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J · Vectors

AQA · A-Level · 数学 · 知识点 10

训练
10.1

Scope and prerequisites

English

AQA A-level Mathematics 7357, section J (Vectors), version 1.3 (first assessment 2018). Original teaching notes; objective-level mapping lives in content/teaching/aqa_a_level_mathematics/objective-review.yaml.

Prerequisites: coordinate geometry from section C and Pythagoras. Each lesson develops its own method before independent transfer.

These are original teaching examples, not official AQA material.

词汇 训练
English 中文 拼音
vector/ˈvektə/ 向量 xiàng liàng
10.2

Vectors 向量

What would explain this observation?

  • A drone flies from A(1, 2) to B(5, 5), but the mission software asks for the return leg too. Which single formula gives both the outward displacement and its exact reverse?
  • Start with a prediction. State what a displacement vector needs beyond a distance, and how the return leg differs.

Build the model

  • A vector carries magnitude and direction. Position vectors locate points from one origin; the displacement 位移向量 from A to B is AB = b − a, and BA = −AB reverses it. Add and subtract components; a scalar multiple keeps a vector parallel.
  • The scalar product 数量积 a·b = a₁b₁ + a₂b₂ = |a||b| cos θ measures the angle: perpendicular vectors have a·b = 0, and a·a = |a|². Magnitude comes from Pythagoras: |(4, 3)| = 5.
  • vector: A quantity with magnitude and direction; displacement: The vector from one point to another, b − a; scalar product: The sum of component products, equal to |a||b| cos θ.
Vectors: original worked-case diagram

Choose evidence that can test it

  • Keep the order of subtraction: BA = −AB, so swapping endpoints reverses every component. A claimed parallel needs a scalar-multiple relation between the vectors; a sketch alone is not a proof.
  • For collinearity of three points, show two displacements are parallel AND share a common point; parallel vectors at different locations prove nothing about one line.

Work from known quantities

  • State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
  • Known: a = (4, 1) and b = (1, 3). The scalar product is a·b = 4 × 1 + 1 × 3 = 7. The magnitudes are |a| = √17 and |b| = √10, so cos θ = 7/(√17 × √10) ≈ 0.537, giving θ ≈ 57.5°. Since a·b ≠ 0, the vectors are not perpendicular.

Example:

With A(1, 2) and B(5, 5), find the displacement AB, its magnitude and the return displacement, using the same sequence. (Answer: AB = (5, 5) − (1, 2) = (4, 3); |AB| = √(4² + 3²) = 5; BA = (−4, −3), the same magnitude in the opposite direction.)


Check the conclusion and its limits

  • A vector answers "how far AND which way"; a distance is only a scalar. The scalar product sees direction: it is largest when the vectors align, zero when perpendicular, and negative when they oppose.
  • Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.

Warn:

AB and BA have the same components. This claim is false: BA = −AB reverses every component — from B back to A is (−4, −3), not (4, 3). Only the magnitudes agree.

Key:

Vectors: displacement = end − start, reversed by the return leg; components add; scalar multiples stay parallel; the scalar product gives the angle, with perpendicularity exactly at a·b = 0.

词汇 训练
English 中文 拼音
displacement/dɪˈspleɪsmənt/ 位移向量 wèi yí xiàng liàng
scalar product/ˈskeɪlə ˈprɒdʌkt/ 数量积 shù liàng jī

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