Higher Tier: combine hydrogen fuel-cell half equations
도입됨| English | 의미 |
|---|---|
| fuel-cell anode/ˈfjuːəl sel ˈænəʊd/ | 연료전지 양극 |
| fuel-cell cathode/ˈfjuːəl sel ˈkæθəʊd/ | 연료전지 음극 |
What would explain this observation?
- Higher Tier: A hydrogen fuel cell separates oxidation and reduction at two electrodes. The same number of electrons must be released at one electrode and accepted at the other.
- Start with a prediction. State the quantities or features you would compare, then decide what evidence could distinguish two explanations.
Build the model
- For the explicitly acidic-electrolyte model, hydrogen oxidation is 2H₂ → 4H⁺ + 4e⁻. Oxygen reduction is O₂ + 4H⁺ + 4e⁻ → 2H₂O. Adding the half equations cancels four hydrogen ions and four electrons, leaving 2H₂ + O₂ → 2H₂O. Oxidation means electron loss and reduction electron gain. These half equations are the embedded Higher-only part of the source section.
- fuel-cell anode 燃料电池阳极: The electrode where hydrogen oxidation releases electrons in the stated generating cell; fuel-cell cathode 燃料电池阴极: The electrode where oxygen reduction accepts electrons in the stated generating cell.
Which acidic hydrogen half equation shows oxidation?
난이도 1/5 · 100 코인 + 오늘 첫 완료 시 소액 보너스
Oxidation loses electrons, so the hydrogen half equation is H2 -> 2H+ + 2e-, balanced for atoms (2:2) and charge (0 each side). Electrons on the left would describe reduction, and oxygen alone cannot form water without hydrogen species.
Match each technical term to its precise meaning.
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
Use the definitions to distinguish related quantities and processes.
Choose evidence that can test it
- Check atoms and charges separately. The hydrogen half equation has four hydrogen atoms on each side and zero net charge because +4 from H⁺ balances −4 from electrons. The oxygen half equation has two oxygen atoms and four hydrogen atoms on each side, again zero net charge. In this generating cell electrons leave the hydrogen anode through the external circuit and reach the oxygen cathode. The anode is negative and the cathode positive while the cell supplies electricity.
- Begin with one consistent electrolyte model. Balance hydrogen with H⁺, oxygen with water and charge with electrons, then scale to equal electron numbers and cancel. Do not mix an acidic half equation with an alkaline one containing OH⁻. The electrode names identify oxidation at the anode and reduction at the cathode; signs must be interpreted for a generating fuel cell, rather than copied from an externally powered electrolytic cell.
Which two habits make the investigation or model in this case more defensible?
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
Stating the conditions and assumptions lets others repeat the work exactly, and recording the supporting evidence lets them check the conclusion. Hiding disagreeing results removes the evidence that could challenge a wrong conclusion, and one measurement can never establish a wider claim.
Work from known quantities
- State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
- Known: starting from H₂ → 2H⁺ + 2e⁻, multiply by two to match the four electrons consumed by O₂ + 4H⁺ + 4e⁻ → 2H₂O. Two represented H₂ molecules supply four electrons and one O₂ molecule accepts four. If three O₂ molecules react in the same scaled model, twelve electrons pass through the external circuit and six H₂O molecules form. Electrons cancel from the overall equation.
Each represented H₂ molecule releases two electrons in the stated half equation. How many are released by eight H₂ molecules? Use the same sequence: known quantities → model → relation → substitution → unit and interpretation.
Each represented H₂ molecule releases two electrons in the stated half equation. How many are released by eight H₂ molecules?
난이도 2/5 · 140 코인 + 오늘 첫 완료 시 소액 보너스
The result is 16 electrons. Known: each H2 releases 2 electrons in the stated half equation. For eight H2 molecules: 8 x 2 = 16 electrons released, flowing through the external circuit to the oxygen electrode.
Check the conclusion and its limits
- Do not put electrons on the reactant side for hydrogen oxidation, allow them to remain in the overall reaction, or say they pass through the electrolyte like they do through a metal wire. Common-tier students still need the overall reaction and fuel-cell evaluation, but these half equations and charge reasoning are Higher-only.
- Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.
Electrons remain as a product of the complete balanced fuel-cell reaction. This claim is false: Electrons travel through the EXTERNAL circuit and cancel when the half equations combine: H2 releases exactly what O2 consumes. The overall reaction 2H2 + O2 -> 2H2O contains no electrons.
Higher Tier: combine hydrogen fuel-cell half equations: Check atoms and charges separately. The hydrogen half equation has four hydrogen atoms on each side and zero net charge because +4 from H⁺ balances −4 from electrons. The oxygen half equation has two oxygen atoms and four hydrogen atoms on each side, again zero net charge. In this generating cell electrons leave the hydrogen anode through the external circuit and reach the oxygen cathode. The anode is negative and the cathode positive while the cell supplies electricity.
Electrons remain as a product of the complete balanced fuel-cell reaction.
난이도 1/5 · 100 코인 + 오늘 첫 완료 시 소액 보너스
Electrons travel through the EXTERNAL circuit and cancel when the half equations combine: H2 releases exactly what O2 consumes. The overall reaction 2H2 + O2 -> 2H2O contains no electrons.
The electrode where hydrogen oxidation releases electrons in the stated generating cell: write the technical term.
난이도 1/5 · 100 코인 + 오늘 첫 완료 시 소액 보너스
fuel-cell anode means The electrode where hydrogen oxidation releases electrons in the stated generating cell.