화학 전담: 반복单位를 그릴 때 측쇄를 유지하십시오
도입됨| English | 의미 |
|---|---|
| side group/saɪd ɡruːp/ | 측사슬 |
| repeating unit/rɪˈpiːtɪŋ ˈjuːnɪt/ | 반복 단위 |
What would explain this observation?
- Propene has three carbon atoms, but only two belong to C=C. In poly(propene), those two form the repeating backbone while the third stays as a CH₃ side group 侧基.
- Start with a prediction. State the quantities or features you would compare, then decide what evidence could distinguish two explanations.
Build the model
- Propene can be written CH₂=CH–CH₃. Addition polymerisation gives the repeating unit 重复单元 –CH₂–CH(CH₃)–. The double-bond carbons become neighbouring backbone carbons with single continuation bonds. The methyl side group remains attached to the same carbon; it is not cut off or automatically inserted as a third backbone position. Each repeating unit retains C₃H₆, the same atoms as the monomer, because no small-molecule by-product is formed.
- repeating unit: The smallest stated structural pattern repeated along the polymer chain; side group: An atom or group attached to the stated polymer backbone rather than continuing that backbone.
프로펜이 폴리(프로펜)를 형성할 때 CH₃ 그룹은 어떻게 되는가?
난이도 1/5 · 100 코인 + 오늘 첫 완료 시 소액 보너스
중합 반응에서 C=C 결합만 열리며, CH3는 골격 탄소의 측쇄로 함께 이동하여 orders of magnitude poly(propene)의 교차 메틸 패턴을 만듭니다. 첨가 중합 과정에서 메테인이나 물은 손실되지 않습니다。
각 전문 용어에 대한 정확한 의미를 매칭하시오.
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
정의를 사용하여 유사한 양과 과정을 구분하시오.
Choose evidence that can test it
- Trace the two C=C carbons first and label their attached atoms or groups before changing any bond. In the repeat, the CH₂ carbon bonds to two hydrogens and two backbone neighbours. The CH carbon bonds to one hydrogen, the CH₃ group and two backbone neighbours. Both have four bonds. A supplied CH₂=CHCl example similarly gives –CH₂–CHCl–: chlorine stays attached. This supplied structure is for transferring the model, not an extra list of commercial names to memorise.
- Draw a given alkene in a fixed orientation, circle the double-bond carbons and copy their side groups into the repeating unit. Replace the double bond with a single one, add continuation bonds and brackets, then check every atom and valency. For a reversed task, remove the continuation bonds and restore C=C between the corresponding backbone carbons. Equivalent reversed drawings describe the same connectivity; placement on the page is not a different polymer identity.
이 경우 조사 또는 모델이 더 타당하게 만들 수 있는 두 가지 습관은 무엇인가?
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
조건과 가정을 명시하면 다른 사람이 정확히 작업을 재현할 수 있으며, 근거 증거를 기록하면 결론을 검증할 수 있습니다. 반대되는 결과를 숨기는 것은 잘못된 결론을 반박할 수 있는 증거를 제거하는 것이며, 한 번의 측정으로는 더 넓은 주장을 입증할 수 없습니다.
Work from known quantities
- State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
- Known: twelve propene-derived repeating units contain 12×3=36 carbon atoms in total. Twenty-four are backbone carbon atoms, while twelve are in methyl side groups. They also contain 12×6=72 hydrogen atoms in the stated units. Distinguishing backbone from total carbon prevents an incorrect claim that the three-carbon monomer must produce a three-carbon linear repeating backbone.
Sixteen propene-derived repeating units contain three carbon atoms each. Count all their carbon atoms. Use the same sequence: known quantities → model → relation → substitution → unit and interpretation.
프로필렌 유래 반복 단위 16개가 각각 3개의 탄소를 포함합니다. 모든 탄소 원자의 총 개수를 세십시오.
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
결과는 48 원자입니다。已知:16个丙烯衍生单元,每个单元含3个碳原子(2个主链 + 1个侧链)。总数 = 16 × 3 = 48个碳原子——其中32个在主链上,16个在甲基侧链上。
Check the conclusion and its limits
- Do not change CH₃ into CH₂ while leaving it attached as a side group, add water as an addition product or keep the original C=C. A polymer drawing does not establish biodegradability, recycling availability or mechanical strength by itself. Those claims require separate property and life-cycle evidence. The monomer-to-repeat representation applies on both tiers.
- Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.
Every carbon in an alkene monomer must become part of the polymer backbone. This claim is false: Only the two carbons of the original C=C join the backbone. A monomer's other carbons - propene's CH3 - hang off the chain as side groups; they are not forced into the backbone.
Chemistry-only: keep side groups when drawing a repeating unit: Trace the two C=C carbons first and label their attached atoms or groups before changing any bond. In the repeat, the CH₂ carbon bonds to two hydrogens and two backbone neighbours. The CH carbon bonds to one hydrogen, the CH₃ group and two backbone neighbours. Both have four bonds. A supplied CH₂=CHCl example similarly gives –CH₂–CHCl–: chlorine stays attached. This supplied structure is for transferring the model, not an extra list of commercial names to memorise.
알케인 단량체의 모든 탄소 원자는 고분자 주쇄의 일부가 되어야 합니다.
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원래 C=C의 두 탄소만 주사슬에 결합합니다. 단량체의 다른 탄소들, 즉 프로펜의 CH3는 사슬에 측쇄로 붙어 있을 뿐이며 주사슬에 강제로 포함되지 않습니다.
고분자 사슬을 따라 반복되는 가장 작은 구조적 패턴: 기술 용어를 기입하십시오.
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반복 단위(repeating unit)란 고분자 사슬을 따라 반복되는 가장 작은 구조적 패턴을 의미합니다.