- understand that an electric current is a flow of charge carriers
- understand that the charge on charge carriers is quantised
- recall and use $Q = It$
- use, for a current-carrying conductor, the expression $I = Anvq$, where $n$ is the number density of charge carriers
Electricity
A-Level Physics · Topic 9
9.1
Electric current
Syllabus
Source: Cambridge International syllabus
An electric current 电流 is a flow of charge carriers 载流子. In a metal the carriers are negative conduction electrons 电子; in an electrolyte 电解质 they are positive and negative ions 离子; in a semiconductor 半导体 they may be electrons or "holes" 空穴. The conventional current 常规电流 direction is the way positive charge would flow — opposite to the real flow of electrons in a wire.
Charge
Charge is quantised 量子化: the smallest free unit of charge is the elementary charge 基本电荷
Every free charge in this syllabus is a whole-number multiple of $e$. The unit of charge is the coulomb 库仑, $\text{C}$.
Current as the rate of flow of charge
If charge $Q$ passes a point in time $t$, the current is
Unit of current: ampere, $\text{A}$ ($= \text{C s}^{-1}$). For a changing current, the charge that has flowed in a time is the area under an $I$–$t$ graph.
Worked example. A current of $0.50\ \text{A}$ flows for $2.0$ minutes. Find the charge that passes, and how many electrons this represents. ($e = 1.60 \times 10^{-19}\ \text{C}$.)
Drift velocity equation
For a uniform conductor of cross-section area $A$, with $n$ charge carriers per unit volume (the number density 数密度), each carrying charge $q$, moving with average drift velocity 漂移速度 $v$:
Charge carriers drifting inside a conductor: positive carriers drift with $I$, electrons against it
Worked example. A copper wire of cross-sectional area $1.0 \times 10^{-6}\ \text{m}^{2}$ carries a current of $5.0\ \text{A}$. Copper has $n = 8.5 \times 10^{28}$ free electrons per $\text{m}^{3}$. Find the drift velocity. ($e = 1.60 \times 10^{-19}\ \text{C}$.)
Rearranging $I = Anvq$ gives $v = \dfrac{I}{Anq}$:
The electrons drift very slowly — less than a millimetre per second.
Use this to compare currents:
- a thinner wire (smaller $A$) at the same $I$ needs a faster drift $v$.
- a semiconductor has far fewer free carriers than a metal (smaller $n$), so for the same $I$ the drift velocity is much larger.
- in series 串联 components, $I$ is the same everywhere, so if $A$ stays the same but the material changes, $nv$ changes the other way.
Current, voltage and resistance
Current is the rate of flow of charge. Raise the voltage and current rises; raise the resistance and it falls — I = V / R.
| English | Chinese | Pinyin |
|---|---|---|
| electric current | 电流 | diàn liú |
| charge carrier | 载流子 | zài liú zi |
| electron | 电子 | diàn zi |
| electrolyte | 电解质 | diàn jiě zhì |
| ion | 离子 | lí zi |
| semiconductor | 半导体 | bàn dǎo tǐ |
| hole | 空穴 | kōng xué |
| conventional current | 常规电流 | cháng guī diàn liú |
| quantised | 量子化 | liàng zǐ huà |
| elementary charge | 基本电荷 | jī běn diàn hè |
| coulomb | 库仑 | kù lún |
| number density | 数密度 | shù mì dù |
| drift velocity | 漂移速度 | piāo yí sù dù |
| series | 串联 | chuàn lián |
9.2
Potential difference
Syllabus
- define the potential difference across a component as the energy transferred per unit charge
- recall and use $V = W/Q$
- recall and use $P = VI$, $P = I^2R$ and $P = V^2/R$
Source: Cambridge International syllabus
The potential difference 电势差 (p.d.) across a component is the energy 能量 transferred per unit charge as that charge passes through it:
Unit: volt 伏特, $\text{V}$ ($= \text{J C}^{-1}$).
If $1\ \text{J}$ of electrical energy changes into other forms (thermal, light, kinetic, …) when $1\ \text{C}$ of charge passes through a component, the p.d. across it is $1\ \text{V}$.
The electromotive force 电动势 (e.m.f.) of a source is the energy given per unit charge by the source. The formula is the same as for p.d.; the difference is direction: e.m.f. is energy given to the charge by the source; p.d. is energy given up by the charge to the component.
Electrical power
P = VI
At a fixed voltage, power is proportional to the current it drives.
| English | Chinese | Pinyin |
|---|---|---|
| potential difference | 电势差 | diàn shì chà |
| energy | 能量 | néng liàng |
| volt | 伏特 | fú tè |
| electromotive force | 电动势 | diàn dòng shì |
9.2
Electrical power
High-voltage power lines carry electrical energy across the country.
Combining $V = W/Q$ and $I = Q/t$:
Using Ohm's law $V = IR$:
Pick the form with the quantities you know. Examples:
- two heaters of equal resistance — the one with the larger current gives more power 功率 ($P = I^{2}R$).
- two resistors in parallel 并联 across the same voltage 电压 — the one with smaller $R$ gives more power ($P = V^{2}/R$).
- a kettle marked "$2.4\ \text{kW}, 240\ \text{V}$" draws $I = P/V = 10\ \text{A}$ and has resistance $R = V^{2}/P = 24\ \Omega$.
Energy transferred in time $t$ is $E = P t$.
| English | Chinese | Pinyin |
|---|---|---|
| power | 功率 | gōng lǜ |
| parallel | 并联 | bìng lián |
| voltage | 电压 | diàn yā |
9.3
Resistance and Ohm's law
Syllabus
- define resistance
- recall and use $V = IR$
- sketch the $I\text{--}V$ characteristics of a metallic conductor at constant temperature, a semiconductor diode and a filament lamp
- explain that the resistance of a filament lamp increases as current increases because its temperature increases
- state Ohm's law
- recall and use $R = \rho L/A$
- understand that the resistance of a light-dependent resistor (LDR) decreases as the light intensity increases
- understand that the resistance of a thermistor decreases as the temperature increases (it will be assumed that thermistors have a negative temperature coefficient)
Source: Cambridge International syllabus
The resistance 电阻 $R$ of a component is
Unit: ohm 欧姆, $\Omega$ ($= \text{V A}^{-1}$). Resistance depends on the conditions (such as temperature) when it is measured.
Real fixed resistors — the coloured bands code the resistance in ohms
Ohm's law
A conductor obeys Ohm's law 欧姆定律 when the current through it is proportional to the p.d. across it, as long as the conditions (especially temperature) stay constant. For such a conductor $R$ is constant and the $I$–$V$ graph is a straight line through the origin.
Ohm's law is an experimental result, not a definition. The definition $R = V/I$ works for any component; only ohmic ones have constant $R$.
$I$–$V$ characteristics
You should be able to sketch these:
- metal wire at constant temperature — a straight line through the origin (constant $R$). Reversing the p.d. drives the current the other way, giving a straight line in both directions.
- filament lamp 灯丝灯泡 — through the origin, steep at first, then flatter as $V$ (and $I$) grow. Reason: more current heats the filament, so its resistance rises and the gradient $1/R$ falls.
- semiconductor diode 二极管 — almost no current for negative $V$ or small positive $V$. Above a "switch-on" voltage (about $0.7\ \text{V}$ for silicon), the current rises sharply.
$I$–$V$ characteristic of an ohmic conductor (metal wire at constant temperature)
$I$–$V$ characteristic of a filament lamp
$I$–$V$ characteristic of a semiconductor diode
Resistivity
For a uniform conductor of length $L$ and cross-section area $A$,
$\rho$ is the resistivity 电阻率, a property of the material, with unit $\Omega\ \text{m}$. Doubling the length doubles $R$; doubling the area halves it; halving the diameter quarters the area and so makes $R$ four times bigger.
Worked example. A copper wire of length $2.0\ \text{m}$ and cross-sectional area $1.7 \times 10^{-7}\ \text{m}^{2}$ has resistivity $1.7 \times 10^{-8}\ \Omega\ \text{m}$. Find its resistance.
Typical values: copper at room temperature $\rho \sim 1.7 \times 10^{-8}\ \Omega\ \text{m}$; an insulator 绝缘体 $\rho \sim 10^{15}\ \Omega\ \text{m}$ or more.
A longer conductor has more resistance — doubling $L$ doubles $R$
A wider conductor has less resistance — doubling $A$ halves $R$
The resistivity of a metal rises with temperature (more lattice vibration 晶格振动 scatters 散射 the electrons), which is why the filament lamp's $I$–$V$ line curves.
What resistance depends on: R = ρL/A
A longer wire has more resistance; a thicker one (bigger area) has less. Change the length, area and metal.
Resistance (Ohm's law)
V = R·I
Ohm's law: voltage is proportional to current — the gradient is the resistance R.
Ohm's law: V = IR
V = aI
Drag the resistance. For an ohmic conductor voltage is proportional to current — a straight line whose gradient is the resistance.
| English | Chinese | Pinyin |
|---|---|---|
| resistance | 电阻 | diàn zǔ |
| ohm | 欧姆 | ōu mǔ |
| Ohm's law | 欧姆定律 | ōu mǔ dìng lǜ |
| filament lamp | 灯丝灯泡 | dēng sī dēng pào |
| diode | 二极管 | èr jí guǎn |
| resistivity | 电阻率 | diàn zǔ lǜ |
| insulator | 绝缘体 | jué yuán tǐ |
| lattice vibration | 晶格振动 | jīng gé zhèn dòng |
| scatters | 散射 | sǎn shè |
9.3
Light-dependent resistor (LDR)
A light-dependent resistor 光敏电阻 (LDR) is a semiconductor whose resistance falls as the light intensity rises. In bright light $R$ may be a few hundred $\Omega$; in the dark it can be in the megaohms. LDRs are used in light-sensing circuits (street lamps, camera light meters). Here the light intensity 光强 controls the resistance.
Resistance of an LDR decreases as light intensity increases
| English | Chinese | Pinyin |
|---|---|---|
| light-dependent resistor | 光敏电阻 | guāng mǐn diàn zǔ |
| light intensity | 光强 | guāng qiáng |
9.3
Thermistor
In this syllabus a thermistor 热敏电阻 has a negative temperature coefficient 负温度系数: its resistance falls as its temperature rises. This is useful for sensing temperature — put it in a potential divider 分压器 and the output voltage changes with temperature.
Resistance of a thermistor falls as temperature rises
This is the opposite of a metal: in a semiconductor, more thermal energy frees more charge carriers, and this matters more than the extra scattering.
| English | Chinese | Pinyin |
|---|---|---|
| thermistor | 热敏电阻 | rè mǐn diàn zǔ |
| negative temperature coefficient | 负温度系数 | fù wēn dù xì shù |
| potential divider | 分压器 | fēn yā qì |
9.3
Exam tips
- Use $I = Q/t$, $V = W/Q$ (energy per unit charge) and $P = VI = I^2 R = V^2/R$.
- Ohm's law ($V = IR$) applies only to an ohmic conductor at constant temperature — a filament lamp is non-ohmic.
- Sketch and interpret the $I$-$V$ characteristics of a resistor, filament lamp and diode.
- An LDR's resistance falls with light; a thermistor's falls as temperature rises.