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Physical quantities and units

A-Level Physics · Topic 1

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1.1

Physical quantities

Syllabus
  1. understand that all physical quantities consist of a numerical magnitude and a unit
  2. make reasonable estimates of physical quantities included within the syllabus

Source: Cambridge International syllabus

A physical quantity 物理量 has two parts: a number (its magnitude 大小) and a unit 单位. The number on its own tells you nothing. You must also say what is measured and in which unit.

Example: "the length is 1.5" is not complete. "The length is 1.5 m" is a physical quantity.

Making estimates

You should be able to estimate 估算 the size of the physical quantities in this syllabus. Learn these rough values:

  • mass 质量 of an adult human: $\sim 70\ \text{kg}$
  • weight 重力 of an adult human: $\sim 700\ \text{N}$
  • height of an adult human: $\sim 1.7\ \text{m}$
  • mass of an apple: $\sim 0.1\ \text{kg}$ (so its weight is about $1\ \text{N}$)
  • speed of sound in air: $\sim 340\ \text{m s}^{-1}$
  • speed of light in a vacuum 真空: $3.0 \times 10^{8}\ \text{m s}^{-1}$
  • acceleration 加速度 of free fall 自由落体: $g \approx 9.81\ \text{m s}^{-2}$

A good estimate has the right order of magnitude 数量级 (the right power of ten). For a human, 70 kg is a good guess; 7 kg is not.

Vocabulary Train
English Chinese Pinyin
physical quantity 物理量 wù lǐ liàng
magnitude 大小 dà xiǎo
unit 单位 dān wèi
estimate 估算 gū suàn
mass 质量 zhì liàng
weight 重力 zhòng lì
vacuum 真空 zhēn kōng
acceleration 加速度 jiā sù dù
free fall 自由落体 zì yóu luò tǐ
order of magnitude 数量级 shù liàng jí
SI units 国际单位制 guó jì dān wèi zhì
base quantity 基本量 jī běn liàng
1.2

SI units 国际单位制

Syllabus
  1. recall the following SI base quantities and their units: mass (kg), length (m), time (s), current (A), temperature (K)
  2. express derived units as products or quotients of the SI base units and use the derived units for quantities listed in this syllabus as appropriate
  3. use SI base units to check the homogeneity of physical equations
  4. recall and use the following prefixes and their symbols to indicate decimal submultiples or multiples of both base and derived units: pico (p), nano (n), micro (\mu), milli (m), centi (c), deci (d), kilo (k), mega (M), giga (G), tera (T)

Source: Cambridge International syllabus

Base units

There are five base quantities 基本量 in the SI system. You must know them and their units:

  • mass — kilogram, $\text{kg}$
  • length 长度 — metre, $\text{m}$
  • time — second, $\text{s}$
  • current 电流 — ampere 安培, $\text{A}$
  • temperature 温度 — kelvin 开尔文, $\text{K}$

Every other unit in this syllabus is built from these five.

Derived units

A derived unit 导出单位 is made by multiplying or dividing base units. You should be able to write any quantity in this syllabus in base units.

Build a derived unit from the equation that defines it:

  • speed 速率 = distance / time, so its unit is $\text{m s}^{-1}$
  • acceleration = change in velocity 速度 / time, so its unit is $\text{m s}^{-2}$
  • force = mass × acceleration, so its unit is $\text{kg m s}^{-2}$. The newton 牛顿 is $1\ \text{N} = 1\ \text{kg m s}^{-2}$.
  • work and energy 能量 = force × distance, so the unit is $\text{kg m}^{2}\ \text{s}^{-2}$. The joule 焦耳 is $1\ \text{J} = 1\ \text{kg m}^{2}\ \text{s}^{-2}$.
  • power 功率 = energy / time, so the unit is $\text{kg m}^{2}\ \text{s}^{-3}$. The watt 瓦特 is $1\ \text{W} = 1\ \text{kg m}^{2}\ \text{s}^{-3}$.
  • pressure 压强 and stress 应力 = force / area, so the unit is $\text{kg m}^{-1}\ \text{s}^{-2}$. The pascal 帕斯卡 is $1\ \text{Pa} = 1\ \text{kg m}^{-1}\ \text{s}^{-2}$.

When a question asks for the SI base units of a quantity, replace each named unit with its base units, then simplify. Example: the SI base units of the watt are $\text{kg m}^{2}\ \text{s}^{-3}$.

Checking that the units match

An equation is homogeneous 量纲一致 when both sides have the same base units. In plain words: the units on both sides match.

Write each side in base units and compare. Take the equation $v^{2} = u^{2} + 2as$:

  • left side: $(\text{m s}^{-1})^{2} = \text{m}^{2}\ \text{s}^{-2}$
  • right side, first term: $(\text{m s}^{-1})^{2} = \text{m}^{2}\ \text{s}^{-2}$
  • right side, second term: $\text{m s}^{-2} \cdot \text{m} = \text{m}^{2}\ \text{s}^{-2}$

Both sides give $\text{m}^{2}\ \text{s}^{-2}$, so the units match.

Be careful: matching units do not prove the whole equation is correct. It could still have a wrong number, or a missing factor of 2. But if the units do not match, the equation is wrong for sure.

Prefixes

A prefix 词头 is a letter put in front of a unit to make it bigger or smaller by powers of ten. You must know these:

The SI prefixes climb in steps of a thousand, from pico up to giga The SI prefixes climb in steps of a thousand, from pico to giga

Prefix Symbol Factor
tera T $10^{12}$
giga G $10^{9}$
mega M $10^{6}$
kilo k $10^{3}$
deci d $10^{-1}$
centi c $10^{-2}$
milli m $10^{-3}$
micro $\mu$ $10^{-6}$
nano n $10^{-9}$
pico p $10^{-12}$

To change a prefixed unit into base units, replace the prefix with its factor, then simplify. Example: change $0.25\ \text{kN mm}^{-2}$ into $\text{N m}^{-2}$:

$$0.25\ \text{kN mm}^{-2} = 0.25 \times \frac{10^{3}\ \text{N}}{(10^{-3}\ \text{m})^{2}} = 0.25 \times \frac{10^{3}}{10^{-6}}\ \text{N m}^{-2} = 2.5 \times 10^{8}\ \text{N m}^{-2}.$$

Take special care with squared units like $\text{mm}^{2}$: you must square the factor too.

Vocabulary Train
English Chinese Pinyin
length 长度 cháng dù
current 电流 diàn liú
ampere 安培 ān péi
temperature 温度 wēn dù
kelvin 开尔文 kāi ěr wén
derived unit 导出单位 dǎo chū dān wèi
speed 速率 sù lǜ
velocity 速度 sù dù
force
newton 牛顿 niú dùn
work gōng
energy 能量 néng liàng
joule 焦耳 jiāo ěr
power 功率 gōng lǜ
watt 瓦特 wǎ tè
pressure 压强 yā qiáng
stress 应力 yīng lì
pascal 帕斯卡 pà sī kǎ
homogeneous 量纲一致 liàng gāng yí zhì
prefix 词头 cí tóu
1.3

Errors and uncertainties

Syllabus
  1. understand and explain the effects of systematic errors (including zero errors) and random errors in measurements
  2. understand the distinction between precision and accuracy
  3. assess the uncertainty in a derived quantity by simple addition of absolute or percentage uncertainties

Source: Cambridge International syllabus

A vernier caliper measuring an object A vernier caliper measures length precisely, with a small uncertainty.

Every measurement 测量 has some uncertainty 不确定度 — we are never fully sure of the value. A good experimenter knows where the uncertainty comes from, makes a fair estimate of it, and carries it through to the final answer.

A labelled photograph of a real micrometer screw gauge: the anvil and spindle close onto the object, the C-shaped frame holds them, the sleeve carries the main scale, the thimble carries the thimble scale, and the ratchet closes it gently The main parts of a real micrometer screw gauge, which measures to the nearest 0.01 mm

Two micrometer readings. Panel a is a zero reading: the thimble edge is at 0 mm and the thimble 0 lines up with the datum line, so it reads 0.00 mm. Panel b is a measurement: the thimble edge has passed 5.5 mm on the main scale and the thimble 28 lines up with the datum line, giving 5.5 + 0.28 = 5.78 mm Reading a micrometer: add the main scale reading to the thimble reading

A close-up photograph of a real micrometer scale: the sleeve's main scale on the left meets the rotating thimble scale on the right at the datum line Reading a real micrometer: read the mm and half-mm on the sleeve, then add the thimble scale

A metal vernier caliper with its jaws and a main centimetre scale, and a shorter sliding vernier scale that gives the extra digit of the reading Vernier calipers measure to the nearest 0.1 mm — the sliding scale gives the extra digit

How to read a vernier caliper. The main scale gives the whole millimetres at the vernier zero (here 15 mm); the one vernier line that lines up with a main line gives the tenths (line 4, so 0.4 mm); the reading is 15.4 mm Reading a vernier caliper: whole millimetres from the main scale, plus the tenths from the vernier line that lines up

Systematic and random errors

A systematic error 系统误差 changes every reading by the same amount, in the same direction. You cannot find it by repeating the measurement. Common causes:

  • a zero error 零点误差 (the scale does not read zero when the true value is zero)
  • a calibration 校准 error (the scale itself is wrong)
  • parallax 视差 (your eye is always to one side of the scale)

An analogue ammeter with a 0 to 5 A scale. With no current flowing the needle should rest on zero, but it rests just below the zero mark. A dashed line shows the true zero position and a small arrow marks the gap, labelled zero error An ammeter with a zero error: the needle reads below zero before any current flows

A pointer raised above a ruler, viewed by three eyes. The eye straight above reads the true value; an eye too far left reads too low and an eye too far right reads too high, because each sight line crosses the scale at a different mark Parallax error: different viewing angles give different scale readings

A systematic error makes the accuracy 准确度 worse, but it does not change the precision 精密度.

A random error 随机误差 makes readings jump above and below the true value, with no pattern. Causes include how carefully you read the scale, changing conditions, and the smallest step the instrument 仪器 can show. If you repeat the measurement many times and take the mean 平均值 (the average), random errors partly cancel out.

A random error makes the precision worse. But with enough repeats, the mean can still be accurate.

Precision and accuracy

Precision is how close repeated readings are to each other. Precise readings are grouped very close together.

Accuracy is how close a reading (or the mean of several readings) is to the true value.

Two distribution curves, both centred on the true value T. The top curve is narrow and tall, labelled precise and accurate; the bottom curve is wide and low, labelled imprecise but accurate. Both peaks sit on T, so precision is about how narrow the curve is Precision: how narrow the distribution is around the true value T

A set of readings can be:

  • precise and accurate — close together and near the true value
  • precise but not accurate — close together, but away from the true value (a systematic error)
  • accurate but not precise — spread out, but the mean is near the true value
  • neither — spread out and away from the true value

Two distribution curves whose peaks are both offset from the true value T. The top curve is narrow but its peak is to the right of T, labelled precise but not accurate; the bottom curve is wide and its peak is also to the right of T, labelled imprecise and not accurate. A double-headed arrow marks the offset from T in each Accuracy: whether the peak of the distribution is centred on the true value T

When a question gives a table of repeated readings, look at the spread (precision) and the mean (accuracy) separately.

Uncertainty in a derived quantity

A measurement is often written as $x \pm \Delta x$. Here $\Delta x$ is the absolute uncertainty 绝对不确定度. The percentage uncertainty 百分比不确定度 is

$$\text{percentage uncertainty in } x = \frac{\Delta x}{|x|} \times 100\%.$$

A derived quantity 导出量 is one you calculate from measured values. Its uncertainty is found by simple rules:

  • Adding or subtracting — add the absolute uncertainties. If $y = a + b$ or $y = a - b$, then $\Delta y = \Delta a + \Delta b$.
  • Multiplying or dividing — add the percentage uncertainties. If $y = \dfrac{a \cdot b}{c}$, then
    $$\frac{\Delta y}{|y|} = \frac{\Delta a}{|a|} + \frac{\Delta b}{|b|} + \frac{\Delta c}{|c|}.$$
  • Powers — multiply the percentage uncertainty by the power. If $y = a^{n}$, then $\dfrac{\Delta y}{|y|} = |n| \cdot \dfrac{\Delta a}{|a|}$.

Worked example. A ball's diameter 直径 is measured as $d = (5.26 \pm 0.02)\ \text{cm}$. The volume 体积 of a sphere is $V = \tfrac{4}{3}\pi r^{3} = \tfrac{4}{3}\pi (d/2)^{3}$, so $V \propto d^{3}$ ($V$ depends on $d$ cubed).

The percentage uncertainty in $d$ is

$$\frac{0.02}{5.26} \times 100\% \approx 0.38\%.$$

Because $V \propto d^{3}$, the percentage uncertainty in $V$ is three times this, about $1.14\%$. The volume is $\tfrac{4}{3}\pi(2.63)^{3} \approx 76.2\ \text{cm}^{3}$. So the absolute uncertainty is $0.0114 \times 76.2 \approx 0.87\ \text{cm}^{3}$. The final answer is $V = (76.2 \pm 0.9)\ \text{cm}^{3}$.

Significant figures

When you write a calculated quantity, give it the same number of significant figures 有效数字 as the least precise measurement you used — usually two or three in this syllabus. Too many significant figures makes the answer look more exact than it really is. Too few loses useful information.

Vocabulary Train
English Chinese Pinyin
measurement 测量 cè liáng
uncertainty 不确定度 bù què dìng dù
systematic error 系统误差 xì tǒng wù chā
zero error 零点误差 líng diǎn wù chā
calibration 校准 jiào zhǔn
parallax 视差 shì chà
accuracy 准确度 zhǔn què dù
precision 精密度 jīng mì dù
random error 随机误差 suí jī wù chā
instrument 仪器 yí qì
mean 平均值 píng jūn zhí
absolute uncertainty 绝对不确定度 jué duì bù què dìng dù
percentage uncertainty 百分比不确定度 bǎi fēn bǐ bù què dìng dù
derived quantity 导出量 dǎo chū liàng
diameter 直径 zhí jìng
volume 体积 tǐ jī
significant figures 有效数字 yǒu xiào shù zì
1.4

Scalars and vectors

Syllabus
  1. understand the difference between scalar and vector quantities and give examples of scalar and vector quantities included in the syllabus
  2. add and subtract coplanar vectors
  3. represent a vector as two perpendicular components

Source: Cambridge International syllabus

Resolving a force into components

A scalar 标量 has size only. A vector 矢量 has both size and direction.

Examples from the syllabus:

  • scalars: mass, time, temperature, energy, work, power, distance, speed, pressure, density 密度, electric charge 电荷
  • vectors: displacement 位移, velocity, acceleration, force (including weight), momentum 动量

Quick test: if it makes sense to ask "in which direction?", the quantity is a vector. You cannot ask "in which direction is the temperature?", so temperature is a scalar. You can ask "in which direction is the velocity?", so velocity is a vector.

Adding and subtracting vectors

A vector is drawn as an arrow: the direction of the arrow gives the direction of the quantity, and the length of the arrow (drawn to scale) gives the magnitude.

Two velocity vectors drawn as arrows to scale, with a north-south compass reference and a scale key of 1 unit to 5 metres per second. Arrow a points due east and is three units long for 15 metres per second; arrow b points due south and is two units long for 10 metres per second Vectors represented as arrows drawn to scale

To add two coplanar 共面 vectors (vectors in the same flat plane), draw them tip to tail. The resultant 合矢量 goes from the tail of the first arrow to the tip of the second.

To find $\vec{X} - \vec{Y}$, add the reverse of $\vec{Y}$: $\vec{X} + (-\vec{Y})$. The reverse of $\vec{Y}$ has the same size as $\vec{Y}$ but points the opposite way.

Adding and subtracting parallel vectors, drawn tip to tail. Row a: 20 N up plus 30 N up, stacked tip to tail, gives a 50 N resultant pointing up. Row b: 20 N up minus 30 N down, so the 30 N is drawn pointing down tip to tail, giving a 10 N resultant pointing down Adding and subtracting parallel vectors

If the two vectors are at right angles (90°), the size of the resultant is

$$|\vec{R}| = \sqrt{X^{2} + Y^{2}},$$

and its direction comes from $\tan\theta = Y / X$.

Worked example. A swimmer heads north at $1.2\ \text{m s}^{-1}$ across a river that flows east at $0.5\ \text{m s}^{-1}$. Find the size and direction of the resultant velocity.

The two velocities are perpendicular, so

$$|\vec{R}| = \sqrt{1.2^{2} + 0.5^{2}} = \sqrt{1.69} = 1.3\ \text{m s}^{-1},$$

at an angle $\tan\theta = 0.5/1.2$, giving $\theta \approx 23°$ east of north.

The swimmer example as a vector triangle: a 1.2 m/s north arrow and a 0.5 m/s east arrow drawn tip to tail, with the resultant from start to finish at angle theta east of north, of magnitude the square root of 1.2 squared plus 0.5 squared Two perpendicular vectors add to a resultant of size $\sqrt{X^2+Y^2}$ at angle $\theta$

If two vectors have the same size $F$ with an angle $2\alpha$ between them, the resultant has size $2F\cos\alpha$ and lies along the line that cuts the angle in half.

Splitting a vector into perpendicular parts

Any vector can be split into two perpendicular 垂直 (at right angles) components 分量. Usually these are horizontal 水平 and vertical 竖直, or along and across a surface. For a vector $\vec{v}$ at angle $\theta$ to the horizontal:

$$v_{\text{H}} = v\cos\theta, \qquad v_{\text{V}} = v\sin\theta.$$

A force F at angle theta to the horizontal, resolved into perpendicular components. A dashed horizontal arrow is the horizontal component F_H = F cos theta and a dashed vertical arrow is the vertical component F_V = F sin theta; together with F they form a right-angled triangle Resolving a vector into horizontal and vertical components

Choose the directions that make the problem easiest. On a slope (an inclined plane 斜面), split the weight into one part along the slope and one part at right angles to it:

$$W_{\parallel} = W\sin\theta, \qquad W_{\perp} = W\cos\theta,$$

where $\theta$ is the angle of the slope to the horizontal.

You split a vector into components whenever you need to know how much of it acts in one direction. For example: the part of a force that acts along a slope, or the horizontal and vertical parts of a ball's velocity after it is thrown.

Vocabulary Train
English Chinese Pinyin
scalar 标量 biāo liàng
vector 矢量 shǐ liàng
density 密度 mì dù
electric charge 电荷 diàn hè
displacement 位移 wèi yí
momentum 动量 dòng liàng
coplanar 共面 gòng miàn
resultant 合矢量 hé shǐ liàng
perpendicular 垂直 chuí zhí
component 分量 fèn liàng
horizontal 水平 shuǐ píng
vertical 竖直 shù zhí
inclined plane 斜面 xié miàn
Exercise sheet
1.4

Exam tips

  • Give every answer a unit, and check homogeneity — both sides of an equation must have the same base units.
  • Distinguish random error (reduce by repeating and averaging) from systematic error (a zero or calibration error that repeats do not remove).
  • Combine uncertainties: add absolute uncertainties when adding/subtracting, add percentage uncertainties when multiplying/dividing (and multiply the % by any power).
  • Distinguish precision (small spread) from accuracy (close to the true value).
  • Resolve a vector into perpendicular components ($F\cos\theta$, $F\sin\theta$); add vectors tip-to-tail or by components.

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