Differential equations and numerical solutions · 微分方程与数值解法
| English | 中文 | Pinyin · 拼音 |
|---|---|---|
| initial condition/ɪˈnɪʃl kənˈdɪʃn/ | 初始条件 | chū shǐ tiáo jiàn |
What does the starting value decide?
- A growing population's rate is proportional to its current size. The rate equation describes a whole family until an initial population is supplied.
- This lesson studies initial condition 初始条件: A specified value that selects a particular solution from a family.
初始值决定了什么？
- 增长型种群的增长率与其当前大小成正比。该速率方程描述了一族解，直到提供初始种群数据为止。
- 本课学习initial condition（初始条件）：从一族解中选定特定解的一个指定值。
Choose the mathematical structure
- Separate the variables in dy/dx=ky, integrate both sides and apply an initial condition. Include any equilibrium solution excluded when dividing by y.
- State the allowed inputs and units before calculating. An equation should express the relationship, not just record a calculator entry.
选择数学结构
- 分离 dy/dx=ky 中的变量，对两边积分并应用初始条件。注意包含在除以 y 时被排除的平衡解。
- 计算前请先明确允许的输入项和单位。方程应表达关系本身，而不仅仅是记录计算器按键过程。
Which description correctly defines initial condition? · 以下哪项描述正确定义了初始条件？
A specified value that selects a particular solution from a family. · 从一族解中选定特定解的指定值。
Work through a checked case
- Check the result against the starting quantities. Substitute into the original relation, or compare the graph and numerical answer where appropriate.
For dy/dx=0.5y and y(0)=2, separation gives ln|y|=0.5x+C, hence y=Ae^(0.5x). The initial value gives A=2. Differentiate the result to check the equation and substitute x=0 to check the initial condition.
通过验证案例进行推导
- 将结果与初始量进行比对。代入原始关系式，或在适当情况下对比图表与数值答案。
对于 dy/dx=0.5y 且 y(0)=2，分离变量得 ln|y|=0.5x+C，因此 y=Ae^(0.5x)。初始值给出 A=2。对结果求导以验证方程，并代入 x=0 以验证初始条件。
Differential equations and numerical solutions · 微分方程与数值解法
Separate the variables in dy/dx=ky, integrate both sides and apply an initial condition · 分离 dy/dx=ky 的变量，对两边积分并应用初始条件。
Compare the model with the worked case and explain one change. · 对比模型与已解案例，并说明其中一处变化。
For y=2e^(0.5x), find y(0). · 已知 y=2e^(0.5x)，求 y(0)。
At x=0, e⁰=1, so y=2. · 当 x=0 时，e⁰=1，因此 y=2。
Test a tempting shortcut
- An initial condition determines the integration constant; it is not a replacement for integrating. Dividing by y can omit an equilibrium solution y=0. Euler accuracy depends on step size and the equation.
- When a shortcut fails, identify the assumption it breaks. Keep an exact value until the requested final rounding.
An initial condition never changes the constant in a differential-equation solution. This claim is false. Explain which definition or assumption it violates.
检验一个诱人的捷径
- 初始条件用于确定积分常数；它不能替代积分过程。除以 y 可能会遗漏平衡解 y=0。欧拉法的精度取决于步长和方程本身。
- 当捷径失效时，找出其违背的假设。保留精确值直到题目要求的最终舍入步骤。
初始条件永远不会改变微分方程解中的常数。此说法错误。请解释它违反了哪一定义或假设。
For that solution, find the initial derivative. · 对于该解，求初始导数。
Differentiate y=2e^(0.5x): y prime=e^(0.5x). At zero it is 1. · 对 y=2e^(0.5x) 求导：y' = e^(0.5x)。在零处的值为 1。
An initial condition never changes the constant in a differential-equation solution. · 初始条件不会改变微分方程解中的常数项。
An initial condition determines the integration constant; it is not a replacement for integrating. Dividing by y can omit an equilibrium solution y=0. Euler accuracy depends on step size and the equation. · 初始条件用于确定积分常数；它不能替代积分过程。除以 y 可能会遗漏平衡解 y=0。欧拉法的精度取决于步长和方程本身。
Interpret a new situation
- This unit uses first-order separation and initial conditions. Euler numerical integration and second-order complementary functions are excluded from this lesson.
- A complete solution gives the mathematical result and explains what it means. Check that it is possible in the stated context.
解读新情境
- 本单元涉及一阶分离变量法和初始条件。欧拉数值积分和二阶互补函数不包含在本课内容中。
- 完整解答需给出数学结果并解释其含义。检查其在所述背景下是否可行。
For that solution, find y divided by e when x=2. · 对于该解，求当 x=2 时 y 除以 e 的值。
At x=2, y=2e, hence y/e=2. · 当 x=2 时，y=2e，因此 y/e=2。
Match each part of a complete solution to its purpose. · 将完整解答的每个部分与其目的相匹配。
An assumption justifies the model; a check tests the result; interpretation connects it to the question. · 假设用于论证模型的合理性；检查用于验证结果；解释用于将其与问题建立联系。
Use this in your course
- 7357 · A-level · H. Match the target tier and specification before assigning extensions.
- Give the method before the final answer, and use the paper's calculator and formula rules. Review a wrong answer by locating the first invalid step.
A specified value that selects a particular solution from a family. Choose the relationship, show the method, check its assumptions and interpret the result.
将其应用于你的课程
- 7357 · A-level · H. 在布置拓展任务前，先匹配目标层级和课程大纲。
- 在给出最终答案前先展示解题方法，并遵循试卷的计算器及公式使用规则。通过定位第一个无效步骤来复盘错误答案。
从一族解中选定特定解的一个指定值。请选择关系式，展示该方法，检查其适用条件并解释结果。