Running sum

Return a new array where position i holds the sum of all elements up to and including i: [1, 2, 3, 4] → [1, 3, 6, 10]. Keep a running total and fill a fresh int[] of the same length.

Complete runningSum(int[] nums) so result position i is the sum nums[0] + ... + nums[i]. Example: [1,2,3,4] becomes [1,3,6,10].

public class Solution {
    public static int[] runningSum(int[] nums) {
        return nums;   // change this
    }
}

Click Run to see the output here.

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Running sum

Running sum

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