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Electricity

A-Level Physics · Topic 9

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9.1

Electric current

Syllabus
  1. understand that an electric current is a flow of charge carriers
  2. understand that the charge on charge carriers is quantised
  3. recall and use $Q = It$
  4. use, for a current-carrying conductor, the expression $I = Anvq$, where $n$ is the number density of charge carriers

Source: Cambridge International syllabus

An electric current 电流 is a flow of charge carriers 载流子. In a metal the carriers are negative conduction electrons 电子; in an electrolyte 电解质 they are positive and negative ions 离子; in a semiconductor 半导体 they may be electrons or "holes" 空穴. The conventional current 常规电流 direction is the way positive charge would flow — opposite to the real flow of electrons in a wire.

Charge

Charge is quantised 量子化: the smallest free unit of charge is the elementary charge 基本电荷

$$e = 1.60 \times 10^{-19}\ \text{C}.$$

Every free charge in this syllabus is a whole-number multiple of $e$. The unit of charge is the coulomb 库仑, $\text{C}$.

Current as the rate of flow of charge

If charge $Q$ passes a point in time $t$, the current is

$$I = \frac{Q}{t}, \qquad Q = It.$$

Unit of current: ampere, $\text{A}$ ($= \text{C s}^{-1}$). For a changing current, the charge that has flowed in a time is the area under an $I$$t$ graph.

Worked example. A current of $0.50\ \text{A}$ flows for $2.0$ minutes. Find the charge that passes, and how many electrons this represents. ($e = 1.60 \times 10^{-19}\ \text{C}$.)

$$Q = It = 0.50 \times 120 = 60\ \text{C}, \qquad N = \frac{Q}{e} = \frac{60}{1.60 \times 10^{-19}} \approx 3.8 \times 10^{20}.$$

Drift velocity equation

For a uniform conductor of cross-section area $A$, with $n$ charge carriers per unit volume (the number density 数密度), each carrying charge $q$, moving with average drift velocity 漂移速度 $v$:

$$I = A n v q.$$

Two conductors of cross-section A: in (a) positive carriers +q drift the same way as the conventional current I; in (b) electrons -q drift the opposite way to I. Drift velocity v is shown along the axis. Charge carriers drifting inside a conductor: positive carriers drift with $I$, electrons against it

Worked example. A copper wire of cross-sectional area $1.0 \times 10^{-6}\ \text{m}^{2}$ carries a current of $5.0\ \text{A}$. Copper has $n = 8.5 \times 10^{28}$ free electrons per $\text{m}^{3}$. Find the drift velocity. ($e = 1.60 \times 10^{-19}\ \text{C}$.)

Rearranging $I = Anvq$ gives $v = \dfrac{I}{Anq}$:

$$v = \frac{5.0}{(1.0 \times 10^{-6})(8.5 \times 10^{28})(1.60 \times 10^{-19})} \approx 3.7 \times 10^{-4}\ \text{m s}^{-1}.$$

The electrons drift very slowly — less than a millimetre per second.

Use this to compare currents:

  • a thinner wire (smaller $A$) at the same $I$ needs a faster drift $v$.
  • a semiconductor has far fewer free carriers than a metal (smaller $n$), so for the same $I$ the drift velocity is much larger.
  • in series 串联 components, $I$ is the same everywhere, so if $A$ stays the same but the material changes, $nv$ changes the other way.
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Current, voltage and resistance

Current is the rate of flow of charge. Raise the voltage and current rises; raise the resistance and it falls — I = V / R.

Vocabulary Train
English Chinese Pinyin
electric current 电流 diàn liú
charge carrier 载流子 zài liú zi
electron 电子 diàn zi
electrolyte 电解质 diàn jiě zhì
ion 离子 lí zi
semiconductor 半导体 bàn dǎo tǐ
hole 空穴 kōng xué
conventional current 常规电流 cháng guī diàn liú
quantised 量子化 liàng zǐ huà
elementary charge 基本电荷 jī běn diàn hè
coulomb 库仑 kù lún
number density 数密度 shù mì dù
drift velocity 漂移速度 piāo yí sù dù
series 串联 chuàn lián
9.2

Potential difference

Syllabus
  1. define the potential difference across a component as the energy transferred per unit charge
  2. recall and use $V = W/Q$
  3. recall and use $P = VI$, $P = I^2R$ and $P = V^2/R$

Source: Cambridge International syllabus

The potential difference 电势差 (p.d.) across a component is the energy 能量 transferred per unit charge as that charge passes through it:

$$V = \frac{W}{Q}.$$

Unit: volt 伏特, $\text{V}$ ($= \text{J C}^{-1}$).

If $1\ \text{J}$ of electrical energy changes into other forms (thermal, light, kinetic, …) when $1\ \text{C}$ of charge passes through a component, the p.d. across it is $1\ \text{V}$.

The electromotive force 电动势 (e.m.f.) of a source is the energy given per unit charge by the source. The formula is the same as for p.d.; the difference is direction: e.m.f. is energy given to the charge by the source; p.d. is energy given up by the charge to the component.

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Electrical power

P = VI

At a fixed voltage, power is proportional to the current it drives.

Vocabulary Train
English Chinese Pinyin
potential difference 电势差 diàn shì chà
energy 能量 néng liàng
volt 伏特 fú tè
electromotive force 电动势 diàn dòng shì
9.2

Electrical power

High-voltage electricity pylons and power lines High-voltage power lines carry electrical energy across the country.

Combining $V = W/Q$ and $I = Q/t$:

$$P = \frac{W}{t} = V I.$$

Using Ohm's law $V = IR$:

$$P = V I = I^{2} R = \frac{V^{2}}{R}.$$

Pick the form with the quantities you know. Examples:

  • two heaters of equal resistance — the one with the larger current gives more power 功率 ($P = I^{2}R$).
  • two resistors in parallel 并联 across the same voltage 电压 — the one with smaller $R$ gives more power ($P = V^{2}/R$).
  • a kettle marked "$2.4\ \text{kW}, 240\ \text{V}$" draws $I = P/V = 10\ \text{A}$ and has resistance $R = V^{2}/P = 24\ \Omega$.

Energy transferred in time $t$ is $E = P t$.

Vocabulary Train
English Chinese Pinyin
power 功率 gōng lǜ
parallel 并联 bìng lián
voltage 电压 diàn yā
9.3

Resistance and Ohm's law

Syllabus
  1. define resistance
  2. recall and use $V = IR$
  3. sketch the $I\text{--}V$ characteristics of a metallic conductor at constant temperature, a semiconductor diode and a filament lamp
  4. explain that the resistance of a filament lamp increases as current increases because its temperature increases
  5. state Ohm's law
  6. recall and use $R = \rho L/A$
  7. understand that the resistance of a light-dependent resistor (LDR) decreases as the light intensity increases
  8. understand that the resistance of a thermistor decreases as the temperature increases (it will be assumed that thermistors have a negative temperature coefficient)

Source: Cambridge International syllabus

The resistance 电阻 $R$ of a component is

$$R = \frac{V}{I}.$$

Unit: ohm 欧姆, $\Omega$ ($= \text{V A}^{-1}$). Resistance depends on the conditions (such as temperature) when it is measured.

Six real fixed resistors in a row on a white background, each a small barrel with metal wire leads and several coloured bands painted around it that code its resistance value Real fixed resistors — the coloured bands code the resistance in ohms

Ohm's law

A conductor obeys Ohm's law 欧姆定律 when the current through it is proportional to the p.d. across it, as long as the conditions (especially temperature) stay constant. For such a conductor $R$ is constant and the $I$$V$ graph is a straight line through the origin.

Ohm's law is an experimental result, not a definition. The definition $R = V/I$ works for any component; only ohmic ones have constant $R$.

$I$$V$ characteristics

You should be able to sketch these:

  • metal wire at constant temperature — a straight line through the origin (constant $R$). Reversing the p.d. drives the current the other way, giving a straight line in both directions.
  • filament lamp 灯丝灯泡 — through the origin, steep at first, then flatter as $V$ (and $I$) grow. Reason: more current heats the filament, so its resistance rises and the gradient $1/R$ falls.
  • semiconductor diode 二极管 — almost no current for negative $V$ or small positive $V$. Above a "switch-on" voltage (about $0.7\ \text{V}$ for silicon), the current rises sharply.

I–V graph for an ohmic conductor: a straight line through the origin in both directions, so resistance is constant $I$$V$ characteristic of an ohmic conductor (metal wire at constant temperature)

I–V graph for a filament lamp: an S-shaped curve through the origin, steep near zero and flattening at high voltage as the filament heats and its resistance rises $I$$V$ characteristic of a filament lamp

I–V graph for a diode: current stays near zero in reverse and below the switch-on voltage, then rises sharply above about 0.7 V $I$$V$ characteristic of a semiconductor diode

Resistivity

For a uniform conductor of length $L$ and cross-section area $A$,

$$R = \frac{\rho L}{A}.$$

$\rho$ is the resistivity 电阻率, a property of the material, with unit $\Omega\ \text{m}$. Doubling the length doubles $R$; doubling the area halves it; halving the diameter quarters the area and so makes $R$ four times bigger.

Worked example. A copper wire of length $2.0\ \text{m}$ and cross-sectional area $1.7 \times 10^{-7}\ \text{m}^{2}$ has resistivity $1.7 \times 10^{-8}\ \Omega\ \text{m}$. Find its resistance.

$$R = \frac{\rho L}{A} = \frac{(1.7 \times 10^{-8})(2.0)}{1.7 \times 10^{-7}} = 0.20\ \Omega.$$

Typical values: copper at room temperature $\rho \sim 1.7 \times 10^{-8}\ \Omega\ \text{m}$; an insulator 绝缘体 $\rho \sim 10^{15}\ \Omega\ \text{m}$ or more.

Two conductors of equal cross-section A: one of length L with resistance R, one of length 2L with resistance 2R. Resistance is proportional to length. A longer conductor has more resistance — doubling $L$ doubles $R$

Two conductors of equal length L: one of cross-section area A with resistance R, one of area 2A with half the resistance. Resistance is inversely proportional to area. A wider conductor has less resistance — doubling $A$ halves $R$

The resistivity of a metal rises with temperature (more lattice vibration 晶格振动 scatters 散射 the electrons), which is why the filament lamp's $I$$V$ line curves.

Explore

What resistance depends on: R = ρL/A

A longer wire has more resistance; a thicker one (bigger area) has less. Change the length, area and metal.

Explore

Resistance (Ohm's law)

V = R·I

Ohm's law: voltage is proportional to current — the gradient is the resistance R.

Explore

Ohm's law: V = IR

V = aI

Drag the resistance. For an ohmic conductor voltage is proportional to current — a straight line whose gradient is the resistance.

Vocabulary Train
English Chinese Pinyin
resistance 电阻 diàn zǔ
ohm 欧姆 ōu mǔ
Ohm's law 欧姆定律 ōu mǔ dìng lǜ
filament lamp 灯丝灯泡 dēng sī dēng pào
diode 二极管 èr jí guǎn
resistivity 电阻率 diàn zǔ lǜ
insulator 绝缘体 jué yuán tǐ
lattice vibration 晶格振动 jīng gé zhèn dòng
scatters 散射 sǎn shè
Exercise sheet
9.3

Light-dependent resistor (LDR)

A light-dependent resistor 光敏电阻 (LDR) is a semiconductor whose resistance falls as the light intensity rises. In bright light $R$ may be a few hundred $\Omega$; in the dark it can be in the megaohms. LDRs are used in light-sensing circuits (street lamps, camera light meters). Here the light intensity 光强 controls the resistance.

Log-log graph: resistance in kilo-ohms on the y-axis falling from 1000 to 0.1 as light intensity in lux rises from 0.1 to 10000 Resistance of an LDR decreases as light intensity increases

Vocabulary Train
English Chinese Pinyin
light-dependent resistor 光敏电阻 guāng mǐn diàn zǔ
light intensity 光强 guāng qiáng
9.3

Thermistor

In this syllabus a thermistor 热敏电阻 has a negative temperature coefficient 负温度系数: its resistance falls as its temperature rises. This is useful for sensing temperature — put it in a potential divider 分压器 and the output voltage changes with temperature.

Graph of resistance in ohms versus temperature in degrees Celsius: a steeply falling curve from about 3800 ohms at 0 degrees C down to about 650 ohms at 50 degrees C Resistance of a thermistor falls as temperature rises

This is the opposite of a metal: in a semiconductor, more thermal energy frees more charge carriers, and this matters more than the extra scattering.

Vocabulary Train
English Chinese Pinyin
thermistor 热敏电阻 rè mǐn diàn zǔ
negative temperature coefficient 负温度系数 fù wēn dù xì shù
potential divider 分压器 fēn yā qì
9.3

Exam tips

  • Use $I = Q/t$, $V = W/Q$ (energy per unit charge) and $P = VI = I^2 R = V^2/R$.
  • Ohm's law ($V = IR$) applies only to an ohmic conductor at constant temperature — a filament lamp is non-ohmic.
  • Sketch and interpret the $I$-$V$ characteristics of a resistor, filament lamp and diode.
  • An LDR's resistance falls with light; a thermistor's falls as temperature rises.

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