Relative frequency and expected frequency
| English | Chinese | Pinyin |
|---|---|---|
| bias | 偏倚 | piān yǐ |
| relative frequency | 相对频率 | xiāng duì pín lǜ |
| expected frequency | 期望频数 | qī wàng pín shuò |
Is the coin fair?
- You flip a coin 100 times and get 60 heads. Is the coin biased 偏倚?
- Theoretical probability says $\dfrac{1}{2}$. Experimental probability (the relative frequency 相对频率) says $\dfrac{60}{100} = 0.6$. With more flips, you'll know for sure.
Relative frequency
- When outcomes are not equally likely, run an experiment:
- More trials → a better estimate of the true probability.
- A fair object gives equal chances; one with bias does not.
A drawing pin is dropped 200 times and lands point-up $84$ times. Relative frequency of point-up $= \dfrac{84}{200} = 0.42$.
A sample space diagram lists every outcome; for two dice there are $36$ equally likely totals
Two-dice probability
Roll the two dice many times: the bars start jumpy but settle into the theoretical triangle peaking at 7 — experimental probability closing in on theory.
Relative frequency is calculated as:
Relative frequency = successes ÷ number of trials.
Relative frequency becomes a better estimate as the number of trials increases.
More trials → the relative frequency converges to the true probability.
A drawing pin is dropped 200 times and lands point-up 84 times. The relative frequency of point-up is (to 2 dp):
84/200 = 0.42.
Expected frequency 期望频数
- How many times you expect an event in $n$ trials:
Expected ≠ guaranteed. An expected frequency of $50$ sixes in $300$ rolls doesn't mean you'll get exactly $50$. It's the average over many sets of $300$ rolls.
The probability of rolling a six is 1/6. How many sixes are expected in 300 rolls?
(1/6) × 300 = 50.
An event has probability 0.2. How many times is it expected in 50 trials?
0.2 × 50 = 10.
Expected frequency = P(event) × number of ______.
Expected frequency = probability × number of trials.
Worked example
- $\text{P}(\text{six}) = \dfrac{1}{6}$. In $300$ rolls: expected $= \dfrac{1}{6} \times 300 = 50$ sixes.
- $\text{P}(\text{rain}) = 0.2$. In $50$ days: expected $= 0.2 \times 50 = 10$ rainy days.
Expected frequency grows linearly with trials: double the trials, double the expected count.
You've got it
- relative frequency $= \dfrac{\text{times happened}}{\text{total trials}}$ — improves with more trials
- expected frequency $= \text{P}(\text{event}) \times n$
- $\dfrac{1}{6} \times 300 = 50$ expected sixes