Algorithmic efficiency · アルゴリズムの効率性
What we'll do
- Two programs can both be correct but take very different time.
- This lesson is about efficiency: how the work grows as the input grows.
- Read and think about the ideas; then a few short tasks let you count the steps yourself.
Counting the work
- We measure an algorithm by how many steps it does, not seconds.
- Steps in seconds depend on the computer; counting steps does not.
- More input usually means more steps. The question is how much more.
Reasonable vs unreasonable run time
- Some algorithms grow slowly: double the input, do about double the work.
- Some algorithms grow fast: a little more input means a huge jump in work.
- "Reasonable" run time grows slowly enough to finish; "unreasonable" blows up.
Input size: 10 20 40
Search a list: 10 20 40 (slow growth - reasonable)
Try all orders: 3,628,800 ... a number with 48 digits (explodes!)
A tiny demo: counting steps
- Below we count the comparisons a linear search makes.
- The count grows in step with the list size — slow, steady growth.
- Try changing the size to see the count follow it.
def count_steps(n):
steps = 0
data = list(range(n))
target = -1 # not in the list, so we scan everything
for item in data:
steps = steps + 1
if item == target:
break
return steps
print(count_steps(10))
print(count_steps(20))
print(count_steps(40))
When fast is not enough
- Some problems have no known fast algorithm.
- The only methods try a huge number of possibilities — too slow for big input.
- For these, we often accept a good-enough answer instead of the perfect one.
Undecidable problems
- Worse than slow: some problems cannot be solved by any algorithm at all.
- These are called undecidable problems.
- No matter how fast computers get, no program can always give the right answer.
Fast : finishes quickly, even for big input
Slow but doable : finishes, but may take a very long time
Undecidable : no algorithm can solve it for every input
Key ideas to remember
- Efficiency is about how work grows with input size.
- Slow-growing algorithms scale to big inputs; fast-growing ones do not.
- Some problems are unreasonable to solve exactly, and some are undecidable.
Common mistakes
- Big-O describes how the running time GROWS with the input size.
- A reasonable-time algorithm scales; an unreasonable one does not.
Now you try
- Write small functions that count steps to feel how the work grows.
- Compare a single loop, a nested loop, and "try all orders". Press Check answer.
How algorithms scale · アルゴリズムのスケーリング
As input grows, O(n²) explodes while O(log n) barely moves. · 入力が大きくなると、O(n²) は 爆発的 に増大するのに対し、O(log n) はほとんど動きません。
Write scan_compares(data, target) that returns how many comparisons a linear search makes. Compare each item to target, counting one each time, and stop as soon as you find it. If it is not in the list, you compared every item. Example: scan_compares([5, 8, 2], 8) → 2. · scan_compares(data, target) を書き、線形探索が行う比較回数を 返す ようにします。各アイテムを target と比較し、每一次計数し、 見つけ次第停止 します。リストにない場合は全アイテムと比較しました。例: scan_compares([5, 8, 2], 8) → 2 。
Click Run to see the output here. · 実行ボタンをクリックして出力を確認してください。
Write pair_count(n) that uses a loop inside a loop (both over range(n)) and returns how many times the inner step runs. This is n × n. Example: pair_count(3) → 9. This grows much faster than a single loop. · pair_count(n) を記述し、ループの中にループ(どちらも range(n) に対するループ)を使って、内側のステップが何回実行されるかを返してください。これは n × n です。例:pair_count(3) → 9。単一のループよりもはるかに大きく成長します。
Click Run to see the output here. · 実行ボタンをクリックして出力を確認してください。
Write count_orderings(n) that returns how many different orders n items can be placed in — that is 1 × 2 × ... × n (n factorial). count_orderings(0) is 1. Example: count_orderings(3) → 6. Notice how fast it explodes: count_orderings(10) is over 3 million. · count_orderings(n) を書き、n 個のアイテムを並べ替える異なる順序がいくつあるかを返す——つまり 1 × 2 × ... × n (n の階乗) を計算する。count_orderings(0) は 1 です。例:count_orderings(3) → 6。その爆発的な増大に気づいてください:count_orderings(10) は 3 百万を超えます。
Click Run to see the output here. · 実行ボタンをクリックして出力を確認してください。