Format respons kuantitatif: semua nilai valid dan entri numerik
GRE General Test Topik 10 2:27 Narasi bahasa Inggris · Subtitle bahasa Inggris + 中文 disematkan langsung
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This unit selects every allowed answer without assuming a fixed number, states numerical answers in the requested form and unit, and uses estimation and substitution to verify a result.
本单元选出所有允许的答案而不预设数量，按要求的形式和单位给出数值答案，并用估算和代入来验证结果。
Read the response instruction before calculating, and note restrictions such as integer, positive or rounded.
计算前先看作答要求，并注意整数、正数或四舍五入等限制。
Solving a transformed equation yields candidates: a denominator or an unsquared radical can remove one, so substitute into the original.
解变形后的方程得到的是候选值：分母或未平方的根式可能排除其中一个，所以要代回原式。
A requested fraction and a requested decimal need different entry forms; equivalent fractions are accepted.
要求分数和要求小数时，输入形式不同；等值分数都可接受。
Round only at the end when told to, and check units: a percent of 25 differs from a probability of 0.25.
只在被要求时于最后一步四舍五入，并检查单位：百分数 25 与概率 0.25 不同。
Estimate before the calculator to catch an order-of-magnitude slip.
用计算器前先估算，以发现数量级错误。
x minus 2 times x plus 3 equals zero gives minus 3 and 2, both verified; if x must be positive, only 2 remains.
(x − 2)(x + 3) = 0 得 −3 和 2，都经验证；若 x 必须为正，只剩 2。
Three of eight counters marked gives 3 over 8, so enter 0.375, not the percent 37.5 or the count 3.
8 个筹码中 3 个有标记，概率 3/8，所以输入 0.375，而不是百分数 37.5 或个数 3。
The number of correct select-all choices comes from the constraints, not from a guessed pattern.
多选题正确答案的个数由约束条件决定，而不是猜出来的规律。
Numeric form is part of the task.
数值的形式也是题目要求的一部分。
The original radical requires x nonnegative.
原式的根式要求 x 非负。
Squaring gives x squared minus x minus 6 equals zero, with candidates 3 and minus 2.
平方得 x² − x − 6 = 0，候选值 3 和 −2。
The candidate -2 fails the sign condition and substitution.
候选值 −2 不满足符号条件，代入也不成立。
At 3 both sides equal three.
x = 3 时两边都等于 3。
For the counters, 7 over 20 is 0.35, not 35.
筹码题中 7/20 = 0.35，不是 35。
The first restriction keeps the integers minus 2 to 3, and the strict squared inequality excludes -1,0,1 at once.
第一个限制保留 −2 到 3 的整数，严格的平方不等式排除了 −1、0、1。
Four fails the strict upper end, and -3 fails the lower bound.
4 不满足严格的上界，−3 不满足下界。
And 7 over 12 is 0.5833, which rounds to 0.58.
7/12 = 0.5833…，四舍五入为 0.58。
Check yourself.
自我检测。
With x positive, the roots leave 2.
x 为正时只剩 2。
The radical equation has 3 only.
根式方程只有 3。
Three eighths is 0.375.
3/8 = 0.375。
The integers are minus 2, 2 and 3.
整数是 −2、2、3。
And 7 twelfths rounds to 0.58.
7/12 约为 0.58。