallic solid and/or alloy using a model to show essential characteristics of the structure and interactions present in the substance.

  • 2.4.A.1 Metallic bonding can be represented as an array of positive metal ions surrounded by delocalized valence electrons (i.e., a "sea of electrons").
  • 2.4.A.2 Interstitial alloys form between atoms of significantly different radii, where the smaller atoms fill the interstitial spaces between the larger atoms (e.g., with steel in which carbon occupies the interstices in iron).
  • 2.4.A.3 Substitutional alloys form between atoms of comparable radius, where one atom substitutes for the other in the lattice. (e.g., in certain brass alloys, other elements, usually zinc, substitute for copper.)

Source: College Board AP Course and Exam Description

In a metal, cations sit in a lattice bathed in delocalized 离域 electrons, which explains conductivity, malleability, and luster. An alloy 合金 mixes metals: a substitutional alloy swaps in similar-sized atoms; an interstitial alloy (like steel) fits small atoms into the gaps, making it harder.

Different-sized atoms in an alloy stop the layers sliding, so it is harder Different-sized atoms in an alloy stop the layers sliding, so it is harder

Metallic bonding: positive ions in a sea of delocalised electrons Metallic bonding: positive ions in a sea of delocalised electrons

Explore

Slide layers in a metallic lattice

A metal is positive ions in a sea of delocalised electrons. The layers can slide without breaking the bond, so metals are malleable and conduct.

Vocabulary Train
English Chinese Pinyin
delocalized 离域 lí yù
alloy 合金 hé jīn
2.5

Lewis Diagrams

Syllabus
Learning ObjectiveEssential Knowledge

2.5.A
Represent a molecule with a Lewis diagram.

  • 2.5.A.1 Lewis diagrams can be constructed according to an established set of principles.

Source: College Board AP Course and Exam Description

A Lewis diagram 路易斯结构 shows valence electrons as bonding pairs and lone pairs 孤对电子, giving most atoms an octet 八隅体 (8 valence electrons; H wants 2). Steps: count total valence electrons, connect atoms with single bonds, complete octets on outer atoms, then form multiple bonds if the central atom is short.

Dot-and-cross diagrams show the bonding pairs and lone pairs in a molecule Dot-and-cross diagrams show the bonding pairs and lone pairs in a molecule

Worked example. Draw carbon dioxide, $\text{CO}_2$. Total valence electrons $=4+2(6)=16$. Put C in the centre; single bonds to each O use $4$ electrons and leave the outer O atoms short. Completing octets forces two double bonds, $\text{O}=\text{C}=\text{O}$: each O then has two lone pairs, C has none, and all $16$ electrons are placed with every atom at an octet.

Vocabulary Train
English Chinese Pinyin
Lewis diagram 路易斯结构 lù yì sī jié gòu
lone pairs 孤对电子 gū duì diàn zi
octet 八隅体 bā yú tǐ
2.6

Resonance and Formal Charge

Syllabus
Learning ObjectiveEssential Knowledge

2.6.A
Represent a molecule with a Lewis diagram that accounts for resonance between equivalent structures or that uses formal charge to select between nonequivalent structures.

  • 2.6.A.1 In cases where more than one equivalent Lewis structure can be constructed, resonance must be included as a refinement to the Lewis structure. In many such cases, this refinement is needed to provide qualitatively accurate predictions of molecular structure and properties.
  • 2.6.A.2 The octet rule and formal charge can be used as criteria for determining which of several possible valid Lewis diagrams provides the best model for predicting molecular structure and properties.
  • 2.6.A.3 As with any model, there are limitations to the use of the Lewis structure model, particularly in cases with an odd number of valence electrons.

Source: College Board AP Course and Exam Description

When two or more valid Lewis diagrams differ only in electron placement, the true structure is an average – resonance 共振. Formal charge 形式电荷 (valence electrons minus lone-pair electrons minus half the bonding electrons) picks the best structure: the one with formal charges closest to zero, and any negative charge on the most electronegative atom.

Worked example. Assign formal charges in the nitrate ion, $\text{NO}_3^{-}$ (one double bond, two single bonds). For N (4 bonds, no lone pairs): $5-0-4=+1$. For the double-bonded O (2 lone pairs): $6-4-2=0$. For each single-bonded O (3 lone pairs): $6-6-1=-1$. The total is $+1+0+(-1)+(-1)=-1$, matching the ion's overall charge – a good check that the structure is drawn correctly. Because the three O atoms are equivalent by resonance, the real ion has three identical bonds.

Vocabulary Train
English Chinese Pinyin
resonance 共振 gòng zhèn
Formal charge 形式电荷 xíng shì diàn hè
2.7

VSEPR and Bond Hybridization

Syllabus
Learning ObjectiveEssential Knowledge

2.7.A
Based on the relationship between Lewis diagrams, VSEPR theory, bond orders, and bond polarities:

  • i. Explain structural properties of molecules.
  • ii. Explain electron properties of molecules.
  • 2.7.A.1 VSEPR theory uses the Coulombic repulsion between electrons as a basis for predicting the arrangement of electron pairs around a central atom.
  • 2.7.A.2 Both Lewis diagrams and VSEPR theory must be used for predicting electronic and structural properties of many covalently bonded molecules and polyatomic ions, including the following:
    • i. Molecular geometry (linear, trigonal planar, tetrahedral, trigonal pyramidal, bent, trigonal bipyramidal, seesaw, T-shaped, octahedral, square pyramidal, square planar)
    • ii. Bond angles
    • iii. Relative bond energies based on bond order
    • iv. Relative bond lengths (multiple bonds, effects of atomic radius)
    • v. Presence of a dipole moment
    • vi. Hybridization of valence orbitals for atoms within a molecule or polyatomic ion
  • 2.7.A.3 The terms "hybridization" and "hybrid atomic orbital" are used to describe the arrangement of electrons around a central atom. When the central atom is $sp$ hybridized, its ideal bond angles are $180°$; for $sp^2$ hybridized atoms the bond angles are $120°$; and for $sp^3$ hybridized atoms the bond angles are $109.5°$.
    • Exclusion statement: An understanding of the derivation and depiction of hybrid orbitals will not be assessed on the AP Exam. The course includes the distinction between sigma and pi bonding, the use of VSEPR to explain the shapes of molecules, and the $sp$, $sp^2$, and $sp^3$ nomenclature.
    • Exclusion statement: Hybridization involving d orbitals will not be assessed on the AP Exam. When an atom has more than four pairs of electrons surrounding the central atom, students are only responsible for the shape of the resulting molecule.
  • 2.7.A.4 Bond formation is associated with overlap between atomic orbitals. In multiple bonds, such overlap leads to the formation of both sigma and pi bonds. The overlap is stronger in sigma than pi bonds, which is reflected in sigma bonds having greater bond energy than pi bonds. The presence of a pi bond also prevents the rotation of the bond and leads to geometric isomers.
    • Exclusion statement: Molecular orbital theory is recommended as a way to provide deeper insight into bonding. However, the AP Exam will neither explicitly assess molecular orbital diagrams, filling of molecular orbitals, nor the distinction between bonding, nonbonding, and antibonding orbitals.

Source: College Board AP Course and Exam Description

VSEPR: molecular shapes

VSEPR 价层电子对互斥 theory predicts shape: electron pairs (bonds and lone pairs) around a central atom spread out as far apart as possible. Counting electron domains gives the geometry (linear, trigonal planar, tetrahedral, …); lone pairs push bonds closer, bending the shape. Hybridization 杂化 ($sp$, $sp^2$, $sp^3$) describes the mixed orbitals matching that geometry. Molecular shape and bond polarity together decide whether the whole molecule is polar.

Hybridisation and shape: sp3 tetrahedral, sp2 planar, sp linear Hybridisation and shape: sp3 tetrahedral, sp2 planar, sp linear

The common VSEPR shapes and their bond angles The common VSEPR shapes and their bond angles

Worked example. Predict the shape of ammonia, $\text{NH}_3$. Nitrogen has $3$ bonding pairs and $1$ lone pair – four electron domains, so the electron geometry is tetrahedral and the hybridization is $sp^3$. The lone pair is invisible in the shape but still pushes the bonds together, so the molecular shape is trigonal pyramidal with a bond angle of about $107^{\circ}$ (a little less than the ideal $109.5^{\circ}$). The three N–H dipoles do not cancel, so the molecule is polar.

Bonds form when atomic orbitals overlap. Every single bond is one sigma bond σ – orbitals overlapping head-on along the line joining the two atoms. A multiple bond adds a pi bond π, made by $p$ orbitals overlapping sideways above and below that line: a double bond is one sigma + one pi, a triple bond one sigma + two pi. Head-on overlap is more effective, so a sigma bond is stronger (higher bond energy) than a pi bond – which is why a double bond is stronger than a single bond but not twice as strong. A pi bond also locks the two atoms so they cannot rotate about the bond; a C=C double bond therefore has fixed cis and trans forms – geometric isomers 几何异构体 that a freely-rotating single bond could never show.

Worked example. Count the bonds in ethene, $\text{H}_2\text{C}=\text{CH}_2$. The four C–H bonds are single bonds (one sigma each); the C=C is one sigma plus one pi. So ethene has 5 sigma and 1 pi bond, and that single pi bond is exactly what stops the two $\text{CH}_2$ ends from twisting relative to each other.

Explore

Predict molecular shape with VSEPR

VSEPR: electron pairs repel and spread as far apart as possible, setting the molecule's shape. Add bonding and lone pairs and watch the geometry change.

Vocabulary Train
English Chinese Pinyin
VSEPR 价层电子对互斥 jià céng diàn zi duì hù chì
Hybridization 杂化 zá huà
sigma bond σ键 σ jiàn
pi bond π键 π jiàn
geometric isomers 几何异构体 jǐ hé yì gòu tǐ
Exercise sheet
2.7

Exam tips

  • Decide the bond type from the atoms: ionic (metal + non-metal, electron transfer), covalent (non-metals, sharing), metallic (sea of delocalised electrons).
  • An ionic solid conducts only when molten or dissolved (ions free to move), never as a solid.
  • Draw Lewis structures to satisfy the octet (H wants 2), then use VSEPR — electron pairs spread as far apart as possible — to predict the shape.
  • Lone pairs take up space and push bonds closer, bending the shape (water is bent, ammonia pyramidal).
  • A molecule can have polar bonds yet be non-polar overall if its symmetry makes the dipoles cancel ($\text{CO}_2$).
  • A single bond is 1 sigma bond; a double bond is 1 sigma + 1 pi, a triple bond 1 sigma + 2 pi. Sigma is stronger than pi, and a pi bond blocks rotation, giving cis/trans geometric isomers.

Log in or create account

IGCSE & A-Level