Photons and the photoelectric effect
導入済み| English | 意味 |
|---|---|
| photon/ˈfəʊtɒn/ | 光子 |
| work function/wɜːk ˈfʌŋkʃn/ | 仕事関数 |
What would explain this observation?
- Bright low-frequency light can fail to eject electrons while dim higher-frequency light succeeds. Photon 光子 energy depends on frequency, not intensity alone.
- Start with a prediction. State the quantities or features you would compare, then decide what evidence could distinguish two explanations.
Build the model
- A photon has energy proportional to frequency. The work function 逸出功 is the minimum energy needed to release an electron from a surface. Above threshold, excess photon energy can become electron kinetic energy.
- photon: A quantum of electromagnetic radiation; work function: Minimum surface energy needed to release an electron.
At fixed above-threshold frequency, increasing intensity mainly increases what?
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
Photon energy depends only on frequency (E = hf), so raising intensity at fixed frequency adds more photons, each unchanged. More photons above threshold liberate more electrons per second; the work function is a property of the surface.
Match each technical term to its precise meaning.
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Use the definitions to distinguish related quantities and processes.
Choose evidence that can test it
- Use photon energy = Planck constant × frequency. Maximum kinetic energy = photon energy - work function. Increasing intensity at fixed frequency increases photon arrival rate, not individual photon energy.
- Read axes carefully on a stopping-potential or kinetic-energy graph. Identify threshold frequency from the zero-energy intercept. State the metal and experimental conditions because work function is material-specific.
Which two habits make the investigation or model in this case more defensible?
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
Stating the conditions and assumptions lets others repeat the work exactly, and recording the supporting evidence lets them check the conclusion. Hiding disagreeing results removes the evidence that could challenge a wrong conclusion, and one measurement can never establish a wider claim.
Work from known quantities
- State the known values and their units. Choose the relation because its assumptions fit this case, then rearrange before substitution.
- Known: photon energy is 5.0 electronvolts and work function is 2.0 electronvolts. Maximum kinetic energy = photon energy - work function = 5.0 - 2.0 = 3.0 electronvolts. A 1.5 electronvolt photon cannot cause emission from that surface in this model.
Photon energy is 4.8 eV and work function 2.1 eV. Find maximum kinetic energy. Use the same sequence: known quantities → model → relation → substitution → unit and interpretation.
Photon energy is 4.8 eV and work function 2.1 eV. Find maximum kinetic energy.
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
The result is 2.7 eV. Known: photon energy 4.8 eV; work function 2.1 eV. Use maximum kinetic energy = photon energy - work function. KE max = 4.8 - 2.1 = 2.7 eV. A photon below 2.1 eV would eject nothing, however intense the light.
Check the conclusion and its limits
- Electrons do not accumulate many sub-threshold photons in the elementary single-photon model. Do not confuse photon number with photon energy.
- Return to the original observation. Explain what the result supports, which conditions it assumes, and one way to test a competing explanation.
Doubling light intensity doubles each photon energy at fixed frequency. This claim is false: Intensity is the number of photons arriving per second; photon energy is set by frequency alone (E = hf). Doubling intensity doubles the electron count, not each electron's energy - exactly what the photoelectric equation shows.
Photons and the photoelectric effect: Use photon energy = Planck constant × frequency. Maximum kinetic energy = photon energy - work function. Increasing intensity at fixed frequency increases photon arrival rate, not individual photon energy.
Doubling light intensity doubles each photon energy at fixed frequency.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
Intensity is the number of photons arriving per second; photon energy is set by frequency alone (E = hf). Doubling intensity doubles the electron count, not each electron's energy - exactly what the photoelectric equation shows.
A quantum of electromagnetic radiation: write the technical term.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
photon means A quantum of electromagnetic radiation.