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Numbers and the number system

Pearson Edexcel · International GCSE · Mathematics A Topic 1 6:02 English narration · English + 中文 subtitles burned in

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Chapters

Transcript
Four families carry topic 1. 第 1 主题有四类要点。
Every percentage change is a multiplier, and a reverse percentage divides by it. 每个百分比变化都是一个乘数,反向百分比就除以它。
A rounded value has bounds half a unit either side. 近似值的上下界各差半个单位。
Standard form keeps a between 1 and 10. 科学记数法中 a 在 1 到 10 之间。
And a ratio shares an amount by parts over the total. 按比分配就是用份数除以总份数再乘总量。
Order matters: 3 plus 4 times 2 squared is 19, because the index and the multiplication come before the addition. 运算顺序很重要:3 + 4 × 2² = 19,因为乘方和乘法先于加法。
Brackets change it: 3 plus 4, times 2, is 14. 括号会改变结果:(3 + 4) × 2 = 14。
Split 72 into 8 and 9, and keep splitting until every branch ends in a prime: 72 is 2 cubed times 3 squared. 把 72 分成 8 和 9,一直分下去,直到每一枝都是质数:72 = 2³ × 3²。
Fractions add over a common denominator. 分数相加要先通分。
One third is four twelfths and one quarter is three twelfths, so together they make seven twelfths. 三分之一等于十二分之四,四分之一等于十二分之三,所以合起来是十二分之七。
A fraction of an amount multiplies: three quarters of 48 is 36. 求一个量的几分之几用乘法:48 的四分之三 是 36。
To divide, multiply by the reciprocal. 除以一个分数,就乘以它的倒数。
For a recurring decimal, let x equal 0.306306 and so on; then 1000 x is 306.306 and so on. 对于循环小数,设 x 等于 0.306306……,那么 1000x 等于 306.306……。
Subtracting removes the tail: 999 x equals 306, so x is 306 over 999, which cancels to 34 over 111. 相减消去循环部分:999x 等于 306,所以 x 等于九百九十九分之三百零六,约分得一百一十一分之三十四。
Factor to primes first; the Venn diagram then reads off both answers. 先分解质因数,然后用韦恩图同时读出两个答案。
360 is 2 cubed times 3 squared times 5, and 84 is 2 squared times 3 times 7. 360 等于 2 的三次方乘 3 的平方乘 5,84 等于 2 的平方乘 3 乘 7。
The primes they share go in the overlap: 2, 2 and 3. 共有的质因数放在重叠 部分:2、2 和 3。
The rest of 360, which is 2, 3 and 5, goes on its own side, and 84 keeps its 7. 360 剩下的 2、3 和 5 放在它自己的一侧,84 留下 7。
The highest common factor is the overlap's product, 2 times 2 times 3, which is 12. 最大公因数是重叠部分的乘积,2 乘 2 乘 3,等于 12。
The lowest common multiple is the product of everything, 12 times 30 times 7, which is 2520. 最小公倍数 是所有数的乘积,12 乘 30 乘 7,等于 2520。
Take the largest square factor out: root 50 is root 25 times root 2, which is 5 root 2. 提出最大的平方因数:√50 = √25 × √2 = 5√2。
To rationalise 5 over 3 minus root 2, multiply top and bottom by the conjugate, 3 plus root 2: the denominator becomes 9 minus 2, which is 7. 要使 5/(3 − √2) 分母有理化,分子分母同乘共轭 3 + √2:分母变成 9 − 2 = 7。
For 6 over root 3, multiply by root 3 over root 3: 2 root 3. 对于 6/√3,乘以 √3/√3:得 2√3。
Fill every region, then make the regions add up to the total. 先填好每个区域,再检查各区域之和等于总数。
Of 30 students, 18 play cricket, 15 play tennis and 7 play both. 30 名学生中,18 人打板球,15 人打网球,7 人两样都打。
The overlap is filled first with 7. 先在重叠部分填 7。
Cricket only is 18 minus 7, which is 11; tennis only is 15 minus 7, which is 8. 只打板球的是 18 减 7,等于 11;只打网球的是 15 减 7,等于 8。
That accounts for 26 students, so 4 play neither, and they sit outside both circles. 这样共 26 人,所以有 4 人两样都不打,他们在两个圆之外。
Check: 11 plus 7 plus 8 plus 4 is 30. 检验:11 加 7 加 8 加 4 等于 30。
Every percentage change is a multiplier. 每一次百分比变化都是一个乘数。
A 12 percent rise multiplies by 1.12; a 20 percent fall multiplies by 0.8. 增加百分之十二就乘以 1.12;减少百分之二十就乘以 0.8。
A reverse percentage divides: 6225 after a 17 percent fall means 6225 divided by 0.83, which is 7500 rupees, never 6225 plus 17 percent. 逆向百分比用除法:减少百分之十七之后是 6225, 意味着 6225 除以 0.83,等于 7500 卢比,绝不是 6225 再加上百分之十七。
Compound change applies the multiplier once per year: 2000 at 3 percent grows to 2060, then 2121.80, then 2185.45, and after four years 2251.02. 复利变化每年乘一次乘数:2000 按百分之三增长到 2060,然后 2121.80,然后 2185.45,四年后是 2251.02。
Count the total parts before sharing, and find one unit before scaling. 分配之前先数总份数,按比例放大之前先求一份。
Simplify a ratio by dividing through: 45 to 60 is 3 to 4. 化简比时两边同除:45 比 60 等于 3 比 4。
To share 350 pounds in the ratio 2 to 5, there are 7 parts, so one part is 50 pounds; the shares are 100 and 250. 把 350 英镑按 2 比 5 分配,共 7 份,所以一份 是 50 英镑;两份分别是 100 和 250。
The unitary method finds one first: 7 pens cost 4.20, so one pen costs 0.60, and 12 pens cost 7.20. 单一法先求一个:7 支笔 4.20,所以一支笔 0.60,12 支笔 7.20。
Choose the extremes the question needs, then compute once. 先选出题目需要的极端值,再只计算一次。
A value carries bounds of plus or minus half its accuracy unit. 一个数值的上下界是加减精度单位的一半。
A speed of 19 kilometres per hour to the nearest whole lies from 18.5 up to 19.5, and a time of 1.5 hours to 1 decimal place lies from 1.45 up to 1.55. 速度为每小时 19 千米、精确到整数,范围是 18.5 到 19.5;时间 1.5 小时、精确到一位小数,范围是 1.45 到 1.55。
The greatest distance uses both upper bounds: 19.5 times 1.55 is 30.2 kilometres to 3 significant figures. 最大距离用两个上界:19.5 乘 1.55 等于 30.2 千米,保留三位有效数字。
To estimate, round to 1 significant figure first. 估算时先把每个数保留一位有效数字。
In standard form, 604000 is 6.04 times 10 to the 5. 用标准形式写,604000 等于 6.04 乘 10 的 5 次方。
A metre is 100 centimetres, but one square metre is not 100 square centimetres. 1 米是 100 厘米,但 1 平方米不是 100 平方厘米。
It holds 100 rows of 100 small squares: 10 000 square centimetres. 它包含 100 行、每行 100 个小方格:10 000 平方厘米。
Volume cubes the factor, so a litre is 1000 cubic centimetres. 体积要立方,所以 1 升是 1000 立方厘米。
And on the calculator, keep full precision and round only at the end. 用计算器时保持全部精度,最后才取近似。
Check yourself. 自我检测。
3 plus 4 times 2 squared is 19. 3 + 4 × 2² = 19。
Root 50 is 5 root 2. √50 = 5√2。
A 12 000 pound car losing 15 percent a year is worth 12 000 times 0.85 cubed after 3 years: 7369 pounds 50. 价值 12 000 英镑的车每年贬值 15%,3 年后是 12 000 × 0.85³ = 7369.50 英镑。
350 pounds in the ratio 2 to 5 is 100 and 250. 350 英镑按 2:5 分是 100 和 250。
And 0.00007 is 7 times 10 to the minus 5. 0.00007 = 7 × 10⁻⁵。

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