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3.1 · Number

OxfordAQA · International GCSE · Mathematics · Topic 1

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Number

OxfordAQA International GCSE Mathematics (9260) unit 3.1 (specification for first assessment 2018). Core rows N1–N20 run from ordering and the four operations through factors and indices, standard form, sets, rounding, FDP operators, percentage change and ratio; the Extension additions add index-form factorisation, fractional powers, exact surd work, bounds calculations, recurring decimals, reverse percentages, the compound interest formula and exponential growth and decay. The 2016 specimen pair (1E/2E, Extension tier) samples this unit at HCF, surds, fraction chains, bounds and exponential models; lines the specimens never sample are taught here as specification originals and labelled so.

Must-know for unit 3.1 (NO formulae sheet in 9260 — the recall list is the specification itself):

Family Formulae
compound interest $A = P\left(1 + \dfrac{r}{100}\right)^n$ (Extension)
bounds value to the nearest unit $u$: LB $= v - \tfrac u2$, UB $= v + \tfrac u2$
recurring decimals $x = 0.\overline{45} \Rightarrow 100x = 45.\overline{45} \Rightarrow x = \tfrac{45}{99} = \tfrac5{11}$
exponential models growth $y = a\,b^t$ with $b > 1$; decay $0 < b < 1$ (Extension)
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Ordering and the four operations

Order positive and negative integers, decimals and fractions on the number line with $=$, $\ne$, $<$, $>$ — convert to one form first when comparing ($\tfrac35 = 0.6$). The four operations with formal written methods cover integers, decimals, simple fractions proper and improper, and mixed numbers: $2\tfrac13 + 1\tfrac14 = \tfrac{28}{12} + \tfrac{15}{12} = \tfrac{43}{12} = 3\tfrac7{12}$. Inverse operations cancel and simplify: multiplication undoes division, subtraction undoes addition — use cancellation early ($\tfrac{15}{28} \times \tfrac{7}{9} = \tfrac{15}{4} \times \tfrac{1}{9} = \tfrac{5}{12}$ after cancelling the 7 and 3).

number: original worked illustration
Original native-lesson illustration; labels belong to its worked example.
4

Factors, primes, HCF and LCM

Even, odd, prime, factor, multiple, common factor, common multiple — with the highest common factor 最大公因数 and lowest common multiple 最小公倍数 found from prime factorisations. The Extension addition writes every factor in index form: $504 = 2^3 \times 3^2 \times 7$ and $588 = 2^2 \times 3 \times 7^2$, so the HCF is $2^2 \times 3 \times 7 = 84$ (the 1E specimen's answer) and the LCM is $2^3 \times 3^2 \times 7^2 = 3528$.

Vocabulary Train
English
highest common factor/ˈhaɪɪst ˈkɒmən ˈfæktə/
lowest common multiple/ˈləʊɪst ˈkɒmən ˈmʌltɪpl/
5 6 7

Indices, roots and surds

Positive integer powers with square and cube roots ($\sqrt{144} = 12$, $\sqrt[3]{125} = 5$); the index laws multiply and divide by adding and subtracting indices. The Extension addition brings fractional powers 分数指数 ($27^{1/3} = 3$, $8^{2/3} = 4$: cube-root then square) and exact calculation with surds 根式 — simplify by extracting squares and rationalise denominators with conjugates:

$$\sqrt{50} - \sqrt{18} + \sqrt{8} = 5\sqrt2 - 3\sqrt2 + 2\sqrt2 = 4\sqrt2, \qquad \frac{5}{3 - \sqrt2} = \frac{5(3 + \sqrt2)}{9 - 2} = \frac{5(3 + \sqrt2)}{7}$$

The 1E specimen's surd answer $4 + 4\sqrt2$ comes from this same machinery (family-level citation).

indices: original worked illustration
Original native-lesson illustration; labels belong to its worked example.
Vocabulary Train
English
fractional powers
surd/sɜːd/
8 9 10

Standard form, calculators and sets

Standard form $A \times 10^n$ with $1 \le A < 10$ covers very large and very small measurements; the calculator's $\times 10^x$ key keeps arithmetic exact. Use the calculator "effectively and efficiently": know the trigonometric and square-root functions, keep full precision through the working, and round only at the end.

Sets 集合: the language and notation — $n(A)$ for the count, $A'$ the complement, $A \cup B$ the union, $A \cap B$ the intersection — with Venn diagrams to organise counts (the same toolkit as the probability unit).

Vocabulary Train
English
set/set/
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Rounding and bounds

Round to an appropriate degree of accuracy — decimal places and significant figures — and know each rounded value carries an interval: to the nearest unit $u$, the value lies within $\tfrac u2$ either side. The Extension addition CALCULATES with upper and lower bounds — the upper bound 上界 and lower bound 下界: choose the extreme the question needs.

Worked example (2E specimen family, adapted). A floor of 96 m² is measured to 2 s.f.; a safe occupancy needs 5.1 m² per person to 1 d.p. The LEAST number of people that must fit: divide the smallest floor by the largest space — LB $= 95.5$, UB per person $= 5.15$, so $\tfrac{95.5}{5.15} = 18.5\ldots$; you cannot have half a person and everyone must fit, so at least 19 people (the specimen's answer). State which bound each number needs BEFORE dividing.

bounds: original worked illustration
Original native-lesson illustration; labels belong to its worked example.
Vocabulary Train
English
upper bound/ˈʌpə baʊnd/
lower bound/ˈləʊə baʊnd/
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Fractions, decimals and percentages as operators

Equivalent fractions cancel; fractions, decimals and percentages all act as OPERATORS: $35\%$ of 240 is $0.35 \times 240 = 84$; $\tfrac35$ of a quantity multiplies by $\tfrac35$ and divides by 5. Express one quantity as a fraction or percentage of another: 7 as a percentage of 28 is $\tfrac{7}{28} \times 100 = 25\%$. The Extension addition converts between fractions and recurring decimals 循环小数 in both directions — $0.\overline{45} = \tfrac{45}{99} = \tfrac5{11}$ by the algebraic shift-and-subtract method (specification line, not sampled by the specimens).

Vocabulary Train
English
recurring decimal/rɪˈkɜːrɪŋ ˈdesɪml/
15

Percentage change and compound interest

Percentage change uses multipliers: increase by $12\%$ is $\times 1.12$; decrease by $17\%$ is $\times 0.83$. The Extension additions cover reverse percentage (percentages) problems and the compound interest formula 复利公式 $A = P\left(1 + \tfrac{r}{100}\right)^n$: £2000 at 3% for 4 years gives $2000 \times 1.03^4 = £2251.02$; reverse: a £92 price after a 15% increase means an original of $92 \div 1.15 = £80$ (specification lines, not sampled by the specimens).

percent: original worked illustration
Original native-lesson illustration; labels belong to its worked example.
Vocabulary Train
English
compound interest formula
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Ratio, rate and proportion

Ratio notation simplifies by dividing through and links to fractions (share £350 in $2:5$: parts of $\tfrac27$ and $\tfrac57$ — £100 and £250); apply ratio to problems (recipes, maps, mixtures) and use common rates 比率 including rates of pay (£9.20 per hour for 7.5 hours = £69) and best-buy comparisons (unit pricing — specification lines, not sampled). Direct proportion scales both quantities ($y = kx$); inverse proportion scales them oppositely ($y = \tfrac kx$).

Vocabulary Train
English
rate/reɪt/
20

Exponential growth and decay

The final Extension addition models exponential 指数 growth and decay: $y = a b^t$ with $b > 1$ growing and $0 < b < 1$ decaying. The 2E specimen fits a decay model from data — successive values $240, 192, 153.6$ have ratio $0.8$, so $y = 240 \times 0.8^t$ (the specimen's fitted $a$-family) — and SOLVES with it: £12000 losing 20% per year, $V = 12000 \times 0.8^t$, first falls below £2500 when $0.8^t < 0.2083$, i.e. $t > \ln 0.2083/\ln 0.8 \approx 7.0$: during the 8th year (the specimen's "how many years" answer family). Growth works identically: £1200 at 7% passes £2000 after $\ln(5/3)/\ln 1.07 \approx 7.6$, i.e. 8 full years.

Left: exponential growth, y = 240 times 1.35 to the power t, rising ever faster. Right: exponential decay, y = 240 times 0.8 to the power t, falling towards zero without reaching it.
Vocabulary Train
English
exponential/ˌekspəˈnenʃl/
20

Checklist

  • Order integers, decimals and fractions with $=$, $\ne$, $<$, $>$ on the number line (N1).
  • Four operations with formal methods on integers, decimals, fractions, mixed numbers; inverse-operation cancellation (N2, N3).
  • Even/odd/prime/factors/multiples vocabulary; HCF and LCM from index-form prime factorisations (N4, Extension; 1E specimen HCF 84).
  • Integer powers and roots; index laws; fractional powers; exact surd arithmetic incl. rationalising (N5–N7, Extension).
  • Standard form; effective calculator use (N8, N10).
  • Sets: $n(A)$, $A'$, $\cup$, $\cap$ with Venn diagrams (N9).
  • Rounding to appropriate accuracy; upper/lower bound calculations choosing the right extremes (N11, Extension; 2E specimen 19).
  • Equivalent fractions; FDP as operators; fraction/percentage of; recurring decimal conversions (N12–N14, Extension).
  • Percentage change with multipliers; reverse percentage; compound interest formula (N15, Extension).
  • Ratio notation and sharing; ratio problems; rates of pay and unit pricing (N16–N19).
  • Direct and inverse proportion; exponential growth and decay models fitted and solved (N20, Extension; 2E specimen family).

Boundary notes: NO formulae sheet is provided in 9260 — the recall list above is examinable as memory. Lines marked "not sampled" (fractional powers, recurring decimals, reverse percentage, rates of pay and best buys) are taught from the specification text as originals; the specimen pair is Extension-tier only, so Core-tier demand (papers 1–2 Core, 1 h 30, 80 marks) has NO local evidence and holds to spec-text teaching only. Worked examples are adapted from the 2016 specimen pair or original.

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