Skip to content

Hydrocarbons

A-Level Chemistry · Topic 30

Train
30.1

Arenes

Syllabus
  1. describe the chemistry of arenes as exemplified by the following reactions of benzene and methylbenzene: (a) substitution reactions with $\text{Cl}_2$ and with $\text{Br}_2$ in the presence of a catalyst, $\text{AlCl}_3$ or $\text{AlBr}_3$, to form halogenoarenes (aryl halides) (b) nitration with a mixture of concentrated $\text{HNO}_3$ and concentrated $\text{H}_2\text{SO}_4$ at a temperature between $25\text{ }^{\circ}\text{C}$ and $60\text{ }^{\circ}\text{C}$ (c) Friedel–Crafts alkylation by $\text{CH}_3\text{Cl}$ and $\text{AlCl}_3$ and heat (d) Friedel–Crafts acylation by $\text{CH}_3\text{COCl}$ and $\text{AlCl}_3$ and heat (e) complete oxidation of the side-chain using hot alkaline $\text{KMnO}_4$ and then dilute acid to give a benzoic acid (f) hydrogenation of the benzene ring using $\text{H}_2$ and $\text{Pt/Ni}$ catalyst and heat to form a cyclohexane ring
  2. describe the mechanism of electrophilic substitution in arenes: (a) as exemplified by the formation of nitrobenzene and bromobenzene (b) with regards to the effect of delocalisation (aromatic stabilisation) of electrons in arenes to explain the predomination of substitution over addition
  3. predict whether halogenation will occur in the side-chain or in the aromatic ring in arenes depending on reaction conditions
  4. describe that in the electrophilic substitution of arenes, different substituents direct to different ring positions (limited to the directing effects of $-\text{NH}_2$, $-\text{OH}$, $-\text{R}$, $-\text{NO}_2$, $-\text{COOH}$ and $-\text{COR}$)

Source: Cambridge International syllabus

Arenes 芳烃 are aromatic hydrocarbons, built on the benzene ring. The delocalised ring of electrons is stable and electron-rich, so benzene mostly reacts by electrophilic substitution 亲电取代 — keeping the ring — rather than by addition.

A pile of white mothballs Naphthalene, used in mothballs, is a simple arene — two benzene rings fused together

Reactions of benzene and methylbenzene

Reaction Reagents and conditions Product
halogenation $\text{Cl}_2$ or $\text{Br}_2$, with $\text{AlCl}_3$ or $\text{AlBr}_3$ as a catalyst 催化剂 a halogenoarene 卤代芳烃 (aryl halide)
nitration 硝化 concentrated $\text{HNO}_3$ + concentrated $\text{H}_2\text{SO}_4$, $25$$60\,°\text{C}$ nitrobenzene
Friedel–Crafts alkylation 傅克烷基化 $\text{CH}_3\text{Cl}$ + $\text{AlCl}_3$, heat methylbenzene (adds an alkyl group)
Friedel–Crafts acylation 傅克酰基化 $\text{CH}_3\text{COCl}$ + $\text{AlCl}_3$, heat a phenyl ketone (adds an acyl group)
side-chain oxidation hot alkaline $\text{KMnO}_4$, then dilute acid benzoic acid 苯甲酸
hydrogenation 氢化 $\text{H}_2$, $\text{Pt/Ni}$ catalyst, heat cyclohexane

Friedel-Crafts alkylation adds an alkyl group; acylation adds an acyl group Friedel-Crafts: alkylation adds an alkyl group, acylation an acyl group

Benzene at the centre with arrows to chlorobenzene, nitrobenzene, methylbenzene, a phenyl ketone and cyclohexane, each labelled with its reagents Benzene keeps its stable ring, reacting mostly by electrophilic substitution (and by addition only with hydrogen)

In the side-chain oxidation, the whole side-chain 侧链 (such as the $\text{–CH}_3$ on methylbenzene) is turned into a $\text{–COOH}$ group, giving benzoic acid. In the hydrogenation, three molecules of $\text{H}_2$ add to the benzene ring 苯环 to make a saturated cyclohexane ring.

The mechanism: electrophilic substitution

Take nitration as the example. The acid mix makes the electrophile $\text{NO}_2^+$. Then:

  1. the delocalised electrons of the ring form a bond to the electrophile, giving an unstable intermediate.
  2. an $\text{H}^+$ is lost from that carbon, which restores the stable ring.

Substitution wins over addition because the delocalisation 离域 (aromatic stabilisation) of the ring is kept. Addition would destroy this stable system, so it is not favoured.

The nitration mechanism: the ring attacks NO2+ with a curly arrow to give a positive intermediate, which loses H+ to restore the ring as nitrobenzene Electrophilic substitution (nitration): the ring attacks the electrophile NO$_2^+$ to give an unstable intermediate, then loses H$^+$ to restore the ring

Side-chain or ring?

Where a halogen reacts depends on the conditions:

  • with a halogen-carrier catalyst (such as $\text{AlCl}_3$) and no UV light → substitution in the ring.
  • with UV light and no catalyst → free-radical substitution in the side-chain.

Methylbenzene with chlorine branching two ways: with AlCl3 and no UV the chlorine substitutes the ring, with UV and no catalyst it substitutes the side-chain methyl group The conditions decide: a halogen carrier (AlCl₃) substitutes the ring; UV light substitutes the side-chain

Directing effects

A group already on the ring decides where the next group goes — its directing effect 定位效应:

Two numbered benzene rings: one with positions 2 and 4 highlighted for amino, hydroxyl and alkyl groups, the other with position 3 highlighted for nitro, carboxyl and acyl groups A group already on the ring directs the next one: –NH$_2$/–OH/–R send it to positions 2 and 4; –NO$_2$/–COOH/–COR send it to position 3

Group already present Directs the new group to
$\text{–NH}_2$, $\text{–OH}$, $\text{–R}$ positions 2 and 4
$\text{–NO}_2$, $\text{–COOH}$, $\text{–COR}$ position 3

Worked example. Methylbenzene and nitrobenzene are each nitrated. Predict where the new $\text{NO}_2$ group goes, and which compound reacts faster. Look at the group already on the ring. In methylbenzene the $\text{–CH}_3$ is an alkyl group: it directs the new group to positions 2 and 4, and it releases electrons into the ring, making the ring more attractive to an electrophile - so methylbenzene nitrates faster than benzene. In nitrobenzene the $\text{–NO}_2$ directs to position 3, and it withdraws electrons from the ring - so nitrobenzene nitrates more slowly than benzene. The group already present controls both the position and the rate, and the two always travel together: 2,4-directors activate the ring, 3-directors deactivate it.

Explore

Arene substitution route

Follow electrophilic substitution on benzene.

Explore

Directing effects lab

Classify substituents by how they affect the benzene ring.

Vocabulary Train
English Chinese Pinyin
arene 芳烃 fāng tīng
benzene běn
electrophilic substitution 亲电取代 qīn diàn qǔ dài
catalyst 催化剂 cuī huà jì
halogenoarene 卤代芳烃 lǔ dài fāng tīng
nitration 硝化 xiāo huà
Friedel–Crafts alkylation 傅克烷基化 fù kè wán jī huà
Friedel–Crafts acylation 傅克酰基化 fù kè xiān jī huà
benzoic acid 苯甲酸 běn jiǎ suān
hydrogenation 氢化 qīng huà
side-chain 侧链 cè liàn
benzene ring 苯环 běn huán
delocalisation 离域 lí yù
directing effect 定位效应 dìng wèi xiào yìng
30.1

Exam tips

  • Benzene undergoes electrophilic substitution, not addition, because addition would destroy the stable delocalised ring.
  • Learn nitration (concentrated $\text{HNO}_3$/$\text{H}_2\text{SO}_4$, $50-60\ ^\circ\text{C}$) and halogenation (halogen + $\text{AlCl}_3$) with the electrophile-generating step.
  • Compare reactivity: benzene resists addition far more than an alkene because of delocalisation.

Log in or create account

IGCSE & A-Level