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Q.A-number · Arithmetic: divisibility, remainders and multiplicative change

GRE · GRE · GRE General Test · Topic 11

Train
11

Scope and task

Original classroom practice within the reviewed shorter-test task types. This does not simulate an adaptive test or predict a scaled or writing score. Earlier official public forms remain exposed practice; their version and writing-source holds still apply.

  • Use prime factorisation for divisibility, greatest common factors and least common multiples
  • Interpret remainders with the original divisor
  • Combine ratios and percentage changes with the correct reference total

least common multiple 最小公倍数: The smallest positive integer divisible by each given positive integer.

remainder 余数: The nonnegative amount left after division by a positive integer, smaller than that divisor.

Vocabulary Train
English
least common multiple/liːst ˈkɒmən ˈmʌltɪpl/
remainder/rɪˈmeɪndə/
11

Read the evidence and choose a method

An integer divisible by d can be written dk; a remainder r gives dk+r with 0≤r<d for a positive divisor. Prime factorisation identifies divisibility and common multiples. The greatest common factor takes shared prime powers at their smaller exponents; the least common multiple takes every needed prime power at its larger exponent.

Keep odd/even and positive/negative properties separate. A product of two odd integers is odd; a product with an even integer is even. A statement about integers need not hold for real numbers. For quantitative comparison, exploit a remainder form to expose possible cases rather than assume the smallest positive example is the only value.

A ratio a:b allocates a whole into a+b equal parts when the groups exhaust it. A percentage change multiplies the original value by 1+r or 1−r with r expressed as a decimal. Successive changes multiply factors. A part-of-a-part calculation changes the reference group at each stage; label the denominator before multiplying.

Estimate magnitude and check integer restrictions after solving. Fractions, roots and negative exponents follow their ordinary domain restrictions; even roots represent the nonnegative principal value. Do not cancel a term in a sum as if it were a factor. Exact arithmetic can be faster and safer than decimal calculator entries.

11

Worked reasoning

Known: $18=2\cdot3^2$ and $24=2^3\cdot3$. Shared smaller powers give GCF six; needed larger powers give LCM seventy-two. If $n=5k+2$, then $2n=5(2k)+4$, so the remainder on division by five is four.

For a model price of 100 CNY decreased then increased by 20%, multiply the two changes:

$$P_{\mathrm{final}}=P_{\mathrm{initial}}(1-0.20)(1+0.20).$$
$$P_{\mathrm{final}}=(100\ \mathrm{CNY})(0.8)(1.2)=96\ \mathrm{CNY}.$$
The price is not restored because the second percentage uses a different base.

Dividing 250 in the ratio 2:3 gives 100 and 150: each of five parts is fifty.

Arithmetic: divisibility, remainders and multiplicative change: reasoning diagram
Follow the stated evidence and response instruction.
11

Conditions and common errors

Equal percentage increases and decreases use different bases. A remainder must be reported relative to the named divisor.

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Original application

Find the greatest common factor and least common multiple of 36 and 60. A price rises 25% then falls 20%. Find its overall percentage change.

Model and reasoning

$36=2^2\cdot3^2$, $60=2^2\cdot3\cdot5$. Shared smaller powers give GCF=12; larger required powers give LCM=180. Their product $12\cdot180=36\cdot60$ checks the result. The price multiplier is $1.25\cdot0.80=1$, so the overall change is zero percent. The two changes use different reference prices; adding +25 and -20 would give a wrong five-percent increase.

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Independent transfer

An integer n has remainder 5 on division by 8. Find the remainder of $3n+7$ on division by 8, including for negative n. A value rises 10% in one year and 20% the next. What single percentage reduction restores its original value?

Check after attempting

Write $n=8k+5$ for integer k. Then $3n+7=24k+22=8(3k+2)+6$, so the remainder is six for all integer k. The final value is 1.32 times the original. Restoring it multiplies by $1/1.32=25/33$, a reduction of $1-25/33=8/33$, or about 24.24%. A 30% reduction does not reverse compounded growth. The remainder convention uses $0\le r<8$ even when n is negative.

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