Thermal measurements and particle models
| English | Español |
|---|---|
| specific heat capacity/spəˈsɪfɪk hiːt kəˈpæsɪti/ | capacidad calorífica específica |
| latent heat/ˈleɪtənt hiːt/ | calor latente |
What would explain this observation?
- Two equal masses receive the same energy but show different temperature rises. Material properties determine how energy transfer changes temperature.
- Start with a prediction. State the quantities or features you would compare, then decide what evidence could distinguish two explanations.
Build the model
- Specific heat capacity 比热容 is energy needed to raise the temperature of unit mass by one degree. Specific latent heat · calor latente 潜热 relates energy to change of state without temperature change for the idealized process.
- specific heat capacity: Energy per mass per temperature rise; latent heat: Energy associated with a change of state.
Why can temperature stay constant while a pure substance melts?
Temperature relates to particle motion in a model; internal energy includes kinetic and potential contributions. During a change of state, energy can change particle arrangements rather than temperature.
Match each technical term to its precise meaning.
Use the definitions to distinguish related quantities and processes.
Choose evidence that can test it
- Temperature relates to particle motion in a model; internal energy includes kinetic and potential contributions. During a change of state, energy can change particle arrangements rather than temperature.
- Measure mass, electrical input and temperature change for an insulated block. Ensure the temperature sensor has good contact, allow time for equilibration, and consider energy transferred to the surroundings.
Which two habits make the investigation or model in this case more defensible?
Measure mass, electrical input and temperature change for an insulated block. Ensure the temperature sensor has good contact, allow time for equilibration, and consider energy transferred to the surroundings.
Work from known quantities
- State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
- Known: a 0.50 kg block gains 2,000 J and rises 10 °C. Use E = mcΔT. Rearranging gives c = E/(mΔT). c = 2,000/(0.50×10) = 400 J per kilogram per degree. Heat loss would make the value inferred from electrical input too large.
A 2 kg sample with c=500 J per kilogram per degree warms by 3 °C. Find energy gain. Use the same sequence: known quantities → model → relation → substitution → unit and interpretation.
A 2 kg sample with c=500 J per kilogram per degree warms by 3 °C. Find energy gain.
The result is 3000 J. Known: a 0.50 kg block gains 2,000 J and rises 10 °C. Use E = mcΔT. Rearranging gives c = E/(mΔT). c = 2,000/(0.50×10) = 400 J per kilogram per degree. Heat loss would make the value inferred from electrical input too large.
Check the conclusion and its limits
- A flat section of a heating curve can show a phase change, not absence of energy transfer. Do not substitute temperature for a temperature difference in E = mcΔT.
- Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.
A temperature plateau always means zero energy transfer. This claim is false: A flat section of a heating curve can show a phase change, not absence of energy transfer. Do not substitute temperature for a temperature difference in E = mcΔT.
Thermal measurements and particle models: Temperature relates to particle motion in a model; internal energy includes kinetic and potential contributions. During a change of state, energy can change particle arrangements rather than temperature.
A temperature plateau always means zero energy transfer.
A flat section of a heating curve can show a phase change, not absence of energy transfer. Do not substitute temperature for a temperature difference in E = mcΔT.
Energy per mass per temperature rise: write the technical term.
specific heat capacity means Energy per mass per temperature rise.