Algorithms: searching
What we'll do
- An algorithm is a clear list of steps that solves a problem.
- A very common job is searching: find where a value is in a list.
- We will learn two algorithms: linear search and binary search.
Linear search
- Check the items one by one, from start to end.
- If you find the value, return its index (position).
- If you reach the end and never find it, return
-1.
def linear_search(lst, target):
for i in range(len(lst)):
if lst[i] == target:
return i
return -1
print(linear_search([4, 8, 15, 16], 15))
print(linear_search([4, 8, 15, 16], 99))
Why a sorted list helps
- Linear search works on any list, even a messy one.
- But if the list is sorted (small to big), we can be much faster.
- Binary search uses the sorted order to skip half the list each time.
Binary search
- Look at the middle item.
- If it is the target, you are done.
- If the target is smaller, search the left half; if bigger, the right half. Repeat.
def binary_search(sorted_lst, target):
low = 0
high = len(sorted_lst) - 1
while low <= high:
mid = (low + high) // 2
if sorted_lst[mid] == target:
return mid
elif sorted_lst[mid] < target:
low = mid + 1
else:
high = mid - 1
return -1
print(binary_search([1, 3, 5, 7, 9], 7))
print(binary_search([1, 3, 5, 7, 9], 4))
Putting ideas together
- A search combines three building blocks you already know.
- Sequencing: do steps in order. Selection:
if/elif/else. - Iteration: a loop (
fororwhile) repeats the check.
In AP CSP pseudocode
- The exam writes a loop and a check like this.
FOR EACHvisits every item;IFselects;REPEAT UNTILloops until a test is true.
PROCEDURE contains(list, target)
{
FOR EACH item IN list
{
IF (item = target)
{
RETURN(true)
}
}
RETURN(false)
}
Common mistakes
- Binary search needs a sorted list.
- Linear search checks each item in turn.
Now you try
- Each task gives a procedure name and what it must return.
- Press Check answer to test your code.
Searching a list
Binary search needs a sorted list but is far faster than linear.
Difficulty 3/5 · 200 coins + a small bonus on first completion today
Write linear_search(lst, target). Return the index of target in lst, or -1 if it is not there. Check items one by one.
Click Run to see the output here.
Difficulty 3/5 · 200 coins + a small bonus on first completion today
Write binary_search(sorted_lst, target) for a list sorted small to big. Return the index of target, or -1. Look at the middle and cut the search in half each time.
Click Run to see the output here.
Difficulty 3/5 · 200 coins + a small bonus on first completion today
Write contains(lst, target) that returns True if target is in lst, else False. You may reuse linear search and compare the result to -1.
Click Run to see the output here.