| English | 意味 |
|---|---|
| cumulative frequency/ˈkjuːmjʊlətɪv ˈfriːkwənsi/ | 累積度数 |
| median/ˈmiːdiːən/ | 中央値 |
| quartile/ˈkwɔːtaɪl/ | 四分位数 |
The running total
- In a marathon, you don't just count runners per age group — you want to know "how many runners have finished by time $t$?"
- That's a cumulative frequency 累积频数: a running total that builds up from the lowest class to the highest.
Cumulative frequency route
Follow raw data into a cumulative frequency curve and percentile reading.
Drawing the curve
- Plot cumulative frequency against the upper end of each class.
- Join the points with a smooth curve (or straight lines).
- The curve always goes up (or stays flat) — it never goes down, because you're adding.
Classes $0$–$10$ (freq $5$), $10$–$20$ (freq $8$), $20$–$30$ (freq $12$): cumulative frequencies are $5, 13, 25$. Plot at $10, 20, 30$.
On a histogram with unequal class widths the bar AREA (not height) is the frequency, so the axis is frequency density
Cumulative frequency is:
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Each point adds the next class frequency to the total so far.
Cumulative frequency is plotted against the upper end of each class.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
Always plot the running total at the top boundary of the class.
A cumulative frequency curve can go down.
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Cumulative frequency is a running total — it always increases or stays flat, never decreases.
Reading the curve
- Median 中位数: go across at half the total cumulative frequency, then down to the $x$-axis.
- Lower quartile 四分位数 (LQ): at $\dfrac{1}{4}$ of the total.
- Upper quartile (UQ): at $\dfrac{3}{4}$ of the total.
- IQR $=$ UQ $-$ LQ.
Across then down. To read a value from a cumulative frequency curve: go across from the $y$-axis to the curve, then down to the $x$-axis. Going the wrong way gives the wrong answer.
Read the median at half the total and the quartiles at one quarter and three quarters: go across to the curve, then down
A cumulative frequency curve has total 80. At what cumulative frequency do you read the median?
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The median is at half the total: 80 ÷ 2 = 40.
Total cumulative frequency is 120. At what cumulative frequency do you read the upper quartile?
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
UQ is at 3/4 of the total: (3/4) × 120 = 90.
To read the median from a cumulative frequency curve, go ______ from the y-axis to the curve, then down to the x-axis.
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Go across (horizontally) from the y-value to the curve, then down to read the x-value.
Worked example
- Total cumulative frequency $= 80$. Median at $80 \div 2 = 40$. Read across at $40$ on the $y$-axis, then down — suppose it reads $24$. The median is $24$.
A cumulative frequency curve always rises — the shape is like an elongated S, steep where data is concentrated.
There are 25 observations and cumulative frequency 13 at 20. How many are at least 20?
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Subtract the count below 20: 25 − 13 = 12.
Include the start and read a count
- For classes $0\le t<10,10\le t<20,20\le t<30$ with frequencies 5,8,12, plot $(0,0),(10,5),(20,13),(30,25)$. The first point states that none are below the lower starting boundary.
- At 20, cumulative frequency is 13, so $25-13=12$ observations are at least 20. Quartile positions are $25/4=6.25$ and $3(25)/4=18.75$ on the cumulative axis; read values from the drawn curve.
You've got it
- cumulative frequency $=$ running total, plotted at each class's upper end
- read the median at half the total; quartiles at $\dfrac{1}{4}$ and $\dfrac{3}{4}$
- across to the curve, then straight down to the value