| English | 意味 |
|---|---|
| specific heat capacity/spəˈsɪfɪk hiːt kəˈpæsɪti/ | 比熱容量 |
| latent heat/ˈleɪtənt hiːt/ | 潜熱 |
What would explain this observation?
- Two equal masses receive the same energy but show different temperature rises. Material properties determine how energy transfer changes temperature.
Build the model
- Specific heat capacity 比热容 is energy needed to raise the temperature of unit mass by one degree.
- Specific latent heat 潜热 relates energy to change of state without temperature change for the idealized process.
- specific heat capacity: Energy per mass per temperature rise.
- latent heat: Energy associated with a change of state.
Why can temperature stay constant while a pure substance melts?
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
During melting the incoming energy does work separating particles against their attractions - the latent heat - rather than raising kinetic energy, so temperature stays constant. Energy is still entering; it changes arrangement, not temperature.
Match each technical term to its precise meaning.
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
Use the definitions to distinguish related quantities and processes.
Choose evidence that can test it
- Temperature relates to particle motion in a model; internal energy includes kinetic and potential contributions.
- During a change of state, energy can change particle arrangements rather than temperature.
In the lab: Measure mass, electrical input and temperature change for an insulated block. Ensure the temperature sensor has good contact, allow time for equilibration, and consider energy transferred to the surroundings.
Which two habits make the investigation or model in this case more defensible?
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
Stating the conditions and assumptions lets others repeat the work exactly, and recording the supporting evidence lets them check the conclusion. Hiding disagreeing results removes the evidence that could challenge a wrong conclusion, and one measurement can never establish a wider claim.
Work from known quantities
- Known: a 0.50 kg block gains 2,000 J and rises 10 °C.
- Use E = mcΔT.
- Rearranging gives c = E/(mΔT). c = 2,000/(0.50×10) = 400 J per kilogram per degree.
- Heat loss would make the value inferred from electrical input too large.
Your turn: A 2 kg sample with c=500 J per kilogram per degree warms by 3 °C. Find energy gain.
A 2 kg sample with c=500 J per kilogram per degree warms by 3 °C. Find energy gain.
難易度 2/5 · 140 コイン + 今日初回完了時に小ボーナス付与
The result is 3000 J. Known: mass 2 kg; c = 500 J per kilogram per degree; temperature rise 3 degrees C. Use E = mc x temperature change. E = 2 x 500 x 3 = 3,000 J. This is the energy gained by the sample, ignoring losses.
Check the conclusion and its limits
- A flat section of a heating curve can show a phase change, not absence of energy transfer.
- Do not substitute temperature for a temperature difference in E = mcΔT.
Not true: A temperature plateau always means zero energy transfer. A plateau on a heating curve marks a phase change, where energy goes into changing particle arrangement as latent heat. Energy transfer continues; only the temperature pauses.
- Specific heat capacity is energy needed to raise the temperature of unit mass by one degree.
- Temperature relates to particle motion in a model; internal energy includes kinetic and potential contributions.
- Watch for: A flat section of a heating curve can show a phase change, not absence of energy transfer.
Write from an energy gain of 900 J
- A 0.25 kg sample has specific heat capacity 600 J per kilogram per degree and warms by 6 degrees.
- Find the energy gain. A temperature plateau is not zero energy transfer.
A temperature plateau always means zero energy transfer.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
A plateau on a heating curve marks a phase change, where energy goes into changing particle arrangement as latent heat. Energy transfer continues; only the temperature pauses.
Energy per mass per temperature rise: write the technical term.
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
specific heat capacity means Energy per mass per temperature rise.
A 0.25 kg sample with specific heat capacity 600 J per kilogram per degree warms by 6 degrees. What energy does it gain, and what can a temperature plateau mean?
Energy gain is mass times specific heat capacity times temperature rise. Latent heat is transferred without a temperature change.
What energy does the sample gain?
難易度 1/5 · 100 コイン + 今日初回完了時に小ボーナス付与
0.25 times 600 times 6 is 900 J. The prompt uses 2 kg, 500 J per kilogram per degree and a 3 degree rise.