| English | 意味 |
|---|---|
| rational/ˈræʃənl/ | 有理数 |
| irrational/ɪˈræʃənl/ | 無理数 |
| natural numbers/ˈnætʃərəl ˈnʌmbəz/ | 自然数 |
| integers/ˈɪntɪdʒəz/ | 整数 |
| factor/ˈfæktə/ | 因数 |
| multiple/ˈmʌltɪpl/ | 倍数 |
| prime/praɪm/ | 素数 |
| prime factorisation/praɪm ˌfæktəraɪˈzeɪʃn/ | 素因数分解 |
| HCF/ˌeɪtʃ siː ˈef/ | 最大公約数 |
| LCM/ˌel siː ˈem/ | 最小公倍数 |
| reciprocal/rɪˈsɪprəkl/ | 逆数 |
A question that stumped the ancient Greeks
- Is every number a fraction? The Greeks thought yes — until someone proved $\sqrt{2}$ cannot be written as $\dfrac{a}{b}$.
- Legend says the discoverer was thrown overboard for revealing this uncomfortable truth.
- Today we sort numbers into families, and that split — rational 有理数 vs irrational 无理数 — is still the big one.
The number families
- Natural numbers 自然数 $\mathbb{N} = \{1, 2, 3, \dots\}$ — the counting numbers (some definitions include $0$).
- Integers 整数 $\mathbb{Z} = \{\dots, -2, -1, 0, 1, 2, \dots\}$ — whole numbers, positive, negative and zero.
- Rational numbers $\mathbb{Q}$ — anything that can be written $\dfrac{a}{b}$ where $a, b$ are integers and $b \neq 0$.
- Irrational numbers — everything else ($\pi$, $\sqrt{2}$, $e$): they cannot be expressed as a fraction.

Natural → Integer → Rational, each a bigger family. Irrational numbers live outside.
数の集合
すべての整数は有理数であり、すべての有理数は実数です。数の集合がどのように包含され、並合と共通部分によってどう組み合わさるかを確認しましょう。
各数字を最も小さな数のグループに結びつけなさい。
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
−5 と 0 は整数(負を含む自然数)です。3/7 は有理数(整数の分数)です。√3 は無理数(a/b で表せない)です。
Factors 因数, multiples 倍数 and primes 质数
- A factor of $n$ divides into $n$ exactly. Factors of $12$: $1, 2, 3, 4, 6, 12$.
- A multiple of $n$ is $n \times$ an integer. Multiples of $5$: $5, 10, 15, 20, \dots$.
- A prime has exactly two factors: $1$ and itself.
- $2, 3, 5, 7, 11, 13, \dots$ are prime. $1$ is not prime (only one factor).
1 is NOT prime. A prime must have exactly two distinct factors. $1$ has only one factor (itself), so it fails the definition.

Every natural number is an integer, every integer is rational, and every rational is real; irrational numbers like $\pi$ and $\sqrt{2}$ are real but not rational
次のうち素数はいくつですか?
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
13 の約数はちょうど2つ(1 と 13)です。1 は素数ではありません;9 = 3×3;15 = 3×5。
数字 1 は素数である。
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
1 の約数は1つだけ(自分自身)です。素数はちょうど2つの異なる約数を持つ必要があります。
最小の素数は ______ です。
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
2 が最小(かつ唯一の偶数)の素数です。
Prime factorisation 质因数分解, HCF 最大公因数 and LCM 最小公倍数
- Write any number as a product of primes: $72 = 2^3 \times 3^2$, $120 = 2^3 \times 3 \times 5$.
- HCF (highest common factor): take the lowest power of each shared prime.
- HCF of $72$ and $120$ $= 2^3 \times 3 = 24$.
- LCM (lowest common multiple): take the highest power of every prime that appears.
- LCM of $72$ and $120$ $= 2^3 \times 3^2 \times 5 = 360$.

Keep splitting until every branch ends on a prime (circled); collecting them gives $72 = 2^3 \times 3^2$
Quick check. HCF × LCM should equal the product of the two numbers: $24 \times 360 = 8640$ and $72 \times 120 = 8640$. ✓
72 と 120 の最大公因数を求めよ。(72 = 2³×3², 120 = 2³×3×5)
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
共通する最低の累乗を選ぶ:2³ × 3 = 8 × 3 = 24。
72 と 120 の最小公倍数を求めよ。
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
最大の累乗を選ぶ:2³ × 3² × 5 = 8 × 9 × 5 = 360。
Fun fact
- There are infinitely many primes (Euclid proved this around 300 BC).
- The largest known prime (as of 2024) has over 41 million digits — it's $2^{136{,}279{,}841} - 1$, a Mersenne prime.
Reciprocals and place value
- The reciprocal 倒数 of a nonzero number multiplies it to 1: for $3/7$ it is $7/3$, since $(3/7)(7/3)=1$. Zero has no reciprocal.
- Group large numbers into thousands: 6000042 is six million and forty-two. $6\,000\,042=6(1\,000\,000)+42$; the zeros hold the missing place values.

5/9 の逆数を求めよ。
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
逆数は 9/5 = 1.8 であり、5/9 を掛けると 1 となる。
You've got it
- natural $\mathbb{N}$ → integer $\mathbb{Z}$ → rational $\mathbb{Q}$; irrational numbers live outside
- prime = exactly two factors ($1$ is not prime)
- HCF = lowest shared prime powers; LCM = highest prime powers of every prime
- $72 = 2^3 \times 3^2$, $120 = 2^3 \times 3 \times 5$ → HCF $24$, LCM $360$