Elimination and SN1/SN2 mechanisms
Elimination and the SN1/SN2 mechanisms
- The same halogenoalkane can substitute or eliminate.
- Nucleophilic substitution follows one of two mechanisms.
- And the C–X bond strength sets the reactivity.
Substitution vs elimination
- $\text{NaOH}$ in water → nucleophilic substitution → an alcohol.
- $\text{NaOH}$ in ethanol, heated → elimination → an alkene:
$$\text{C}_2\text{H}_5\text{Br} + \text{NaOH} \rightarrow \text{C}_2\text{H}_4 + \text{NaBr} + \text{H}_2\text{O}$$
Practice
Heating a halogenoalkane with NaOH dissolved in ethanol gives:
NaOH in ethanol with heat favours elimination of HX to form an alkene; NaOH in water favours substitution.
SN1 and SN2
- SN2: one step — the nucleophile attacks as the halogen leaves, through a crowded transition state. Rate depends on both reactants.
- SN1: two steps — the C–X bond breaks to a carbocation first, then the nucleophile attacks. Rate depends only on the halogenoalkane.
- Primary → mostly SN2; tertiary → mostly SN1 (its carbocation is well stabilised); secondary uses both.
Practice
The SN1 mechanism:
SN1: C–X breaks first to a carbocation, then the nucleophile attacks; tertiary halogenoalkanes favour it.
Practice
The SN2 mechanism:
SN2 is a single concerted step; primary halogenoalkanes favour it and its rate depends on both species.
Reactivity and the C–X bond
- Reactivity depends on the C–X bond strength (bond energy).
- C–I is weakest → iodoalkanes react fastest; C–Cl is strongest → chloroalkanes slowest.
Practice
Which halogenoalkane reacts fastest?
The weaker the C–X bond, the faster the reaction, so C–I (weakest) reacts fastest and C–Cl slowest.
You've got it
Key idea
- NaOH in water → substitution (alcohol); NaOH in ethanol + heat → elimination (alkene)
- SN2 = one step, rate depends on both; SN1 = two steps via a carbocation, rate depends on the halogenoalkane only
- primary → SN2, tertiary → SN1; iodoalkanes react fastest (weakest C–X bond)