Temperature and solid size: explain two different rate effects
導入済み| English | 意味 |
|---|---|
| surface-area-to-volume ratio/ˈsɜːfɪs ˈeərɪə tə ˈvɒljuːm ˈreɪʃɪəʊ/ | 表面積体積比 |
| energetic collision/ˌenəˈdʒetɪk kəˈlɪʒn/ | 高エネルギー衝突 |
What would explain this observation?
- Warming particles and crushing a solid can both speed reactions, but they act differently. Temperature changes particle energies; crushing exposes more contact surface.
- Start with a prediction. State the quantities or features you would compare, then decide what evidence could distinguish two explanations.
Build the model
- At higher temperature particles move faster and collide more frequently. Collisions are more energetic, so a greater fraction has at least the activation energy and can react. Temperature does not lower the activation energy of the unchanged pathway. For a reacting solid, only accessible surface contacts the other reactant. Smaller pieces at the same total solid volume have a greater surface-area-to-volume ratio 表面积体积比, exposing more sites and increasing collision frequency.
- energetic collision 高能碰撞: A collision carrying enough energy to meet the reaction’s activation requirement; surface-area-to-volume ratio: Surface area divided by volume, measuring exposed area relative to material volume.
Why does higher temperature commonly increase rate?
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
Heating speeds the particles up, so collisions are more frequent AND a larger fraction exceed the activation energy - the second effect dominates. Activation energy does not fall to zero, and atoms never grow.
Match each technical term to its precise meaning.
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
Use the definitions to distinguish related quantities and processes.
Choose evidence that can test it
- A cube model makes the size comparison explicit. A cube side L has area 6L² and volume L³. Cutting it into eight half-side cubes preserves total volume but doubles total area. This model assumes newly exposed faces are accessible and not clumped or coated. Real powders need appropriate containment; aggregate formation can reduce accessible area. Do not claim every ten-degree temperature rise always doubles rate: exact effects depend on reaction and conditions.
- Investigate one factor at a time with teacher-approved dilute reactants and moderate controlled temperatures. Use a water bath where appropriate and measure the reacting mixture’s temperature, not only the bath label. Compare equal solid masses with the same composition and control acid concentration and volume. Fine powders can create exposure hazards; use the approved particle sizes rather than grinding unknown materials independently. Explain the measured trend through the relevant collision mechanism.
Which two habits make the investigation or model in this case more defensible?
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
Stating the conditions and assumptions lets others repeat the work exactly, and recording the supporting evidence lets them check the conclusion. Hiding disagreeing results removes the evidence that could challenge a wrong conclusion, and one measurement can never establish a wider claim.
Work from known quantities
- State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
- Known: an original model cube of side 2 cm has volume 8 cm³ and area 24 cm². Eight cubes of side 1 cm have total volume 8 cm³ and total area 8×6=48 cm², twice the original area. For this accessible-face model the increased contact area supports faster reaction with the same solid amount; it does not alone predict an exact measured doubling of rate.
One 2 cm cube is cut into eight 1 cm cubes with all faces accessible. Find total surface area of the eight cubes. Use the same sequence: known quantities → model → relation → substitution → unit and interpretation.
One 2 cm cube is cut into eight 1 cm cubes with all faces accessible. Find total surface area of the eight cubes.
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
The result is 48 cm². Known: eight cubes of side 1 cm, all faces accessible. Each face = 1 cm^2, six faces per cube: area per cube = 6 cm^2. Total = 8 x 6 = 48 cm^2 - double the original 2 cm cube's 24 cm^2, at the same total volume.
Check the conclusion and its limits
- Do not say hot particles become physically larger, or that smaller pieces have intrinsically lower activation energy. Surface area and total amount are different. Raising temperature changes the energy distribution; cutting changes geometry. Both can increase successful collision frequency, but explanations should not swap their causes.
- Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.
Crushing a solid necessarily lowers the activation energy of its reaction pathway. This claim is false: Crushing exposes more surface for collisions - a geometric change. The activation energy is a property of the reaction pathway and is unchanged; only a catalyst offering a new pathway can lower it.
Temperature and solid size: explain two different rate effects: A cube model makes the size comparison explicit. A cube side L has area 6L² and volume L³. Cutting it into eight half-side cubes preserves total volume but doubles total area. This model assumes newly exposed faces are accessible and not clumped or coated. Real powders need appropriate containment; aggregate formation can reduce accessible area. Do not claim every ten-degree temperature rise always doubles rate: exact effects depend on reaction and conditions.
Crushing a solid necessarily lowers the activation energy of its reaction pathway.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
Crushing exposes more surface for collisions - a geometric change. The activation energy is a property of the reaction pathway and is unchanged; only a catalyst offering a new pathway can lower it.
A collision carrying enough energy to meet the reaction’s activation requirement: write the technical term.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
energetic collision means A collision carrying enough energy to meet the reaction’s activation requirement.